Class 5 Maths Chapter 9 NCERT Solutions: Coconut Farm Answers

NCERT Solutions Class 5 Maths Mela Chapter 9 Coconut Farm (2025-26)

Exercise Questions & Answers

Observe the following array of coconuts.
Write two division facts using the given multiplication fact.

• Given: 35 ÷ 7 = 5, 35 split into 7 groups has 5 in each group.
• Multiplication Fact: 5 × 7 = 35
• 35 ÷ 5 = 7, 35 split into 5 groups has 7 in each group.
• So, two division facts:
  • 35 ÷ 7 = 5
  • 35 ÷ 5 = 7

Division Facts

Write two division facts for the following multiplication fact (for 99):

• Multiplication fact: 11 × 9 = 99
• 99 ÷ 11 = 9
• 99 ÷ 9 = 11

Let Us Play

1. Solve the following multiplication problems. Write two division statements in each case.
   
   • 30 × 30 = 900
     900 ÷ 30 = 30
     900 ÷ 30 = 30
   • 400 × 8 = 3200
     3200 ÷ 8 = 400
     3200 ÷ 400 = 8
   • 15 × 60 = 900
     900 ÷ 15 = 60
     900 ÷ 60 = 15
   • 200 × 16 = 3200
     3200 ÷ 16 = 200
     3200 ÷ 200 = 16

Patterns in Division and Place Value

• How many 3s in 150? 50 × 3 = 150; 150 ÷ 3 = 50.
• 10 × 100 = 1000; 1000 ÷ 10 = 100.
• 5 × 100 = 500; 500 ÷ 5 = 100.
• 44 × 10 = 440; 440 ÷ 44 = 10.
• 37 × 100 = 3700; 3700 ÷ 37 = 100.

• 1000 ÷ 10 = 100
• 100 ÷ 10 = 10
• 2000 ÷ 2 = 1000
• 200 ÷ 20 = 10
• 3300 ÷ 3 = 1100
• 80 ÷ 4 = 20
• 1000 ÷ 100 = 10
• 300 ÷ 100 = 3
• 2000 ÷ 20 = 100
• 440 ÷ 44 = 10
• 3300 ÷ 300 = 11
• 500 ÷ 5 = 100
• 1600 ÷ 4 = 400
• 500 ÷ 50 = 10
• 3700 ÷ 37 = 100
• 630 ÷ 63 = 10
• 4000 ÷ 40 = 100

Now fill the place value chart:

Let Us Do

1. Sabina cycles 160 km in 20 days and the same distance each day. How many kilometres does she cycle each day?
   Answer: 160 ÷ 20 = 8 km each day.
2. How many notes of ₹100 does Seema need to carry if she wants to buy coconuts worth ₹4200?
   Answer: 4200 ÷ 100 = 42 notes of ₹100.
3. The owner of an electric store has decided to distribute ₹5500 equally amongst 5 of his employees as a Diwali gift. What amount will each employee get?
   Answer: 5500 ÷ 5 = ₹1100 each.
   What will happen if he distributes the same amount of money among 10 employees? Will each employee get more or less? How much money would he have to distribute if everyone must get the same amount as earlier?
   Answer: Each will get less. For each to get ₹1100, owner must distribute 10 × 1100 = ₹11,000.
4. Place the numbers 1 to 8 in the following boxes so that all operations give correct results (No answer specified in book above.)
5. Fill in the blanks:
   (a) 1800 ÷ 18 = 100
   (b) 6100 ÷ 10 = 610
   (c) 7200 ÷ 100 = 72
   (d) 1000 ÷ 100 = 10
   (e) 870 ÷ 10 = 87
   (f) 7000 ÷ 100 = 70
   (g) 200 ÷ 100 = 2
   (h) 130 ÷ 10 = 13

Mental Strategies for Division

1. 1248 ÷ 6 = 1200 ÷ 6 (200) + 48 ÷ 6 (8) = 208
2. 1992 ÷ 4 = 2000 ÷ 4 (500) – 8 ÷ 4 (2) = 500 – 2 = 498
3. 128 ÷ 4: Half of 128 is 64, half of 64 is 32, so 128 ÷ 4 = 32

More division examples using splitting/mental methods:

• 64 ÷ 4 = 16
• 265 ÷ 5 = 53
• 1560 ÷ 8 = 195
• 4824 ÷ 24 = 201
• 168 ÷ 8 = 21

Solve the following problems using strategies used previously:

• 256 ÷ 4 = 64
• 545 ÷ 5 = 109
• 147 ÷ 7 = 21
• 1212 ÷ 6 = 202
• 648 ÷ 12 = 54
• 9648 ÷ 48 = 201
• 775 ÷ 25 = 31
• 796 ÷ 4 = 199

Let Us Solve

1. Susie and Sunitha have a large coconut farm and they have harvested 1,117 coconuts in April. They sold 582 coconuts equally to 6 regular customers. How many coconuts did each customer get?
   Answer: 582 ÷ 6 = 97 coconuts to each customer.
2. Each bag can hold 25 coconuts. How many bags would be needed to pack 97 coconuts?
   Answer: 3 bags hold 75 coconuts; remaining coconuts: 97 – 75 = 22; another bag will be needed, so total 4 bags.
3. They pack the remaining coconuts for drying and extracting oil. The number of coconuts left after selling 582 coconuts is 1117 – 582 = 535. Number of bags needed is 535 ÷ 25 = 21 full bags, plus one more for the last 10 coconuts, i.e., 22 bags.

Word Problems

1. Rani is planning to host a party. She estimates that 250 guests will attend. She plans to serve one samosa to each guest. Samosas are available in packs of 6 or 8. Which pack should Rani buy? Explain your answer.
   Answer: 250 ÷ 8 = 31 packs remainder 2; 31 × 8 = 248, needs 32 packs of 8 (256 samosas, 6 extra). For 6 per pack: 250 ÷ 6 = 41.67; needs 42 packs for 6 per pack (252 samosas, 2 extra). Buying 8 per pack gives fewer extra samosas for the same coverage.
2. 342 students from a school are going on a trip to the Science Park. Each bus can carry a maximum of 41 students. How many buses does the school need to arrange?
   Answer: 342 ÷ 41 = 8.34..., so 9 buses needed.
3. Sofia has only ₹50 and ₹20 notes. She needs to pay ₹520 using these notes. How many ₹50 and ₹20 notes does she need to make ₹520? Find out the different possible combinations.
   Answer: Let number of ₹50 notes = x, ₹20 notes = y.
   50x + 20y = 520. Try x = 10: 50×10=500; 20y=20, y=1 ⇒ x=10, y=1.
   x=9: 450, 20y=70, y=3.5(not possible, must be integer).
   Try x=8: 400, 120 left ⇒ y=6. Thus, possible combinations: (x=10, y=1), (x=8, y=6), (x=6, y=11), (x=4, y=16), (x=2, y=21), (x=0, y=26).
4. Three friends decide to split the money spent on their picnic equally. They buy snacks and sweets for ₹157, juice and fruits for ₹124 and pulav and paratha for ₹136. How much should each person pay to share the cost equally?
   Answer: Total: 157+124+136=₹417; each pays 417 ÷ 3 = ₹139.
5. Identify the remainder, if any. Check if N = D × Q + R.
   (a) 887 ÷ 3 = 295 R2. 3×295=885, 885+2=887.
   (b) 283 ÷ 8 = 35 R3. 8×35=280, 280+3=283.
   (c) 745 ÷ 5 = 149. 5×149=745.
   (d) 767 ÷ 26 = 29 R13. 26×29=754, 754+13=767.
   (e) 530 ÷ 41 = 12 R38. 41×12=492, 492+38=530.
   (f) 888 ÷ 67 = 13 R17. 67×13=871, 871+17=888.

Let Us Solve

1. In a particular year, Susie and Sunitha used 4376 coconuts for extracting coconut oil. They can extract 1l of oil from 8 coconuts. What quantity of oil were they able to extract?
   Answer: 4376 ÷ 8 = 547 litres of oil.
2. How much will they earn if they sell the oil at ₹175 for 1 l ?
   Answer: 547 × 175 = ₹95,725.

Vegetable Market Table

Total money earned through the sale: ₹2,028 + ₹2,240 + ₹1,792 + ₹3,125 = ₹9,185

What information is recorded in this table?
The cost per kg, quantity supplied, and the total amount received for each vegetable.

Divide the following. Identify the remainder, if any, and check whether N = D × Q + R.

• 506 ÷ 5 = 101 R1. 5×101=505+1=506.
• 918 ÷ 8 = 114 R6. 8×114=912+6=918.
• 8,126 ÷ 7 = 1,161 R1. 7×1,161=8,127-1=8126.
• 9,324 ÷ 4 = 2,331. 4×2,331=9,324.
• 876 ÷ 6 = 146. 6×146=876.
• 7,008 ÷ 3 = 2,336. 3×2,336=7,008.
• 934 ÷ 12 = 77 R10. 12×77=924+10=934.
• 829 ÷ 23 = 36 R1. 23×36=828+1=829.
• 705 ÷ 18 = 39 R3. 18×39=702+3=705.
• 8,704 ÷ 32 = 272. 32×272=8,704.
• 6,790 ÷ 45 = 150 R40. 45×150=6,750+40=6,790.
• 5,074 ÷ 21 = 241 R13. 21×241=5,061+13=5,074.

Mathematical Statements

• "When two odd numbers are added, the sum is even." Examples:
  1+3=4, 3+5=8, 7+9=16, 5+11=16, 11+13=24. To show statement false: 3+4=7 (but 4 is not odd).
• "Multiplying a number by 2 can give an odd number." No example possible; always even.
• "Halving a number always leads to an even number." Halving 4=2 (even), 6=3 (odd), 8=4 (even). So, not always an even number; eg. half of 6 is 3.

Tick in the appropriate cell for the following statements:

Complete the following statements so that they are true:

• (a) 7 × 6 = 42 + 0 or 25
• (b) 87 + 6 = 3 × 31
• (c) 63 + 7 = 74 – 4
• (d) 72 ÷ 9 = 16 ÷ 2; 72 ÷ 9 = 8, 16 ÷ 2 = 8

Division and Multiplication Concepts in NCERT Solutions Class 5 Maths Mela Chapter 9 Coconut Farm

Mastering division and multiplication facts is crucial in NCERT Solutions Class 5 Maths Mela Chapter 9 Coconut Farm (2025-26). Students should focus on understanding the relationship between dividend, divisor, and quotient for strong foundational skills.

This chapter introduces real-life word problems and clever strategies to solve division and multiplication questions. Practicing these problems boosts calculation speed, promotes logical thinking, and ensures full concept clarity before exams.

Review each exercise solution and pattern in the chapter to build confidence. Regular revision and application of these concepts will help you score better and face complex problems with ease in your NCERT Maths exams.