NCERT Solutions for Class 6 Maths Chapter 8 Decimals

Exercise 8.1  – Hundredth

Just as the tenth, the hundredth decimal is also a part of the student’s syllabus as they learn about how this decimal helps in calculation. There are different examples present to ease the student’s process of learning this segment.

Exercise 8.2 – Comparing Decimals

This part of  Chapter 8 Class 6 Maths focuses on comparing decimals that usually start with the tenth place. The student needs to understand which decimal is greater and how through this segment.

Exercise 8.3 – Using Decimals

Decimals are quite applicable in normal day calculation, and the inclusion of Class 6 Chapter 8 Decimals is to enable students to learn more about them. This basic knowledge will prove to be useful for students in later years.

Exercise 8.4 – Addition of Numbers with Decimals

Learning how to perform the addition of decimals without breaking them can ease the calculation process. This part itself is quite important and is usually where most examination questions tend to come from.

Access NCERT Solutions for Class 6 Maths Chapter 8 – Decimals

Exercise-8.1

1. Which is greater?

1. $$0.3$$ or $$0.4$$

2. $$0.07$$ or $$0.02$$

3. $$3$$ or $$0.8$$

4. $$0.5$$ or $$0.05$$

5. $$1.23$$ or $$1.2$$

6. $$0.099$$ or $$0.19$$

7. $$1.5$$ or $$1.50$$

8. $$1.431$$ or $$1.490$$

9. $$3.3$$ or $$3.300$$

10. $$5.64$$ or $$5.603$$

Ans:

1. $$0.3$$ or $$0.4$$

Whole parts for the two numbers are the same but it can be seen that the tenth part of $$0.4$$ is greater than that of $$0.3$$.

$$\therefore \,\,\,\,0.4 > 0.3$$

2. $$0.07$$ or $$0.02$$

Here, given two numbers have the same parts up to the tenth place but the hundredth part of $$0.07$$ is greater than that of $$0.02$$.

$$\therefore \,\,\,\,0.07 > 0.02$$

3. $$3$$ or $$0.8$$

Here, it can be seen that the whole part of $$3$$ is greater than that of $$0.8$$.

$$\therefore \,\,\,\,3 > 0.8$$

4. $$0.5$$ or $$0.05$$

Here, the whole parts of these given two numbers are same but It can be seen that the tenth part of $$0.5$$ is greater than that of $$0.05$$.

$$\therefore \,\,\,\,0.5 > 0.05$$

5. $$1.23$$ or $$1.2$$

Here, the whole and tenth parts of these given two numbers are same but It can be seen that the hundredth part of $$1.23$$ is greater than that of $$1.2$$.

$$\therefore \,\,\,\,1.23 > 1.2$$

6. $$0.099$$ or $$0.19$$

Here, the whole parts of these given two numbers are same but It can be seen that the tenth part of $$0.19$$ is greater than that of $$0.099$$.

$$\therefore \,\,\,\,0.19 > 0.099$$

7. $$1.5$$ or $$1.50$$

Here, the whole and tenth parts of these given two numbers are the same. Also, there is no digit at the hundredth place of $$1.5$$, this implies that this digit will be $$0$$, which is the same as the digit at the hundredth place of $$1.50$$. Therefore, both the numbers are equal. 

$$\therefore \,\,\,\,1.5 = 1.50$$

8. $$1.431$$ or $$1.490$$

Here, the whole and tenth parts of these given two numbers are same but It can be seen that the hundredth part of $$1.490$$ is greater than that of $$1.431$$.

$$\therefore \,\,\,\,1.490 > 1.431$$

9. $$3.3$$ or $$3.300$$

Here, the whole and tenth parts of these given two numbers are the same. Also, there is no digit at the hundredth and thousandth place of $$3.3$$, this implies that this digit will be $$0$$, which is the same as the digit at the hundredth and thousandth place of $$3.300$$. Therefore, both the numbers are equal. 

$$\therefore \,\,\,\,3.3 = 3.300$$

10. $$5.64$$ or $$5.603$$

Here, the whole and tenth parts of these given two numbers are same but It can be seen that the hundredth part of $$5.64$$ is greater than that of $$5.603$$.

$$\therefore \,\,\,\,5.64 > 5.603$$

Q2. Make five more examples and find the greater:

1. $$1.8$$ or $$1.82$$ 

2. $$1.0009$$ or $$1.09$$

3. $$10.01$$ or $$100.1$$ 

4. $$5.100$$ or $$5.0100$$

5.  $$04.213$$ or $$0421.3$$

Ans:

1. $$1.8$$ or $$1.82$$ 

$$\therefore \,\,\,\,1.82 > 1.8$$

2. $$1.0009$$ or $$1.09$$

$$\therefore \,\,\,\,1.09 > 1.0009$$

3. $$10.01$$ or $$100.1$$ 

$$\therefore \,\,\,\,100.1 > 10.01$$

4. $$5.100$$ or $$5.0100$$

$$\therefore \,\,\,\,5.100 > 5.0100$$

5.  $$04.213$$ or $$0421.3$$

$$\therefore \,\,\,\,0421.3 > 04.213$$

Exercise-8.2

Q1. Express as rupees using decimals:

(a) $$5$$ paise

(b) $$75$$ paise 

(c) $$20$$ paise

(d) $$50$$ rupees $$90$$ paise 

(e) $$725$$ paise

Ans:

We know that: 

$$1$$ rupee $$ = $$ $$100$$ paise

$$1$$ paise $$ = $$ $$\dfrac{1}{{100}}$$ rupee.

1. $$5$$ paise 

$$ \Rightarrow \,\,5 \times \dfrac{1}{{100}}$$

$$ \Rightarrow \,\,\dfrac{5}{{100}} = 0.05$$

$$\therefore \,\,\,5$$ paise $$ = $$$$0.05$$ Rs.

2. $$75$$ paise 

$$ \Rightarrow \,\,75 \times \dfrac{1}{{100}}$$

$$ \Rightarrow \,\,\dfrac{{75}}{{100}} = 0.75$$

$$\therefore \,\,\,75$$ paise $$ = $$$$0.75$$ Rs.

3. $$20$$ paise 

$$ \Rightarrow \,\,20 \times \dfrac{1}{{100}}$$

$$ \Rightarrow \,\,\dfrac{{20}}{{100}} = 0.2$$

$$\therefore \,\,\,20$$ paise $$ = $$$$0.2$$ Rs.

4. $$50$$ rupees $$90$$ paise 

$$ \Rightarrow \,\,5 + 90 \times \dfrac{1}{{100}}$$

$$ \Rightarrow \,\,5 + \dfrac{{90}}{{100}} = 5 + 0.9 = 5.9$$

$$\therefore \,\,\,5$$ rupees $$90$$ paise $$ = $$$$5.9$$ Rs.

5. $$20$$ paise 

$$ \Rightarrow \,\,20 \times \dfrac{1}{{100}}$$

$$ \Rightarrow \,\,\dfrac{{20}}{{100}} = 0.2$$

$$\therefore \,\,\,20$$ paise $$ = $$$$0.2$$ Rs.

Q2. Express as meters using decimals:

(a) $$15$$cm

(b) $$6$$cm 

(c) $$2$$m $$45$$cm

(d) $$9$$m $$7$$cm 

(e) $$419$$cm

Ans:

We know that: 

$$1$$m $$ = $$ $$100$$cm

$$1$$cm $$ = $$ $$\dfrac{1}{{100}}$$ m.

1. $$15$$ cm 

$$ \Rightarrow 15 \times \dfrac{1}{{100}}$$

$$ \Rightarrow \dfrac{{15}}{{100}} = 0.15$$

$$\therefore 15$$cm $$ = $$$$0.15$$m.

2. $$6$$ cm 

$$ \Rightarrow \,\,6 \times \dfrac{1}{{100}}$$

$$ \Rightarrow \,\,\dfrac{6}{{100}} = 0.06$$

$$\therefore \,\,\,6$$cm $$ = $$$$0.06$$m.

3. $$2$$ m $$45$$ cm 

$$ \Rightarrow \,\,2 + 45 \times \dfrac{1}{{100}}$$

$$ \Rightarrow \,\,2 + \dfrac{{45}}{{100}} = 2 + 0.45 = 2.45$$

$$\therefore \,\,\,2$$ m $$45$$cm $$ = $$$$2.45$$m.

4. $$9$$ m $$7$$ cm 

$$ \Rightarrow \,\,9 + 7 \times \dfrac{1}{{100}}$$

$$ \Rightarrow \,\,9 + \dfrac{7}{{100}} = 9 + 0.07 = 9.07$$

$$\therefore \,\,\,9$$ m $$7$$cm $$ = $$$$9.07$$m.

5. $$419$$ cm 

$$ \Rightarrow \,\,419 \times \dfrac{1}{{100}}$$

$$ \Rightarrow \,\,\dfrac{{419}}{{100}} = 4.19$$

$$\therefore \,\,\,419$$cm $$ = $$$$4.19$$m.

Q3. Express as cm using decimals: 

(a) $$5$$mm

 (b) $$60$$mm 

(c) $$164$$mm

 (d) $$9$$cm $$8$$mm 

(e) $$93$$mm

Ans:

We know that: 

$$1$$cm $$ = $$ $$10$$mm

$$1$$mm $$ = $$ $$\dfrac{1}{{10}}$$cm.

1. $$5$$mm 

$$ \Rightarrow \,\,5 \times \dfrac{1}{{10}}$$

$$ \Rightarrow \,\,\dfrac{5}{{10}} = 0.5$$

$$\therefore \,\,\,5$$mm $$ = $$ $$0.5$$cm.

2. $$60$$ mm 

$$ \Rightarrow \,\,60 \times \dfrac{1}{{10}}$$

$$ \Rightarrow \,\,\dfrac{{60}}{{10}} = 6.0$$

$$\therefore \,\,\,60$$mm $$ = $$ $$6.0$$cm.

3. $$164$$mm 

$$ \Rightarrow \,\,164 \times \dfrac{1}{{10}}$$

$$ \Rightarrow \,\,\dfrac{{164}}{{10}} = 16.4$$

$$\therefore \,\,\,164$$mm $$ = $$ $$16.4$$cm.

4. $$9$$ cm $$8$$ mm 

$$ \Rightarrow \,\,9 + 8 \times \dfrac{1}{{10}}$$

$$ \Rightarrow \,\,9 + \dfrac{8}{{10}} = 9 + 0.8 = 9.8$$

$$\therefore \,\,\,9$$ cm $$8$$ mm $$ = $$ $$9.8$$ cm.

5. $$93$$ mm 

$$ \Rightarrow \,\,93 \times \dfrac{1}{{10}}$$

$$26$$

$$\therefore \,\,\,93$$mm $$ = $$ $$9.3$$cm.

Q4. Express as km using decimals: 

(a) $$8$$ m

(b) $$88$$ m 

(c) $$8888$$ m

(d) $$70$$ km $$5$$ m

Ans:

We know that: 

$$1$$km $$ = $$ $$1000$$m

$$1$$m $$ = $$ $$\dfrac{1}{{1000}}$$ km.

1. $$8$$ m 

$$ \Rightarrow \,\,8 \times \dfrac{1}{{1000}}$$

$$ \Rightarrow \,\,\dfrac{8}{{1000}} = 0.008$$

$$\therefore \,\,\,8$$ m $$ = $$ $$0.008$$km.

2. $$88$$ m 

$$ \Rightarrow \,\,88 \times \dfrac{1}{{1000}}$$

$$ \Rightarrow \,\,\dfrac{{88}}{{1000}} = 0.088$$

$$\therefore \,\,\,88$$ m $$ = $$ $$0.088$$km.

3. $$8888$$ m 

$$ \Rightarrow \,\,8888 \times \dfrac{1}{{1000}}$$

$$ \Rightarrow \,\,\dfrac{{8888}}{{1000}} = 8.888$$

$$\therefore \,\,\,8888$$ m $$ = $$ $$8.888$$km.

4. $$70$$ km $$5$$ m 

$$ \Rightarrow \,70 + 5 \times \dfrac{1}{{1000}}$$

$$ \Rightarrow \,\,70 + \dfrac{5}{{1000}} = 70 + 0.005 = 70.005$$

$$\therefore \,\,\,70$$ km $$5$$ m $$ = $$ $$70.005$$ km.

5. Express as kg using decimals: 

(a) $$2$$ g

(b) $$100$$ g 

(c) $$3750$$ g

(d) $$5$$ kg $$8$$ g 

(e) 26 kg 50 g

Ans:

We know that: 

$$1$$kg $$ = $$ $$1000$$g

$$1$$g $$ = $$ $$\dfrac{1}{{1000}}$$ kg.

1. $$2$$ g 

$$ \Rightarrow \,\,2 \times \dfrac{1}{{1000}}$$

$$ \Rightarrow \,\,\dfrac{2}{{1000}} = 0.002$$

$$\therefore \,\,\,2$$ g $$ = $$ $$0.002$$ kg.

2. $$100$$ g 

$$ \Rightarrow \,\,100 \times \dfrac{1}{{1000}}$$

$$ \Rightarrow \,\,\dfrac{{100}}{{1000}} = 0.1$$

$$\therefore \,\,\,100$$ g $$ = $$ $$0.1$$ kg.

3. $$3750$$ g 

$$ \Rightarrow \,\,3750 \times \dfrac{1}{{1000}}$$

$$ \Rightarrow \,\,\dfrac{{3750}}{{1000}} = 3.750$$

$$\therefore \,\,\,3750$$ g $$ = $$ $$3.750$$ kg.

4. $$5$$ kg $$8$$ g 

$$ \Rightarrow \,\,5 + 8 \times \dfrac{1}{{1000}}$$

$$ \Rightarrow \,\,5 + \dfrac{8}{{1000}} = 5 + 0.008 = 5.008$$

$$\therefore \,\,\,5$$ kg $$8$$ g $$ = $$ $$5.008$$ kg.

5. $$26$$ kg $$50$$ g 

$$ \Rightarrow \,\,26 + 50 \times \dfrac{1}{{1000}}$$

$$ \Rightarrow \,\,26 + \dfrac{{50}}{{1000}} = 26 + 0.050 = 26.05$$

$$\therefore \,\,\,26$$ kg $$50$$ g $$ = $$ $$26.05$$ kg.

Exercise-8.3

1. Find the sum in each of the following: 

(a) $$0.007{\text{ }} + {\text{ }}8.5{\text{ }} + {\text{ }}30.08$$

(b) $$15{\text{ }} + {\text{ }}0.632{\text{ }} + {\text{ }}13.8$$

(c) $$27.076{\text{ }} + {\text{ }}0.55{\text{ }} + {\text{ }}0.004$$

(d) $$25.65{\text{ }} + {\text{ }}9.005{\text{ }} + {\text{ }}3.7$$

(e) $$0.75{\text{ }} + {\text{ }}10.425{\text{ }} + {\text{ }}2$$

(f) $$280.69{\text{ }} + {\text{ }}25.2{\text{ }} + {\text{ }}38$$

Ans:

(a) $$0.007{\text{ }} + {\text{ }}8.5{\text{ }} + {\text{ }}30.08$$

$ \ \ \ \  0.007 $

$ + \ 8.5 $ 

$ \underline{+ \ 30.08} $ 

$ \ \ \ \ 38.587 $

$$\therefore \,\,\,0.007{\text{ }} + {\text{ }}8.5{\text{ }} + {\text{ }}30.08 = 38.587$$

(b) $$15{\text{ }} + {\text{ }}0.632{\text{ }} + {\text{ }}13.8$$

$ \ \ \ \  15.000 $

$ + \ \ 0.632 $

$ \underline{+ \ 13.8} $ 

$ \ \ \ \ 29.132$

$$\therefore \,\,\,15{\text{ }} + {\text{ }}0.632{\text{ }} + {\text{ }}13.8 = 29.132$$

(c) $$27.076{\text{ }} + {\text{ }}0.55{\text{ }} + {\text{ }}0.004$$

 $ \ \ \ \  27.076 $ 

             $ + \ \ 0.55 $

 $\underline{+ \ \ 0.0004}$ 

 $ \ \ \ \ 27.6304$

$$\therefore \,\,\,\,27.076{\text{ }} + {\text{ }}0.55{\text{ }} + {\text{ }}0.004 = 27.630$$

(d) $$25.65{\text{ }} + {\text{ }}9.005{\text{ }} + {\text{ }}3.7$$

$ \ \ \ \  25.65 $ 

$+ \ \ 9.005 $

$ \underline{+ \ \ 3.7} $ 

 $ \ \ \ \ 38.355 $

$\therefore \,\,\,\,25.65{\text{ }} + {\text{ }}9.005{\text{ }} + {\text{ }}3.7 = 38.355$$

(e) $$0.75{\text{ }} + {\text{ }}10.425{\text{ }} + {\text{ }}2$$

 $ \ \ \ \  \ 0.75 $

$ + \ 10.425$ 

$ \underline{+ \ \  2.0} $

$ \ \ \ \ 13.175 $

$$\therefore \,\,\,\,0.75{\text{ }} + {\text{ }}10.425{\text{ }} + {\text{ }}2 = 13.175$$

(f) $$280.69{\text{ }} + {\text{ }}25.2{\text{ }} + {\text{ }}38$$

$ \ \ \ \  280.69$ 

$ + \ \  25.2 $

$ \underline{+ \ \ 38.0} $

$ \ \ \ \ 343.89 $ 

$$\therefore \,\,\,\,280.69{\text{ }} + {\text{ }}25.2{\text{ }} + {\text{ }}38 = 343.89$$

Q2. Rashid spent $$Rs.{\text{ }}35.75$$ for Maths book and $$Rs.{\text{ }}32.60$$ for Science book. Find the total amount spent by Rashid. 

Ans:

The money spent on Maths books = $$Rs.{\text{ }}35.75$$

The money spent for Science books = $$Rs.{\text{ }}32.60$$

Total money spent = $$Rs.{\text{ }}35.75{\text{ }} + {\text{ }}Rs.{\text{ }}32.60{\text{ }} = {\text{ }}Rs.{\text{ }}68.35$$

Therefore, the total amount spent by Rashid is $$Rs.{\text{ }}68.35$$.

Q3. Radhika’s mother gave her $$Rs.{\text{ }}10.50$$ and her father gave her $$Rs.{\text{ }}15.80$$. Find the total amount given to Radhika by the parents. 

Ans: 

Money given by Radhika’s mother = $$Rs.{\text{ }}10.50$$

Money given by Radhika’s father = $$Rs.{\text{ }}15.80$$

Total money received by Radha = $$Rs.{\text{ }}10.50{\text{ }} + {\text{ }}Rs.{\text{ }}15.80{\text{ }} = {\text{ }}Rs.{\text{ }}26.30$$

Therefore, the total amount given to Radhika by her parents is $$Rs.{\text{ }}26.30$$.

Q4. Nasreen bought $$3m{\text{ }}20cm$$ cloth for her shirt and $$2m{\text{ }}5cm$$ cloth for her trouser. Find the total length of cloth bought by her. 

Ans: 

The cloth bought for shirt = $$3m{\text{ }}20cm{\text{ }} = 3.20m$$

The cloth bought for trouser = $$2m{\text{ }}5cm{\text{ }} = {\text{ }}2.05m$$

Total length of cloth bought by Nasreen = $$3.20+2.05 = 5.25m$$

Therefore, the total length of cloth bought by Nasreen is $$5.25{\text{ }}m\,\, = \,5m\,25cm$$.

Q5. Naresh walked $$2km\,35m$$ in the morning and $$1km\,7m$$ in the evening. How much distance did he walk in all? 

Ans: 

The distance travelled in morning = $$2{\text{ }}km{\text{ }}35{\text{ }}m{\text{ }} = {\text{ }}2.035{\text{ }}km$$

The distance travelled in evening = $$1{\text{ }}km{\text{ }}7{\text{ }}m{\text{ }} = {\text{ }}1.007{\text{ }}km$$

Total distance travelled = $$2.035+1.007 = 3.042km$$

Therefore, the total distance covered by Naresh is $$3.042km\,\, = \,3km\,42m$$.

Q6. Sunita travelled $$15{\text{ }}km{\text{ }}268{\text{ }}m$$ by bus, $$7{\text{ }}km{\text{ }}7{\text{ }}m$$ by car and $$500{\text{ }}m$$ by foot in order to reach her school. How far is her school from her residence? 

Ans:

The distance travelled by bus = $$15{\text{ }}km{\text{ }}268{\text{ }}m{\text{ }} = {\text{ }}15.268{\text{ }}km$$

The distance travelled by car = $$7km{\text{ }}7m = 7.007km$$

The distance travelled on foot = $$500m= 0.500km$$

Total distance travelled = $$15.268+7.007+0.500 = 22.775km$$

Therefore, the distance between Sunita’s residence and her school is $$22.775{\text{ }}km\,\, = \,\,22km\,\,775m$$.

Q7. Ravi purchases $$5{\text{ }}kg{\text{ }}400{\text{ }}g$$ rice, $$2{\text{ }}kg{\text{ }}20{\text{ }}g$$ sugar and $$10{\text{ }}kg{\text{ }}850{\text{ }}g$$ flour. Find the total weight of his purchases.

Ans:

The weight of Rice $$ = {\text{ }}5{\text{ }}kg{\text{ }}400{\text{ }}g{\text{ }} = {\text{ }}5.400{\text{ }}kg$$

The weight of Sugar = $$2{\text{ }}kg{\text{ }}20{\text{ }}g{\text{ }} = {\text{ }}2.020{\text{ }}kg$$

The weight of Flour = $$10{\text{ }}kg{\text{ }}850{\text{ }}g{\text{ }} = {\text{ }}10.850{\text{ }}kg$$

Total weight = $$5.400{\text{ }} + {\text{ }}2.020{\text{ }} + {\text{ }}10.850{\text{ }} = {\text{ }}18.270{\text{ }}kg$$

Therefore, the total weight of Ravi purchases is $$18.270{\text{ }}kg\,\, = \,\,18kg\,\,270g$$.

Exercise-8.4

Q1. Subtract: 

(a) $$Rs.{\text{ }}18.25$$ from $$Rs.{\text{ }}20.75$$

(b) $$202.54{\text{ }}m$$ from $$250{\text{ }}m$$

(c) $$Rs.{\text{ }}5.36$$ from $$Rs.{\text{ }}8.40$$

(d) $$2.051{\text{ }}km$$ from $$5.206{\text{ }}km$$

(e) $$0.314{\text{ }}kg$$ from $$2.107{\text{ }}kg$$

Ans:

Given that both quantities have the same quantity, we can subtract.

1. $$Rs.{\text{ }}18.25$$ from $$Rs.{\text{ }}20.75$$

$20,.75$

$ \underline { - \,18\,\,.\,\,25}$

$2.50 $

Therefore, $$Rs.\,\,20.75\,\, - \,\,Rs.{\text{ }}18.25 = Rs.\,2.50$$

2. $$202.54{\text{ }}m$$ from $$250{\text{ }}m$$

$250.00$

$\underline{ -202.54} $

$47.46 $

Therefore, $$250m - 202.54m = 47.46m$$

3. $$Rs.{\text{ }}5.36$$ from $$Rs.{\text{ }}8.40$$

$8\,\,.\,\,40$

$\underline {-5.36}$

$3.04$

Therefore, $$Rs.\,\,8.40 - Rs.{\text{ }}5.36 = Rs.\,\,3.04$$

4. $$2.051{\text{ }}km$$ from $$5.206{\text{ }}km$$

$5.206$ 

$ \underline { -2.051}$

$3.155 $

Therefore, $$5.206\,km\, - 2.051{\text{ }}km = 3.155\,km$$

5. $$0.314{\text{ }}kg$$ from $$2.107{\text{ }}kg$$

$2.107$

$ \underline {-0.314}$ 

$1.793$

Therefore, $$2.107\,kg\, - 0.314{\text{ }}kg = 1.793\,kg$$

2. Find the value of: 

(a) $$9.756{\text{ }}-{\text{ }}6.28$$                              

(b) $$21.05{\text{ }}-{\text{ }}15.27$$

(c) $$18.5{\text{ }}-{\text{ }}6.79$$                                

 (d) $$11.6{\text{ }}-{\text{ }}9.847$$

Ans:

1. $$9.756{\text{ }}-{\text{ }}6.28$$

 $9.756 $

$ \underline {-6.280} $ 

$3.476$

$$\therefore 9.756{\text{ }}-{\text{ }}6.28 = 3.476$$

2. $$21.05{\text{ }}-{\text{ }}15.27$$

 $21.05$

 $\underline {-15.27}$

$5.78$

$$\therefore \,\,\,21.05{\text{ }}-{\text{ }}15.27 = 5.78$$

3. $$18.5{\text{ }}-{\text{ }}6.79$$

$18.50$

$\underline {-6.79}$

$11.71$

$$\therefore \,\,\,18.5{\text{ }}-{\text{ }}6.79 = 11.71$$

4. $$18.5{\text{ }}-{\text{ }}6.79$$

$11.600$

$\underline {-9.847}$

$1.753$

$$\therefore \,\,\,11.6{\text{ }}-{\text{ }}9.847 = 1.753$$

Q3. Raju bought a book of $$Rs.{\text{ }}35.65.$$ He gave $$Rs.{\text{ }}50$$ to the shopkeeper. How much money did he get back from the shopkeeper?

Ans:

The total amount given to shopkeeper = $$Rs.{\text{ }}50$$

The cost of book = $$Rs.{\text{ }}35.65$$

Amount left = $$Rs.{\text{ }}50.00{\text{  -  }}Rs.{\text{ }}35.65{\text{ }} = {\text{ }}Rs.{\text{ }}14.35$$

Therefore, $$Rs.{\text{ }}14.35$$ will get back from the shopkeeper to Raju.

Q4. Rani had $$Rs.{\text{ }}18.50.$$ She bought one ice-cream for $$Rs.{\text{ }}11.75.$$ How much money does she have now?

Ans: 

The total money = $$Rs.{\text{ }}18.50$$

The cost of Ice-cream = $$Rs.{\text{ }}11.75$$

Amount left = $$Rs.{\text{ }}18.50{\text{ }}-{\text{ }}Rs.{\text{ }}11.75{\text{ }} = {\text{ }}Rs.{\text{ }}6.75$$

Therefore, Rani has $$Rs.{\text{ }}6.75$$.

Q5. Tina had $$20{\text{ }}m{\text{ }}5{\text{ }}cm$$ long cloth. She cuts $$4m{\text{ }}50cm$$ length of cloth from this for making a curtain. How much cloth is left with her?

Ans: 

The total length of cloth $$ = {\text{ }}20{\text{ }}m{\text{ }}5{\text{ }}cm$$= $$20.05{\text{ }}m$$

The length of cloth used = $$4{\text{ }}m{\text{ }}50{\text{ }}cm{\text{ }} = {\text{ }}4.50{\text{ }}m$$

Remaining cloth = $$20.05{\text{ }}m{\text{ }}-{\text{ }}4.50{\text{ }}m{\text{ }} = {\text{ }}15.55{\text{ }}m$$

Therefore $$15.55{\text{ }}m$$ cloth is left with her.

Q6. Namita travels $$20{\text{ }}km{\text{ }}50m$$ every day. Out of this she travels $$10km{\text{ }}200m$$ by bus and the rest by auto. How much distance does she travel by auto?

Ans: The total distance travel = $$20km{\text{ }}50m = 20.050km$$

Distance travelled by bus = $$10km{\text{ }}200m = 10.200km$$

Distance travelled by auto = $$20.050-10.200 = 9.850km$$

Therefore, $$11.6-9.847$$ distance covered by Namita through auto.

Q7. Aakash bought vegetables weighing $$10kg.$$ Out of this $$3kg{\text{ }}500g$$ in onions, $$2kg{\text{ }}75g$$ is tomatoes and the rest is potatoes. What is the weight of the potatoes?

Ans: 

The weight of onions = $$3kg{\text{ }}500g = 3.500kg$$

The weight of tomatoes = $$2kg{\text{ }}75g = 2.075kg$$

Total weight of onions and tomatoes = $$3.500+2.075 = 5.575kg$$

The weight of potatoes = $$10kg - 5.575kg = 4.425kg$$

Therefore, the weight of potatoes is $$4kg\,425g$$.

Overview of Deleted Syllabus for CBSE Class 6 Maths Decimals

Class 6 Maths Chapter 8: Exercises Breakdown

Conclusion

In conclusion, Class 6 Maths Chapter 8 Decimals Solutions provides a comprehensive understanding of decimals, an important mathematical concept with wide-ranging applications. Through Class 6 Chapter 8 Decimals PDF, students have learned to identify and use the place value system for decimals, convert between fractions and decimals, and perform basic arithmetic operations involving decimals. They have also developed skills to compare and order decimal numbers, enhancing their numerical literacy.

Other Study Material for CBSE Class 6 Maths Chapter 8

Chapter-Specific NCERT Solutions for Class 6 Maths

Given below are the chapter-wise NCERT Solutions for Class 6 Maths. Go through these chapter-wise solutions to be thoroughly familiar with the concepts.