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NCERT Solutions for Class 11 Chemistry Chapter 10 - The S Block Elements

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NCERT Solutions for Class 11 Chemistry Chapter 10 - The s-Block Elements

S block elements constitute a crucial part in class 11 Chemistry syllabus. Along with the broad examination, several all India Entrance examinations like NEET, JEE Mains and Advanced, etc. also ask different questions from this topic. Hence, students who aspire for such examinations should take this chapter seriously.


Class:

NCERT Solutions for Class 11

Subject:

Class 11 Chemistry

Chapter Name:

Chapter 10 - The S Block Elements

Content-Type:

Text, Videos, Images and PDF Format

Academic Year:

2024-25

Medium:

English and Hindi

Available Materials:

Chapter Wise

Other Materials

  • Important Questions

  • Revision Notes


Nonetheless, irrespective of the examinations, S block elements Class 11 NCERT solutions can prove to be beneficial for students who aspire to pursue their career in the world of science.


s-Block Combined Elements Chapter at a Glance - Class 11 NCERT Solutions


Atomic and Physical Properties of s-Block Elements


Atomic and Physical Properties of s-Block Elements


Chemical Properties of s-Block Elements


Chemical Properties of s-Block Elements

Competitive Exams after 12th Science

Access NCERT Solutions for Class 11 Chemistry Chapter – 10 The s-Block Elements

NCERT Exercise:

1. What are the common physical and chemical features of alkali metals?

Ans: Physical Properties of Alkali Metals: 

  • Alkali metals have low ionization enthalpies. 

  • Alkali metals are highly electropositive in nature 

  • Alkali metals exhibit +1 oxidation states in their compounds.

  • Alkali metals impart characteristic colours to the flame. 

Chemical Properties of Alkali Metals: 

  • Alkali metals are highly reactive in nature. 

  • Alkali metals hydroxides are highly basic in nature. 

  • Alkali metals dissolve in liquid ammonia to form blue and conducting solution. 


2. Discuss the general characteristics and gradation in properties of alkaline earth metals.

Ans: General characteristics and gradation of alkaline earth metals:

  • Atomic size goes on increasing down the group.

  • Ionization energy goes on decreasing down the group.

  • They are harder than alkali metals.

  • They are less electropositive than alkali metals.

  • Electropositive character increases on going down the group. 


3. Why are alkali metals not found in nature?

Ans: Alkali metals are highly reactive in nature. That’s why they always exist in a combined state in nature.


4. Find out the oxidation state of sodium in $N{{a}_{2}}{{O}_{2}}$ .

Ans: let x be the oxidation of sodium in $N{{a}_{2}}{{O}_{2}}$

\[2x+2(-1)=0\] 

\[2x-2=0\Rightarrow x=+1\] 


5. Explain why sodium is less reactive than potassium.

Ans: it is because ionization enthalpy $\Delta {{H}_{i}}$ of potassium = 419 kJ/mol

Ionization enthalpy of sodium = 496 kJ/mol

Since, ionization enthalpy of potassium is less than that of sodium, potassium is more reactive than sodium


6. Compare the alkali metals and alkaline earth metals with respect to

a. Ionization Enthalpy

Ans: Because of high nuclear charge the ionization enthalpy of alkaline earth metals are higher than those of the corresponding alkali metals. 

b. Basicity of Oxides

Ans: Basicity of oxides of alkali metals are higher than that of alkaline earth metals.

c. Solubility of Hydroxides

Ans: Solubility of hydroxides of alkali metals are higher than that of alkaline earth metals. Alkali metals due to lower ionization enthalpy are more electropositive than the corresponding group 2 elements.


7. In what ways lithium shows similarities to magnesium in its chemical behavior?

Ans: 

  • Both react with nitrogen to form nitrides

  • Both react with ${{O}_{2}}$ to form monoxides.

  • Both the elements have the tendency to form covalent compounds

  • Both can form complex compounds


8. Explain why alkali and alkaline earth metals can not be obtained by chemical reduction methods.

Ans: Alkali and alkaline earth metals are better reducing agents, and reducing agents better than alkali metals are not available. That is why these metals are not obtained by chemical reduction methods.


9. Why are potassium and caesium, rather than lithium used in photoelectric cells?

Ans: Potassium and caesium have much lower ionization enthalpy than that of lithium. As a result, these metals easily emit electrons on exposure to light. Due to this, K and Cs are used in photoelectric cells rather than lithium.


10. When alkali metal dissolves in liquid ammonia, the solution can acquire different colors. Explain the reason for this type of color change.

Ans: Alkali metals dissolve in liquid ammonia and give deep blue solutions which are conducting in nature because ammoniated electrons absorb energy in the visible region of light and impart blue colour.

\[M+(x+y)N{{H}_{3}}\to {{[M{{(N{{H}_{3}})}_{x}}]}^{+}}+\underset{Ammoniated\text{ }electrons}{\mathop{{{e}^{-}}{{(N{{H}_{3}})}_{y}}}}\,\]


11. Beryllium and magnesium do not give colour to flame whereas other alkaline earth metals do so. Why?

Ans: Due to the small size, the ionization enthalpies of Be and Mg are much higher than those of other alkaline earth metals. Therefore, a large amount of energy is needed to excite their valence electrons, and that’s why they do not impart colour to the flame.


12. Discuss the various reactions that occur in the Solvay process.

Ans: 

\[CaC{{O}_{3}}(s)\xrightarrow{Heat}CaO+C{{O}_{2}}\] 

\[N{{H}_{3}}+{{H}_{2}}O\to N{{H}_{4}}^{+}+O{{H}^{-}}\] 

\[NaCl+N{{H}_{4}}OH+C{{O}_{2}}\to NaHC{{O}_{3}}+N{{H}_{4}}Cl\] 

\[2NaHC{{O}_{3}}(s)\overset{heat}{\mathop{\to }}\,N{{a}_{2}}C{{O}_{3}}+C{{O}_{2}}+{{H}_{2}}O\] 

\[N{{a}_{2}}C{{O}_{3}}+10{{H}_{2}}O\to N{{a}_{2}}C{{O}_{3}}.10{{H}_{2}}O\]


13. Potassium Carbonate cannot be prepared by solvay process. Why?

Ans: Potassium carbonate being more soluble than sodium bicarbonate does not get precipitated when $C{{O}_{2}}$  is passed through a concentrated solution of KCl saturated with ammonia.


14. Why is $L{{i}_{2}}C{{O}_{3}}$decomposed at a lower temperature whereas $N{{a}_{2}}C{{o}_{3}}$ at high temperature?

Ans: $L{{i}_{2}}C{{O}_{3}}$ is a covalent compound whereas $N{{a}_{2}}C{{o}_{3}}$ is an ionic compound. Therefore, Lattice energy of $N{{a}_{2}}C{{o}_{3}}$ is higher than that of$L{{i}_{2}}C{{O}_{3}}$. Thus, $L{{i}_{2}}C{{O}_{3}}$ is decomposed at a lower temperature.


15. Compare the solubility and thermal stability of the following compounds of the alkali metals with those of the alkaline earth metals.

a. Nitrates

Ans: Nitrates of both group 1 and group 2 elements are soluble in water because Hydration energy is more than the lattice energy. 

Nitrates of both group 1 and group 2 elements are thermally unstable but they decompose differently except $LiC{{O}_{3}}$ e.g.

\[2NaN{{O}_{3}}\xrightarrow{heat}2NaN{{O}_{2}}+{{O}_{2}}\] 

\[2KN{{O}_{3}}\xrightarrow{\Delta }2KN{{O}_{2}}+{{O}_{2}}\] 

\[4LiN{{O}_{3}}\xrightarrow{\Delta }2Li{{O}_{2}}+4N{{O}_{2}}+{{O}_{2}}\]

\[2Mg{{(N{{O}_{3}})}_{2}}\xrightarrow{\Delta }2MgO+4N{{O}_{2}}+{{O}_{2}}\]

b. Carbonates

Ans: carbonates of group 1 elements are soluble in water except $L{{i}_{2}}C{{O}_{3}}$

\[L{{i}_{2}}C{{O}_{3}}\xrightarrow{\Delta }L{{i}_{2}}O+C{{O}_{2}}\] 

Group 2 carbonates are insoluble in water because their Lattice energy is higher than hydration energy.Thermal stability of carbonates of group 2 increases down the group because Lattice energy goes on increasing due to increase in ionic character.

c. Sulphates

Ans:  Sulphates of group 1 are soluble in water except  $L{{i}_{2}}S{{O}_{4}}$. They are thermally stable. Solubility of sulphates of group 2 decreases down the group because Lattice energy dominates over hydration energy. Sulphates of group 2 elements are thermally stable and increasing down the group due to increases in Lattice energy


16. Starting with sodium chloride how could you proceed to prepare

a. Sodium Metal

Ans: sodium metal is manufactured by electrolysis of a fused mass of NaCl 40% and $CaC{{l}_{2}}$ 60% in Down’s cell at 873K, using iron as cathode and graphite as anode. Na is liberated at the cathode.

At cathode: $N{{a}^{+}}+{{e}^{-}}\to Na(l)$ 

At anode: $2C{{l}^{-}}(melt)\to C{{l}_{2}}(g)+2{{e}^{-}}$

b. Sodium Hydroxide

Ans: sodium hydroxide is manufactured by electrolysis of an aqueous solution of NaCl (brine) in Castner- Kellner cell

At Cathode: 

\[N{{a}^{+}}+{{e}^{-}}\to Na\] 

\[2Na+Hg\to Na-Hg+2{{H}_{2}}O\] 

\[2Na-Hg+2{{H}_{2}}O\to 2NaOH+{{H}_{2}}+Hg\]

At Anode: 

\[C{{l}^{-}}-{{e}^{-}}\to Cl\]

\[Cl+Cl\to C{{l}_{2}}\]

c. Sodium Peroxide

Ans: $4Na+2{{O}_{2}}\to 2N{{a}_{2}}O+{{O}_{2}}$
 

d. Sodium Carbonate

Ans: sodium carbonate is obtained by Solvay ammonia process

\[NaCl+N{{H}_{3}}+C{{O}_{2}}+{{H}_{2}}O\to NaHC{{O}_{3}}\downarrow +N{{H}_{4}}Cl\] 

\[2NaHC{{O}_{3}}\xrightarrow{\Delta }N{{a}_{2}}C{{O}_{3}}+C{{O}_{2}}+{{H}_{2}}O\] 


17. What happens when (i) magnesium is burnt in air, (ii) Quick lime is heated with silica (iii) chlorine reacts with slaked lime (iv) calcium nitrate is heated?

Ans: 

a. $2Mg(s)+{{O}_{2}}(g)\xrightarrow{\Delta }2MgO(s)$ 

b. $CaO(s)+Si{{O}_{2}}(s)\xrightarrow{\Delta }CaSi{{O}_{3}}(s)$ 

c.  $2Ca{{(OH)}_{2}}+2C{{l}_{2}}\to CaC{{l}_{2}}+Ca{{(OCl)}_{2}}+2{{H}_{2}}O$ 

d. $2Ca{{(N{{O}_{3}})}_{2}}(s)\xrightarrow{\Delta }2CaO(s)+4N{{O}_{2}}(g)+{{O}_{2}}(g)$ 


18. Describe the two important uses of the following.

a. Caustic soda

Ans: 

  1. It is used in the manufacturing of soap paper , artificial silk etc.

  2. It is used in the textile industries

b. Sodium Carbonate

Ans:

  1. Used in the softening of water, for laundry and cleaning purposes.

  2. It is used in glass manufacturing

c. Quick Lime

Ans: 

  1. It is used in the preparation of bleaching powder

  2. Used in the purification of sugar and in the manufacturing of cement.


19. Draw the structure of the following:

a. $BeC{{l}_{2}}(vapour)$ 

Ans: in the vapor site , it exists as a chloro bridged dimer

(image will be uploaded soon)

b. $BeC{{l}_{2}}(solid)$

(image will be uploaded soon)


20. The hydroxides and carbonates of sodium and potassium are easily soluble in water while the corresponding salts of magnesium and calcium are sparingly soluble in water. Explain 

Ans: Since group 1 hydroxides and carbonates due to large size contain higher hydration energy than the lattice energy so, they are easily soluble in water. Whereas, in magnesium and calcium due to small size, their lattice energy dominates over hydration energy. Hence they are sparingly soluble in water.


21.  Describe the importance of the following.

a. Limestone

Ans: 

  • Extensively used in manufacturing of high quality paper

  • Used in mild abrasive in toothpaste

  • As a filler in cosmetics

  • Used as an antacid

b. Cement

Ans:

  • An important building material

  • Used in concrete and reinforced cement

c. Plaster of Paris

Ans: 

  • Used in plasters

  • In dentistry, in ornamental work for making status


22. Why are lithium salts commonly hydrated and those of the other alkali metal ions usually anhydrous?

Ans: Due to smallest size, $L{{i}^{+}}$ can polarize water molecules easily than the other alkali metal ions


23. Why is LiF almost insoluble in water whereas LiCl soluble not only in water but also in acetone?

Ans: It is due to high lattice energy of LiF as compared to LiCl. 

LiCl is soluble in water because its hydration energy is higher than its lattice energy


24. Explain the significance of sodium, potassium, magnesium and calcium in biological fluids.

Ans: 

Sodium Ions:

  • $N{{a}^{+}}$ ions participate in the transmission of nerve signals, in regulating the flow of water across cell membranes.

  • In the transport of sugars and amino acids into cell

Potassium Ions:

  • They active many enzymes

  • Participate in the oxidation of glucose to produce ATP.

Magnesium Ions:

  • All enzymes that utilize ATP in phosphate transfer require magnesium as a cofactor.

  • Mg is the main pigment for the absorption of light in plants.

Calcium Ions:

  • $C{{a}^{+2}}$ ions are present in bones

  • Plays important roles in neuromuscular function

25. What happens when

a. Sodium metal is dropped in water?

Ans: $2Na+2{{H}_{2}}O\to 2NaOH+{{H}_{2}}$

b. Sodium metal is heated in a free supply of air?

Ans: $2Na+{{O}_{2}}\to N{{a}_{2}}{{O}_{2}}$

c. Sodium peroxide dissolves in water?

Ans: $N{{a}_{2}}{{O}_{2}}+2{{H}_{2}}O\to 2NaOH+{{H}_{2}}{{O}_{2}}$ 


26. Comment on each of the following observation:

a. The mobility of the alkali metal ions in aqueous solutions are $L{{i}^{+}} < N{{a}^{+}} < {{K}^{+}} < R{{b}^{+}} < C{{s}^{+}}$ 

Ans: Smaller the size of the ion, more highly it is hydrated and hence greater is the mass of the hydrated ion and thus the ionic mobility becomes lesser. The extent of hydration decreases in the order.

$L{{i}^{+}} < N{{a}^{+}} < {{K}^{+}} < R{{b}^{+}} < C{{s}^{+}}$

Thus, the mobility of $C{{s}^{+}}$ will be the highest

b. Lithium is the only alkali metal to form a nitride directly.

Ans: due to its smaller size lithium can form nitride directly

c. ${{E}^{\Theta }}$ for ${{M}^{+2}}(aq)+2{{e}^{-}}\to M(s)$( where M= Ca, Sr, or Ba)

Ans: it is because reduction potential depends upon sublimation energy, ionization energy and hydration energy. Their resultant is almost constant for these ions.


27. State as to why

a. A solution of $N{{a}_{2}}C{{O}_{3}}$ is alkaline?

Ans: $N{{a}_{2}}C{{O}_{3}}$ is a salt of a weak acid, carbonic acid $({{H}_{2}}C{{O}_{3}})$ and a strong base NaOH. Thus it undergoes hydrolysis to produce a strong base NaOH and its aqueous solution is alkaline in nature.

\[N{{a}_{2}}C{{O}_{3}}(s)+{{H}_{2}}O(l)\to 2NaOH\]  

b. Alkali metals are prepared by electrolysis of their fused chlorides?

Ans: Because the discharge potential of alkali metals is much higher than that of hydrogen, therefore when the aqueous solution of any alkali metal chlorides is subjected to electrolysis, ${{H}_{2}}$ , instead of the alkali metal, is produced at the cathode. Therefore alkali metals are prepared by electrolysis of their fused chlorides.

c. Sodium is found to be more useful than potassium?

Ans: since potassium is more reactive than sodium and it is found in nature to a less extent than Na, sodium is found to be more useful.


28. Write balanced equations for reactions between.

a. \[N{{a}_{2}}{{O}_{2}}\] and water

Ans: $N{{a}_{2}}{{O}_{2}}+2{{H}_{2}}O\to 2NaOH+{{H}_{2}}{{O}_{2}}$

b. $K{{O}_{2}}$ and water

Ans: $2K{{O}_{2}}+2{{H}_{2}}O\to 2KOH+{{O}_{2}}+{{H}_{2}}{{O}_{2}}$

c. $N{{a}_{2}}O$ and $C{{O}_{2}}$ 

Ans: $N{{a}_{2}}O+C{{O}_{2}}\to N{{a}_{2}}C{{O}_{3}}$ 


29. How would you explain the following observations?

a. BeO is almost insoluble. $BeS{{O}_{4}}$ is soluble in water.

Ans: Lattice energy of BeO is comparatively higher than the hydration energy. Therefore, it is almost insoluble in water. Whereas $BeS{{O}_{4}}$ is ionic in nature and its hydration energy dominates the lattice energy.

b. BaO is soluble but $BaS{{O}_{4}}$ is insoluble in water.

Ans: Both BaO and $BaS{{O}_{4}}$ are ionic compounds but the hydration energy of BaO is higher than the lattice energy therefore it is soluble in water.

c. LiI is more soluble than KI in ethanol.

Ans: Since the size of $L{{i}^{+}}$  ion is very small in comparison to ${{K}^{+}}$  ion, it polarizes the electron cloud I- ion to great extent. Thus LiI dissolves in ethanol more easily than the KI. 


30. Which of the following alkali metals has the least melting point?

a. Na

b. K

c. Rb

d. Cs

Ans: size of Cs is the biggest thus, its melting point is the lowest. Option (d) is correct


31. Which one of the following alkali metals gives hydrated salts?

a. Li

b. Na

c. K

d. Cs

Ans: Li is the smallest. Thus it has the highest charge density and hence attracts the water molecules more strongly.


32. Which one of the following alkaline earth metal carbonates is thermally most stable?

a. $MgC{{O}_{3}}$ 

b. $CaC{{O}_{3}}$ 

c. $SrC{{O}_{3}}$ 

d. $BaC{{O}_{3}}$ 

Ans: $BaC{{O}_{3}}$

I. Very Short Answer Type Questions

1. Name the alkali metal which shows diagonal relationship with magnesium?

Ans: Lithium (Li)


2. Why alkali and alkaline earth metals cannot be obtained by chemical reduction method?

Ans: Because alkali and alkaline earth metals are themselves stronger reducing agents than the majority of other reducing agents.


3. Name the compounds used for the manufacture of washing soda by Solvay process.

Ans: $NaCl,CaC{{O}_{3}}\And N{{H}_{3}}$ 


4. Which electrolyte is used to obtain sodium in Castner’s process?

Ans: Fused NaOH


5. What happens when crystals of washing soda are exposed to air?

Ans: Monohydrate ($N{{a}_{2}}C{{O}_{3}}-{{H}_{2}}O$) is formed as a result efflorescence. 


6. Name the alkaline earth metals whose salt do not impart colour to a non-luminous flame.

Ans: beryllium does not impart colour to a non-luminous flame.


7. What is dead burnt plaster?

Ans: it is anhydrous calcium sulphate ($CaS{{O}_{4}}$)


8. What is Quicklime? What happens when it is added to water?

Ans: CaO is quicklime. When it is added to water, $Ca{{(OH)}_{2}}$ is formed.


9. Arrange the following in the increasing order of solubility in water?

$MgC{{l}_{2}},CaC{{l}_{2}},SrC{{l}_{2}},BaC{{l}_{2}}$ 

Ans:$BaC{{l}_{2}} < SrC{{l}_{2}} < CaC{{l}_{2}} < MgC{{l}_{2}}$ 


10. Give the chemical formula of Epsom salt.

Ans: $MgS{{O}_{4}}.7{{H}_{2}}O$ 


11. How would you prepare sodium silicate from silica?

Ans: 

\[N{{a}_{2}}C{{O}_{3}}+Si{{O}_{2}}\xrightarrow{Fuse}\underset{\text{Sod}\text{. Silicate}}{\mathop{N{{a}_{2}}Si{{O}_{3}}}}\,+C{{O}_{2}}\] 


12. What happens when sodium metal is heated in a free supply of air?

Ans: sodium peroxide is formed

\[2Na+{{O}_{2}}\to N{{a}_{2}}{{O}_{2}}\] 


13. What is the general name for elements of group 1?

Ans: Alkali metals


14. Why are alkali metals soft?

Ans: since the atoms of alkali metals have bigger kernels and smaller number of valence electrons, the metallic bonds in them are very weak and hence are soft.


15. What do you mean by diagonal relationship in periodic table?

Ans: The resemblance of the first element of the second period with diagonally situated elements of neighboring elements is called diagonal relationship.


16. Why is $BeC{{l}_{2}}$ soluble in organic solvent?

Ans: Since, $BeC{{l}_{2}}$is a covalent compound it is soluble in organic solvent.


17. Why do alkali metals give characteristic flame coloration?

Ans: Alkali metals due to low ionization energy absorb energy from the visible region to radiate complementary color. 


18. Why is the solution of alkali metals in liquid ammonia conducting in nature?

Ans: Due to ammoniated electrons and cations.


19. Which is more basic NaOH or $Mg{{(OH)}_{2}}$ ?

Ans: NaOH is more basic


20. Which alkaline earth metals do not impart color to the flame?

Ans: Be and Mg


21. What is soda ash?

Ans: soda ash is anhydrous sodium carbonate ($N{{a}_{2}}C{{O}_{3}}$)


II. Short Answer Type Questions

1. Why are alkali metals always univalent? Which alkali metal ion forms the largest hydrated ion in aqueous solution?

Ans: they are always univalent because after losing one electron, they acquire the nearest inert gas configuration. $L{{i}^{+}}$ forms largest hydrated cations because it has the highest hydration energy.

 

2. What is the effect of heat on the following compounds (give equations for the reactions)

a. $CaC{{O}_{3}}$ 

Ans: $CaC{{O}_{3}}\xrightarrow{\Delta }CaO+C{{O}_{2}}$

b. $CaS{{O}_{4}}.2{{H}_{2}}O$ 

Ans: 

\[CaS{{O}_{4}}.2{{H}_{2}}O\xrightarrow{\Delta }\underset{Dead\text{ }burnt\text{ }plaster}{\mathop{CaS{{O}_{4}}}}\,+2{{H}_{2}}O\]


3. Explain the following:

i. Lithium iodide is more covalent than lithium fluoride

Ans: According to Fazan’s rule, $L{{i}^{+}}$  ion can polarize ${{I}^{-}}$  ion more than the ${{F}^{-}}$  ion due to bigger size of the anion. Thus LiI has more covalent character than LiF.

ii. Lattice enthalpy of LiF is maximum among all the alkali metal halides.

Ans: Smaller the size (internuclear distance), more is the value of Lattice enthalpy since internuclear distance is expected to be least in the LiF. 

 

4. Write the chemical formula of the following compounds.

i. Chile Saltpetre

Ans: $NaN{{O}_{3}}$ 

ii. Marble

Ans: $CaC{{O}_{3}}$ 

iii. Brine

 Ans: $NaCl$ 


5. Explain the following:

a. Why is Cs considered as the most electropositive element?

Ans: Due to its lowest ionization energy, Cs is considered as the most electropositive element.

b. Lithium cannot be used in making photoelectric cells

Ans: lithium cannot be used in making photoelectric cells because out of all alkali metals it has highest ionization energy and thus cannot emit electrons when exposed to light.

c. Lithium does not form alums

Ans: due to small size, lithium does not form alums.


6. a. What makes lithium show properties uncommon to the rest of the alkali metals?

Ans: The unusual properties of lithium as compared to other alkali metals are due to its exceptionally small size of atom and its ion and its high polarizing power.

b. When is cation highly polarizing? Which alkali metal cation has the highest polarizing power?

Ans: A cation is highly polarizing if its charge/size ratio is very high. $L{{i}^{+}}$ 

ion has the highest polarizing power.


7. Why are ionic hydrides of only alkali metals and alkaline earth metals known? Give two examples.

Ans: Alkali metals and alkaline earth metals are most electropositive due to low ionization enthalpy therefore they form ionic hydrides, e.g. NaH, KH and $Ca{{H}_{2}}$ .


8. Why does the solution of alkali metals become blue in liquid ammonia? Give the chemical equation also

Ans: The blue colour of the solution is due to an ammoniated electron which absorbs energy in the visible region of light and imparts blue colour.

\[Na(am)+{{e}^{-}}(am)+N{{H}_{3}}(l)\to NaN{{H}_{2}}(am)+(-\frac{1}{2}){{H}_{2}}(g)\] 


9. Give the important uses of the following:

(i). $NaHC{{O}_{3}}$

Ans:

  • It is used in fire extinguisher

  • It is mild antiseptic for skin infections

  • It is used as an antacid.

(ii). $NaOH$ 

Ans:

  • It is used in soap industry

  • It is used in textile industry

  • It is used as reagent in laboratory

  • It is used in absorbing poisonous gases


10. What is the mixture of $Ca{{C}_{2}}$ and ${{N}_{2}}$ called? How is it prepared?

Ans: it is called Nitro lime.

It is prepared by heating $Ca{{C}_{2}}$ with ${{N}_{2}}$ at high temperature.

$Ca{{C}_{2}}+{{N}_{2}}\to CaC{{N}_{2}}+C$ 


III. Long Answer Type Questions

1. Compare

a) Compare four properties of alkali and alkaline earth metals


Alkali metals

Alkaline earth metals

(i) They are soft metals

(i) They are harder than alkali metals

(ii) Alkali metals show +1 oxidation state

(ii) Alkaline earth metals show +2 oxidation state

(iii) Their carbonates are soluble in water except $L{{i}_{2}}C{{O}_{3}}$ 

(iii) Their carbonates are insoluble in water

(iv) Except Li, alkali metals do not form complex compounds

(iv) They can form complex compounds


b) What happens when alkali metals are dissolved in ammonia?

Ans: they form a blue colored solution. The solution is paramagnetic in nature.

c) $MgC{{l}_{2}}$ is electrolyzed.

Ans: $MgC{{l}_{2}}\xrightarrow{electrolysis}M{{g}^{+2}}+2C{{l}^{-}}$

At Cathode: 

$M{{g}^{2+}}(aq)+2{{e}^{-}}\xrightarrow{electrolysis}Mg(s)$ 

At anode:

$2C{{l}^{-}}(aq)-2{{e}^{-}}\to C{{l}_{2}}(g)$ 


2. State as to why

a). Alkali metals show only +1 oxidation state.

Ans: Alkali metals have low ionization enthalpies. 

They have a strong tendency to lose 1 electron to form unipositive ions. Thus they show an oxidation state of +1 and are strongly electropositive

b). Na and K impart colour to the flame but Mg does not.

Ans: Valence electrons of alkali metals like Na and K easily absorb energy from the flame and are excited to higher energy levels. When these electrons return to the ground state, the energy is emitted in the form of light.

Magnesium atoms have small size so electrons are strongly bound to the nucleus. Thus they need a large amount of energy for excitation of electrons to higher energy levels which is not possible in Bunsen flame.

c). Lithium on being heated in air mainly forms the monoxide and not the peroxide.

Ans: Due to the small size of $L{{i}^{+}}$ it has a strong positive field which attracts the negative charge so strongly that it does not permit the oxide ion, 02-to combine with another oxygen atom to form peroxide ion

d). Li is the best reducing agent in aqueous solution

Ans: Since, among alkali metals, lithium has the most negative electrode potential (${{E}^{0}}=-3.04V$ ) so, it is the strongest reducing agent in the aqueous solution.


IV. Multiple Choice Questions

1. The reducing property of alkali metals follows that order

a) $Na < K < Rb < Cs < Li$ 

b) $K < Na < Rb < Cs < Li$ 

c) $Li < Cs < Rb < K < Na$ 

d) $Rb < Cs < K < Na < Li$ 

Ans: a) $Na < K < Rb < Cs < Li$


2. Which of the following is least thermally stable?

a) $MgC{{O}_{3}}$ 

b) $CaC{{O}_{3}}$ 

c) $SrC{{O}_{3}}$ 

d) $BeC{{O}_{3}}$ 

Ans: $BeC{{O}_{3}}$


3. When heated to ${{800}^{o}}C$ , $NaN{{O}_{3}}$ gives

a) $Na+{{N}_{2}}+{{O}_{2}}$ 

b) $NaN{{O}_{2}}+{{O}_{2}}$ 

c) $N{{a}_{2}}O+{{O}_{2}}+{{N}_{2}}$ 

d) $Na{{N}_{3}}+{{O}_{2}}$ 

Ans: $N{{a}_{2}}O+{{O}_{2}}+{{N}_{2}}$


4. Lithium shows a diagonal relationship with

a) Sodium

b) Silicon

c) Nitrogen

d) Magnesium

Ans: Magnesium


5. In the Solvay process 

a). An ammoniacal brine solution is bicarbonate with $C{{O}_{2}}$, forming $NaHC{{O}_{3}}$ which on decomposition at ${{150}^{0}}C$ produces $N{{a}_{2}}C{{O}_{3}}$ 

b). A sodium amalgam reacts with water to produce NaOH which gives $N{{a}_{2}}C{{O}_{3}}$ on reacting with $C{{O}_{2}}$ 

c). A brine solution is made react with $BaC{{O}_{3}}$ to produce $N{{a}_{2}}C{{O}_{3}}$ 

d). All of the above

Ans: An ammoniacal brine solution is bicarbonate with $C{{O}_{2}}$, forming $NaHC{{O}_{3}}$ which on decomposition at ${{150}^{0}}C$ produces $N{{a}_{2}}C{{O}_{3}}$ 


6. The oxide of which of the following metals is amphoteric?

a) Pb

b) Mg

c) Ca

d) Al

Ans: a) Pb and d) Al


7. Alkaline earth metals are

a) More reactive

b) Less reducing

c) More oxidizing

d) Less basic than alkali metals

Ans: b) less reducing and d) less basic than alkali metals


8. Which of the following is not peroxides?

a) $K{{O}_{2}}$ 

b) $Cr{{O}_{5}}$ 

c) $N{{a}_{2}}{{O}_{2}}$ 

d) $Ba{{O}_{2}}$

Ans: a) $K{{O}_{2}}$


9. Hydrides as well as halides of alkaline earth metals tend to polymerize

a) Sr

b) Ca

c) Be

d) Mg

Ans: c) Be


10. Which of the following is used in photovoltaic cells?

a) Na

b) K

c) Li

d) Cs

Ans: Cs


V. Hots Questions:

1. Why are alkalis metals soft and have low melting points?

Ans: Alkali metals have only one valence electron per metal atom. As a result, the binding energy of alkali metal ions in the close-packed metal lattices are weak. Therefore, these are soft and have low melting points.


2. Which out of the following can be used to store an alkali metal?

${{H}_{2}}O,{{C}_{2}}{{H}_{5}}OH\And {{C}_{6}}{{H}_{6}}$ 

Ans: benzene can be used to store an alkali metal because other substances react with alkali metal as:

\[Na+{{H}_{2}}O\to NaOH+\frac{1}{2}{{H}_{2}}\] 

\[Na+{{C}_{2}}{{H}_{5}}OH\to {{C}_{2}}{{H}_{5}}ONa+\frac{1}{2}{{H}_{2}}\] 


3. Potassium carbonate cannot be prepared by Solvay process. Why?

Ans: This is due to the reason that potassium bicarbonate ($KHC{{O}_{3}}$) formed as an intermediate (when $C{{O}_{2}}$ gas is passed through ammoniated solution of potassium chloride) is highly soluble in water and cannot be separated by filtration.


4. The hydroxides and carbonates of sodium and potassium are easily soluble in water while the corresponding salts of magnesium and calcium are sparingly soluble in water. Explain.

Ans: All the compounds are crystalline solids and their solubility in water is guided by both lattice enthalpy and hydration enthalpy. In case of sodium and potassium compounds, the magnitude of lattice enthalpy is quite small as compared to sodium and potassium that are mentioned, readily dissolve in water. However, in case of corresponding magnesium and calcium compounds, the cations have smaller sizes and more magnitude of positive charge. This means that their lattice enthalpies are more as compared to the compounds of sodium and potassium. Therefore, the hydroxides and carbonates of these metals are only sparingly soluble in water.


5. Why is LiF almost insoluble in water whereas LiCl soluble not only in water but also in acetone?

Ans: The low solubility of LiF in water is due to its very high lattice enthalpy (${{F}^{-}}$ ion is very small in size). On the other hand, in lithium chloride (LiCl) the lattice enthalpy is comparatively very small. This means that the magnitude of hydration enthalpy is quite large. Therefore lithium chloride dissolves in water. It is also soluble in acetone due to dipolar attraction. (Acetone is polar in nature).


Download NCERT Solutions for Class 11 Chemistry S Block Elements PDF

S Block Elements form a distinct group in the periodic table. Resultantly, they also show some particular characteristics. It is these features that make such elements from other metals on the periodic table. S block elements Class 11 NCERT solutions, therefore informs all the standard and unique characteristics of these elements that students require to know.


Besides, learning these concepts from textbooks, students can download the same copy in PDF format for free and study them whenever they wish to. NCERT Solutions for Class 11 Chemistry Chapter 10 not only aid students to score better grades in the examination but also allow them to develop significant insight into the topic.


Topic Wise Solutions of NCERT Solutions of S Block Elements Class 11th

S Block Elements Class 11 solutions are classified into different sub-topics that facilitate understanding of the core matter of the concept with ease. Following are the topics that this solution covers -

  1. Group 1 Materials: Alkali Metals.

  2. Biological Importance of Sodium and Potassium.

  3. Some Important Compounds of Sodium.

  4. Anomalous Properties of Lithium.

  5. General Characteristics of Compounds of Alkali Metals.

  6. Group 2 Elements: Alkaline Earth Metals.

  7. Anomalous Behaviour of Beryllium.

  8.  Biological Importance of Magnesium and Calcium.

  9. Some Important Compounds of Calcium.

  10. General Characteristics of Compounds of Alkaline Earth Metals.

Short Questions

The first part of  S Block Elements Class 11 NCERT solutions contains short questions like what are the physical and chemical properties of alkali metals, the reason for the absence of alkali in nature, etc. Along with that questions like why potassium is more reactive than sodium, different comparisons between alkali metals and alkaline earth metals, etc. are also part of this segment.


Very Short Questions

This part of  Class 11 Chemistry Ch 10 NCERT Solutions comprises numerous questions that students have to explain in a few words. Here, they will find the answers for questions like which compounds are used in the Solvay process for washing soda manufacturing, which electrolyte is added in Castner’s process to obtain sodium and so on.


Long Questions

CBSE Class 11 Chemistry Chapter 10 Solutions also provide solved answers of several long questions which are mostly conceptual. Students here will find the solutions for questions like the oxidation state of alkali metals, why Li is considered the best reducing agent, especially in aqueous solution and other part questions. Such questions further contain several parts that students have to answer one-by-by.


Multiple Choice Questions

The last part of Ch 10 Chemistry Class 11 NCERT solutions involves several multiple questions. However, to answer these questions, students need to read the entire textbook minutely. Nonetheless, reading S block elements in Class 11 NCERT solutions, they can also cover the syllabus in a short time.


Why Should Students Choose NCERT Solution of S Block Elements Class 11?

Since considerable numbers of questions come from s block elements, it is vital for students to understand the basics of these elements well. In this regard, S Block Elements in Class 11 NCERT Solutions are the most favourites of both students and teachers.

Here is why -

  • This solution provides to-the-point answers to each question.

  • Each answer contains appropriate equations and diagrams that help students to stay immersed in the topic.

  • Along with text knowledge, students will get additional information on each topic as well.

  • It follows the question and answer pattern that of the final examination. Hence, students can be exam-ready from the beginning.

  • Practicing Class 11th Chemistry Chapter 10 solutions within stimulated time also helps in time management. Thereby students can finish the complete paper in the exam hall.

Additionally, Class 11 Chemistry chapter S block element NCERT solutions are also available on different online educational portals like Vedantu. Besides the free PDF version of the same, they also offer online tutorials on various subjects, including chemistry that you can watch online.

For more information regarding s block elements, visit Vedantu’s website today!

FAQs on NCERT Solutions for Class 11 Chemistry Chapter 10 - The S Block Elements

1. What are the Standard Features of S Block Elements?

S Block Elements show some common features like -

  1. All of them are metals.

  2. They possess low ionization enthalpy.

  3. To form a cation, they release the outermost electron.

  4. Down the group, their metallic nature increases.

  5. Group 1 metals lose one electron whereas group 2 ones lose two.

Apart from these, several other characteristics are there that students can learn from S Block Elements Class 11 NCERT solutions.

2. Where can I Learn About S Block Elements?

Primarily you can read about s block elements from NCERT textbooks. Along with that, you will also get detailed information about the same from S Block Elements Class 11 PDF Solutions.


Along with learning any topic, you need to practise varieties of questions on that topic to get a concrete idea of that. Henceforth, you should also solve all the questions from the exercises to fetch good marks in the examination.

3. How Many Questions are There in S Block Elements?

In total there are almost 32 questions from s block elements. For instance, Iit includes 2 multiple-choice questions, 15 very short questions and so on.

However, students do not have to look for multiple places to search for the answers to these questions. They can simply follow ch 10 Chemistry class 11 solutions where the answers of all these questions are elucidated with good example and equation.

4. How are NCERT Solutions for Class 11 Chemistry Chapter 10 helpful for Class 11 students?

Class 11 Chemistry is important not only for board examinations but also for various competitive examinations held at the national level. In such a scenario, it becomes exceedingly essential for students to know all their concepts properly so that they are able to answer any question they might be asked in Vedantu's Class 11 NCERT Chemistry Chapter 10 Solutions. 

5. Why should we follow NCERT Solutions for Class 11 Chemistry Chapter 10?

Vedantu has compiled a list of all the various exercises present at the back of each chapter of Chemistry alongside its solutions. Following these solutions will help you get better clarity and understanding regarding the subjects present in it. Students often make the mistake of not solving questions after completing studying a chapter. By checking out these solutions on Vedantu’s website, students will be able to find the answers to all the questions they might be having trouble answering. 

6. Where to download NCERT Solutions for Class 11 Chemistry Chapter 10?

Class 11 Chemistry Chapter 10 is on S Block Elements. These are the first periodic blocks of elements that are taught to students in Chemistry. Questions are frequently set from this chapter as it forms an important part of the periodic table. To download, click on NCERT Solutions for Class 11 Chemistry Chapter 10. You will be redirected to a page by Vedantu, where you can access all the solutions for free. You can access the same on the Vedantu Mobile app.

7. What are the S block elements?

S block elements are those that have the last electron of their electronic configuration present in the S orbital. They form a distinct group in the periodic table. These elements are taught to the students alongside all their unique physical and chemical properties. Their reactions with other S block elements are studied in detail, and unique identification features are discussed. Some common examples of S block elements are sodium, potassium, hydrogen, beryllium, magnesium, etc. 

8. What are the classifications of S block elements?

S block elements are categorised into two subgroups. Group 1 elements are called Alkali Metals, while Group 2 elements are called Alkaline Earth Metals. The alkali metals are reactive and combined with other elements, as well as found in nature. They are called reactive as their reaction with water yields alkalies. On the other hand, alkaline earth metals, although still very reactive, do not undergo reactions that are as vigorous as alkali metals.