Question

The binding energy per nucleon of ${8^{{O^{16}}}}$ is 7.97 $M\;eV$ and that of ${8^{{O^{17}}}}$ is 7.75 $M\;eV$. The energy required to remove one neutron from ${8^{{O^{17}}}}$ is ___________________________ $M\;eV$.
(A) 3.62
(B) 6.52
(C) 4.23
(D) 7.86

Answer 1

Hint We should know that by binding energy we mean the amount of energy that is required to separate a particle from a specific system of particles or to disperse all the particles that are present in the system.

Complete step by step answer
We know that the nuclear reaction is given as:
${8^{{O^{16}}}} \to {8^{O17}} + {0^{n1}}$
$\therefore$ energy to remove neutron
Now we have to write the expression more elaborately to understand the reaction:
= binding energy of${8^{{O^{17}}}}$- binding energy of ${8^{{O^{16}}}}$=$(17 \times 7.75) - (16 \times 7.79) = 4.43\;MeV.$
So, we can say that:
The energy required to remove one neutron from ${8^{{O^{17}}}}$ is 4.23 MeV.

So, the correct answer is Option C.

Note It should be known to us that the concept of binding energy is especially applicable for the subatomic particles which are present in the nucleus of the atom. This is also applicable to the electrons which are bound to the nuclei in the atoms and the ions which are bound together in the crystals.