NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals (EX 2.3) Exercise 2.3

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals (EX 2.3) Exercise 2.3

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Access NCERT Solutions for Class 7 Maths Chapter 2 – Fractions and Decimals

Exercise 2.3

1. Find:

(i) $\dfrac{\text{1}}{\text{4}}\,\text{of}$ (a) $\dfrac{\text{1}}{\text{4}}$ (b) $\dfrac{\text{3}}{\text{5}}$ (c) $\dfrac{\text{4}}{\text{3}}$

Ans:

(a) Calculating the value,

$\dfrac{\text{1}}{\text{4}}\,\text{of}\,\dfrac{\text{1}}{\text{4}}\text{=}\dfrac{\text{1}}{\text{4}}\text{ }\!\!\times\!\!\text{ }\dfrac{\text{1}}{\text{4}}\text{=}\dfrac{\text{1 }\!\!\times\!\!\text{ 1}}{\text{4 }\!\!\times\!\!\text{ 4}}\text{=}\dfrac{\text{1}}{\text{16}}$

(b) Calculating the value,

$\dfrac{\text{1}}{\text{4}}\,\text{of}\,\dfrac{\text{3}}{\text{5}}\text{=}\dfrac{\text{1}}{\text{4}}\text{ }\!\!\times\!\!\text{ }\dfrac{\text{3}}{\text{4}}\text{=}\dfrac{\text{1 }\!\!\times\!\!\text{ 3}}{\text{4 }\!\!\times\!\!\text{ 4}}\text{=}\dfrac{\text{3}}{\text{16}}$

(c) Calculating the value,

$\dfrac{\text{1}}{\text{4}}\,\text{of}\,\dfrac{\text{4}}{\text{3}}\text{=}\dfrac{\text{1}}{\text{4}}\text{ }\!\!\times\!\!\text{ }\dfrac{\text{4}}{\text{3}}\text{=}\dfrac{\text{1 }\!\!\times\!\!\text{ 4}}{\text{4 }\!\!\times\!\!\text{ 3}}\text{=}\dfrac{\text{1}}{\text{3}}$

(ii) $\dfrac{\text{1}}{\text{7}}\,\text{of}$ (a) $\dfrac{\text{2}}{\text{9}}$ (b) $\dfrac{\text{6}}{\text{5}}$ (c) $\dfrac{\text{3}}{\text{10}}$

Ans:

(a) Calculating the value,

$\dfrac{\text{1}}{\text{7}}\,\text{of}\,\dfrac{\text{2}}{\text{9}}\text{=}\dfrac{\text{1}}{\text{7}}\text{ }\!\!\times\!\!\text{ }\dfrac{\text{2}}{\text{9}}\text{=}\dfrac{\text{1 }\!\!\times\!\!\text{ 2}}{\text{7 }\!\!\times\!\!\text{ 9}}\text{=}\dfrac{\text{2}}{\text{63}}$

(b) Calculating the value,

$\dfrac{\text{1}}{\text{7}}\,\text{of}\,\dfrac{\text{2}}{\text{9}}\text{=}\dfrac{\text{1}}{\text{7}}\text{ }\!\!\times\!\!\text{ }\dfrac{\text{6}}{\text{5}}\text{=}\dfrac{\text{1 }\!\!\times\!\!\text{ 6}}{\text{7 }\!\!\times\!\!\text{ 5}}\text{=}\dfrac{\text{6}}{\text{35}}$

(c) Calculating the value,

$\dfrac{\text{1}}{\text{7}}\,\text{of}\,\dfrac{\text{2}}{\text{9}}\text{=}\dfrac{\text{1}}{\text{7}}\text{ }\!\!\times\!\!\text{ }\dfrac{\text{3}}{\text{10}}\text{=}\dfrac{\text{1 }\!\!\times\!\!\text{ 3}}{\text{7 }\!\!\times\!\!\text{ 10}}\text{=}\dfrac{3}{70}$

2. Multiply and reduce to lowest form (if possible):

(i) $\dfrac{\text{2}}{\text{3}}\text{ }\!\!\times\!\!\text{ 2}\dfrac{\text{2}}{\text{3}}$

Ans:

Multiplying and reducing to lowest form,

$\dfrac{2}{3}\times 2\dfrac{2}{3}=\dfrac{2}{3}\times \dfrac{8}{3}=\dfrac{2\times 8}{3\times 3}=\dfrac{16}{9}=1\dfrac{7}{9}$

(ii) $\dfrac{\text{2}}{\text{7}}\text{ }\!\!\times\!\!\text{ }\dfrac{\text{7}}{\text{9}}$

Ans:

Multiplying and reducing to lowest form,

$\dfrac{2}{7}\times \dfrac{7}{9}=\dfrac{2\times 7}{7\times 9}=\dfrac{2}{9}$

(iii) $\dfrac{\text{3}}{\text{8}}\text{ }\!\!\times\!\!\text{ }\dfrac{\text{6}}{\text{4}}$

Ans:

Multiplying and reducing to lowest form,

$\dfrac{3}{8}\times \dfrac{6}{4}=\dfrac{3\times 6}{8\times 4}=\dfrac{3\times 3}{8\times 2}=\dfrac{9}{16}$

(iv) $\dfrac{\text{9}}{\text{5}}\text{ }\!\!\times\!\!\text{ }\dfrac{\text{3}}{\text{5}}$

Ans:

Multiplying and reducing to lowest form,

$\dfrac{9}{5}\times \dfrac{3}{5}=\dfrac{9\times 3}{5\times 5}=\dfrac{27}{25}=1\dfrac{2}{25}$

(v) $\dfrac{\text{1}}{\text{3}}\text{ }\!\!\times\!\!\text{ }\dfrac{\text{15}}{\text{8}}$

Ans:

Multiplying and reducing to lowest form,

$\dfrac{1}{3}\times \dfrac{15}{8}=\dfrac{1\times 15}{3\times 8}=\dfrac{1\times 5}{1\times 8}=\dfrac{5}{8}$

(vi) $\dfrac{\text{11}}{\text{2}}\text{ }\!\!\times\!\!\text{ }\dfrac{\text{3}}{\text{10}}$

Ans:

Multiplying and reducing to lowest form,

$\dfrac{11}{2}\times \dfrac{3}{10}=\dfrac{11\times 3}{2\times 10}=\dfrac{33}{20}=1\dfrac{3}{20}$

(vii) $\dfrac{\text{4}}{\text{5}}\text{ }\!\!\times\!\!\text{ }\dfrac{\text{12}}{\text{7}}$

Ans:

Multiplying and reducing to lowest form,

$\dfrac{4}{5}\times \dfrac{12}{7}=\dfrac{4\times 12}{5\times 7}=\dfrac{48}{35}=1\dfrac{13}{35}$

3. Multiply the following fractions:

(i) $\dfrac{\text{2}}{\text{5}}\text{ }\!\!\times\!\!\text{ 5}\dfrac{\text{1}}{\text{4}}$

Ans:

Performing multiplication,

$\dfrac{2}{5}\times 5\dfrac{1}{4}=\dfrac{2}{5}\times \dfrac{21}{4}=\dfrac{2\times 21}{5\times 4}=\dfrac{1\times 21}{5\times 2}=\dfrac{21}{10}=2\dfrac{1}{10}$

(ii) $\text{6}\dfrac{\text{2}}{\text{5}}\text{ }\!\!\times\!\!\text{ }\dfrac{\text{7}}{\text{9}}$

Ans:

Performing multiplication,

$6\dfrac{2}{5}\times \dfrac{7}{9}=\dfrac{32}{5}\times \dfrac{7}{9}=\dfrac{32\times 7}{5\times 9}=\dfrac{224}{45}=4\dfrac{44}{45}$

(iii) $\dfrac{\text{3}}{\text{2}}\text{ }\!\!\times\!\!\text{ 5}\dfrac{\text{1}}{\text{3}}$

Ans:

Performing multiplication,

$\dfrac{3}{2}\times 5\dfrac{1}{3}=\dfrac{3}{2}\times \dfrac{16}{3}=\dfrac{48}{6}=8$

(iv) $\dfrac{\text{5}}{\text{6}}\text{ }\!\!\times\!\!\text{ 2}\dfrac{\text{3}}{\text{7}}$

Ans:

Performing multiplication,

$\dfrac{5}{6}\times 2\dfrac{3}{7}=\dfrac{5}{6}\times \dfrac{17}{7}=\dfrac{85}{42}=2\dfrac{1}{42}$

(v) $\text{3}\dfrac{\text{2}}{\text{5}}\text{ }\!\!\times\!\!\text{ }\dfrac{\text{4}}{\text{7}}$

Ans:

Performing multiplication,

$3\dfrac{2}{5}\times \dfrac{4}{7}=\dfrac{17}{7}\times \dfrac{4}{7}=\dfrac{68}{35}=1\dfrac{33}{35}$

(vi) $\text{2}\dfrac{\text{3}}{\text{5}}\text{ }\!\!\times\!\!\text{ 3}$

Ans:

Performing multiplication,

$2\dfrac{3}{5}\times 3=\dfrac{13}{5}\times \dfrac{3}{1}=\dfrac{13\times 3}{5\times 1}=\dfrac{39}{5}=7\dfrac{4}{5}$

(vii) $\text{3}\dfrac{\text{4}}{\text{7}}\text{ }\!\!\times\!\!\text{ }\dfrac{\text{3}}{\text{5}}$

Ans:

Performing multiplication,

$3\dfrac{4}{7}\times \dfrac{3}{5}=\dfrac{25}{7}\times \dfrac{3}{5}=\dfrac{5\times 3}{7\times 1}=\dfrac{15}{7}=2\dfrac{1}{7}$

4. Which is greater:

(i) $\dfrac{\text{2}}{\text{7}}\,\text{of}\,\dfrac{\text{3}}{\text{4}}\,\text{or}\,\dfrac{\text{3}}{\text{5}}\,\text{of}\,\dfrac{\text{5}}{\text{8}}$

Ans:

Calculating the greater term,

$\dfrac{\text{2}}{\text{7}}\,\text{of}\,\dfrac{\text{3}}{\text{4}}\,\text{or}\,\dfrac{\text{3}}{\text{5}}\,\text{of}\,\dfrac{\text{5}}{\text{8}}$

$\Rightarrow \dfrac{\text{2}}{\text{7}}\text{ }\!\!\times\!\!\text{ }\dfrac{\text{3}}{\text{4}}\,\text{or}\,\dfrac{\text{3}}{\text{5}}\text{ }\!\!\times\!\!\text{ }\dfrac{\text{5}}{\text{8}}$

$\Rightarrow \dfrac{\text{3}}{\text{14}}\,\text{or}\,\dfrac{\text{3}}{\text{8}}$

$\Rightarrow \dfrac{3}{14}<\dfrac{3}{8}$

Hence, $\dfrac{\text{3}}{\text{5}}\,\text{of}\,\dfrac{\text{5}}{\text{8}}$ is greater.

(ii) $\dfrac{\text{1}}{\text{2}}\,\text{of}\,\dfrac{\text{6}}{\text{7}}\,\text{or}\,\dfrac{\text{2}}{\text{3}}\,\text{of}\,\dfrac{\text{3}}{\text{7}}$

Ans:

Calculating the greater term,

$\dfrac{\text{1}}{\text{2}}\,\text{of}\,\dfrac{\text{6}}{\text{7}}\,\text{or}\,\dfrac{\text{2}}{\text{3}}\,\text{of}\,\dfrac{\text{3}}{\text{7}}$

$\Rightarrow \dfrac{\text{1}}{\text{2}}\text{ }\!\!\times\!\!\text{ }\dfrac{\text{6}}{\text{7}}\,\text{or}\,\dfrac{\text{2}}{\text{3}}\text{ }\!\!\times\!\!\text{ }\dfrac{\text{3}}{\text{7}}$

$\Rightarrow \dfrac{\text{6}}{\text{14}}\,\text{or}\,\dfrac{\text{2}}{\text{7}}$

$\Rightarrow \dfrac{\text{6}}{\text{14}}>\dfrac{\text{2}}{\text{7}}$

Hence, $\dfrac{\text{1}}{\text{2}}\,\text{of}\,\dfrac{\text{6}}{\text{7}}$ is greater.

5. Saili plants $\text{4}$ saplings in a row in her garden. The distance between two adjacent saplings is $\dfrac{\text{3}}{\text{4}}$ m. Find the distance between the first and the last sapling.

Ans:

Given: Saili plants $4$ saplings in a row where the distance between two adjacent saplings $=\dfrac{3}{4}$m.

(Image will be uploaded soon)

The number of gaps in saplings $=\text{ }3$

Hence,

The distance between the first and the last saplings$\text{=3 }\!\!\times\!\!\text{ }\dfrac{\text{3}}{\text{4}}\text{=}\dfrac{\text{9}}{\text{4}}\text{m=2}\dfrac{\text{1}}{\text{4}}\text{m}$

Therefore, the distance between the first and the last saplings is $\text{2}\dfrac{\text{1}}{\text{4}}\,\text{m}$

6.       Lipika reads a book for $\text{1}\dfrac{\text{3}}{\text{4}}$ hours every day. She reads the entire book in $\text{6}$ days. How many hours in all were required by her to read the book?

Ans:

Given: Time taken for reading a book by Lipika $=1\dfrac{3}{4}$ hours.

Lipika reads the entire book in $6$ days

Calculating the Total hours taken by Lipika to read the entire book,

$=1\dfrac{3}{4}\times 6=\dfrac{7}{4}\times 6=\dfrac{21}{2}=10\dfrac{1}{2}$ hours.

Hence, it would take $10$ hours to read the book.

7. A car runs $\text{16}$ km using $\text{1}$ litre of petrol. How much distance will it cover using   $\text{2}\dfrac{\text{3}}{\text{4}}$ litres of petrol?

Ans:

Given: A car covers the distance$\text{=16}\,\text{km}$ in $1$ litre of petrol.

Calculating the distance covered by car in $2\dfrac{3}{4}$ litres of petrol,

Distance$\text{=2}\dfrac{\text{3}}{\text{4}}\,\text{of}\,\text{16}\,\text{km=}\dfrac{\text{11}}{\text{4}}\text{ }\!\!\times\!\!\text{ 16=44}\,\text{km}$

Therefore, car will cover a distance of $44$ km in $2\dfrac{3}{4}$ litres of petrol.

8. (a) (i) Provide the number in the box $___$, such that $\dfrac{\text{2}}{\text{3}}\text{ }\!\!\times\!\!\text{ }\text{=}\dfrac{\text{10}}{\text{30}}$

(ii) The simplest form of the number obtained in $___$ is _____.

Ans:

(i) The number inside the box should be $\dfrac{2}{3}\times =\dfrac{10}{30}$

(ii) The simplest form of the number obtained in $\dfrac{\text{5}}{\text{10}}\,\text{is}\,\dfrac{\text{1}}{\text{2}}$

(b) (i) Provide the numberin the box $___$ , such that $\dfrac{3}{5}\times =\dfrac{24}{75}$.

(ii) The simplest form of the number obtained in $___$ is______.

Ans:

(i) The number inside the box should be $\dfrac{3}{5}\times =\dfrac{24}{75}$

(ii) The simplest form of the number obtained in $\dfrac{\text{8}}{\text{15}}\,\text{is}\,\dfrac{\text{8}}{\text{15}}$

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Exercise 2.3

Opting for the NCERT solutions for Ex 2.3 Class 7 Maths is considered as the best option for the CBSE students when it comes to exam preparation. This chapter consists of many exercises. Out of which we have provided the Exercise 2.3 Class 7 Maths NCERT solutions on this page in PDF format. You can download this solution as per your convenience or you can study it directly from our website/ app online.

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