NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations (EX 4.3) Exercise 4.3

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NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations (EX 4.3) Exercise 4.3

Free PDF download of NCERT Solutions for Class 7 Maths Chapter 4 Exercise 4.3 (EX 4.3) and all chapter exercises at one place prepared by expert teacher as per NCERT (CBSE) books guidelines. Class 7 Maths Chapter 4 Simple Equations Exercise 4.3 Questions with Solutions to help you to revise complete Syllabus and Score More marks. Register and get all exercise solutions in your emails. Every NCERT Solution is provided to make the study simple and interesting on Vedantu. Subjects like Science, Maths, English will become easy to study if you have access to NCERT Solution for Class 7 Science , Maths solutions and solutions of other subjects.

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Exercise: 4.3

1. Solve the following equations:

a) \[2y+\frac{5}{2}=\frac{37}{2}\]

Ans:     

       \[\Rightarrow 2y=\frac{37}{2}-\frac{5}{2}=\frac{37-5}{2}=\frac{32}{2}=16\]

       \[\Rightarrow 2y=16\]

       \[\Rightarrow y=\frac{16}{2}=8\]

       \[\Rightarrow y=8\]


b) \[5t+28=10\]

Ans:

       \[\Rightarrow 5t=10-28=-18\]

       \[\Rightarrow 5t=-18\]

       \[\Rightarrow t=\frac{-18}{5}\]


c) \[\frac{a}{5}+3=2\]

Ans:

      \[\Rightarrow \frac{a}{5}=2-3=-1\]

      \[\Rightarrow \frac{a}{5}=-1\]

     \[\Rightarrow a=-1\times 5=-5\]

     \[\Rightarrow a=-5\]


d) \[\frac{q}{4}+7=5\]

Ans:

     \[\Rightarrow \frac{q}{4}=5-7=-2\]

     \[\Rightarrow \frac{q}{4}=-2\]

     \[\Rightarrow q=-2\times 4=-8\]

     \[\Rightarrow q=-8\]


e) \[\frac{5}{2}x= -10\]

Ans:     

        \[\Rightarrow x= -10\times \frac{2}{5}=-4\]

         \[\Rightarrow x=-4\]


f) \[\frac{5}{2}x=\frac{25}{4}\]

Ans:   

     \[\Rightarrow x=\frac{25}{4}\times \frac{2}{5}=\frac{5}{2}\]

      \[\Rightarrow x=\frac{5}{2}\]


g) \[7m+\frac{19}{2}=13\]

Ans:    

      \[\Rightarrow 7m=13-\frac{19}{2}=\frac{13\times     2-19}{2}=\frac{26-19}{2}=\frac{7}{2}\]

      \[\Rightarrow 7m=\frac{7}{2}\]

      \[\Rightarrow m=\frac{7}{2}\times \frac{1}{7}=\frac{1}{2}\]


h) \[6z+10=-2\]

Ans:    

      \[\Rightarrow 6z=-2-10=-12\]

      \[\Rightarrow 6z=-12\]

      \[\Rightarrow z=\frac{-12}{6}=-2\]

      \[\Rightarrow z=-2\]


i) \[\frac{3l}{2}=\frac{2}{3}\]

Ans:    

      \[\Rightarrow 3l=\frac{2\times 2}{3}=\frac{4}{3}\]

      \[\Rightarrow 3l=\frac{4}{3}\]

      \[\Rightarrow l=\frac{4}{3\times 3}=\frac{4}{9}\]

      \[\Rightarrow l=\frac{4}{9}\]


j) \[\frac{2b}{3}-5=3\]

Ans:    

      \[\Rightarrow \frac{2b}{3}=3+5=8\]

      \[\Rightarrow \frac{2b}{3}=8\]

      \[\Rightarrow 2b=8\times 3=24\]

      \[\Rightarrow 2b=24\ \ \ \ \ \]

      \[\Rightarrow b=\frac{24}{2}=12\]

      \[\Rightarrow b=12\]


2. Solve the following equations:

a) \[2\left( x+\text{ }4 \right)=12~\]

Ans:    

\[\Rightarrow x+4=\frac{12}{2}=6\]

\[\Rightarrow x=6-4=2\]

\[\Rightarrow x=2\]


b) \[3\left( n-5 \right)=21\]

Ans:    

\[\Rightarrow n-5=\frac{21}{3}=7\]

\[\Rightarrow n=7+5=12\]


c) \[3\left( n-5 \right)=-21\text{ }\]

Ans

\[\Rightarrow n-5=\frac{21}{3}=-7\]

\[\Rightarrow n=-7+5=-2\]

\[\Rightarrow n=-2\]


d) \[-4\left( 2+x \right)=8\]

Ans:    

\[\Rightarrow -4\times 2-\left(  4\times x \right)\text{=8}\]

\[\Rightarrow -8-4x=8\]

\[\Rightarrow -4x=8+8=16\]

 \[\Rightarrow x=\frac{-16}{4}=-4\]


e) \[4\left( 2-x \right)=8\]

Ans:    

 \[\Rightarrow 4\times 2-\left(  4\times x \right)\text{=8}\]

\[\Rightarrow 8-4x=8\]

\[\Rightarrow -4x=8-8\]

\[\Rightarrow x=0\]


3. Solve the following equations:

a) \[4=5\left( p-2 \right)\]

Ans:    

      \[\Rightarrow 4=5\times p-5\times 2\]

      \[\Rightarrow 4=5p-10\]

      \[\Rightarrow 5p=4+10\]

      \[\Rightarrow 5p=14\]

      \[\Rightarrow p=\frac{14}{5}\]


b) \[-4=5\left( p-2 \right)\]

Ans:    

       \[\Rightarrow -4=5\times p-5\times 2\]

       \[\Rightarrow -4=5p-10\]

       \[\Rightarrow 5p=-4+10\]

       \[\Rightarrow 5p=6\]

       \[\Rightarrow p=\frac{6}{5}\]


c) \[16=4+3\left( t+2 \right)\]

Ans:    

       \[\Rightarrow 16-4=3\left( t+2 \right)\]    

       \[\Rightarrow 12=3\left( t+2 \right)\]

       \[\Rightarrow \frac{12}{3}=\left( t+2 \right)\]

       \[\Rightarrow 4-2=t\]

       \[\Rightarrow t=2\]


d) \[4+5\left( p-1 \right)=34\]

Ans:    

       \[\Rightarrow 4+5\times p-5\times 1 = 34\]

       \[\Rightarrow 4+5p-5=34\]

       \[\Rightarrow 5p=34+1\]

       \[\Rightarrow 5p=35\]

       \[\Rightarrow p=\frac{35}{5}\]

       \[\Rightarrow p=7\]


e) \[0=16+4\left( m-6 \right)\]

Ans:    

     \[\Rightarrow 0=16+4\left( m-6 \right)\]

     \[\Rightarrow \frac{-16}{4}=\left( m-6 \right)\]

     \[\Rightarrow -4=m-6\]

     \[\Rightarrow -4+6=m\]

      \[\Rightarrow m=2\]


4. 

a) Construct 3 equations starting with \[x=2\].

Ans: The following equation can be solving in following steps;

Step I: 

\[x=2\]  

Multiplying both sides by 10,

\[10x=20\]                  

Adding 2 both sides

\[10x+2=20+2=22\]

\[10x+2=22\]

Step II:

Multiplying both sides by 5

\[x=2\]

\[5x=10\]

Subtracting 3 from both sides

\[5x-3=10-3=7\]

\[5x-3=7\]

Step III:

Dividing both sides by 5

\[x=2\]

\[\frac{x}{5}=\frac{2}{5}\]


b) Construct 3 equations starting with \[x=-2\].

Ans: The following equation can be solving in following steps;

Step I: 

\[x=-2\]

Multiplying both sides by 3

\[3x=-6\]

Step II:

Multiplying both sides by 3

\[x=-2\] 

\[3x=-2\times 3=-6\]

\[3x=-6\]

Adding 7 to both sides

\[3x+7=-6+7=1\]

\[3x+7=1\]

Step III:

Multiplying both sides by 3 

\[x=-2\]

\[3x=-2\times 3=-6\]

\[3x=-6\]

Adding 10 to both sides

\[3x+10=-6+10\]

\[3x+10=4\]


NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Exercise 4.3

Opting for the NCERT solutions for Ex 4.3 Class 7 Maths is considered as the best option for the CBSE students when it comes to exam preparation. This chapter consists of many exercises. Out of which we have provided the Exercise 4.3 Class 7 Maths NCERT solutions on this page in PDF format. You can download this solution as per your convenience or you can study it directly from our website/ app online.

Vedantu in-house subject matter experts have solved the problems/ questions from the exercise with the utmost care and by following all the guidelines by CBSE. Class 7 students who are thorough with all the concepts from the Maths textbook and quite well-versed with all the problems from the exercises given in it, then any student can easily score the highest possible marks in the final exam. With the help of this Class 7 Maths Chapter 4 Exercise 4.3 solutions, students can easily understand the pattern of questions that can be asked in the exam from this chapter and also learn the marks weightage of the chapter. So that they can prepare themselves accordingly for the final exam.

Besides these NCERT solutions for Class 7 Maths Chapter 4 Exercise 4.3, there are plenty of exercises in this chapter which contain innumerable questions as well. All these questions are solved/answered by our in-house subject experts as mentioned earlier. Hence all of these are bound to be of superior quality and anyone can refer to these during the time of exam preparation. In order to score the best possible marks in the class, it is really important to understand all the concepts of the textbooks and solve the problems from the exercises given next to it. 

Do not delay any more. Download the NCERT solutions for Class 7 Maths Chapter 4 Exercise 4.3 from Vedantu website now for better exam preparation. If you have the Vedantu app in your phone, you can download the same through the app as well. The best part of these solutions is these can be accessed both online and offline as well.

FAQs (Frequently Asked Questions)

Q1. How many questions are there in NCERT Solutions for Chapter 4 “Simple Equations” of Class 7 Maths?

Ans: NCERT Solutions for Chapter 4 of Class 7 Maths has approximately 18 questions distributed over four exercises. The NCERT Solutions provide detailed answers for each question, so you can comprehend the concepts step-by-step. These questions demand a lot of attention and practice since each step is crucial for the examinations. The more time you spend solving every question along with the examples, the better you will grasp the Chapter.

Q2. Do I need to practice all the questions provided in NCERT Solutions for Chapter 4 Simple Equations of Class 7 Maths?

Ans: Yes, it is necessary to solve all the questions provided in NCERT Solutions for Chapter 4 of Class 7 Maths. Simple Equation is a Chapter that requires a lot of practice for a thorough understanding of the topics and to be able to learn their application in solving the questions. You can easily evaluate your progress using the solutions or use them as reference guides for clarifications. Preparing Chapter 4 is a smooth sail with the help of NCERT Solutions for Chapter 4 of Class 7 Maths.

Q3. What do you mean by simple equations according to Chapter 4 of Class 7 Maths?

Ans: A simple equation is the representation of the relationship between two expressions on either side of the ‘=’ sign. These equations must have one but can have two or more variables. Students can get in-depth knowledge about simple equations in the NCERT Solutions for Chapter 4 of Class 7 Maths. The NCERT Solutions provide you with accurate methods to solve each question in a manner that helps you comprehend them at the same time.

Q4. How do you write an equation according to Chapter 4 of Class 7 Maths?

Ans: You can learn how to write an equation and all about Chapter 4 Simple Equations in the NCERT Solutions. For example the question states to write an equation for the sum of two numbers that is equal to 8 while one of the two numbers is 3. To form an equation we assume the unknown number as x or any other variable and following the details in the question the equation is: 3 + x = 8.

Q5. How many questions are there in Exercise 4.3 of Chapter 4 of Class 7 Maths?

Ans: Exercise 4.3 has four questions with various sub-parts to each question. You can download an offline PDF for NCERT Solutions of Chapter 4 of Class 7 Maths for accurate answers to these questions and of other exercises in the Chapter. Learning the theory and application of all the fundamentals becomes easier with NCERT Solutions. It is also a great aid for self-assessment and reference purposes. With the right preparation, you can be exam-ready.

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