course-recommendation-image

NCERT Solutions for Class 10 Maths Chapter 6 Exercise 6.2

Bookmark added to your notes.
View Notes
×

NCERT Solutions for Class 10 Maths Chapter 6 - Triangles

We started learning about triangles right from the 1st standard. However, the concepts grew with every passing year. The CBSE Solutions of Maths exercise 6.2 Class 10 provides an overview of the concept of similarity of triangles. Along with this, chapter 6 of mathematics also uses the knowledge of Pythagoras theorem which the students learnt earlier. Experts at Vedantu provide you with the comprehensive ex 6.2 Class 10 Maths NCERT Solution to help you understand the concepts quickly and easily. Moreover, our maths experts have crafted the solutions well according to the latest CBSE syllabus and patterns. You can also download the NCERT Solution for Class 10 Science free PDFs on our website.

Chapter 6-Triangles part-1
Loading More Solutions...
FAQ (Frequently Asked Questions)

1. There is a vertical pole with length 6m casting a shadow of 4m on the ground. At the same time, the other tower casts a shadow 28m long. What is the height of the other tower?

(Image to be added soon)

Given:

AB= 6m 

BC= 4m

Similarly, DF= h

EF= 28m 

In the given triangles, 

∠C = ∠E

∠B = ∠F (right angles)

By the angle-angle similarity, 

Triangles ABC and DEF are similar. 

Following this, the ratio of the length of their sides will be proportional. 

AB/DF = BC/EF

6/h = 4/48

h= 42m

Therefore, the height of the tower is 42m. 

2. The angles of a given quadrilateral are in the ratio 3:5:9:13. What are the angles of the quadrilateral?

Consider the common ratio between the angles as x

Then, 

3x + 5X + 9x + 13x= 360°

x= 12°

Therefore, the angles of the quadrilateral will be:

36°, 60°, 108° and 156°. 

The figure is given with the conditions PS/SQ = PT/TR, and ∠PST = ∠PRQ. Prove that PQR is an isosceles triangle. 

(Image to be added soon)

If a line divides the given sides of a triangle in the same ratio, the line is parallel to the third side.

Therefore, ST||QR

And also, ∠PST = ∠PQR (being corresponding angles)

∠PST = ∠PRQ (given)

Therefore, 

∠PRQ = ∠PQR

So, the sides opposite to equal angles are also equal,

Therefore, PQ = PR. 

So, PQR is an isosceles triangle. 

Hence, proved.

meter-image
Do you wish to have an edge over others?
YES, I WANT A FREE HOME DEMO
DISMISS
Please select atleast one box