
Which of the following will displace the halogen from the solution of the halide?
(A) $B{{r}_{2}}$ added to $NaCl$ solution
(B) $C{{l}_{2}}$ added to $KCl$ solution
(C) $KCl$ added to $NaF$ solution
(D) $B{{r}_{2}}$ added to $KI$ solution
Answer
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Hint: Displacement reactions are those in which a part of one reactant is replaced by another reactant. There are two types of displacement reaction: Single displacement reaction and double displacement reaction. For an element to displace another element, it should have higher reactivity.
Complete Step by Step Solution:
The order of reactivity of halogens is: Fluorine > Chlorine > Bromine > Iodine
When $B{{r}_{2}}$ is added to $NaCl$ solution, the bromine will not displace chlorine as it is less reactive than chlorine. So, there will be no reaction. When $C{{l}_{2}}$is added to $KCl$ solution, there will be no change. When $KCl$is added to $NaF$ solution, chlorine will not displace fluorine as it is less reactive than fluorine. So, there will be no reaction.
When $B{{r}_{2}}$ is added to $KI$ solution, the bromine will displace iodine from potassium iodide to form potassium bromide. The reason for this is that bromine is more reactive than iodine.

Correct Option: (D) $B{{r}_{2}}$ added to $KI$ solution
Additional Information: The chemical reactivity of metals depends upon their position in the reactivity series. An element placed at a higher position can displace an element placed at a lower position. A cation always displaces a cation and an anion always displaces an anion.
Note: The halogens are very reactive species. This is because it contains seven electrons in the valence shell and thus requires only one electron to complete its octet.
Complete Step by Step Solution:
The order of reactivity of halogens is: Fluorine > Chlorine > Bromine > Iodine
When $B{{r}_{2}}$ is added to $NaCl$ solution, the bromine will not displace chlorine as it is less reactive than chlorine. So, there will be no reaction. When $C{{l}_{2}}$is added to $KCl$ solution, there will be no change. When $KCl$is added to $NaF$ solution, chlorine will not displace fluorine as it is less reactive than fluorine. So, there will be no reaction.
When $B{{r}_{2}}$ is added to $KI$ solution, the bromine will displace iodine from potassium iodide to form potassium bromide. The reason for this is that bromine is more reactive than iodine.

Correct Option: (D) $B{{r}_{2}}$ added to $KI$ solution
Additional Information: The chemical reactivity of metals depends upon their position in the reactivity series. An element placed at a higher position can displace an element placed at a lower position. A cation always displaces a cation and an anion always displaces an anion.
Note: The halogens are very reactive species. This is because it contains seven electrons in the valence shell and thus requires only one electron to complete its octet.
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