Question

What is the current flowing in the circuit?

(A) $\dfrac{5}{{40}}A$
(B) $\dfrac{5}{{50}}A$
(C) $\dfrac{5}{{10}}A$
(D) $\dfrac{5}{{20}}A$

Answer 1

Hint: We will use the combination of resistances theory to solve this problem. The resistors can be combined in series, parallel or mixed grouping. The voltage of the circuit is already given, after we determine the equivalent resistance of the circuit we will have to apply Ohm’s law to calculate the current flowing through the circuit.

Complete step by step solution:
Let’s start with the direction of flow of current in the given circuit. Current always flows from higher potential to lower potential in the circuit which is in this case from the positive terminal of the battery to the negative terminal.
Noticed the presence of semiconductor diodes in the circuit? Semiconductor diodes when connected to the circuit such that they are forward biased, conduct electricity and when they are present in reverse biased state they block the flow of electricity.

In this case the diode D1 is reverse biased and the diode D2 is forward biased. This implies that the top portion of the circuit will carry no current.
Thus the effective circuit will be like the following representation.

For this circuit the equivalent resistance will be calculated as per series connection of resistances.
So, $R = {R_1} + {R_2}$
Where $R$ is the equivalent resistance of the circuit containing resistances ${R_1}$ and ${R_2}$ connected in series.
Putting their respective values we get,
$ \Rightarrow R = 30 + 20 = 50\Omega $
As we have determined the equivalent resistance of the circuit, let’s apply Ohm’s law.
So the net current flowing through the circuit will be,
$I = \dfrac{V}{R}$
Where $V$ is the potential difference of the circuit.
Putting the respective values we get
$ \Rightarrow I = \dfrac{5}{{50}}A$

So the correct answer is option B.

Note:
Forward biasing of a junction diode or semiconductor diode means that the positive terminal of the diode is connected to the positive terminal of the circuit. Reverse biasing also simply means that the positive terminal is connected to the negative terminal of the circuit and as we have discussed, reverse biased junction diode blocks the flow of current in the circuit.