
Which halogen does not show variable oxidation state?
A. ${F_2}$
B. $C{l_2}$
C. $B{r_2}$
D. ${I_2}$
Answer
161.7k+ views
Hint: An element's oxidation state is indicated by a number that is assigned to it to indicate how many electrons have been lost from it or consumed by it. Both positive and negative oxidation states are possible.
Complete Step by Step Solution:
Fluorine lacks d orbitals in its valence shell and is the most electro-negative element. It is exceedingly challenging to connect a more electronegative element with fluorine in order for it to display a positive oxidation state.
The lightest halogen, fluorine, is a very poisonous, pale yellow diatomic gas under normal conditions. It is the chemical element that is most reactive. It also has a strong affinity for electrons. With the exception of minute amounts of the free element in radium-irradiated fluorspar, fluorine is solely present in nature as chemical compounds.
Since F is the most electronegative element, it cannot possibly share an electron with another element that is more electronegative than it. Its great capacity to attract electrons (it is the most electronegative element) and the small size of its atoms are both responsible for its high level of chemical activity. Fluorine does not exhibit positive oxidation states due to this. Fluorine is the most electronegative atom so it accepts electrons very easily and shows only -1 oxidation state.
Hence the correct option is A.
Note: Excitation of outer s and p-orbitals into d-orbitals makes it possible to achieve positive oxidation states by making 3, 5, or 7 unpaired electrons readily available for bonding. Higher oxidation states are not capable of being displayed by elements without unoccupied d orbitals.
Complete Step by Step Solution:
Fluorine lacks d orbitals in its valence shell and is the most electro-negative element. It is exceedingly challenging to connect a more electronegative element with fluorine in order for it to display a positive oxidation state.
The lightest halogen, fluorine, is a very poisonous, pale yellow diatomic gas under normal conditions. It is the chemical element that is most reactive. It also has a strong affinity for electrons. With the exception of minute amounts of the free element in radium-irradiated fluorspar, fluorine is solely present in nature as chemical compounds.
Since F is the most electronegative element, it cannot possibly share an electron with another element that is more electronegative than it. Its great capacity to attract electrons (it is the most electronegative element) and the small size of its atoms are both responsible for its high level of chemical activity. Fluorine does not exhibit positive oxidation states due to this. Fluorine is the most electronegative atom so it accepts electrons very easily and shows only -1 oxidation state.
Hence the correct option is A.
Note: Excitation of outer s and p-orbitals into d-orbitals makes it possible to achieve positive oxidation states by making 3, 5, or 7 unpaired electrons readily available for bonding. Higher oxidation states are not capable of being displayed by elements without unoccupied d orbitals.
Recently Updated Pages
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Main Mock Test Series Class 12 Chemistry for FREE

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Displacement-Time Graph and Velocity-Time Graph for JEE

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Classification of Drugs

JoSAA JEE Main & Advanced 2025 Counselling: Registration Dates, Documents, Fees, Seat Allotment & Cut‑offs

Other Pages
NCERT Solutions for Class 12 Chemistry Chapter 1 Solutions

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Solutions Class 12 Notes: CBSE Chemistry Chapter 1

NCERT Solutions for Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes

NCERT Solutions for Class 12 Chemistry Chapter 2 Electrochemistry

Electrochemistry Class 12 Notes: CBSE Chemistry Chapter 2
