NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Ex 4.1) Exercise 4.1

Top
Download PDF
FAQ
course-recommendation-image

NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Ex 4.1) Exercise 4.1

Bookmark added to your notes.
View Notes
×

Before talking about the NCERT solutions for Class 10 Maths chapter 4 exercise 4.1, let’s do a quick recapitulation- from chapter Polynomials, we already know what quadratic polynomials are. Isn’t it? When a polynomial of quadratic order of the form as  ax2 + bx + c = 0 (a ≠ 0) becomes zero, we termed it as a quadratic equation. Now ax2 + bx + c = 0 (a ≠ 0) is known as the general form of the quadratic equation where ‘a’ and ‘b’ are called variables of the first-order and c is a constant. Maths class 10 chapter 4 exercise 4.1 puts students into the practice of solving quadratic equations. And class 10 maths chapter 4 exercise 4.1 solutions lend them a helping hand and make them understand the right method of solving those problems. Students can now download free Chapter 4 Exercise 4.1 NCERT Book Solutions PDF for Class 10 to boost their exam preparation. Vedantu provides NCERT Solutions for Class 10 Science as well which will help students to prepare for their science exam.

Chapter 4-Quadratic Equations part-1
Loading More Solutions...
FAQ (Frequently Asked Questions)

1.  The Altitude of a Right Triangle is 7 cm Less than its Base. If the Hypotenuse is 13 cm, Find the Other Two Sides.

Answer: You can find the following in class 10 Maths ex 4.1 solutions:

Let x be the base, the altitude will be x - 7

Now as per Pythagoras theorem,

x2 + (x − 7)2 = 132

= x2 + x2 - 14x + 49 = 169

= 2x2 -14x = 120

= x2 - 7x = 60

= x2 - 12x + 5x - 60 = 0

= x(x - 12) + 5(x - 12) = 0

= (x - 12)(x + 5) = 0

x = 12 or -5

Since x cannot be negative x = 12.

So base is 12 cm and altitude is (12 - 7) = 5 cm.

2.  If Zeba were Younger by 5 years than what she really is then the Square of her age Would have been 11 more than five times her actual age. What is her age now?

Answer: The solution according to exercise 4.1 class 10 Maths NCERT solutions is as follows:

Let age of Zeba be x years
As per the question:

(x − 5)2 = 11 + 5x(x − 5)2 = 11 + 5x
=> x2 + 25 − 10x = 11 + 5x(x)2 + 25 − 10x = 11 + 5x
=> x2 − 15x + 14 = 0 x 2 − 15x + 14 = 0 x 2 − 14x − x + 14 = 0 x 2 − 14x − x + 14 = 0
=> (x - 1)(x - 14)

Therefore, age of Zeba is 14 years.