Class 9 Maths Chapter 3 Exercise 3.2: The World of Numbers
Exercise 3.2 gives you a chance to look at numbers from a different angle and apply the ideas introduced in The World of Numbers. The questions encourage you to work out patterns, use number properties, and explain your reasoning.
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The Class 9 Maths Chapter 3 Exercise 3.2 solutions present these ideas simply, so you can understand the method rather than just note the answer.
When a question feels difficult, going through the NCERT solutions for Class 9 Maths Chapter 3 Exercise 3.2 can help you see where to begin and how the solution develops. Try each question first, then use the NCERT Maths solutions for Class 9, Chapter 3, Exercise 3.2 to check your approach and strengthen your understanding.
FAQs on NCERT Solutions for Class 9 Maths Chapter 3 Exercise 3.2 2026-27
1. How do you solve a temperature drop of 15°C from 4°C?
Represent the drop by −15 and calculate 4 + (−15). Therefore, the midnight temperature is −11°C.
2. How is a loan represented using integers in Exercise 3.2?
A loan or debt is represented by a negative integer. For example, a loan of ₹850 is written as −850.
3. What is the final financial standing of the spice trader in Question 2?
The calculation is −850 + 1200 − 450 = −100. Thus, the trader remains ₹100 in debt.
4. What happens when a negative number is multiplied by a positive number?
The result is negative. For example, (−12) × 5 = −60.
5. Why is the product of two negative numbers positive?
Using the debt-and-removal idea in the exercise, removing a debt increases your financial position. Hence, (−3) × (−4) = +12.
6. How do you calculate 0 − (−14)?
Subtracting a negative number is equivalent to adding its positive value: 0 − (−14) = 0 + 14 = 14.
7. What is the answer to (−20) ÷ 4 in Class 9 Maths Chapter 3 Exercise 3.2?
A negative number divided by a positive number gives a negative result. Therefore, (−20) ÷ 4 = −5.
8. Why does 10 − (−5) become 10 + 5?
The exercise explains a negative value as a debt. Removing a debt of ₹5 improves the position by ₹5, so 10 − (−5) = 15.
9. What are Brahmagupta’s laws used for in Exercise 3.2?
They help determine the signs and results when performing multiplication and division with positive and negative numbers.
10. What should students remember when solving integer questions in Chapter 3?
Pay close attention to the signs before operating. A positive or negative sign can change the meaning and final result of the calculation.
11. How do the Class 9 Maths Chapter 3 solutions exercise 3.2 explain integer operations?
They explain addition, subtraction, multiplication, and division of integers using examples involving temperature, debt, profit, and loss.
12. Where can I find Class 9 Maths Chapter 3 Exercise 3.2 question answers?
Vedantu provides the Class 9 Maths Chapter 3 Exercise 3.2 question answers with step-by-step explanations for the exercise and the Think and Reflect activity.
13. Why are Chapter 3 maths class 9 exercise 3.2 solutions useful for revision?
They bring together the key calculations and concepts from Exercise 3.2, making it easier to review integer operations and sign rules before a test.
14. What is the main idea behind the debt example in Exercise 3.2?
It shows that a negative number can represent a debt and that removing a debt can be understood as adding a positive amount.
