
The diagram shows two resistors X and Y connected in parallel across a voltage source. Choose the correct statement from the option given below:

(A) The combined resistance is equal to the sum of the resistance
(B) The current at every point in the circuit is the same
(C) The current from the source is equal to the sum of the currents in X and Y
(D) The sum of the potential difference across X and across Y is equal to the potential difference across the voltage source.
Answer
232.8k+ views
Hint: Any amount of charge that enters a system is equal to the amount that goes out of it. This basic principle is also well-known as one of Kirchhoff’s laws and is used to determine the current and/or voltage at a node.
Complete step by step answer:
We are provided with two resistors X and Y connected in parallel. We know that the equivalent resistance in the case of a parallel connection is given by:
$\dfrac{1}{{{R_{eq}}}} = \dfrac{1}{{{R_1}}} + \dfrac{1}{{{R_2}}}$
Hence, this rules out the first option as the sum is not equal to the linear sum of two resistances.
We also know that Kirchoff’s law states that the amount of current entering a node is equal to the amount of current leaving the node. So, if ${I_1}$ current enters X and ${I_2}$ current enters Y through the node beside them, the total current that should be going into the node is:
$I = {I_1} + {I_2}$
This implies that option B is wrong and option C is correct. But what about the option D? We know that the potential difference across a component does not get distributed along node lines as the current does.
So, option D is wrong.
Hence, option C is the right answer.
Note: The voltage drop across a component does not get divided in the same way as the current does. This is because the potential difference depends directly on both the current and the resistance of the component. So, even if the current remains constant across two components from the same node, the different resistances would cause a different potential drop.
Complete step by step answer:
We are provided with two resistors X and Y connected in parallel. We know that the equivalent resistance in the case of a parallel connection is given by:
$\dfrac{1}{{{R_{eq}}}} = \dfrac{1}{{{R_1}}} + \dfrac{1}{{{R_2}}}$
Hence, this rules out the first option as the sum is not equal to the linear sum of two resistances.
We also know that Kirchoff’s law states that the amount of current entering a node is equal to the amount of current leaving the node. So, if ${I_1}$ current enters X and ${I_2}$ current enters Y through the node beside them, the total current that should be going into the node is:
$I = {I_1} + {I_2}$
This implies that option B is wrong and option C is correct. But what about the option D? We know that the potential difference across a component does not get distributed along node lines as the current does.
So, option D is wrong.
Hence, option C is the right answer.
Note: The voltage drop across a component does not get divided in the same way as the current does. This is because the potential difference depends directly on both the current and the resistance of the component. So, even if the current remains constant across two components from the same node, the different resistances would cause a different potential drop.
Recently Updated Pages
Circuit Switching vs Packet Switching: Key Differences Explained

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

Electricity and Magnetism Explained: Key Concepts & Applications

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2025-26

Understanding Uniform Acceleration in Physics

Understanding the Electric Field of a Uniformly Charged Ring

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

