## NCERT Solutions for Class 6 Maths Chapter 8 Decimals (Ex 8.4) Exercise 8.4

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## Access NCERT Class 6 Mathematics Chapter 8- Decimals

Exercise 8.4

1. Express as rupees using decimals:

a) 5 paise

Ans: Since₹1 is equal to 100 paise.

So,\[1{\text{ paise}} = {\text{Rs}}.0.01\]

${\text{5 paise = Rs}}{\text{.}}\;{\text{0}}{\text{.01}} \times {\text{5 = Rs}}{\text{.}}\;{\text{0}}{\text{.05}}$

b) 75 paise

Ans: Since ₹1 is equal to 100 paise.

So, ${\text{1 paise = Rs}}{\text{.0}}{\text{.01}}$

${\text{75 paise = Rs}}{\text{.0}}{\text{.01}}\times {\text{75 = Rs}}{\text{.0}}{\text{.75}}$

c) 20 paise

Ans: Since ₹1 is equal to 100 paise.

So, ${\text{1 paise = Rs}}{\text{.0}}{\text{.01}}$

\[{\text{20 paise = Rs}}{\text{. 20}} \times {\text{0}}{\text{.01 = Rs}}{\text{. 0}}{\text{.2}}\]

d) 50 rupees 90 paise

Ans: Since ${\text{1 paise = Rs}}{\text{.0}}{\text{.01}}$

So, \[{\text{90 paise = Rs}}{\text{.}}\;{\text{90}}\times {\text{0}}{\text{.01 =}}\;{\text{Rs}}{\text{.}}\;{\text{0}}{\text{.9}}\]

50 rupees 90 paise = ₹ $50.90$

e) 725 paise

Ans: Since ₹1 is equal to 100 paise.

So, ${\text{1 paise = Rs}}{\text{.0}}{\text{.01}}$

\[{\text{725 paise = Rs}}{\text{. 725}} \times {\text{0}}{\text{.01 = Rs}}{\text{. 7}}{\text{.25}}\]

2. Express as meters using decimals:

a) 15 cm

Ans: Since 1 m is equal to 100 cm.

So, \[{\text{1 cm = 0}}{\text{.01}}\;{\text{m}}\]

$15\;{\text{cm}}\;{\text{ = }}\;15 \times 0.01\;{\text{m}}\;{\text{ = }}\;{\text{0}}{\text{.15}}\;{\text{m}}$

b) 6 cm

Ans: Since 1 m is equal to 100 cm.

So, \[{\text{1 cm = 0}}{\text{.01}}\;{\text{m}}\]

$6\;{\text{cm}}\;{\text{ = 6}} \times {\text{0}}{\text{.01m = }}\;{\text{0}}{\text{.06}}\;{\text{m}}$

c) 2 m 45 cm

Ans: Since 1 m is equal to 100 cm.

So, \[{\text{1 cm = 0}}{\text{.01}}\;{\text{m}}\]

$45\;{\text{cm}}\;{\text{ = }}\;45 \times 0.01\;{\text{m}}\; = {\text{0}}{\text{.45}}\;{\text{m}}$

${\text{2 m 45 cm}}\;{\text{ = }}\;{\text{2}}{\text{.45 m}}$

d) 9 m 7 cm

Ans: Since 1 m is equal to 100 cm.

So, \[{\text{1 cm = 0}}{\text{.01}}\;{\text{m}}\]

${\text{7}}\;{\text{cm}}\;{\text{ = }}\;{\text{7}} \times {\text{0}}{\text{.01m = 0}}{\text{.07}}\;{\text{m}}$

${\text{9}}\;{\text{m 7 cm = 9}}{\text{.07 m}}$

e) 419 cm

Ans: Since 1 m is equal to 100 cm.

So, \[{\text{1 cm = 0}}{\text{.01}}\;{\text{m}}\]

$419\;{\text{cm}}\;{\text{ = }}\;419 \times 0.01{\text{m}} = 4.19\;{\text{m}}$

3. Express as cm using decimals:

a) 5 mm

Ans: Since 1 cm is equal to 10 mm.

So, \[{\text{1 mm = 0}}{\text{.1 cm}}\]

${\text{5}}\;{\text{mm}}\;{\text{ = }}\;5 \times 0.1\;{\text{cm}} = {\text{0}}{\text{.5}}\;{\text{cm}}$

b) 60 mm

Ans: Since 1 cm is equal to 10 mm.

So, \[{\text{1 mm = 0}}{\text{.1 cm}}\]

$60\;{\text{mm}}\;{\text{ = 60}} \times {\text{0}}{\text{.1cm = }}\;6.{\text{0}}\;{\text{cm}}$

c) 164mm

Ans: Since 1 cm is equal to 10 mm.

So, \[{\text{1 mm = 0}}{\text{.1 cm}}\]

$164\;{\text{mm}}\;{\text{ = }}\;164 \times 0.1\;{\text{cm = }}16.{\text{4}}\;{\text{cm}}$

d) 9 cm 8 mm

Ans: Since 1 cm is equal to 10 mm.

So, \[{\text{1 mm = 0}}{\text{.1 cm}}\]

\[{\text{8}}\;{\text{mm}}\;{\text{ = }}\;{\text{0}}{\text{.8}}\;{\text{cm}}\]

\[{\text{9 cm 8 mm = 9}}{\text{.8 mm}}\]

e) 93mm

Ans: Since 1 cm is equal to 10 mm.

So, \[{\text{1 mm = 0}}{\text{.1 cm}}\]

$93\;{\text{mm}}\;{\text{ = }}\;93 \times 0.1\;{\text{cm}} = 9.{\text{3}}\;{\text{cm}}$

4. Express as km using decimals:

a) 8 m

Ans: Since 1 Km is equal to 1000 m.

So, \[{\text{1 m = 0}}{\text{.001 Km}}\]

\[{\text{8 m = 8}} \times {\text{0}}{\text{.001 Km = 0}}{\text{.008 Km}}\]

b) 88 m

Ans: Since 1 Km is equal to 1000 m.

So, \[{\text{1 m = 0}}{\text{.001 Km}}\]

\[{\text{88 m = 88}} \times {\text{0}}{\text{.001 Km = 0}}{\text{.088 Km}}\]

c) 8888 m

Ans: Since 1 Km is equal to 1000 m.

So, \[{\text{1 m = 0}}{\text{.001 Km}}\]

\[{\text{8888 m = 8888}} \times {\text{0}}{\text{.001 Km}} = {\text{8}}{\text{.888 Km}}\]

d) 70Km 5 m

Ans: Since 1 Km is equal to 1000 m.

So, \[{\text{1 m = 0}}{\text{.001 Km}}\]

\[{\text{5 m = 5}} \times {\text{0}}{\text{.001Km = 0}}{\text{.005 Km}}\]

\[{\text{70 Km 5 m = 70}}{\text{.005 Km}}\]

5. Express as kg using decimals:

a) 2g

Ans: Since 1 Kg is equal to 1000 g.

So, \[{\text{1 g = 0}}{\text{.001 Kg}}\]

\[{\text{2 g = 2}} \times {\text{0}}{\text{.001 Kg = 0}}{\text{.002 Kg}}\]

b) 100g

Ans: Since 1 Kg is equal to 1000 g.

So, \[{\text{1 g = 0}}{\text{.001 Kg}}\]

\[{\text{100 g = 100}} \times {\text{0}}{\text{.001 Kg = 0}}{\text{.1 Kg}}\]

c) 3750g

Ans: Since 1 Kg is equal to 1000 g.

So, \[{\text{1 g = 0}}{\text{.001 Kg}}\]

\[{\text{3750 g = 3750}} \times 0.001\;{\text{Kg = 3}}{\text{.75 Kg}}\]

d) 5Kg 8 g

Ans: Since 1 Kg is equal to 1000 g.

So, \[{\text{1 g = 0}}{\text{.001 Kg}}\]

\[{\text{8 g = 8}} \times {\text{0}}{\text{.001 Kg = 0}}{\text{.008 Kg}}\]

\[{\text{5 Kg 8 g = 5}}{\text{.008 Kg}}\]

e) 26 Kg 50 g

Ans: Since 1 Kg is equal to 1000 g.

So, \[{\text{1 g = 0}}{\text{.001 Kg}}\]

\[{\text{50 g = 50}} \times {\text{0}}{\text{.001 Kg = 0}}{\text{.05 Kg}}\]

\[{\text{26 Kg 50 g = 26}}{\text{.05 Kg}}\]

## NCERT Solutions for Class 6 Maths Chapter 8 Decimals Exercise 8.4

Opting for the NCERT solutions for Ex 8.4 Class 6 Maths is considered as the best option for the CBSE students when it comes to exam preparation. This chapter consists of many exercises. Out of which we have provided the Exercise 8.4 Class 6 Maths NCERT solutions on this page in PDF format. You can download this solution as per your convenience or you can study it directly from our website/ app online.

Vedantu in-house subject matter experts have solved the problems/ questions from the exercise with the utmost care and by following all the guidelines by CBSE. Class 6 students who are thorough with all the concepts from the Subject Decimals textbook and quite well-versed with all the problems from the exercises given in it, then any student can easily score the highest possible marks in the final exam. With the help of this Class 6 Maths Chapter 8 Exercise 8.4 solutions, students can easily understand the pattern of questions that can be asked in the exam from this chapter and also learn the marks weightage of the chapter. So that they can prepare themselves accordingly for the final exam.

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