# Class 10 NCERT Solutions for Science Chapter 1 - Chemical Reactions and Equations

## NCERT Solutions for Class 10 Science Chapter 1 - Chemical Reactions and Equations

Chapter 1 Chemical Reactions and Equations for Class 10 NCERT Solutions is the foundation of Chemistry. In this chapter, we learn about chemical equations and how to write an equation and balance it. This topic also includes different types of reactions. You can download the free PDF of the NCERT Solution from the official website of Vedantu. These solutions are developed by our subject experts and they are very helpful for the preparation of your exams. Our experienced teachers will guide you through the topic and clear all your doubts.

You can also download NCERT Solutions for Class 10 Maths and NCERT Solution for Class 10 Science to help you to revise complete syllabus and score more marks in your examinations.

## Class 10 Science Chemical Reactions and Equations - Mind Map

1. Chemical Equation

• Balanced Chemical Equation

• Balancing of a Chemical Equation

1. Oxidation in Everyday Life

• Rusting

• Corrosion

• Rancidity

1. Types of Chemical Reactions

• Combination Reaction

• Exothermic Reactions

• Oxidation

• Reduction

• Redox Reactions

• Decomposition Reaction

• Endothermic Reactions

• Displacement Reactions

• Double Displacement Reactions

• Precipitation Reaction

## Features of NCERT Solutions for Class 10 Science Chapter 1 - Chemical Reactions and Equations

• Students will be able to comprehensively practise the balancing of various kinds of equations.

• NCERT Solutions for Class 10 Science Chapter 1 - Chemical Reactions and Equations will aid students in writing different types of chemical equations properly.

• It will help students get a hang of solving questions from different levels of difficulty before sitting for the actual CBSE Term I exam. Access and go through Class 10 NCERT Solutions for Science Chapter 1, which is on Chemical Reactions and Equations, to scorer desirably in CBSE Class 10 exams.

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## Access NCERT Solutions for Class 10 Science

Intext Exercise 1

1. Why should a magnesium ribbon be cleaned before burning in air?

Ans:

Magnesium is a kind of a reactive metal. It will react with oxygen and form a white layer of magnesium oxide (MgO) on its surface. Magnesium oxide is a stable compound and will prevent the further reaction of the metal. So, a magnesium ribbon is cleaned before burning in air to remove the layer of magnesium oxide from its surface.

2. Write the balanced equation for the following chemical reactions.

i) Hydrogen + Chlorine $\to$ Hydrogen chloride

Ans: A balanced equation consists of the same number of moles on the reactants and the products side. The balanced equation for the given reaction is:${{H}_{2(g)}}+C{{l}_{2(g)}}\to 2HC{{l}_{(g)}}$

ii) Barium chloride + Aluminium sulphate $\to$ Barium sulphate + Aluminium chloride

Ans: A balanced equation consists of the same number of moles on the reactants and the products side. The balanced equation for the given reaction is:$3BaC{{l}_{2(s)}}+A{{l}_{2}}{{(S{{O}_{4}})}_{3(s)}}\to 3BaS{{O}_{4(s)}}+2AlC{{l}_{3(s)}}$

iii) Sodium + Water $\to$ Sodium hydroxide + Hydrogen

Ans:

A balanced equation consists of the same number of moles on the reactants and the products side. The balanced equations for the given reaction is $2N{{a}_{(s)}}+2{{H}_{2}}{{O}_{(l)}}\to 2NaO{{H}_{(aq)}}+{{H}_{2}}_{(g)}$

3. Write a balanced chemical equation with state symbols for the following reactions.

i) Solutions of barium chloride and sodium sulphate in water react to give insoluble barium sulphate and the solution of sodium chloride.

Ans: A balanced chemical equation has the same number of moles of reactants and products. The balanced chemical equation is:$BaC{{l}_{2(aq)}}+N{{a}_{2}}S{{O}_{4(aq)}}\to BaS{{O}_{4(s)}}+2NaC{{l}_{(aq)}}$

ii) Sodium hydroxide solution (in water) reacts with hydrochloric acid solution (in water) to produce sodium chloride solution and water.

Ans: A balanced chemical equation has the same number of moles of reactants and products. The balanced chemical equation is:$NaO{{H}_{(aq)}}+HC{{l}_{(aq)}}\to NaC{{l}_{(aq)}}+{{H}_{2}}{{O}_{(l)}}$

Intext Exercise 2

1. A solution of a substance 'X ' is used for white washing.

i) Name the substance 'X' and write its formula.

Ans: Substance ‘X’ is calcium oxide also known as quicklime that is used in white washing. Its chemical formula is CaO.

ii) Write the reaction of the substance 'X' named in (i) above with water.

Ans:Calcium oxide reacts with water in a combination reaction to from calcium hydroxide also called slaked lime, the reaction is:

$Ca{{O}_{(s)}}+{{H}_{2}}{{O}_{(l)}}\to Ca{{(OH)}_{2(aq)}}$

2. Why is the amount of gas collected in one of the test tubes in Activity 1.7 double of the amount collected in the other? Name this gas.

Ans:

Water consists of hydrogen and oxygen atoms. It is a combination of two hydrogen and one oxygen atom. In electrolysis, hydrogen moves towards the cathode and oxygen towards the anode. So, the ratio of hydrogen and oxygen is 2:1. And hydrogen is double the amount of oxygen.

$2{{H}_{2}}O\to 2{{H}_{2}}+{{O}_{2}}$

Intext Exercise 3

1. Why does the color of copper sulphate solution change when an iron nail is dipped in it?

Ans:

When an iron nail is dipped in a solution of copper sulphate, then the more reactive metal displaces the less reactive metal. As a result the blue solution of copper sulphate gets faded and forms a green compound known as ferrous sulphate.

$\underset{\text{Iron}}{\mathop{F{{e}_{(s)}}}}\,+\underset{\begin{smallmatrix}\text{ Copper sulphate } \\ (\text{Blue}) \end{smallmatrix}}{\mathop{CuS{{O}_{4(aq)}}}}\,\to \underset{\text{Ferrous sulphate}}{\mathop{FeS{{O}_{4(aq)}}}}\,+\underset{\begin{smallmatrix} \text {Copper} \\ (\text{Green}) \end{smallmatrix}}{\mathop{C{{u}_{(s)}}}}\,$

2. Give an example of a double displacement reaction other than the one given in Activity 1.10.

Ans:

A double displacement reaction consists of two ions replacing each other’s position from the reactants to form new compounds in the products. A double displacement reaction occurs when Potassium iodide reacts with lead nitrate to form lead iodide (yellow precipitate) and potassium nitrate.

$2KI+Pb{{(N{{O}_{3}})}_{2}}\to Pb{{I}_{2}}\downarrow +2KN{{O}_{3}}$

3. Identify the substances that are oxidised and the substances that are reduced in the following reactions

i) $\text{4N}{{\text{a}}_{\text{(s)}}}\text{+}{{\text{O}}_{\text{2(g)}}}\to \text{2N}{{\text{a}}_{\text{2}}}{{\text{O}}_{\text{(s)}}}$

Ans: Any species is said to be oxidised when it loses electrons and increases the oxidation state, while any species is said to be reduced when it gains electrons and decreases the oxidation state. Sodium (Na) is oxidised and oxygen gets reduced.

$4\text{Na}+{{\text{O}}_{2}}\to 2\text{N}{{\text{a}}_{2}}\text{O}$

ii) $\text{Cu}{{\text{O}}_{\text{(s)}}}\text{+}{{\text{H}}_{\text{2(g)}}}\to \text{Cu(s)+}{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{(l)}}}$

Ans: Any species is said to be oxidised when it loses electrons and increases the oxidation state, while any species is said to be reduced when it gains electrons and decreases the oxidation state. Copper oxide (CuO) is reduced to copper (Cu) as it loses oxygen and hydrogen $\left( {{H}_{2}} \right)$is oxidized to water $({{H}_{2}}O)$

$CuO+{{H}_{2}}\xrightarrow{\Delta }Cu+{{H}_{2}}O$

NCERT exercises

1. Which of the statements about the reaction below are incorrect?

$\text{2Pb}{{\text{O}}_{\text{(s)}}}\text{+}{{\text{C}}_{\text{(s)}}}\to \text{2P}{{\text{b}}_{\text{(s)}}}\text{+C}{{\text{O}}_{\text{2(g)}}}$

b. Carbon dioxide is getting oxidised.

c. Carbon is getting oxidised.

d. Lead oxide is getting reduced.

Options

i) (a) and (b)

ii) (a) and (c)

iii) (a),(b) and (c)

iv) all

Ans:

Incorrect option is (i) (a) and (b)

2. $\text{F}{{\text{e}}_{\text{2}}}{{\text{O}}_{\text{3}}}\text{+2Al}\to \text{A}{{\text{l}}_{\text{2}}}{{\text{O}}_{\text{3}}}\text{+2Fe}$

The above reaction is an example of a _______________

Options:

a) Combination reaction.

b) Double displacement reaction.

c) Decomposition reaction.

d) Displacement reaction.

Ans:

(d) The given reaction is an example of a single displacement reaction.

3. What happens when dilute hydrochloric acid is added to iron filings? Tick the correct answer.

a. Hydrogen gas and iron chloride are produced.

b. Chlorine gas and iron hydroxide are produced.

c. No reaction takes place,

d. Iron salt and water are produced.

Ans:

(a) Hydrogen gas and iron chloride are produced. The reaction is as follows:

$F{{e}_{(s)}}+2HC{{l}_{(aq)}}\to FeC{{l}_{2(aq)}}+{{H}_{2}}\uparrow$

4. What is a balanced chemical equation? Why should chemical equations be balanced?

Ans:

A balanced chemical equation consists of the equal number of moles of the elements in the reactants and that in the products.

Chemical equations should be balanced, as according to the law of conservation of mass, mass can neither be created nor can be destroyed. Therefore, in a chemical reaction, the total mass of reactant should be equal to the total mass of products. Hence, a balanced chemical equation has total mass of reactants equal to total mass of products.

5. Translate the following statements into chemical equations and then balance them.

a) Hydrogen gas combines with nitrogen to form ammonia.

Ans: $3{{H}_{2(g)}}+{{N}_{2(g)}}\to 2N{{H}_{3(g)}}$

b) Hydrogen sulphide gas burns in air to give water and sulphur dioxide.

Ans:$2{{H}_{2}}{{S}_{(g)}}+3{{O}_{2(g)}}\to 2{{H}_{2}}{{O}_{(l)}}+2S{{O}_{2(g)}}$

c) Barium chloride reacts with aluminium sulphate to give aluminium chloride and a precipitate of barium sulphate.

Ans:$3BaC{{l}_{2(aq)}}+A{{l}_{2}}{{(S{{O}_{4}})}_{3(aq)}}\to 2AlC{{l}_{3(aq)}}+3BaS{{O}_{4(s)}}$

d) Potassium metal reacts with water to give potassium hydroxide and hydrogen gas

Ans:$2{{K}_{(s)}}+2{{H}_{2}}{{O}_{(l)}}\to 2KO{{H}_{(aq)}}+{{H}_{2(g)}}$

6. Balance the following chemical equations

a)$\text{HN}{{\text{O}}_{3}}+\text{Ca}{{(\text{OH})}_{2}}\to \text{Ca}{{\left( \text{N}{{\text{O}}_{3}} \right)}_{2}}+{{\text{H}}_{2}}\text{O}$

Ans: $2HN{{O}_{3}}+Ca{{(OH)}_{2}}\to Ca{{\left( N{{O}_{3}} \right)}_{2}}+2{{H}_{2}}O$

b)$\text{NaOH}+{{\text{H}}_{2}}\text{S}{{\text{O}}_{4}}\to \text{N}{{\text{a}}_{2}}\text{S}{{\text{O}}_{4}}+{{\text{H}}_{2}}\text{O}$

Ans: $2NaOH+{{H}_{2}}S{{O}_{4}}\to N{{a}_{2}}S{{O}_{4}}+2{{H}_{2}}O$

c)$\text{NaCl}+\text{AgN}{{\text{O}}_{3}}\to \text{AgCl}+\text{NaN}{{\text{O}}_{3}}$

Ans: $NaCl+AgN{{O}_{3}}\to AgCl+NaN{{O}_{3}}$

d)$\text{BaC}{{\text{l}}_{\text{2}}}\text{+}{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\to \text{BaS}{{\text{O}}_{\text{4}}}\text{+HCl}$

Ans:$BaC{{l}_{2}}+{{H}_{2}}S{{O}_{4}}\to BaS{{O}_{4}}+2HCl$

7. Write the balanced chemical equations for the following reactions.

a) Calcium hydroxide + Carbon dioxide $\to$ Calcium carbonate + Water

Ans: $Ca{{(OH)}_{2}}+C{{O}_{2}}\to CaC{{O}_{3}}+{{H}_{2}}O$

b) Zinc + Silver nitrate $\to$Zinc nitrate +Silver

Ans: $Zn+2AgN{{O}_{3}}\to Zn{{\left( N{{O}_{3}} \right)}_{2}}+2Ag$

c) Aluminium + Copper chloride $\to$Aluminium chloride + Copper

Ans: $2Al+3CuC{{l}_{2}}\to 2AlC{{l}_{3}}+3Cu$

d) Barium chloride + Potassium sulphate$\to$Barium sulphate + Potassium chloride

Ans:$BaC{{l}_{2}}+{{K}_{2}}S{{O}_{4}}\to BaS{{O}_{4}}+2KCl$

8. Write the balanced chemical equation for the following and identify the type of reaction in each case.

a) Potassium bromide (aq) + Barium iodide (aq) $\to$Potassium iodide (aq) + Barium bromide(s)

Ans: $2KB{{r}_{(aq)}}+Ba{{I}_{2(aq)}}\to 2K{{I}_{(aq)}}+BaB{{r}_{2(aq)}}$ ; Double displacement reaction

b) Zinc carbonate (s) $\to$Zinc oxide (s) + Carbon dioxide (g)

Ans: $ZnC{{O}_{3(s)}}\to Zn{{O}_{(s)}}+C{{O}_{2(g)}}$ ; Decomposition reaction

c) Hydrogen (g)+ Chlorine (g)$\to$Hydrogen chloride (g)

Ans: ${{H}_{2(g)}}+C{{l}_{2(g)}}\to 2HC{{l}_{(g)}}$ ; Combination reaction

d) Magnesium (s) + Hydrochloric acid (aq) $\to$Magnesium chloride (aq) + Hydrogen (g)

Ans:$M{{g}_{(s)}}+2HC{{l}_{(aq)}}\to MgC{{l}_{2}}_{(aq)}+{{H}_{2}}_{(g)}$ ; Single displacement reaction

9. What does one mean by exothermic and endothermic reactions? Give examples.

Ans:

Exothermic Reaction: The reactions in which heat is evolved along with the formation of new products are called exothermic reactions. In these reactions the energy of the reactants is more than that of the products, so energy is released to complete the reaction.

Energy of reactants > Energy of products

Example: Complete combustion of methane gas produces carbon dioxide and water along with heat and light.

$C{{H}_{4}}(~g)+2{{O}_{2}}(~g)\to C{{O}_{2}}+2{{H}_{2}}O+heat+light$

Another example of exothermic reactions is respiration and decomposition of vegetable matter.

Endothermic Reaction: The reactions in which energy is absorbed by the reactants to carry on the reaction are called endothermic reactions. In this type of reaction, the energy of the reactants is less than that of the products, so energy is needed and absorbed.

Energy of reactants <Energy of products

Example: Process of Photosynthesis, where plants absorb sunlight in the presence of carbon dioxide and water and make their food in the form of glucose and release oxygen.

$6C{{O}_{2(g)}}+6{{H}_{2}}{{O}_{(l)}}\xrightarrow{sunlight}{{C}_{6}}{{H}_{12}}{{O}_{4(aq)\text{ }}}+6{{O}_{2(g)}}$

10. Why is respiration considered an exothermic reaction? Explain.

Ans:

Exothermic reactions are the reactions in which heat is going to be released. These reactions result in the formation of energy as the energy of reactants is greater than that of products. Respiration is the process in which the glucose from our body combines with oxygen in the cells to provide us with energy. The glucose is broken down through the process of digestion that along with oxygen provides us with energy and hence respiration is an exothermic reaction. The reaction that happens is as follows:

${{C}_{6}}{{H}_{12}}{{O}_{6(aq)}}+6{{O}_{2(g)}}\to 6C{{O}_{2(g)}}+6{{H}_{2}}{{O}_{(l)}}+energy$

11. Why are decomposition reactions called the opposite of combination reactions? Write equations for these reactions.

Ans:

A decomposition reaction consists of a single reactant that breaks down into two or more simpler products.

Example: Decomposition of calcium carbonate to give calcium oxide and carbon dioxide as,

$CaC{{O}_{3}}+\text{ }Energy\text{ }\to CaO+C{{O}_{2}}$

A combination reaction consists of two reactants that combine or mix together to form a single product.

Example: Combination of Calcium oxide and carbon dioxide to form one single product calcium carbonate

$CaO+C{{O}_{2}}\to CaC{{O}_{3}}+\text{ }energy\text{ }$

Hence, decomposition reactions are the opposite of combination reactions.

12. Write one equation each for decomposition reactions where energy is supplied in the form of heat, light or electricity.

Ans:

Decomposition reactions are the reactions where a reactant breaks down into two or more products.

a) Decomposition by heat:

Ferrous sulphate decomposes to give ferrous oxide, sulphur dioxide and sulphur trioxide as,

$2FeS{{O}_{4(s)}}\xrightarrow{\Delta }F{{e}_{2}}{{O}_{3(s)}}+S{{O}_{2(g)}}+S{{O}_{3(g)}}$

b) Decomposition by light:

Silver chloride decomposes in light to form silver and chlorine as,

$2AgC{{l}_{(s)}}\xrightarrow{Light}2A{{g}_{(s)}}+C{{l}_{2(g)}}$

c) Decomposition by electricity:

Water decomposes in presence of electricity to form hydrogen and oxygen gases as,

$2{{H}_{2}}O\xrightarrow{Electricity}2{{H}_{2}}+{{O}_{2}}$

13. What is the difference between displacement and double displacement reactions? Write equations for these reactions.

Ans:

A displacement reaction is a reaction in which a more reactive element displaces a less reactive element from its compound. The elements at the top in the activity series can replace the elements at the bottom.

Example: Zinc is more reactive than copper and replaces copper from copper sulphate as:

$CuS{{O}_{4(aq)}}+Z{{n}_{(s)}}\to ZnS{{O}_{4(aq)}}+C{{u}_{(s)}}$

Double displacement reaction is the type of reaction where two compounds react in the way that there is exchange of positive and negative ions and new compounds are formed as products.

Example: On mixing sodium sulphate solution with barium chloride solution, a white precipitate of barium sulphate is formed as:

$N{{a}_{2}}S{{O}_{4(aq)}}+BaC{{l}_{2(aq)}}\to BaS{{O}_{4(s)}}+2NaC{{l}_{(aq)}}$

14. In the refining of silver, the recovery of silver from silver nitrate solution involved displacement by copper metal. Write down the reaction involved.

Ans:

The equation of recovery of silver from silver nitrate solution in silver refining is as follows:

$2AgN{{O}_{3(aq)}}+C{{u}_{(s)}}\to Cu{{(N{{O}_{3}})}_{2(aq)}}+2A{{g}_{(s)}}$

Here displacement of silver by copper happens as copper is more reactive than silver.

15. What do you mean by a precipitation reaction? Explain by giving examples.

Ans:

The type of reaction where an insoluble substance called a precipitate is formed when there is exchange of ions between the reactants is called a precipitation reaction.

Example 1: On mixing sodium carbonate solution with calcium chloride solution, a white precipitate of calcium carbonate is formed.

$N{{a}_{2}}C{{O}_{3(aq)}}+CaC{{l}_{2(aq)}}\to CaC{{O}_{3(s)}}\downarrow +2NaC{{l}_{(aq)}}$

Example 2: On mixing sodium sulphate solution with barium chloride solution, a white precipitate of barium sulphate is formed.

$N{{a}_{2}}S{{O}_{4(aq)}}+BaC{{l}_{2(aq)}}\to BaS{{O}_{4(s)}}\downarrow +2NaC{{l}_{(aq)}}$

16. Explain the following in terms of gain or loss of oxygen with two examples each.

a) Oxidation

Ans: Oxidation:  A type of reaction in which oxygen or an electronegative species is added to a substance or there is removal of hydrogen or a positive species from a substance is called oxidation.

For example:

$C{{O}_{2}}+{{H}_{2}}\to CO+{{H}_{2}}O$ (Addition of oxygen to${{H}_{2}}$)

$2Cu+{{O}_{2}}\to 2CuO$ (Addition of oxygen to Cu)

b) Reduction

Ans: Reduction: A type of reaction in which hydrogen or an electropositive species is added to a substance or oxygen or an electronegative species is removed, is called reduction.

For example:

$C{{O}_{2}}+{{H}_{2}}\to CO+{{H}_{2}}O$ (Oxygen is removed from$C{{O}_{2}}$)

$CuO+{{H}_{2}}\xrightarrow{\Delta }Cu+{{H}_{2}}O$ (Oxygen is removed from CuO)

17. A shiny brown-coloured element ‘X’ on heating in air becomes black in colour. Name the element ‘X’ and the black-coloured compound formed.

Ans:

Copper (Cu) is ‘X’ and the black colour compound is copper (II) oxide (CuO). Copper reacts with oxygen to form a black colour compound called copper (II) oxide as:

$2Cu+{{O}_{2}}\to 2CuO$

18. Why do we apply paint on iron articles?

Ans:

Iron is a reactive metal and can react with moisture and air. Iron articles, if exposed for a long time in moisture or air, can get corroded and form rust. So, paint is applied on iron articles to prevent rusting and form a protective layer for exposure to air and moisture.

19. Oil and fat containing food items are flushed with nitrogen. Why?

Ans:

Oils and fat containing items are perishable and can be spoiled when exposed to oxygen. This is because oil and fats are reactive and can react with oxygen easily and get oxidised. To prevent oxidation, these items are flushed with nitrogen gas. Nitrogen is an inert gas and cannot react with oils or fats easily. So, food items with oils and fats are kept in packets having nitrogen gas that increases the shelf life and makes these items last for a long time.

20. Explain the following terms with one example each.

a) Corrosion

Ans: Corrosion: Corrosion is defined as a process where a substance, generally metal deteriorates and forms a layer of oxide on its surface. Metals get converted into their hydrated oxides or sulphides. Ex; Iron, Cu, Ag

$4Fe+3{{O}_{2}}+n{{H}_{2}}O\to \underset{Hydrated\,iron\,oxide}{\mathop{2F{{e}_{2}}{{O}_{3}}.n{{H}_{2}}O}}\,$

$2Ag+{{H}_{2}}~S\to A{{g}_{2}}~S+{{H}_{2}}$

b) Rancidity

Ans: Rancidity: It is a process in which food items like fats and oils are oxidised. This results in the change in taste and smell of the food item and is called rancidity. For example, when any fried food is exposed to air for a long time then it has a change in smell and taste and it becomes rancid.

Rancidity can be avoided by:

• Adding antioxidants like BHA (Butylated tri hydroxy anisole)

• Refrigerate the food items

• keep food items in airtight containers

• Adding nitrogen to food packets to prevent oxidation.

## NCERT Solutions for Class 10 Science Chapter 1 – A Brief Overview

Introduction

Every day in our life, we go through different kinds of physical and chemical changes. A physical change is a change that can be reversed like the melting of wax, freezing of water, etc. and chemical change is a change that cannot be reversed like digestion of food, rusting of iron, etc. All chemical changes are associated with chemical reactions and they are represented by equations. In this segment, we will study the different kinds of chemical changes represented by chemical reactions and the chemical equations.

You can Find the Solutions of All the Science Chapters below.

NCERT Solutions for Class 10 Science

### Important Concepts Covered in Chapter 1 of Class 10 Science NCERT Solutions

Chapter 1 - Chemical Reactions and Equations of Class 10 Science NCERT Solutions is mainly based on the basic concepts of chemical reactions, types of chemical reactions, and the effects of a chemical oxidation reaction in our daily lives. Writing chemical equations and balancing chemical equations are also discussed in this article. Below are the important concepts students will learn from this chapter.

 Chemical Reactions and Equations 1.1 Chemical Equations 1.1.1 Writing a Chemical Equation 1.1.2 Balanced Chemical Equations 1.2 Types of Chemical Reactions 1.2.1 Combination Reaction 1.2.2 Decomposition Reaction 1.2.3 Displacement Reaction 1.2.4 Double Displacement Reaction 1.2.5 Oxidation and Reduction 1.3 Have You Observed the Effects of Oxidation Reactions in Everyday Life? 1.3.1 Corrosion 1.3.2 Rancidity

### Chemical Reactions

A chemical reaction is a change in which one more substance(s) are reactants(s) react (s) to form new compound substance(s) with entirely different properties.

Reactants are substances like molecules, ions, atoms that react. They undergo a chemical change in the reaction and form a new substance as a result of the reaction. This new substance formed is called a product.

Ex: $\underset{\text{Sodium }}{ 2Na_{(s)}} + \underset{\text{Water}}{2H_2O_{(l)}}\rightarrow \underset{\text{Sodium hydroxide}}{2NaoH_{(aq)}} +\underset{\text{Hydrogen}}{H2_{(g)}{\uparrow}}$

In the above chemical reaction, sodium and water are the reactants and the products formed as a result of the reaction are Sodium hydroxide and Hydrogen.

Identification of Chemical Reaction

The following observations can be identified as changes during a chemical reaction:

(i) Change in state (ii) Change in the colour

(iii) Evolution of a gas (iv) Change in temperature

(v) Formation of a precipitate

Chemical Equations

A chemical equation is a shorthand form for a chemical change represented by symbols. The reactants and the products obtained as a resultant of a chemical change are represented by symbols and formulas.

Ex: Methane + Oxygen → Carbon dioxide + Water

|_________|                   |_____________|

Reactants                   Products

This equation is called the word equation. The word equation can be changed into a chemical equation by writing the formulae and the symbols of the substance instead of their names.

Ex: $\underset{\text{Methane}}{ CH{_4}_{(g)}} + \underset{\text{Oxygen}}{2O{_2}_{(g)}}\rightarrow \underset{\text{Carbon dioxide}}{CO{_2}_{(g)}} +\underset{\text{Water}}{2H_2O_{(I)}}$

Writing a Chemical Equation

A chemical equation shows a change of reactants to final products through an arrow symbol () that is placed between them.

The reactants are written with a plus sign (+) between them on the left-hand side of the arrow. Similarly, the final products are written on the right-hand side with a plus sign (+) between them.

The arrowhead pointing towards the products showing the direction of the reaction.

Ex:        NH4OH  +  HCL   ------------------->  NH4Cl            +  H2O

|________________| Arrow indicates     |_______________|

Reactants                              to                      yield    Products

Represents Direction

In the above reaction, the number of Ammonium Hydroxide and Hydrogen Chloride is reacting to form the products Ammonium Chloride and Water. If you observe, in the above equation the number of atoms in the reactants and the products are not the same on both sides. This kind of unbalanced equation is called a skeletal chemical equation.

Balanced Chemical Equations

When the total number of atoms of each element is equal on both sides of the equation then the equation is known as a balanced chemical equation.

The balancing of a chemical equation is based on the law of conservation of mass. According to the law of conservation of mass, ‘mass can neither be created nor be destroyed during a chemical reaction.’

The method of hit and trial can be used for balancing a chemical equation. In this method, we keep making trials to balance the equation by using the smallest whole number of coefficients. The number of atoms of each element never changes, before and after a chemical reaction in this method.

Balancing of a Chemical Equation

There are many steps involved in balancing a chemical equation.

1. The first step is to write an unbalanced equation and enclose the formulae in brackets.

Ex: $\underset{\text{Sodium}}{ (Na)} + \underset{\text{Water}}{(H_{2}O)}\rightarrow \underset{\text{Sodium Hydroxide}}{(NaOH)} +\underset{\text{Hydrogen}}{(H_2)}$

2. The second step is to make a list of the number of atoms of different elements as present in an unbalanced equation.

 Element Number of Atoms in Reactants (LHS) Number of Atoms in Products (RHS) Na 1 1 H 2 3 O 1 1

3. Next step is to balance the first element. From the above table, it is known that atoms in Hydrogen are not balanced. So, first we need to balance it.

 Atoms of H In Reactants In Products Initially 2 (in H2O) 3 (1 in NaOH and 2 in H2) To balance 2 x 2 2 x 1 in NaOH2 in H2 = 4H - atoms

Thus, the balanced equation is (Na) + 2(H2O) → 2(NaOH) + (H2)

4. Then balance the second element. We examine the obtained equation and select the next unbalanced element. In the above chemical equation, Na is still not balanced. To balance the number of atoms in Na,

 Atoms of Na In Reactants In Products Initially 1 (in Na) 2 (1 in NaOH) To balance 2 x 1 2

Thus, after the balancing the Na, we get the final chemical equation:

2Na + 2H2O → 2NaOH + H2

5. Further, we have to balance the other elements. If we further examine the reaction, no element is found to be unbalanced. This method that we used is called the hit and trial method.

6. Finally, we need to check the accuracy of the equation. To check where the equation is correct, we further tabulate the number of atoms of each element separately.

 Element Number of atoms in Reactants (LHS) Number of atoms in Products (RHS) Na 2 2 H 4 4 O 2 2

The above table clearly reveals that the obtained equation is a balanced equation.

Example: Balance the following equation C2H6 + O2 →  CO2 + H2O

Sol.   Step 1: Enclose all the symbols or formulae in brackets.

(C2H6 )+ (O2 ) →  (CO2 )+ (H2O)

Step 2: Count the number of atoms in each element on both the sides of the equation.

 Elements Number of Atoms in Reactants (LHS) Number of Atoms in Products (RHS) C 2 1 H 6 2 O 2 3

Step 3: From the above table, it is known that hydrogen has the maximum number of atoms. So to balance hydrogen atoms, multiply H2O by 3.

(C2H6 )+ (O2 ) →  (CO2 )+ 3(H2O)

Step 4: Count further the number of atoms in each element on both sides.

 Elements Number of Atoms in Reactants (LHS) Number of Atoms in Products (RHS) C 2 1 H 6 2 O 2 3

Now, to balance the atoms in carbon, multiply CO2 molecules by 2.

(C2H6 )+ (O2 ) →  2(CO2 )+ 3(H2O)

There are 7 O-atoms on RHS. To make 7 O-atoms at LHS, we have to write 72 before O2 but we can use only whole number to balance the equation, so we write 72before  O2 and multiply the whole equation by 2.

[ C2H6 +  7/2 O2  →  2CO2 + 3H2O ] x 2

Thus, after removing the brackets we get the final and correct chemical equation

2C2H6 + 7O2  →  4CO2 + 6H2O

The facts that remain unexplained in a chemical equation are

1. The physical state of the substances like the changes in the colour during the reaction.

2. The reaction conditions.

3. The changes in the evolution or the absorption of energy.

4. Completion of the reaction.

These Limitations Can Be Overcome by Adding the Following Information

1. The physical states of the reactants and products can be represented by using the symbols, (s) for solid, (l) for liquid, (g) for gas and (aq) for aqueous solution, alongwith their respective formulae. Liberation of gas and precipitation can be represented by and respectively.

2. The  circumstances under which reaction takes place like temperature, pressure, catalyst, etc. can be mentioned in the equation.

3. Evolution of heat or absorption of heat can be indicated by writing [+Heat] on the right hand side of the left hand side of the equation, respectively.

Types of Chemical Reactions

The chemical reactions depend upon the type of chemical changes taking place and they are classified as:

1. Combination Reaction

When two or more reactants are combined to form a single substance in a chemical reaction, then the reaction is called a combination reaction.

Ex: Calcium Oxide reacts very fast and strongly with water to form calcium hydroxide (slaked lime). The reaction given below is highly exothermic, because a lot of heat is liberated during the reaction.
$\underset{\text{Calcium oxide}}{CaO_(s)} + \underset{\text{Water}}{H{_2}O_{(l)}}\rightarrow \underset{\text{Calcium Hydroxide}}{Ca(OH){_2}_{(aq)}} +\underset{\text{}}{\text{Heat}}$

2. Decomposition Reaction

This is a reaction in which a single reactant breaks down to form two or more products. This reaction is opposite to combination reaction. On the basis of the energy form required for the reaction, this reaction is classified into three types:

1. Thermal decomposition: This reaction uses the heat energy for decomposition of the reactant.

Ex: Ferrous Sulphate ( FeSO4.7H2O) when heated loses water of crystallisation and forms dehydrated FeSO4 and gives ferric oxide, sulphur dioxide and sulphur trioxide on decomposition.

Heat
$\underset{\text{Ferrous Sulphate}}{2FeSO{_4}_{(s)} } \rightarrow \underset{\text{Ferric oxide}}{Fe_2O{_3}_{(s)} }+\underset{\text{Sulpur dioxide }}{SO{_2}_{(g)}} +\underset{\text{Sulphur trioxide}}{{SO{_3}_{(g)}}}$

2. Electrolysis: These reactions use the electrical energy for the decomposition of the reactant molecules.

Ex: When electric current is passed through water, it decomposes to give water and hydrogen.
Electric current
$\underset{\text{Water }}{2H{_2}O_{(l)} } \rightarrow \underset{\text{Hydrogen }}{ 2H{_2}_{(g) } }+\underset{\text{Oxygen}}{O{_2}_{(g)}}$

3. Photolysis or photochemical decomposition: These reactions use light energy for the purpose of decomposition.

Ex: Silver chloride decomposes to produce silver metal and chlorine gas when exposed to sunlight.

sunlight
$\underset{\text{Silver bromide}}{2AgCI_{(s)} } \rightarrow \underset{\text{Silver}}{ 2Ag_{(s) } }+\underset{\text{Bromine}}{CI{_2}_{(g)}}$

(Pale yellow)   (Greyish white)   (yellowish green)

### 3. Exothermic and Endothermic Reactions

A reaction can be exothermic or endothermic depending on whether heat is liberated or absorbed during a reaction.

1. Exothermic Reactions: The reactions in which the products formed along with the liberation of heat, are called exothermic reactions or combustion reactions. Respiration is an exothermic process. The decomposed vegetable matter that turns into compost is also an exothermic process.

Ex: Burning of magnesium ribbon|
$\underset{\text{Magnesium }}{2Mg_{(s)} } +\underset{\text{Oxygen}}{ O{_2}_{(s) } } \rightarrow \underset{\text{ Magnesium oxide}}{2MgO_{(s)}}+ \text{Heat}$

Endothermic reactions: The reactions which take place by the absorption of heat/ energy (either in the form of light or electricity), are called endothermic reactions. Photosynthesis is an endothermic process. All decomposition reactions are endothermic reactions because the reactions require some form of energy like heat, light or electricity.

sunlight

6CO2 (aq) + 12H2O (l) →  C6H12O6 + 6O2 + 6H2

Chlorophyll   Glucose

### 4. Displacement Reaction

When a more reactive element takes the place of  a less reactive element from its compound, it is called displacement reaction. This reaction is of two kinds:

1. Single Displacement Reaction: This is a type of chemical reaction where an element reacts with a compound and displaces another element in that compound is called single displacement.

Ex: Zinc is more reactive than copper and displaces Cu from CuSO4 solution and forms a new product zinc sulphate and copper metal.
$\underset{\text{Zinc metal }}{Zn } +\underset{\text{Copper sulphate}}{CuSO_4 } \rightarrow \underset{\text{ Zinc Sulphate }}{ZnSO_4}+ \underset{\text{ Copper metal}}{{Cu}}$

(Grey)          solution (blue)          solution (colourless)    (Brown)

2. Double Displacement Reaction: The reaction in which two different ions or groups of atoms in the molecules of a reactant are displaced by each other is called a double displacement reaction. In this reaction, a precipitate is produced so It is also called a precipitation reaction.

Ex: When sodium sulphate is added to barium chloride, a curdy white precipitate of barium sulphate and a solution of sodium chloride are formed as end products.

$\underset{\text{Sodium Sulphate}}{Na{_2}SO{_4}_{(aq)}} +\underset{\text{Barium Chloride}}{BaCl{_2}_{(aq)}} \rightarrow \underset{\text{Barium Sulphate }}{BaSo_4}+ +\underset{\text{ Sodium Chloride }}{{2NaCl_(aq)}}$

Note: The reaction in which acid or acidic oxide react with a base or basic oxide to form salt and water is called neutralization reactions.

$\underset{\text{Sodium Hydroxide }}{2NaOH} +\underset{\text{Sulphuric Acid }}{H_2SO_4} \rightarrow \underset{\text{ Sodium sulphate }}{ Na_2SO_4 }+\underset{\text{ Water}}{H_2O}$

5. Oxidation and Reduction Reactions Oxidation

This reaction is a process in which oxygen is added to a substance or removed from a substance or a substance loses an electron(s). If a substance gains oxygen during a reaction then the substance is said to be oxidized. If a Oxygen is lost from a substance during a reaction, it is said to be reduced.

The substance that oxidizes the other substance is called an Oxidizing agent. The substance  that brings a reduction in another substance is called a Reduction agent.

i). $\underset{\text{Copper }}{2Cu} +\underset{\text{Oxygen }}{O_2} \rightarrow \underset{\text{ Copper oxide }}{2CuO}$

ii). $\underset{\text{Hydrogen sulphide }}{2H_2S} +\underset{\text{Oxygen }}{O_2} \rightarrow \underset{\text{Sulphur }}{2S}+\underset{\text{Hydrogen oxide}}{2H_2O}$

iii). $\underset{\text{ Zinc}}{Zn} \rightarrow \underset{\text{}}{Zn_{2+}} +\underset{\text{}}{2e^{-}}$

Redox Reactions

When a reaction has both oxidation and reduction  taking place simultaneously then the reaction is called a redox reaction.

1. In the reaction below, the copper (II) oxide is losing oxygen and is being reduced while oxygen is added to hydrogen and water is formed.

Reduction
|一一一一一一一|

$\underset{\text{ Copper }}{ CuO } + \underset{\text{Hydrogen}}{H_2} \rightarrow \underset{\text{Copper}}{Cu}+\underset{\text{Water}}{H_2O}$

Oxide |_________________|

Oxidation

2. In the reaction below, HCL is oxidised to HCL is oxidized to Cl2 whereas, MnO2 is reduced to MnCl2

Reduction
|一一一一一一一|

MnO2 (s) + 4HCL → MnCl2 (aq) + Cl2 (g) + 2H2O

(Conc.)

Oxidation
|一一一一一一一|

Effects of Oxidation Reactions in Everyday Life

### Corrosion

The phenomenon due to which the upper surface of the metals get eaten away when they come in contact with air, water and chemicals present in the atmosphere, then it is called corrosion.

Ex: When iron substances are new then they shine but get coated with a reddish brown powder when left for sometime.

Rusting is basically the process of corrosion of iron. The rusting of iron is a redox reaction. Painting, galvanizing, and electroplating are few methods to prevent corrosion.

Corrosion can cause damage to the body of a car, bridge, iron railing, ships because they are made up of iron.

### Rancidity

In this process,  the oil and fat which are volatile in nature present in the food materials slowly get oxidized resulting in the change of smell and taste in them.

The methods to prevent rancidity are:

1. Keep food in air-tight containers to prevent air from getting in.

2. Refrigeration of cooked food.

3. Packing of certain food items in packets containing nitrogen gas.

4. Avoid keeping food under the direct sunlight.

5. Rancidity can also be prevented by adding antioxidants like BHA and BHT.

### Importance of NCERT Solutions for Class 10 Science Chapter 1

Below are some of the benefits of Chapter 1 of Class 10 Science NCERT Solutions.

• Students will get a clear idea of balancing various types of equations.

• The solutions make it easier for the students to formulate chemical equations.

• Provides a large number of practice questions of varying difficulty levels so that board examinations may be taken without worry.

• Each and every question is explained in a step-by-step manner and these solutions are provided keeping in mind CBSE patterns.

## FAQs on Class 10 NCERT Solutions for Science Chapter 1 - Chemical Reactions and Equations

1. Before burning a magnesium ribbon in the air, why should it be cleaned

Magnesium ribbon must be cleaned before burning in the air, so as to remove the layer of MgO formed due to the reaction between magnesium and air.

2. Why not immediately a wall acquires a white colour when a coating of slaked lime is applied to it?

When a solution of slaked lime is applied on the wall, CO2 gas present in the air slowly reacts with a thin layer of calcium hydroxide to form a thin layer of calcium carbonate, that is quite white. Therefore, the newly formed calcium carbonate impart a white look to the walls.

Ca(OH)2 (aq) + CO2 (g) →  CaCO3 (s) + H2O (l)

3. Consider the following reaction:

2FeSO4 (s) → Fe2O3 (s) + SO2 (g) + SO3 (g)

Is it a redox reaction or not? If yes, why?

It is a redox reaction because ferrous (Fe3+) whereas SO2-4 is getting reduced to SO2.

4. Identify the oxidizing agent in the following equation.

MnO2 (s) + 4HCL à MnCl2 (aq) + Cl2 (g) + 2H2O

MnO2 is the oxidizing agent in the equation.

5. Why should students refer to NCERT Solutions provided by Vedantu?

NCERT Solutions provided by Vedantu is very comprehensive and developed in a step-by-step method that makes it self-explanatory. After extensive research and as per the latest syllabus and guidelines of NCERT, our subject-matter experts have designed the notes and the solutions for you to give a better understanding of the concept and they are easily accessible on the Vedantu’s official website. Our experienced teachers are available to clear all your doubts and strengthen your conceptual understanding. Students have shown drastic improvement in their overall performance by the solutions and the reference notes provided by Vedantu.

6. What is the chemical reaction and equations?

A chemical reaction is a process in which one or more substances react with one another and form a different substance known as a product. The product will usually have different physical and chemical properties compared to the reactants. An equation is a symbolic representation of this reaction using formulae, where reactants are on the left hand side and products on the right hand side.

7. What is a balanced chemical equation? Why should chemical equations be balanced?

A chemical equation is a symbolic representation of the entire chemical reaction. It consists of a left-hand side with all the reactants and a right hand side with the products. According to the law of conservation of mass, atoms can neither be created nor destroyed. To follow this universal law, the equation should be balanced so that the total atoms on the left side are equal to the atoms on the right side.

8. What is Chapter 1 of Class 10 Science?

Chapter 1 of NCERT Class 10 Science is Chemical Reactions and Equations. This is one of the basic chapters which is of great importance for building the foundation of Chemistry. It discusses important concepts like chemical formulae, equations reactions, writing a chemical equation, and balancing of chemical equations. These are very important topics that are covered in this chapter and are explained in depth in NCERT Solutions for Chapter 1 of Class 10  by Vedantu.

9. List out the topics and subtopics covered in the NCERT Solutions for Chapter 1 of Class 10 Science.

Chapter 1 of Class 10 Science Chemical Reactions and equations is a very important chapter from an exam point of view and also for building up the basics of the subject. Some of the topics covered are:

1. Chemical reactions and equations

2. Chemical equations

• Writing a chemical equation

• Balanced chemical equation

1. Types of chemical reactions

• Combination reaction

• Decomposition reaction

• Displacement reaction

• Double displacement reaction

• Oxidation and reduction

1. Have you observed the effects of oxidation reactions in everyday life?

• Corrosion

• Rancidity

10. How do solutions provided by Vedantu help in studying Chapter 1 of Class 10 Science?

Class 10 Science forms the building blocks of the basics of Science in Biology, Chemistry and Physics. Many important concepts and theories are covered in it. Therefore it is very important for students to understand these concepts and study the topics with a strong base. Vedantu has solutions for all the important questions of Chapter 1 of Class 10 Science explained in a very detailed yet simple manner so that the students can remember them for long. There are plenty of diagrams, graphs, flow charts and bullet point answers making the student’s work very easy. These solutions can be downloaded from the Vedantu app and from the Vedantu website at free of cost.