NCERT Solutions For Class 6 Maths Chapter 10 The Other Side Of Zero Exercise 10.2 - 2025-26
In NCERT Solutions Class 6 Maths Chapter 10 Exercise 10 2, you’ll discover how to use the token model to understand positive and negative numbers around zero. This exercise makes tricky ideas—like adding and subtracting negatives—much more simple with easy examples. If you’re ever puzzled by what happens “on the other side of zero,” this solution is designed just for you.
Table of Content
Vedantu provides detailed, step-by-step solutions for all questions in this exercise. Need a quick practice or want to double-check your answers? Download the free PDFs and enjoy clear explanations that make exam preparation feel stress-free. You can also refer to the Class 6 Maths syllabus if you’d like to see how this fits within your year’s topics.
Using these NCERT Solutions, you’ll build a strong base in working with negative numbers—an awesome skill for future maths chapters. If you want to explore more, you can always find all the NCERT Solutions for Class 6 Maths as well.
Exercise 10.2
1. Complete the additions using tokens.
a. (+6)+(+4)
Ans: For (+6), we use 6 positive tokens
And for (+4), we use 4 positive tokens
Therefore, by combining we will get
(+6) + ( +4) = (+10)
Hence, Counting all the positive tokens we get (+10)
b. (−3)+(−2)
Ans: For (-3) we use 3 negative tokens
For (-2) we use 2 negative tokens
Token
Now combining them we will get
(-3) + (-2) = -5
Hence, counting all the negative tokens we get (-5)
c. (+5)+(−7)
Ans: For (+5) we use 5 positive tokens
For (-7) we use 7 negative tokens
Now, combining them we will get
Therefore, remaining tokens -= -2
d. (−2)+(+6)
Ans: For (-2) we use 2 negative tokens
For (+6) we use 6 positive tokens
Now, combining we will get
(-2) +(+6) = +4
Hence, Remaining tokens are (+4)
2. Cancel the zero pairs in the following two sets of tokens. On what floor is the lift attendant in each case? What is the corresponding addition statement in each case?
Ans:
a. From the given image we can remove 3 pairs
Therefore the remaining are 2 negative tokens
The lift attendant is on the second floor below the ground floor.
The corresponding addition statement = (+3)+(-5) = (-2)
b. From the given image we can remove 3 pairs.
The remaining are 3 positive tokens.
The lift attendant is on the third floor above the ground floor.
The corresponding addition statement = (+6) + (-3) = (+3)
3. Evaluate the following differences using tokens. Check that you get the same result as with other methods you now know:
a. (+10) –(+7) b. (–8)– (–4) c. (–9) –(–4)
d. (+9) –(+12) e. (–5)– (–7) f. (–2) –(–6)
Ans:
a. Here there are 10 positive tokens take away 7 positive tokens
Therefore, (+10)-(+7) = (+3)
b. Here there are -8 negative tokens take away -4 negative tokens
Therefore, (-8) -( - 4) = (-4)
c. Here there are -9 negative tokens take away -4 negative tokens
Therefore, (-9) -( - 4) = (-5)
d. There are not enough tokens to take out 12 positive tokens from 9 positive tokens.
So we put an extra 3 zero pairs ( 1 pair = a positive and a negative token)
Now we can take out 12 positive tokens
Therefore, (+9) - (+12) = (-3)
e. There are ot enough tokens to take out -7 negative tokens from -5 negative tokens.
So, we put extra 2 zero pairs( 1 pair = a positive and a negative token)
Now, we can take out -7 negative tokens.
Hence, (-5)-(-7) = +2
f. There are not enough tokens to take out -6 negative tokens from -2 negative tokens
So, we put extra 4 zero pairs (1 pair = a negative and a positive token)
Now we can take out -6 negative tokens
Hence, (-2)-(-6) = (+4)
4. Complete the subtractions:
a. (–5) –(–7) b. (+10) –(+13) c. (–7) –(–9)
d. (+3) – (+8) e. (–2) –(–7) f. (+3)–(+15)
Ans:
a. There are not enough tokens to take out -7 negative tokens from -5 negative tokens.
So, we take an extra 2 Zero pairs (1 pair = a positive and a negative token)
Now, we can take out -7 negative tokens.
Hence, (-5)-(-7) = +2
b. There are not enough tokens to take out +10 positive tokens from +13 positive tokens.
So, we take an extra 3 Zero pairs (1 pair = a positive and a negative token)
Now, we can take out +13 positive tokens.
Hence, (+10)-(+13) = -3
c. There are not enough tokens to take out -9 negative tokens from -7 negative tokens.
So, we take an extra 2 Zero pairs (1 pair = a positive and a negative token)
Now, we can take out -9 negative tokens.
Hence, (-7)-(-9) = +2
d. There are not enough tokens to take out +8 positive tokens from +3 positive tokens.
So, we take an extra 5 Zero pairs (1 pair = a positive and a negative token)
Now, we can take out +8 positive tokens.
Hence, (+3) -(+8) = -5
e. There are not enough tokens to take out -7 negative tokens from -2 negative tokens.
So, we take an extra 2 Zero pairs (1 pair = a positive and a negative token)
Now, we can take out -7 negative tokens.
Hence, (-2) - (-7) = +5
f. There are not enough tokens to take out +15 positive tokens from +3 positive tokens.
So, we take an extra 12 Zero pairs (1 pair = a positive and a negative token)
Now, we can take out +15 positive tokens.
Hence, (+3) - (+15) = -12
5. Try to subtract: –3– (+5).
How many zero pairs will you have to put in? What is the result?
Ans: Here we have to take out 5 positives from -3 negatives. But there are not enough positive tokens.
So, we put down an extra 5 zero pairs (1 pair = a negative and positive token)
Now, we can take out 5 positive tokens
Hence, -3-(+5) = - 8
6. Evaluate the following using tokens.
a. (–3)–(+10) b. (+8)– (–7) c. (–5)–(+9)
d. (–9) – (+10) e. (+6) –(–4) f. (–2)–(+7)
Ans:
a. Here we have to take 10 positive tokens from -3 negative tokens. But there are not enough positive tokens.
So, we put down an extra 10 zero pairs (1 pair = a positive and a negative token)
Now, we can take out 10 positive tokens
Hence (-3) - (+10) = -13
b. Here we have to take out -7 negative tokens from 8 positives. But there are not enough negative tokens.
So, we put down an extra 10 zero pairs.(1 pair = a negative and a positive pair)
Now, we can take out 10 positive tokens.
Hence, (-3)-(+10) = -13
b. Here we have to take out -7 negative tokens from 8 positive tokens. Butu there are not enough negative tokens.
So, we put down an extra 7 zero pairs (1 pair = a negative and a positive pair)
Now we can take out -7 negatives tokens
Hence, -5-(+9) = - 14
c. Here we have to take out 9 positives from -5 negative tokens. But there are not enough positive tokens.
So, we put extra 9 zero pairs (1 pair = a positive and a negative token)
Now we can take out 9 positive tokens.
Hence -5 - (-9) = =-14
d. Here we have to take out 10 positive tokens from -9 negative tokens. Butu there are not enough positive tokens.
So, we put down an extra 10 zero pairs (1 pair = a negative and a positive pair)
Now we can take out 10 positive tokens
Hence, -9-(+10) = -19
e. Here we have to take out -4 negative tokens from 6 positive tokens. But there are not enough negative tokens.
So, we put down an extra 4 zero pairs (1 pair = a negative and a positive pair)
Now we can take out -4 negative tokens
Hence, (+6)-(-4) =10
f. Here we have to take out 7 positive tokens from -2 negative tokens. Butu there are not enough positive tokens.
So, we put down an extra 7 zero pairs (1 pair = a negative and a positive pair)
Now we can take out 7 positive tokens
Hence, (-2) - (+7) = -9
Benefits of NCERT Solutions for Class 6 Maths Chapter 10 Exercise 10.2 The Other Side of Zero
Provides clear explanations of the token model, helping students understand positive and negative numbers.
Utilises visual aids to represent numbers, making it easier for students to grasp abstract concepts.
Provides real-life examples where positive and negative numbers are applicable, making the learning relevant.
Encourages students to think critically about how numbers interact on the number line, fostering deeper mathematical reasoning.
The solutions are based on the NCERT curriculum, ensuring that all the important topics are covered thoroughly.
Class 6 Maths Chapter 10: Exercises Breakdown
Important Study Material Links for Class 6 Maths Chapter 10 - The Other Side of Zero
Conclusion
The NCERT Solutions for Class 6 Maths Chapter 10, "The Other Side of Zero," particularly Exercise 10.2 "The Token Model," plays an important role in enhancing students' understanding of numbers. By introducing the token model, students can visualise positive and negative numbers more clearly, making abstract concepts easier to understand. The detailed solutions and structured exercises build confidence and promote critical thinking skills. This chapter not only reinforces foundational math concepts but also prepares students for future topics involving integers. Overall, Vedantu’s solutions provide essential support for students to master these key ideas, ensuring a solid base for their ongoing mathematical journey.
Chapter-Specific NCERT Solutions for Class 6 Maths
The chapter-wise NCERT Solutions for Class 6 Maths are given below. Go through these chapter-wise solutions to be thoroughly familiar with the concepts.
Related Important Links for Maths Class 6
Along with this, students can also download additional study materials provided by Vedantu for Maths Class 6.
FAQs on NCERT Solutions For Class 6 Maths Chapter 10 The Other Side Of Zero Exercise 10.2 - 2025-26
1. Where can I find accurate and step-by-step NCERT Solutions for Class 6 Maths Chapter 10, Mensuration, for the 2025-26 session?
You can find reliable and detailed NCERT Solutions for Class 6 Maths Chapter 10, Mensuration, on Vedantu. Our solutions are prepared by subject matter experts and follow the latest CBSE 2025-26 guidelines, providing a clear, step-by-step methodology for solving every problem in the textbook exercises.
2. What is the main concept taught in Exercise 10.1 of NCERT Class 6 Maths Chapter 10?
Exercise 10.1 primarily focuses on understanding and calculating the perimeter of different closed figures. The NCERT solutions demonstrate the correct method, which involves adding the lengths of all sides of a shape to find the total length of its boundary.
3. How do the NCERT Solutions explain the method for finding the area of a rectangle in Chapter 10?
The NCERT Solutions for Chapter 10 explain that the area of a rectangle is the space it covers. The correct method is to use the formula: Area = length × breadth. The solutions provide solved examples with different units to help you master this concept.
4. What is the fundamental difference between 'perimeter' and 'area' as explained in the Mensuration chapter?
The key difference is what each term measures:
- Perimeter is the total length of the boundary of a closed figure (a one-dimensional measurement). Think of it as the length of a fence needed for a garden.
- Area is the total surface or region enclosed within that boundary (a two-dimensional measurement). Think of it as the space available to plant flowers inside the garden.
5. Why is it important to use the same units while solving Mensuration problems?
It is crucial to use the same units (e.g., all centimetres or all metres) when calculating perimeter or area. If you multiply a length in metres by a breadth in centimetres, the result will be incorrect. The NCERT solutions for Chapter 10 consistently show the step-by-step process of converting measurements to a uniform unit before applying any formula.
6. Can two different rectangles have the same area but different perimeters? How do NCERT Solutions address this?
Yes, two rectangles can have the same area but different perimeters. For example, a rectangle of 8 cm × 3 cm has an area of 24 sq cm and a perimeter of 22 cm. Another rectangle of 6 cm × 4 cm also has an area of 24 sq cm, but its perimeter is 20 cm. The NCERT Solutions for Chapter 10 include such comparative problems to build a deeper understanding of how dimensions affect area and perimeter differently.
7. How are the problems in Exercise 10.3 of the Mensuration chapter solved?
Exercise 10.3 contains problems focused on calculating the area of squares and rectangles, including word problems that require you to compare the areas of two figures. The NCERT solutions provide detailed, step-by-step calculations for each question, showing how to apply the correct formulas (Area of square = side × side; Area of rectangle = length × breadth) to find the correct answer.
8. How do the NCERT Solutions for Class 6 Maths Chapter 10 help in solving real-world problems?
These solutions help apply mathematical concepts to real-life situations. For instance, they guide you on how to solve problems like finding the cost of fencing a field (using perimeter) or calculating the number of tiles needed for a floor (using area). This practical approach makes learning more intuitive and useful.
