NCERT Solutions for Class 9 Maths Chapter 13 (Ex 13.7)
NCERT Solutions for Class 9 Maths Chapter 13: Surface Areas and Volumes - Exercise 13.7
FAQs on NCERT Solutions for Class 9 Maths Chapter 13: Surface Areas and Volumes - Exercise 13.7
1. How many questions are there in NCERT Solution for Class 9 Math Chapter 13 Surface Areas And Volumes Exercise 13.7?
For Chapter 13 Exercise 13.7 in Class 9 Math, there are 9 questions in the NCERT. The questions in this exercise are based on calculating a cone's volume. Students will gain a deeper knowledge of the concepts by practising the NCERT solutions for Class 9 Math Chapter 13 Surface Areas And Volumes Exercise 13.7 offered by Vedantu, which will also help them lay a strong foundation for advanced mathematics courses.
2. What fundamental formulas must students be familiar with to tackle the problems NCERT Class 9 Math Chapter 13 Surface Areas And Volumes Exercise 13.7?
Numerous crucial formulas are covered in the NCERT answers for Class 9 Maths Chapter 13, Exercise 13.7 that students should pay attention to. The idea of finding the formula for the volume of a right circular cone is the main theme of NCERT solutions for Class 9 Math Chapter 13 Surface Areas And Volumes Exercise 13.7. The following are a few crucial formulas :
Volume of a Cone = $(\dfrac{1}{3}) \pi r^2 h$
Curved Surface Area of Cone = $\pi r l$
Download free Vedantu NCERT Solutions PDFs and get started learning!
3. When a cone's height and diameter are known, how can its volume be determined?
We are aware that a cone's volume is equal to (1/3 )πr2h
Where r and h are the radius and height of the given cone.
Let us assume d to be the diameter of the given cone.
Since r = \dfrac{d}{2}
The volume of a cone is $V=\dfrac{1}{3} \pi (\dfrac{d}{2})^2 h$ cubic units
Therefore, if a cone's height and diameter are known, its volume may be calculated using the formula $\dfrac{1}{3} \pi (\dfrac{d}{2})^2 h$ cubic units.
4. How to calculate the area of the base of a cone?
The cone's flat face, which is a circle, forms its base. Therefore, the area of this circle alone constitutes the base area of a cone, which is given by A = πr2 where r is the base radius. The formula A = π(D/2)2 = (πD2)/4 where D is the base's diameter, can also be used to express the cone's base area in terms of its diameter.
5. Where can I get the NCERT Solutions for Class 9 Math Chapter 13 Surface Areas And Volumes Exercise 13.7?
The NCERT Solutions for Class 9 Math Chapter 13 Surface Areas And Volumes Exercise 13.7 are easily accessible via the Vedantu website or app. Vedantu's highly educated and experienced teachers ensure that you get the best and most easily understandable solutions to help you grasp the topic better.