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RD Sharma Solutions for Class 9 Maths Chapter 14 – Quadrilaterals

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RD Sharma Class 9 Maths Quadrilaterals Solutions - Free PDF Download

Students can refer to the RD Sharma Solutions of Class 9 Chapter 14. The solutions are based on the new and latest concepts introduced in the CBSE syllabus of mathematics. The textbooks contain the major content with the updated information and the updated syllabus, which are useful to the students while solving the problems.


Vedantu is a platform that provides free CBSE Solutions (NCERT) and other study materials for students. You can also register Online for Class 9 Science and Class 9 Maths tuition on Vedantu.com to score more marks in your examination.

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Class 9 RD Sharma Textbook Solutions Chapter 14 - Quadrilaterals

Important Theories

  • The sum of all four quadrilateral angles is 360 °.

  • The diagonal of the parallelogram divides it into two interlocking triangles.

  • A quadrilateral is a parallelogram if

o   The opposite sides are equal.

o   The opposing angles are equal,

o   Diagonals are divided into two.

  • A quadrilateral is a parallelogram if

o   Its opposing angles are equal.

o   Its opposite sides are equal.

o   Its diagonals are split in two.

  • A pair of opposite sides are equal and parallel.

  • Rectangular diagonals are divided into two and are equal and opposite.

  • The rhombus diagonals are separated by right angles and are not evenly spaced.

  • Square diagonals divide the other two into right angles and are equal and vice versa.

  • A part of a line connecting points between any two sides of a triangle corresponds to a third and is equal to half of it. (Mid-point theorem)

  • A line drawn in the centre of one side of the triangle, in line with the other side, crosses the third side in its centre. (Speaking of mid-point theorem)

  • A quadrilateral formed by combining points between quadrilateral sides, taken in sequence, parallelogram.

  • In a quadrilateral, if the diagonals divide by two, then form a parallelogram.


Properties of a Parallelogram:

  • A diagonal of a parallelogram, dividing it into parallel triangles.

  • In parallelograms, the opposing sides are equal.

  • In parallelograms, opposing angles are equal.

  • The diagonal of the parallelogram is divided into two parts.


Angle Sum Property Quadrilateral

The sum of the four quadrilateral angles is 360 °. Angle Sum Property when we draw a quadrilateral diagonal, it divides it into two triangles.


We also know that the angle sum property of a triangle i.e. the sum of all the three angles of the triangle is 180 °.


Total angle ∆ADC = 180 °.


Total angle ∆ABC = 180 °.


By adding both we get ∠A + ∠B + ∠C + ∠D = 360 °


Thus, the sum of four quadrilateral angles is 360 °.


The Mid-point Theorem

  • If a line segment joins the midpoints of the two sides of the triangle then it will be parallel to the third side of the triangle.

  • If AB = BC and CD = DE then BD ∥ AE.

  • If a line starts from the midpoint of one line and that line is parallel to the third line then it will intersect the midpoint of the third line.

  • If D is the midpoint of AB and DE∥ BC then E is the midpoint of AC.


Benefits of Studying RD Sharma Solutions for Class 9 Chapter 14 Quadrilaterals from Vedantu

  • Vedantu RD Sharma Class 9 Maths Solutions is believed to be one of the best online resources you can rely on to prepare for your exam.

  • Vedantu RD Sharma solutions were developed to adhere to CBSE guidelines. Our experts have designed solutions in simple steps, straightforward and easy to understand.

  • When you refer to these solutions, you do not need a teacher or teacher's guidance to solve RD Sharma problems for class 9 chapter 14. This is the ultimate solution. Vedantu RD Sharma Solutions will really bring a good increase in your school performance in your exams.


Is it important to practice RD Sharma Solutions for Class 9 Maths Chapter 14 Daily?

Yes, students who practice RD Sharma Solutions Class 9 Chapter 14 daily understand complex concepts in a simple way. These solutions provide a clear description of each step that helps students grasp a variety of ways to solve problems easily. The expertise of experts has developed solutions in an accurate way with the aim of developing cognitive knowledge among students.

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FAQs on RD Sharma Solutions for Class 9 Maths Chapter 14 – Quadrilaterals

1. How do the RD Sharma Solutions for Class 9 Maths Chapter 14 help in preparing for exams?

Vedantu's RD Sharma Solutions for Class 9 Maths Chapter 14 are designed to build a strong conceptual foundation for Quadrilaterals. They provide step-by-step explanations for a wide variety of problems, ranging from basic to advanced. By practising these solutions, students can master the application of theorems, improve their problem-solving speed, and gain the confidence needed to tackle any question in their final exams.

2. What is the step-by-step method to prove a quadrilateral is a parallelogram using the approaches in RD Sharma solutions?

RD Sharma solutions for Chapter 14 demonstrate several methods to prove a quadrilateral is a parallelogram. As per the CBSE 2025-26 syllabus, you can prove it if you can show any one of the following conditions is true:

  • Both pairs of opposite sides are equal.

  • Both pairs of opposite angles are equal.

  • The diagonals bisect each other.

  • One pair of opposite sides is both equal and parallel.

The solutions provide detailed proofs for problems based on each of these properties.

3. How do the problems in RD Sharma Class 9 Chapter 14 on Quadrilaterals differ from those in the NCERT textbook?

While NCERT provides the fundamental concepts and problems for Quadrilaterals, RD Sharma offers a more extensive collection of questions. RD Sharma includes a higher volume of practice problems, a wider variety of question types, and more challenging Higher Order Thinking Skills (HOTS) questions. Using RD Sharma solutions helps students build on their NCERT foundation and prepare for more complex questions that may appear in exams.

4. How does RD Sharma explain and apply the Mid-Point Theorem in Chapter 14?

RD Sharma's solutions thoroughly cover the Mid-Point Theorem, which states that the line segment joining the mid-points of any two sides of a triangle is parallel to the third side and half of it. The solutions demonstrate its application in numerous proofs within the Quadrilaterals chapter. They break down complex geometrical figures to show how this theorem can be used to establish relationships between sides and prove properties of parallelograms, rectangles, and other shapes.

5. What is the best way to use the RD Sharma solutions for Chapter 14 to master complex proofs?

To master complex proofs using RD Sharma solutions, first try to solve the problem on your own. This will help you identify your areas of difficulty. Afterwards, refer to the solution to understand the correct logical flow and the theorems applied at each step. Focus on why a particular property was used rather than just memorising the steps. This approach ensures you are learning the underlying concepts and can solve similar problems independently.

6. Why is it crucial to understand the properties of special quadrilaterals (like rhombus and rectangle) when solving problems in RD Sharma?

Understanding the unique properties of special quadrilaterals is essential because many problems in RD Sharma are based on them. For instance, knowing that the diagonals of a rhombus bisect each other at right angles or that the diagonals of a rectangle are equal provides the key conditions needed to solve specific proofs. Without a clear understanding of these properties, it becomes very difficult to construct a logical argument for the proof-based questions in the exercises.

7. What common mistakes do students make when solving questions from RD Sharma Chapter 14, and how can solutions help?

Common mistakes in this chapter include applying incorrect properties to a given quadrilateral, making logical gaps in proofs, and misunderstanding the conditions of theorems like the Mid-Point Theorem. The detailed RD Sharma solutions help by:

  • Clearly stating the reasons and theorems for each step in a proof.

  • Providing a structured and logical flow that is easy to follow.

  • Reinforcing the correct application of properties, which helps students recognise and avoid these common errors in the future.