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Hydrocarbons Class 11 Notes CBSE Chemistry Chapter 13 [Free PDF Download]

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Revision Notes for CBSE Class 11 Chemistry Chapter 13 (Hydrocarbons) - Free PDF Download

To make studying more fun and easy, the CBSE revision notes for class 11 Chemistry chapter 13 hydrocarbons are available from the Vedantu site for free download. Students can also refer to these PDF notes, which contain a detailed explanation for all the important chapter topics. Using these PDF notes will enable the students to understand every topic clearly and come out with flying colors in the exams.

When we speak about the hydrocarbons in chemistry, they can be explained as organic compounds composed of hydrogen and carbon elements. However, when we study this topic in class 11, which is found in the CBSE books of chapter 13, we need to learn about various things such as the classification of hydrocarbons, alkenes, alkanes, alkynes, toxicity, and carcinogenicity, and understand the equations as well, solving different problems, and many more.

Download CBSE Class 11 Chemistry Revision Notes 2023-24 PDF

Also, check CBSE Class 11 Chemistry revision notes for other chapters:

Hydrocarbons Chapter Related Important Study Materials
It is a curated compilation of relevant online resources that complement and expand upon the content covered in a specific chapter. Explore these links to access additional readings, explanatory videos, practice exercises, and other valuable materials that enhance your understanding of the chapter's subject matter.

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Thermodynamics Class 11 Notes Chemistry - Basic Subjective Questions

Section – A (1 Mark Questions)

1. What do you mean by system?

Ans. A system in thermodynamics refers to that part of the universe in which observations are made.

2. What do you mean by surroundings?

Ans. The rest of the universe which might be in a position to exchange energy and matter with the system is called its surroundings.

3. Explain first law of thermodynamics.

Ans. The first law of thermodynamics states that ‘the energy of an isolated system is constant’.

4. ‘Coffee held in a cup’ is what type of system?

Ans. Coffee held in a cup is an open system because it can exchange matter (water vapors) and energy (heat) with the surroundings.

5. List one example of isolated system.

Ans. Coffee held in a thermos flask is an isolated system because it can neither exchange energy nor matter with the surroundings.

6. If work is done by the system, what will be the effect on internal enery of the system.

Ans. The internal energy of the system will decrease if work is done by the system.

7. In thermodynamics we discuss about open and close sytsem. So, animals and plants belongs to?

Ans. Animals and plants belongs to Open system.

8. Explain state of thermodynamic system?

Ans. The state of thermodynamic system may be defined by specifying values of state variables like temperature, pressure, volume.

9. What do you mean by Enthalpy?

Ans. Enthalpy is defined as total heat content of the system.

10. How do you define enthalpy mathematically?

Ans. Mathematically.

H = U + pV where U is internal energy.

Section – B (2 Marks Questions)

11. Internal energy is state function while work done is not. Why?

Ans. The change in internal energy during a process depends only upon the initial and final state of the system. Therefore, it is a state function. But the work is related the path followed. Therefore, it is not a state function.

12. Predict the sign of $\Delta\text{S}$ for the following reaction



Newman Projection of Ethane
is positive because on the product side we have gaseous CO2. 

13. What do you mean by spontaneous process.

Ans. A spontaneous process is an irreversible process and may only be reversed by some external agency.

14. What do you mean by non-spontaneous process?

Ans. A process is said to be non-spontaneous if it does not occur of its own under given condition and occur only when an external force is continuously applied.

15. The standard heat of formation of Fe2O3(s) is 824.2kJ mol–1. Calculate heat change for the reaction.

4Fe(s) + 3O2(g) → 2Fe2O3(s)




= 2 (-824.2 kJ) - [4 x 0 + 3 x 0]

= - 1648.4 kJ

16. Explain Heat capacity and what are the units of heat capacity?

Ans. The heat capacity for one mole of the substance is the quantity of heat needed to raise the temperature of one mole by one degree Celsius.

Its unit is : J/K

17. Explain specific heat.

Ans. Specific heat/specific heat capacity is the quantity of heat required to raise the temperature of one unit mass of a substance by one degree Celsius (or one Kelvin).

18. For solids or liquids, there is no significant difference between $\Delta\text{H}$ and $\Delta\text{H}$ .

Ans. The difference between $\Delta\text{H}$ and $\Delta\text{U}$ is not usually significant for systems consisting of only solids and/or liquids because they do not suffer any significant volume changes upon heating.

19. Define extensive and intensive properties?

Ans. Extensive property is a property whose value depends on the quantity or size of matter present in the system.

Intensive property is a property which do not depend upon the quantity or size of matter present.

20. C(graphite) + O2(g) → CO2(g) ΔH= - 393.5 kJ mol–1 . This is combustion reaction of C and CO2 is forming. Write the $\Delta\text{H}\degree$ values of the two preocesses. 

Ans. (i) The standard enthalpy of formation of CO2 is –393.5 kJ per mole of CO2.

That is $\Delta\text{H}\degree(\text{CO}_2,\text{g})$ = –393.5 kJ mol–1

(ii) The standard enthalpy of combustion of carbon is 393.5 kJ per mole of carbon i.e

Sawhorse Projection of Ethane

= –393.5 kJ mol–1

Access Class 11 Chemistry Chapter 13 – Hydrocarbons Notes 


Alkanes are the simplest saturated organic compounds or hydrocarbons. They are also called paraffins. General formula of alkanes is${{C}_{n}}{{H}_{2n+2}}$ .The carbon atoms in alkanes are $s{{p}^{3}}$ hybridized and have a tetrahedral shape. The bond length between C–H is$1.12\overset{o}{\mathop{A}}\,$ and between C – C is $1.54\overset{o}{\mathop{A}}\,$ . The simplest alkane is methane $\left( C{{H}_{4}} \right)$.


Alkanes have various conformers existing in space due to free rotation of the C – C single bond.

Different spatial arrangements of atoms give rise to isomers called conformers or rotamers. 

Conformation of ethane$\left( {{\text{C}}_{\text{2}}}{{\text{H}}_{\text{6}}} \right)$ 

Ethane has two types of conformation:

  1. Newman Projection

Reaction of Free Radical with Alkane

Newman Projection of Ethane

Order of stability is, staggered > skew > eclipsed


  1. SawHorse projection

Structure of the Major Product ‘X’

Sawhorse Projection of Ethane

Methods of Preparation 

  1. By catalytic hydrogenation of unsaturated hydrocarbons: Hydrogenation is the process of adding hydrogen to the unsaturated hydrocarbon in the presence of a catalyst. When the catalyst is Nickel and the temperature is $200-{{300}^{o}}C$ (Raney Ni) then the reaction is called Sabatier and Sanderson’s reduction. \[\underset{ethylene}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,+{{H}_{2}}\xrightarrow[{{200}^{o}}C]{Ni}\underset{ethane}{\mathop{C{{H}_{3}}-C{{H}_{3}}}}\,\] 

\[\underset{acetylene}{\mathop{CH\equiv CH}}\,+2{{H}_{2}}\xrightarrow[{{300}^{o}}C]{Ni}\underset{ethane}{\mathop{C{{H}_{3}}-C{{H}_{3}}}}\,\] 

At room temperature, hydrogenation is carried out using platinum or palladium as a catalyst in place of Ni. Methane cannot be produced by this method as an unsaturated hydrocarbon does not have a single carbon atom. 

  1. By the reduction of alkyl halides: 

This method uses alkyl halide which is reduced in presence of $Zn+C{{H}_{3}}COOH,Zn+HCl,Zn+NaOH,Zn+Cu$ along with an alcohol$({{C}_{2}}{{H}_{5}}OH)$ or aluminum amalgam in ${{C}_{2}}{{H}_{5}}OH$ or$LiAl{{H}_{4}}$.

\[R-X+2H\to RH+HX\] 

Alkyl halides can also be reduced by heating them with HI and red phosphorus in a sealed tube (under pressure).


 The function of red phosphorus is to remove iodine. 

  1. By the reduction of alcohols, aldehydes, ketones and fatty acids: 

These compounds and their derivatives can be reduced in the presence of hot hydroiodic acid and red phosphorus at ${{150}^{o}}C$ in a sealed tube to produce alkanes. The reactions are:

\[ROH+2HI\xrightarrow{\text{Red }\text{P}}RH+{{H}_{2}}O+{{I}_{2}}\]

\[RCHO+4HI\xrightarrow{\text{Red }\text{P}}RC{{H}_{3}}+2~{{I}_{2}}+{{H}_{2}}O\]

\[R-COR+4HI\xrightarrow{\text{Red P}}R-C{{H}_{2}}-R+{{H}_{2}}O+2{{I}_{2}}\]

\[R-COOH+6HI\xrightarrow{\text{Red P}}RC{{H}_{3}}+2{{H}_{2}}O+3{{I}_{2}}\] 

Aldehydes and ketones are also reduced to alkanes in the presence of amalgamated zinc and conc. HCl. This reaction is known as Clemmensen reduction. 


Aldehydes can also be reduced to alkanes using hydrazine and KOH at $150-{{200}^{o}}C$ . This reaction is known as Wolff−Kishner reduction. 

\[C{{H}_{3}}CHO+N{{H}_{2}}N{{H}_{2}}\to C{{H}_{3}}CH=NN{{H}_{2}}\xrightarrow{KOH}C{{H}_{3}}C{{H}_{3}}+{{N}_{2}}\] 

  1. By condensing two molecules of alkyl halides: 

When two molecules of alkyl halides are treated with sodium metal in the presence of dry ether, then they are coupled to form an alkane. This reaction is known as Wurtz synthesis. 


  1. By decarboxylation of carboxylic acid: when the sodium salt of carboxylic acid is strongly heated with soda lime, then an alkane is formed by elimination of $C{{O}_{2}}$as carbonate. 


  1. Kolbe’s electrolysis: This involves sodium or potassium salts of fatty acids to be electrolyzed that form higher alkanes at anode. 

\[2C{{H}_{3}}COONa+2{{H}_{2}}O\to C{{H}_{3}}-C{{H}_{3}}+2C{{O}_{2}}+2NaOH+{{H}_{2}}\] 

As the product is higher in alkanes, so methane can’t be prepared by this method. 

  1. By action of water on aluminium carbide or beryllium carbide: \[\underset{aluminium\,carbide}{\mathop{{{A}_{4}}{{C}_{3}}}}\,+12{{H}_{2}}O\to 4Al{{(OH)}_{3}}+3C{{H}_{4}}\uparrow \] 

\[\underset{Beryllium\,carbide}{\mathop{B{{e}_{2}}C}}\,+4{{H}_{2}}O\to 2Be{{(OH)}_{2}}+C{{H}_{4}}\uparrow \] 

Physical Properties  

  1. State: They consist of weak forces, therefore alkanes up to four carbon atoms are colourless and odourless gases, the next thirteen members are colourless and odourless liquids. Alkanes from carbon – 18  onwards are colourless and odourless solids.

In alkenes, except ethene, all are odourless and follow some trend as alkanes. Ethene has a pleasant odour. All are colourless. Alkynes also follow the same trend as alkanes.

  1. Density: The density of alkanes increases steadily with the rise of molecular mass and becomes constant at 0.8. 

  1. Solubility: They are insoluble in polar solvents such as water but soluble in non-polar solvents like ether, carbon tetrachloride$CC{{l}_{4}}$, benzene etc.

  1. Boiling and melting points: As the number of carbons in straight chain alkanes increases, the boiling point also increases. But the increase in melting point is irregular with respect to increase in molecular mass. Alkenes and alkynes also show a gradual increase in boiling and melting points with the increase in molecular mass in homologous series. They are less volatile than alkanes, i.e., their boiling point and melting point are higher than corresponding alkanes. 

Chemical Properties 

Alkanes are highly stable compounds and inert substances due to the presence of non-polar C – C and C – H bonds. Alkanes are saturated compounds with strong sigma bonds which don't break under ordinary conditions. Therefore, Alkanes react at high temperature by a free radical mechanism.

  1. Halogenation (free radical substitution): 

Alkanes react with halogens ($C{{l}_{2}},B{{r}_{2}}$ ) in the presence of light or in dark at high temperature to form corresponding substituted products. 

\[\underset{\text{ }methene\text{ }}{\mathop{C{{H}_{4}}}}\,\xrightarrow[-HCl]{C{{l}_{2}}}\underset{\text{ }methyl\text{ }chloride\text{ }}{\mathop{C{{H}_{3}}C1}}\,\xrightarrow[-HCl]{C{{l}_{2}}}\underset{\text{ }methylene\text{ }chloride\text{ }}{\mathop{C{{H}_{2}}C{{1}_{2}}}}\,\xrightarrow[-HCl]{C{{l}_{2}}}\underset{\text{ }chloroform\text{ }}{\mathop{CHC{{1}_{3}}}}\,\xrightarrow[-HCl]{C{{l}_{2}}}\underset{\text{ }carbon\,tetrachloride\text{ }}{\mathop{CC{{1}_{4}}}}\,\] 

The relative reactivity of halogens has the order ${{F}_{2}} > C{{l}_{2}} > B{{r}_{2}} > {{I}_{2}}$ and alkanes follow the order, ${{3}^{{}^\circ }} > {{2}^{{}^\circ }} > {{1}^{{}^\circ }} > C{{H}_{3}}$ 

  1. Nitration: Nitration is the introduction of the nitro group. It is possible for alkanes having three or more carbon atoms. Nitration of propane yields a mixture of nitro products.


  1. Sulphonation: Higher alkanes (C- 6 hexane onwards) undergo sulfonation when treated with fuming ${{H}_{2}}S{{O}_{4}}$. 

\[\underset{hexane}{\mathop{n-{{C}_{6}}{{H}_{14}}}}\,+HOS{{O}_{3}}H\to \underset{hexane\,sulphonic\,acid}{\mathop{{{C}_{6}}{{H}_{13}}S{{O}_{3}}H}}\,+{{H}_{2}}O\] 

  1. Oxidation or combustion: Alkanes burn in the presence of oxygen to form carbon dioxide and water along with evolution of heat. 

\[C{{H}_{4}}+2{{O}_{2}}\to C{{O}_{2}}+2{{H}_{2}}O\] 

\[2{{C}_{2}}{{H}_{6}}+7{{O}_{2}}\to 4C{{O}_{2}}+6{{H}_{2}}O\] 

Illustration 1: The order of reactivity of halogens towards halogenation of alkane is 

  1. $\text{ }{{F}_{2}} > B{{r}_{2}} > C{{l}_{2}}$ 

  2. $\text{ }{{F}_{2}} > C{{l}_{2}} > B{{r}_{2}}$ 

  3. $C{{l}_{2}} > {{F}_{2}} > B{{r}_{2}}$

  4. $C{{l}_{2}} > B{{r}_{2}} > {{F}_{2}}$ 

Solution: (B). In a group, electronegativity of the atom decreases. So, the reactivity of halogen also decreases in a group. Thus, the order of reactivity is ${{F}_{2}} > C{{l}_{2}} > B{{r}_{2}}$.

Illustration 2 : Consider the following reaction: 


Reaction of Free Radical with Alkane

Identify the structure of the major product ‘X’. 

Cis and Trans Isomers of but-2-ene

Structure of the Major Product ‘X’

Solution: (B). $B{{r}^{\centerdot }}$is less reactive and more selective and so the most stable free radical (${{3}^{o}}$ ) will be the major product.

Exercise 1

1. The compound with the highest boiling point is 

  1. n- hexane

  2. n- pentane

  3. 2,2- dimethylpropane

  4.  2- methyl butane

2. Relative reactivity of halogens on alkanes follow the order 

  1. ${{\text{F}}_{\text{2}}}\text{C}{{\text{l}}_{\text{2}}}\text{B}{{\text{r}}_{\text{2}}}\text{}{{\text{I}}_{\text{2}}}$ 

  2. $\text{C}{{\text{l}}_{\text{2}}}\text{B}{{\text{r}}_{\text{2}}}\text{}{{\text{I}}_{\text{2}}}\text{}{{\text{F}}_{\text{2}}}$ 

  3. ${{\text{F}}_{\text{2}}}\text{}{{\text{I}}_{\text{2}}}\text{B}{{\text{r}}_{\text{2}}}\text{C}{{\text{l}}_{\text{2}}}$ 

  4. ${{\text{I}}_{\text{2}}}\text{B}{{\text{r}}_{\text{2}}}\text{C}{{\text{l}}_{\text{2}}}\text{}{{\text{F}}_{\text{2}}}$ 

3. Propane is obtained from propene by which of the following methods?

  1. Wurtz reaction 

  2. Dehydration 

  3. Frankland reaction 

  4. Catalytic hydrogenation 


Alkenes are unsaturated hydrocarbons having a double bond between two carbon atoms. Alkenes have the general formula${{C}_{n}}{{H}_{2n}}$.


1. Structural isomerism 

Example, Butene has 3structural isomers,



Dehydrohalogenation of Alkyl Halides


2. Geometrical isomers

The hindered rotation around the C – C bond gives rise to stereoisomers having different spatial arrangements. Two isomers exist as follows:

Dehydrohalogenation of Vicinal Dihalides

Cis and Trans Isomers of but-2-ene

Methods of Preparation 

1. By dehydration of alcohol: Dehydration of alcohol in the presence of acids forms alkene. The reaction is an elimination reaction. 

\[R-C{{H}_{2}}-C{{H}_{2}}-OH\xrightarrow[\Delta ]{{{H}^{+}}}R-CH=C{{H}_{2}}+{{H}_{2}}O\] 

2. By the dehydrohalogenation of alkyl halides: it involves an alkyl halide in the presence of alcoholic KOH to yield alkene. \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Br\xrightarrow{alc.KOH}C{{H}_{3}}CH=C{{H}_{2}}+HBr\]

If dehydrogenation of alkyl halide gives two products, the major product will be according to Saytzeff’s rule that states that the most substituted alkene will be the major product. 

Kolbe’s Electrolysis Method

Dehydrohalogenation of Alkyl Halides

The ease of dehydrohalogenation has the order: 

Tertiary alkyl halide > secondary alkyl halide > primary alkyl halide. 

Alkyl halides follow the order: 

alkyl iodide > alkyl bromide > alkyl chloride. 

3. By the dehalogenation of vicinal dihalides: Dehydrohalogenation of vicinal dihalides in the presence of Zinc dust along with alcoholic solution yields pure alkene. 

Markonikov’s and Anti-Markovnikov's Rule for Halogenation of Propene

Dehydrohalogenation of Vicinal Dihalides

4. Kolbe’s electrolysis method: The electrolysis of sodium or potassium salts of dicarboxylic acid produces alkene at anode. 

Reaction of Hypochlorous Acid of Ethylene

Kolbe’s Electrolysis Method

If, $Na/Liq.N{{H}_{3}}$ is used, trans alkene is formed, and in presence of Ni cis alkene is formed. 

Physical Properties

1. Melting point: the trans isomers have a high melting point than cis isomer due to symmetry and crystal lattice.

2. Boiling point: Cis isomer has a more dipole moment as it is more polar and therefore has a high boiling point than trans isomer of alkene.

Chemical Properties 

Alkenes are reactive due to the presence of double bonds. Due to THE presence of $\pi $ bonds alkenes are able to react towards electrophilic addition reaction. They also give free radical addition reactions. 

1. Addition reactions: 

(i) Addition of hydrogen (catalytic hydrogenation) \[C{{H}_{2}}=C{{H}_{2}}+{{H}_{2}}\xrightarrow[200-{{300}^{o}}C]{Ni}C{{H}_{3}}-C{{H}_{3}}\] 

(ii)Addition of halogens (Chlorine and bromine) 

\[C{{H}_{2}}=C{{H}_{2}}+B{{r}_{2}}\to \underset{ethylene\,dibromide\,(colorless)}{\mathop{BrC{{H}_{2}}-C{{H}_{2}}Br}}\,\] 

Addition of bromine is used as a test for detecting the presence of unsaturation (C – C double bond or triple bond). 

(ii) Addition of hydrogen halides 

\[C{{H}_{2}}=C{{H}_{2}}+HX\to C{{H}_{3}}C{{H}_{2}}X\] 

The order of reactivity among hydrogen halides is 

HI > HBr > HCl > HF 

In case of unsymmetrical alkenes, addition occurs according to Markonikov’s rule. This reaction takes place through an ionic mechanism. Electrophilic addition to a carbon–carbon double bond involves the formation of an intermediate that is the  more stable carbocation. 

Deviation from Markonikov’s rule: 

It has been observed that addition of HBr to unsymmetrical alkenes like propene in presence of air, peroxide or light yields n-propyl bromide by anti-Markovnikov's rule. The effect is also called the peroxide effect or Kharasch effect. 

Reaction of Sulphuric Acid of Propene

Markonikov’s and Anti-Markovnikov's Rule for Halogenation of Propene 

  1.  Addition of hypochlorous acid 

Reaction of Hypochlorous Acid of Ethylene

Reaction of Hypochlorous Acid of Ethylene

  1.  Addition of sulphuric acid 

Reaction of Sulphuric Acid of Propene

Reaction of Sulphuric Acid of Propene

Alkyl hydrogen sulphates are water soluble, when heated at about${{160}^{o}}C$ , they give olefins. In reaction with water they give alcohol. 

Formation of Alcohol from Alkyl Hydrogen Sulphates

Formation of Alcohol from Alkyl Hydrogen Sulphates 

  1.  Addition of water 

It is also in accordance with Markovnikov’s rule.

Addition of Water  to Alkene

Addition of Water  to Alkene

  1.  Addition of alkanes (alkylation) 

Alkylation of Alkanes in Alkene

Alkylation of Alkanes in Alkene

  1.  Addition of diborane (hydroboration)

Hydroboration of Alkanes in Alkene

Hydroboration of Alkanes in Alkene

In case of unsymmetrical alkenes, addition follows Anti Markovnikov's rule. 

\[6C{{H}_{3}}C{{H}_{2}}CH=C{{H}_{2}}+{{B}_{2}}{{H}_{6}}\to \underset{tributyl\,borane}{\mathop{2{{\left( C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}} \right)}_{3}}~B}}\,\] 

Trialkyl borane on oxidation $({{H}_{2}}{{O}_{2}}/O{{H}^{-}})$  gives alcohol and on reduction $(LiAl{{H}_{4}})$ gives alkane. 

  1.  Oxymercuration – demercuration 

Oxymercuration – Demercuration of Alkene

Oxymercuration – Demercuration of Alkene

  1.  Addition of oxygen 

Addition of Oxygen in Alkene

Addition of Oxygen in Alkene

1. Oxidation: 

  1.  Oxidation by cold alkaline $KMn{{O}_{4}}$ (Bayer’s reagent) 

Oxidation of Alkene

Oxidation of Alkene

It is a test for detecting double bonds in alkene. Hydroxylation by $KMn{{O}_{4}}$ is always a syn addition. The cis alkene on hydroxylation gives meso compound and trans alkene gives racemic mixture. Like Bayer’s reagent $Os{{O}_{4}}$ also gives glycol and the hydroxylation is a syn addition. 

Hydroxylation of Alkene Using OsO4

Hydroxylation of Alkene Using OsO4

  1.  Oxidation by per acids $(RC{{O}_{3}}H)$ 

Oxidation of Alkene by per Acids $(RC{{O}_{3}}H)$

Oxidation of Alkene by per Acids $(RC{{O}_{3}}H)$ 

Reaction of Acetic Acid with Alkene

Reaction of Acetic Acid with Alkene

This addition occurs in trans manners. The cis alkene gives racemic mixture and trans alkenes give meso compound. 

  1.  Ozonolysis 

Ozonolysis of Alkene

Ozonolysis of Alkene

  1.  Oxidation by hot concentrated alkaline $KMn{{O}_{4}}$ 

\[RCH=C{{H}_{2}}+KMn{{O}_{4}}(conc.)\to RCOOH+C{{O}_{2}}+{{H}_{2}}O\]

1. Substitution reaction: 

Chlorination is done by treating the alkene with carbon tetrachloride in liquid phase or with chlorine gas:

Chlorination of Alkene

Chlorination of Alkene

Allylic bromination (bromination at allylic carbon atom) is very easily achieved by treating the alkene having hydrogen atom at the allylic carbon atom with N-bromosuccinimde (NBS). 

Allylic Bromination of Alkene

Allylic Bromination of Alkene 

Illustration 3 : Which of the following alkene has the lowest heat of hydrogenation? 

Alkene with Lowest Heat of Hydrogenation

Alkene with Lowest Heat of Hydrogenation

Solution: (B). Higher the stability of alkene, lower the heat of hydrogenation. 

Illustration 4 : 


Reaction of Alkene with Alkaline KMnO4

Reaction of Alkene with Alkaline KMnO4

Which is true about this reaction? 

(A) A is meso 1, 2-butan-di-ol formed by syn addition. 

(B) A is meso 1, 2-butan-di-ol formed by anti addition. 

(C) A is a racemic mixture of d and l, 1, 2-butan-di-ol formed by anti addition. 

(D) A is a racemic mixture of d and l, 1, 2-butan-di-ol formed by syn addition. 

Solution: (A). On cis alkene there is syn addition of two –OH groups forming meso compound

Exercise 2

Halogenation of Alkene

Halogenation of Alkene

Predominant A is:

Predominant Product A

Predominant Product A

Product X and Y from Alkene

Product X and Y from Alkene

X and Y are:

  1. $\text{C}{{\text{H}}_{3}}-\text{C}{{\text{H}}_{2}}-\text{CH}=\text{C}{{\text{H}}_{2}},\left( \text{C}{{\text{H}}_{3}}\text{C}{{\text{H}}_{2}}\text{COOH}+\text{C}{{\text{O}}_{2}} \right)$ 

  2. $\text{C}{{\text{H}}_{3}}-\text{CH}=\text{CH}-\text{C}{{\text{H}}_{3}},\text{C}{{\text{H}}_{3}}\text{COOH (2 moles) }$ 

  3. $\text{C}{{\text{H}}_{3}}-\text{CH}=\text{CH}-\text{C}{{\text{H}}_{3}},\text{C}{{\text{H}}_{3}}\text{CHO (2 moles) }$ 

  4. $\text{C}{{\text{H}}_{3}}-\text{C}{{\text{H}}_{2}}-\text{CH}=\text{C}{{\text{H}}_{2}},\left( \text{C}{{\text{H}}_{3}}\text{C}{{\text{H}}_{2}}\text{CHO}+\text{HCHO} \right)$ 

The reaction of propene with HOCl proceeds via the addition of:

  1. ${{H}^{+}}$ in the first step

  2. $C{{l}^{+}}$ the first step

  3. $O{{H}^{-}}$  in the first step

  4. $C{{l}^{+}}$ and $O{{H}^{-}}$ in a single step


Alkynes are characterized by the presence of a triple bond between two carbon atoms. The general formula of alkyne is${{C}_{n}}{{H}_{2n-2}}$ . 

Methods of Preparation 

1. By the dehydrohalogenation of vicinal dihalides: 

\[C{{H}_{2}}=C{{H}_{2}}\xrightarrow{B{{r}_{2}}}Br-C{{H}_{2}}-C{{H}_{2}}-Br+KOH(alc.)\to Br-CH=C{{H}_{2}}\xrightarrow{NaN{{H}_{2}}}CH\equiv CH\] 

\[C{{H}_{3}}-CHB{{r}_{2}}+KOH\text{ }(alc.)\text{ }\to C{{H}_{2}}=CH-Br\xrightarrow{NaN{{H}_{2}}}CH\equiv CH\] 

2. By dehalogenation of vicinal tetrahalides: 

Reaction with active metals like Zinc, Mg etc. gives acetylene. 

Dehalogenation of Vicinal Tetrahalides

Dehalogenation of Vicinal Tetrahalides

3. By Kolbe electrolysis method: 

Kolbe Electrolysis Method

Kolbe Electrolysis Method

4. By heating iodoform or chloroform with silver powder or zinc: This method can be used for the preparation of only acetylene. 

\[CH{{I}_{3}}+6Ag+CH{{I}_{3}}\to CH\equiv CH+6AgI\] 

5. From acetylene: Higher alkynes can be prepared from acetylene when treated with sodium metal in liquid ammonia.

\[CH\equiv CH+Na\xrightarrow{Liq.N{{H}_{3}}}CH\equiv C-Na+{}^{1}/{}_{2}{{H}_{2}}\] 

\[\underset{sodium\,acetylide}{\mathop{CH\equiv CNa}}\,+C{{H}_{3}}Br\to \underset{propyne}{\mathop{CH\equiv C-C{{H}_{3}}}}\,+NaBr\] 

Similarly, $CH\equiv CH\xrightarrow[Liq.N{{H}_{3}}]{2Na}NaC=CNa\xrightarrow{2C{{H}_{3}}Br}C{{H}_{3}}C=CC{{H}_{3}}$ 


Chemical Properties 

Alkyne gives electrophilic addition reactions due to the presence of loosely held $\pi $ electrons, but electrophilic addition reactions in alkynes are slower than that of alkenes. 

Terminal hydrogen present in alkynes is acidic in nature. Since s electrons are closer to the nucleus than p electrons, the electrons present in the bond having more s character will be closer to the nucleus. The amount of s character in various types of C – H bond are as follows 

Hybridisation of Alkene, Percentage of S-Character

Hybridisation of Alkene, Percentage of S-Character

Relative acidities: 

\[\text{HOH}=\text{HOR} > \text{CH}\equiv \text{CR} > \overset{..}{\mathop{\text{N}}}\,{{\text{H}}_{3}} > \text{C}{{\text{H}}_{2}}=\text{C}{{\text{H}}_{2}} > \text{C}{{\text{H}}_{3}}-\text{C}{{\text{H}}_{3}}\]

Relative basicities: 

\[\text{O}{{\text{H}}^{-}}=\text{O}{{\text{R}}^{-}} < {{\text{C}}^{-}}\equiv \text{C}-\text{R} < \text{NH}_{2}^{-} < \text{C}{{\text{H}}^{-}}=\text{C}{{\text{H}}_{2}} < \text{CH}_{2}^{-}-\text{C}{{\text{H}}_{3}}\] 

1. Addition of hydrogen:

\[\underset{acetylene}{\mathop{CH\equiv CH}}\,+{{H}_{2}}\xrightarrow{Ni}\underset{ethylene}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,\xrightarrow{{{H}_{2}}}\underset{ethane}{\mathop{C{{H}_{3}}-C{{H}_{3}}}}\,\] 

In case of alkynes where triple bond is not present at the end of the chain, on reduction gives cis or trans alkene, which depends upon the choice of reducing agent. With sodium in liquid ammonia the alkene is trans form and on catalytic reduction the alkene is cis form.

Addition of Hydrogen to Alkyne

Addition of Hydrogen to Alkyne

2. Electrophilic addition: 

  1. Addition of halogens 

Electrophilic Addition of Chlorine in Alkyne

Electrophilic Addition of Chlorine in Alkyne

The order of reactivity of halogens is $C{{l}_{2}} > B{{r}_{2}} > {{I}_{2}}$ 

  1.  Addition of halogen acid


Electrophilic Addition Halogen Acid of Alkyne

Electrophilic Addition Halogen Acid of Alkyne

The order of reactivity of halogen acids is HI > HBr > HCl.

In the presence of peroxide, anti Markonikov’s product is obtained. 

Halogenation of Alkyne

Halogenation of Alkyne 

  1. Addition of hypohalous acids

Addition of Hypohalous Acids of Alkyne

Addition of Hypohalous Acids of Alkyne 

3. Nucleophilic addition reaction: In these reactions, the addition is initiated by a nucleophile and are generally catalysed by salt of heavy metals (e.g. $H{{g}^{2+}},P{{b}^{2+}},B{{a}^{2+}}$ )which are found to form $\pi $ compound with multiple bonds. 

\[\text{HC}\equiv \text{CH}+\text{H}{{\text{g}}^{2+}}\to \underset{\underset{H{{g}^{2+}}}{\mathop{\downarrow }}\,}{\mathop{\text{CH}=\text{CH}}}\,\] 

  1. Addition of water

Addition of Water to Alkyne

Addition of Water to Alkyne 

  1. Addition of hydrogen cyanide

\[HC\equiv CH+HCN\xrightarrow{Ba{{(CN)}_{2}}}\underset{vinyl\,cyanide}{\mathop{C{{H}_{2}}=CHCN}}\,\]

  1. Addition of acetic acid

Addition of Acetic Acid to Alkyne

Addition of Acetic Acid to Alkyne 


  1. Addition of alcohol 

\[HC\equiv CH+{{C}_{2}}{{H}_{5}}OH\xrightarrow[{{130}^{o}}C]{{{H}_{2}}S{{O}_{4}}}C{{H}_{2}}=CHO{{C}_{2}}{{H}_{5}}\xrightarrow{{{H}_{2}}O}C{{H}_{3}}CHO+{{C}_{2}}{{H}_{3}}OH\] 

  1. Addition of ozone and ozonolysis 

Ozonolysis of alkyne

Ozonolysis of alkyne

4. Oxidation: 

  1. Oxidation with alkaline $KMn{{O}_{4}}$ 

\[\underset{acetylene}{\mathop{HC\equiv CH}}\,+4[O]\xrightarrow{alk.KMn{{O}_{4}}}\underset{oxalic\,acid}{\mathop{HOOC-COOH}}\,\]

Oxidation of Alkyne

Oxidation of Alkyne

  1. Oxidation with acidic ${{K}_{2}}C{{r}_{2}}{{O}_{7}}$ $KMn{{O}_{4}}$ 

\[\underset{acetylene}{\mathop{HC\equiv CH}}\,+\xrightarrow[{{H}^{+}}]{{{K}_{2}}C{{r}_{2}}{{O}_{7}}}HOOC-COOH\to \underset{acetic\,acid}{\mathop{C{{H}_{3}}COOH}}\,\] 

Oxidation of Acidic ${{K}_{2}}C{{r}_{2}}{{O}_{7}}$ / $KMn{{O}_{4}}$

Oxidation of Acidic ${{K}_{2}}C{{r}_{2}}{{O}_{7}}$ / $KMn{{O}_{4}}$ 

5. Formation of metallic derivatives: 

The group –C≡C–H in alkynes is slightly acidic in nature and hence its hydrogen atom can be easily replaced by certain metals to give metallic derivatives called acetylides or alkynides. 

Acidic Hydrogen in Alkenes

Acidic Hydrogen in Alkenes

  1. Formation of sodium acetylides

\[HC\equiv CH+Na\xrightarrow{Liq.N{{H}_{3}}}\underset{monosodium\,acetylide}{\mathop{HC\equiv C-Na}}\,+Na\xrightarrow[{{120}^{o}}C]{NaN{{H}_{2}}}\underset{disodium\,acetylide}{\mathop{NaC=CNa}}\,\] 

Formation of Sodium Propynide

Formation of Sodium Propynide

  1. Formation of copper and silver acetylides 

\[HC\equiv CH+\underset{ammonical\,cuprous\,chloride}{\mathop{2CuC{{l}_{2}}+2N{{H}_{4}}OH}}\,\to \underset{copper\,acetylide\,(red\,ppt.)}{\mathop{Cu-C\equiv C-Cu\downarrow }}\,+2N{{H}_{4}}Cl+2{{H}_{2}}O\] 

\[HC\equiv CH+\underset{ammonical\,silver\,nitrate}{\mathop{2AgN{{O}_{3}}+2N{{H}_{4}}OH}}\,\to \underset{silver\,acetylide\,(white\,ppt)}{\mathop{AgC\equiv CAg\downarrow }}\,+2N{{H}_{4}}N{{O}_{3}}+2{{H}_{2}}O\] 

These reactions are used for detecting the presence of acetylenic hydrogen atoms. 

Illustration 4 : The products obtained via oxymercuration ($HgS{{O}_{4}}+{{H}_{2}}S{{O}_{4}}$) of 1–butyne would be 

Oxymercuration Product of 1–Butyne

Oxymercuration Product of 1–Butyne

Solution: (A)

Oxymercuration reaction of 1–butyne

Oxymercuration reaction of 1–butyne

Class 11 Hydrocarbons Revision Notes

This complete article deals with class 11 hydrocarbons revision notes. Firstly, the term ‘hydrocarbons’ refers to the compounds of hydrogen and carbon only. Hydrocarbons specifically play a crucial role in our lives. 

Moreover, humans obtain kerosene, diesel, and petrol by the fractional distillation of petroleum. In the same way, humans also obtain coal gas by the destructive distillation of coal. All such fuel types, which are the sources of energy, comprises hydrocarbons mixture.

One of the most important alkenes reactions certainly happens to be oxidization, combustion, aromatization, and free radical substitution. Moreover, alkynes and alkenes undergo different multiple reactions. Most notably, these reactions are of addition reactions, which are electrophilic additions mainly. Also, the aromatic hydrocarbons primarily undergo electrophilic substitution reactions despite having unsaturation.

Topics Covered Under Class 11 Chemistry

Some of the topics that fall under the Class 11 Chemistry include:

  • Some basic concepts of Chemistry

  • Classification of the Elements & Periodicity in Properties

  • Structure of Atom

  • States of Matter - Liquids and Gases

  • Chemical Bonding & Molecular Structure

  • Equilibrium

  • Thermodynamics

  • Redox Reactions

  • Hydrocarbons

  • Environmental Chemistry (Not for Examination point of View)

Sub-Topics Covered Under Hydrocarbons

  • Alkanes - Alkanes are known as organic compounds that consist of only hydrogen and carbon atoms which are single-bonded

  • Conformation of Alkanes - The conformation of alkanes deals with the isomers of alkanes whose formation is due to the slight structural changes

  • Preparation of Alkenes and Nomenclature - This basically deals with the preparation of the Alkenes and its naming

  • Preparation of Alkynes and Nomenclature - Naming of Alkynes occurs by counting the longest continuous chain’s number of carbons, and their preparation is mostly the same as those of the alkenes

  • Preparation of Aromatic Hydrocarbons and Nomenclature - According to the IUPAC system, the naming of aromatic hydrocarbons happens as benzene derivatives. In contrast, their preparation happens by different methods, and the most common method used is the isolating coal tar.

  • Properties of Alkanes - Alkanes are known to be the unsaturated form of hydrocarbons

  • Properties of Alkynes - Alkynes are the third type of hydrocarbon which contains at least one triple bond between a pair of carbon atoms

  • Properties of Aromatic Hydrocarbons - The aromatic Hydrocarbons are called cyclic hydrocarbons having the delocalized pi electrons between the carbon atoms of the ring

Importance of Class 11 Revision Notes Hydrocarbons

The Revision Notes of Class 11 Hydrocarbons Chemistry or the CBSE class 11 quick revision notes for Chemistry or other subjects help the students revise the entire syllabus during the exam days. This revision notes of Hydrocarbons covers all the important formulas and concepts given in the chapter. Even if the student wishes to have an overview of a chapter, the quick revision notes will help them. These notes will also save time during stressful exam days.

You can download the Hydrocarbons Class 11 Chemistry Notes, you can visit the official website of Vedantu (, and can apply the search using the keywords such as class 11 chemistry revision notes hydrocarbons, class 11 chemistry revision notes pdf, and more related.

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  • Question Papers

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So, it is highly recommended that the students reach out to Vedantu if they need any important information concerning their Academics. Students can also participate in the merit scholarships and can get awarded for the correct answers given by them.

FAQs on Hydrocarbons Class 11 Notes CBSE Chemistry Chapter 13 [Free PDF Download]

1. What are CNG and LPG?


CNG (Compressed Natural Gas) mainly consists of methane (95%), a relatively unreactive hydrocarbon, and makes its nearly complete combustion possible.


LPG (Liquified Petroleum gas) is a mixture of isobutane and butane containing a small amount of propane. A strong, foul-smelling substance, known as ethyl mercaptan (C2H5SH), is added to the LPG cylinders, detecting the gas leakage.

2. Mention some important points in terms of Hydrocarbons?

Some important points of Hydrocarbons concerning Alkanes can be given as follows.

  • Alkenes are more reactive when compared to Alkanes. This is because of the availability of n electrons.

  • The double bond of carbon-carbon in alkenes is composed of one σ-bond and one π-bond.

3. Explain the classification of Hydrocarbons?

The classification of Hydrocarbons can be depicted clearly with the following representation.

(Image to be added soon)

Students can get a clear understanding by pointing to this pictorial representation at the time of their exams, without any doubt, and can be remembered easily.

4. Explain the importance of revision notes?

Revision Notes are much important for every student because:

  • All the important points will be found regarding the complete chapter in the notes

  • It is easy to carry the revision notes because the size of it is handy

  • Since the students will note the formulas, points to remember, and more related, there is a less possibility of performing the to-do list at the time of exams.

5. Why should we refer to Revision Notes for Class 11 Chemistry Chapter 13?

As Chemistry is a challenging topic, you must practice it as much as possible. In addition, the Class 11 Chemistry Chapter 13 Revision Notes are well-structured and correspond to the CBSE syllabus for Class 11. Going through these notes is important since they cover a wide range of topics and concepts, giving you a solid idea of all the concepts covered in the chapter. As a bonus, these questions teach you how different questions on the same topic may be set. The revision notes can also be downloaded free of cost.

6. What are the topics covered in the Class 11 Chemistry Chapter 13 Revision Notes?

This chapter contains topics related to hydrocarbons such as contents on its classifications. Furthermore, the chapter contains content on alkanes, their nomenclature, isomerism, preparation and so on. Double bond structure, preparation, and isomerism of alkenes are also discussed in this chapter along with the preparation and properties of the triple bond of the alkyne groups. Similar properties are discussed for the groups of aromatic hydrocarbons. Few more topics related to hydrocarbons have been included in this chapter.

7. What are the 4 types of hydrocarbons?

Hydrocarbons are of two types - aliphatic and aromatic hydrocarbons. Alkanes, alkenes, and alkynes are aliphatic hydrocarbons. Benzene is an aromatic hydrocarbon. In general, hydrocarbons are composed of the following compounds: butane, propane, ethane, and methane. Four kinds of hydrocarbons exist. These are alkanes, alkenes, alkynes, and aromatic hydrocarbons (also known as hydrocarbons). Among hydrocarbons, the simplest ones are alkanes. Proper knowledge of all the types of hydrocarbons is important to get an overall idea of their properties and preparation processes and can be accessed through the Vedantu app.

8. Is Chapter 13 “Hydrocarbons” important for JEE?

For the JEE exam, you have to grasp the essential chemical concepts of hydrocarbon name and numbering, reactions with hydrocarbons, and alcohol reactions as well as carboxylic acid reactions with ketones. Hydrocarbons are very important for JEE’s chemistry section and multiple questions will be asked from this part. If you want to score well in your JEE exam, you must practice this chapter judiciously.

9. Does coal have adverse effects?

Combustion of coal produces several significant emissions, including a lot of sulphur dioxide. As a result of nitrogen oxides, smog and respiratory diseases can develop. There are particles in the air that are responsible for the creation of smog, haze, respiratory diseases, and lung disease. Each one of coal's consequences has an economic cost, from the loss of jobs for fishermen living downstream of a coal mine to the health care expenditures for those affected by coal-fired power plant pollution etc.