NCERT Solutions for Class 9 Maths Chapter 4: Linear Equations in Two Variables - Exercise 4.1

EXERCISE 4.1

1. The cost of a notebook is twice the cost of a pen. Write a linear equation in two variables to represent this statement. (Take the cost of a notebook to be Rs. \[\text{x}\] and that of a pen to be Rs. \[\text{y}\] ) 

Ans. Let the cost of a notebook be Rs. \[x\] and the cost of a pen be Rs. \[y\] .

We know that the cost of a notebook is twice the cost of a pen.

Therefore, we can write the required linear equation in the form:

\[Cost\text{ }of\text{ }notebook\text{ }=\text{ }2\text{ }\times \text{ }Cost\text{ }of\text{ }pen~~\]

\[x=2y~\]

\[x-2y~=0\] 

2. Express the following linear equations in the form \[\text{ax+by+c= 0}\] and indicate the values of \[\text{a}\] , \[\text{b}\] , \[\text{c}\] in each case: 

(i) \[\text{2x+3y=9}\text{.3}\overline{\text{5}}\]

Ans. Writing the given equation in standard form \[\text{ax+by+c= 0}\] :

\[2x+3y=9.3\overline{5}\]

\[2x+3y-9.3\overline{5}=0\]

Comparing this equation with standard form of the linear equation, \[\text{ax+by+c= 0}\] we have:

\[a=2\]

\[b=3\]

\[c=-9.3\overline{5}\]

(ii) \[\text{x-}\frac{\text{y}}{\text{5}}\text{-10=0}\]

Ans. Writing the given equation in standard form \[\text{ax+by+c= 0}\] :

\[x-\frac{y}{5}-10=0\]

\[5x-y-50=0\]

Comparing this equation with standard form of the linear equation, \[\text{ax+by+c= 0}\] we have:

\[a=5\]

\[b=-1\]

\[c=-50\]

(iii) \[\text{-2x+3y=6}\] 

Ans. Writing the given equation in standard form \[\text{ax+by+c= 0}\] :

\[-2x+3y=6\]

\[-2x+3y-6=0\]

Comparing this equation with standard form of the linear equation, \[\text{ax+by+c= 0}\] we have:

\[a=-2\]

\[b=3\]

\[c=-6\]

(iv) \[\text{x=3y}\]

Ans. Writing the given equation in standard form \[\text{ax+by+c= 0}\] :

\[x=3y\]

\[x-3y=0\]

Comparing this equation with standard form of the linear equation, \[\text{ax+by+c= 0}\] we have:

\[a=1\]

\[b=-3\]

\[c=0\]

(v) \[2x=-5y\] 

Ans. Writing the given equation in standard form \[\text{ax+by+c= 0}\] :

\[2x=-5y\]

\[2x+5y=0\]

Comparing this equation with standard form of the linear equation, \[\text{ax+by+c= 0}\] we have:

\[a=2\]

\[b=5\]

\[c=0\]

(vi) \[\text{3x+2=0}\]

Ans. Writing the given equation in standard form \[\text{ax+by+c= 0}\] :

\[3x+2=0\]

Comparing this equation with standard form of the linear equation, \[\text{ax+by+c= 0}\] we have:

\[a=3\]

\[b=0\]

\[c=2\]

(vii) \[\text{y-2=0}\] 

Ans. Writing the given equation in standard form \[\text{ax+by+c= 0}\] :

\[y-2=0\]

Comparing this equation with standard form of the linear equation, \[\text{ax+by+c= 0}\] we have:

\[a=0\]

\[b=1\]

\[c=-2\]

(viii) \[\text{5=2x}\]

Ans. Writing the given equation in standard form \[\text{ax+by+c= 0}\] :

\[5=2x\]

\[-2x+5=0\]

Comparing this equation with standard form of the linear equation, \[\text{ax+by+c= 0}\] we have:

\[a=-2\]

\[b=0\]

\[c=5\]

NCERT Solutions for Class 9 Maths Chapter 4 Linear Equations in Two Variables (Ex 4.1) Exercise 4.1

Opting for the NCERT solutions for Ex 4.1 Class 9 Maths is considered as the best option for the CBSE students when it comes to exam preparation. This chapter consists of many exercises. Out of which we have provided the Exercise 4.1 Class 9 Maths NCERT solutions on this page in PDF format. You can download this solution as per your convenience or you can study it directly from our website/ app online.

Vedantu in-house subject matter experts have solved the problems/ questions from the exercise with the utmost care and by following all the guidelines by CBSE. Class 9 students who are thorough with all the concepts from the Subject Maths textbook and quite well-versed with all the problems from the exercises given in it, then any student can easily score the highest possible marks in the final exam. With the help of this Class 9 Maths Chapter 4 Exercise 4.1 solutions, students can easily understand the pattern of questions that can be asked in the exam from this chapter and also learn the marks weightage of the chapter. So that they can prepare themselves accordingly for the final exam.

Besides these NCERT solutions for Class 9 Maths Chapter 4 Exercise 4.1, there are plenty of exercises in this chapter which contain innumerable questions as well. All these questions are solved/answered by our in-house subject experts as mentioned earlier. Hence all of these are bound to be of superior quality and anyone can refer to these during the time of exam preparation. In order to score the best possible marks in the class, it is really important to understand all the concepts of the textbooks and solve the problems from the exercises given next to it. 

Do not delay any more. Download the NCERT solutions for Class 9 Maths Chapter 4 Exercise 4.1 from Vedantu website now for better exam preparation. If you have the Vedantu app in your phone, you can download the same through the app as well. The best part of these solutions is these can be accessed both online and offline as well.

NCERT Solutions for Class 9 Maths

• Chapter 1 - Number System

• Chapter 2 - Polynomials 

• Chapter 3 - Coordinate Geometry

• Chapter 4 - Linear Equations in Two Variables

• Chapter 5 - Introductions to Euclids Geometry

• Chapter 6 - Lines and Angles

• Chapter 7 - Triangles

• Chapter 8 - Quadrilaterals

• Chapter 9 - Areas of Parallelogram and Triangles

• Chapter 10 - Circles

• Chapter 11 - Constructions

• Chapter 12 - Herons formula

• Chapter 13 - Surface area and Volumes

• Chapter 14 - Statistics

• Chapter 15 - Probability

List of Exercises and Topics Covered in Linear Equation In Two Variable Class 9:

• Exercise 4.1 - Linear Equations

• Exercise 4.2 - Solution of a Linear Equation

• Exercise 4.3 - Graph of a Linear Equation in Two Variables

• Exercise 4.4 - Equations of Lines Parallel to the x-axis and y-axis