
If in a triangle the angles are in A. P. and \[b:c = \sqrt 3 :\sqrt 2 \], then \[\angle A\] is equal to
A. \[30^\circ \]
B. \[60^\circ \]
C. \[15^\circ \]
D. \[75^\circ \]
Answer
232.8k+ views
Hint: It is possible to compute the length of a side in the right triangle using slope-intercept form given that it knows the intercepts and slopes.
Using this information, the process to solve for Side Using algebraic manipulation. To solve this problem, it is helpful to use the Law of Sines. The Law of Sines states that in a right triangle, the sine of one angle is equal to the sum of the sine of other two angles. In this case, \[\angle A = sin\left( {75^\circ } \right)\]and \[sin\left( {50^\circ } \right) = cos\left( {75^\circ } \right)\]. Therefore, \[\angle A\]is \[75\] degree.
Complete step by step solution: The given equation is \[b:c = \sqrt 3 :\sqrt 2 \]
The objective is to find \[\angle A\]
Let the equation be \[\angle A = a - d\], \[\angle B = a\]
And \[\angle C = a + d\]
The sum of angles of triangle can be written as,
\[a - d + a + a + d = 180^\circ \]
This equation can also be written as
\[3a = 180^\circ \]
\[a = 60^\circ \]
Hence, \[\angle B = 60^\circ \]
Use the sine law in the equation,
\[\dfrac{{\sin B}}{b} = \dfrac{{\sin C}}{c}\]
This equation is rewritten as,
\[\dfrac{{\sin 60^\circ }}{{\sin c}} = \dfrac{b}{c}\]
The value of \[\sin 60^\circ \]is \[\sqrt 3 /2\]
So. With the value, the equation is written as,
\[\dfrac{{\sqrt 3 /2}}{{\sin c}} = \dfrac{{\sqrt 3 }}{{\sqrt 2 }}\]
\[\sin c = \dfrac{1}{{\sqrt 2 }}\]
The value of \[\dfrac{1}{{\sqrt 2 }}\]is \[\sin 45^\circ \]
\[\sin c = \sin 45^\circ \]
As, \[\angle C\]is equal to \[45^\circ \]
As we already know \[\angle C = a + d\]
\[a + d = 45^\circ \]
\[d = 45^\circ - 60^\circ = - 15^\circ \]
\[\angle A = a - d = 60^\circ - ( - 15^\circ )\]
\[\angle A = 75^\circ \]
So, the correct option is D that is \[75^\circ \].
Note: The computational geometry tool known as Graphing Calculator. a correlation between a triangle's opposite side and the angle's size. When we know about one angle and the side opposite it, as well as another angle and the side opposite it, we may apply the sine rule to determine the missing angle or side in a triangle.
After entering the information into our calculator, we can see that \[\angle A\]is equal to\[75^\circ \].
Using this information, the process to solve for Side Using algebraic manipulation. To solve this problem, it is helpful to use the Law of Sines. The Law of Sines states that in a right triangle, the sine of one angle is equal to the sum of the sine of other two angles. In this case, \[\angle A = sin\left( {75^\circ } \right)\]and \[sin\left( {50^\circ } \right) = cos\left( {75^\circ } \right)\]. Therefore, \[\angle A\]is \[75\] degree.
Complete step by step solution: The given equation is \[b:c = \sqrt 3 :\sqrt 2 \]
The objective is to find \[\angle A\]
Let the equation be \[\angle A = a - d\], \[\angle B = a\]
And \[\angle C = a + d\]
The sum of angles of triangle can be written as,
\[a - d + a + a + d = 180^\circ \]
This equation can also be written as
\[3a = 180^\circ \]
\[a = 60^\circ \]
Hence, \[\angle B = 60^\circ \]
Use the sine law in the equation,
\[\dfrac{{\sin B}}{b} = \dfrac{{\sin C}}{c}\]
This equation is rewritten as,
\[\dfrac{{\sin 60^\circ }}{{\sin c}} = \dfrac{b}{c}\]
The value of \[\sin 60^\circ \]is \[\sqrt 3 /2\]
So. With the value, the equation is written as,
\[\dfrac{{\sqrt 3 /2}}{{\sin c}} = \dfrac{{\sqrt 3 }}{{\sqrt 2 }}\]
\[\sin c = \dfrac{1}{{\sqrt 2 }}\]
The value of \[\dfrac{1}{{\sqrt 2 }}\]is \[\sin 45^\circ \]
\[\sin c = \sin 45^\circ \]
As, \[\angle C\]is equal to \[45^\circ \]
As we already know \[\angle C = a + d\]
\[a + d = 45^\circ \]
\[d = 45^\circ - 60^\circ = - 15^\circ \]
\[\angle A = a - d = 60^\circ - ( - 15^\circ )\]
\[\angle A = 75^\circ \]
So, the correct option is D that is \[75^\circ \].
Note: The computational geometry tool known as Graphing Calculator. a correlation between a triangle's opposite side and the angle's size. When we know about one angle and the side opposite it, as well as another angle and the side opposite it, we may apply the sine rule to determine the missing angle or side in a triangle.
After entering the information into our calculator, we can see that \[\angle A\]is equal to\[75^\circ \].
Recently Updated Pages
Geometry of Complex Numbers Explained

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

Electricity and Magnetism Explained: Key Concepts & Applications

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions For Class 11 Maths Chapter 12 Limits and Derivatives (2025-26)

NCERT Solutions For Class 11 Maths Chapter 10 Conic Sections (2025-26)

Understanding the Electric Field of a Uniformly Charged Ring

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

