
The compound formed by passing ethylene gas into a cold alkaline solution of \[KMn{O_4}\] is.
(a) Ethyl alcohol
(b) Acetaldehyde
(c) Acetic acid
(d) Ethylene glycol
Answer
232.8k+ views
Hint: The double bond of an alkene can be easily oxidised by using a cold alkaline solution of Potassium permanganate (\[KMn{O_4}\]). The 1,2-diol or 1,2-glycols is formed as an oxidised product of an alkene. Whereas, during the oxidation process of alkene the \[KMn{O_4}\]reduced itself into \[Mn{O_2}\].
Complete Step by Step Answer:
The potassium permanganate (\[KMn{O_4}\]) is belongs to the category of an oxidizing agents. It can provide oxygen in neutral or in alkaline reaction conditions to an alkene and oxidize an alkene into syn-diol i.e., into ethane-1,2-diol or ethylene glycol.
Because in this reaction formation of a hydroxyl group is occurs, therefore this reaction also known as the hydroxylation reaction.
The oxidation of an alkene via cold and alkaline potassium permanganate (\[KMn{O_4}\]) can be described by the following reaction:
During the oxidation of alkene by potassium permanganate (\[KMn{O_4}\]) the formation of a cyclic diester of manganese intermediate is observed. Due to this cyclic diester formation of syn-diol or cis-diol is observed.
Image: Formation of a cyclic ester of manganese intermediate and syn-diol.
The reaction of potassium permanganate with an alkene is very useful to determine the unsaturation i.e., the presence of carbon-carbon double bond character. Therefore, the detection of carbon-carbon double bond in an alkene via using \[KMn{O_4}\]is known as Baeyer’s test.
Therefore, from the above discussion, it is quite clear that cold and alkaline potassium permanganate (\[KMn{O_4}\]) is the suitable reagent for the synthesis of Ethylene glycol (syn-diol) from ethylene gas . Hence option (d) will be the correct answer.
Note: Ethylene is obtained by heating the natural gases or by heating petroleum to 900 \[^\circ C\]. Ethylene helps in the ripening of the fruit faster. Ethylene is also used in the production of glass for the automobile industry.
Complete Step by Step Answer:
The potassium permanganate (\[KMn{O_4}\]) is belongs to the category of an oxidizing agents. It can provide oxygen in neutral or in alkaline reaction conditions to an alkene and oxidize an alkene into syn-diol i.e., into ethane-1,2-diol or ethylene glycol.
Because in this reaction formation of a hydroxyl group is occurs, therefore this reaction also known as the hydroxylation reaction.
The oxidation of an alkene via cold and alkaline potassium permanganate (\[KMn{O_4}\]) can be described by the following reaction:
During the oxidation of alkene by potassium permanganate (\[KMn{O_4}\]) the formation of a cyclic diester of manganese intermediate is observed. Due to this cyclic diester formation of syn-diol or cis-diol is observed.
Image: Formation of a cyclic ester of manganese intermediate and syn-diol.
The reaction of potassium permanganate with an alkene is very useful to determine the unsaturation i.e., the presence of carbon-carbon double bond character. Therefore, the detection of carbon-carbon double bond in an alkene via using \[KMn{O_4}\]is known as Baeyer’s test.
Therefore, from the above discussion, it is quite clear that cold and alkaline potassium permanganate (\[KMn{O_4}\]) is the suitable reagent for the synthesis of Ethylene glycol (syn-diol) from ethylene gas . Hence option (d) will be the correct answer.
Note: Ethylene is obtained by heating the natural gases or by heating petroleum to 900 \[^\circ C\]. Ethylene helps in the ripening of the fruit faster. Ethylene is also used in the production of glass for the automobile industry.
Recently Updated Pages
Types of Solutions in Chemistry: Explained Simply

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

Electricity and Magnetism Explained: Key Concepts & Applications

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions For Class 12 Chemistry Chapter 1 Solutions (2025-26)

Solutions Class 12 Chemistry Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 4 The d and f Block Elements (2025-26)

Biomolecules Class 12 Chemistry Chapter 10 CBSE Notes - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 10 Biomolecules (2025-26)

