
The value of \[{\sin ^2}17.5 + {\sin ^2}72.5\] is equal to
A. \[{\cos ^2}{90^ \circ }\]
B. \[{\tan ^2}{45^ \circ }\]
C. \[{\cos ^2}{30^ \circ }\]
D. \[{\sin ^2}{45^ \circ }\]
Answer
218.7k+ views
Hint: In this question, we find the value of the provided expression. To do that, we use the formula \[\sin \left( {90 - \theta } \right) = \cos \theta \] to turn the second term into a cosine function, simplify it once more, then use the formula \[{\sin ^2}\theta + {\cos ^2}\theta = 1\], and finally consult the trigonometric table to obtain the required outcome.
Formula used:
We have been using the following formulas:
1. \[\sin \left( {90 - \theta } \right) = \cos \theta \]
2. \[{\sin ^2}\theta + {\cos ^2}\theta = 1\]
Complete step-by-step solution:
We are given that \[{\sin ^2}17.5 + {\sin ^2}72.5\]
We are asked to find the value of the given expression.
We know that \[\sin \left( {90 - \theta } \right) = \cos \theta \]
Now we apply the above formula in our expression, and we get
\[{\sin ^2}{17.5^ \circ } + {\sin ^2}\left( {{{90}^ \circ } - {{17.5}^ \circ }} \right)\]
Now by simplifying the above expression, we get
\[{\sin ^2}{17.5^ \circ } + {\cos ^2}{17.5^ \circ }\]
We know that \[{\sin ^2}\theta + {\cos ^2}\theta = 1\]
Now by applying the above formula in our expression, we get
\[{\sin ^2}{17.5^ \circ } + {\cos ^2}{17.5^ \circ } = 1\]
Here, \[\theta = {17.5^ \circ }\]
Now,
\[
{\sin ^2}17.5 + {\sin ^2}72.5 = 1 \\
= {1^2}
\]
We know that \[\tan {45^ \circ } = 1\]
So, \[{\tan ^2}{45^ \circ } = 1\]
Therefore, the value of \[{\sin ^2}17.5 + {\sin ^2}72.5\]is equal to \[{\tan ^2}{45^ \circ }\]
Hence, option (B) is correct option
Additional information: Trigonometric Identities are equality statements that hold true for all values of the variables in the equation and that use trigonometry functions. There are numerous distinctive trigonometric identities that relate a triangle's side length and angle. Only the right-angle triangle is the exception to the trigonometric identities.
Note: Students should be careful while applying the trigonometric identity in the above problem since they run the risk of making an error and also be attentive when simplifying this identity. So that this minor error does not have an impact on our results.
Formula used:
We have been using the following formulas:
1. \[\sin \left( {90 - \theta } \right) = \cos \theta \]
2. \[{\sin ^2}\theta + {\cos ^2}\theta = 1\]
Complete step-by-step solution:
We are given that \[{\sin ^2}17.5 + {\sin ^2}72.5\]
We are asked to find the value of the given expression.
We know that \[\sin \left( {90 - \theta } \right) = \cos \theta \]
Now we apply the above formula in our expression, and we get
\[{\sin ^2}{17.5^ \circ } + {\sin ^2}\left( {{{90}^ \circ } - {{17.5}^ \circ }} \right)\]
Now by simplifying the above expression, we get
\[{\sin ^2}{17.5^ \circ } + {\cos ^2}{17.5^ \circ }\]
We know that \[{\sin ^2}\theta + {\cos ^2}\theta = 1\]
Now by applying the above formula in our expression, we get
\[{\sin ^2}{17.5^ \circ } + {\cos ^2}{17.5^ \circ } = 1\]
Here, \[\theta = {17.5^ \circ }\]
Now,
\[
{\sin ^2}17.5 + {\sin ^2}72.5 = 1 \\
= {1^2}
\]
We know that \[\tan {45^ \circ } = 1\]
So, \[{\tan ^2}{45^ \circ } = 1\]
Therefore, the value of \[{\sin ^2}17.5 + {\sin ^2}72.5\]is equal to \[{\tan ^2}{45^ \circ }\]
Hence, option (B) is correct option
Additional information: Trigonometric Identities are equality statements that hold true for all values of the variables in the equation and that use trigonometry functions. There are numerous distinctive trigonometric identities that relate a triangle's side length and angle. Only the right-angle triangle is the exception to the trigonometric identities.
Note: Students should be careful while applying the trigonometric identity in the above problem since they run the risk of making an error and also be attentive when simplifying this identity. So that this minor error does not have an impact on our results.
Recently Updated Pages
The angle of depression of the top and the bottom of class 10 maths JEE_Main

Find the value of sin 50 circ sin 70 circ + sin 10 class 10 maths JEE_Main

The amount of work in a leather factory is increased class 10 maths JEE_Main

The side BC of a triangle ABC is bisected at D O is class 10 maths JEE_Main

The circumference of the base of a 24 m high conical class 10 maths JEE_Main

Mutually Exclusive vs Independent Events: Key Differences Explained

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

JEE Main Syllabus 2026: Download Detailed Subject-wise PDF

JEE Main Previous Year Question Papers (2014–2025) with Answer Keys and Solutions

Exothermic Reactions: Real-Life Examples, Equations, and Uses

Marks vs Percentile JEE Mains 2026: Calculate Percentile Marks

Understanding Newton’s Laws of Motion

Other Pages
NCERT Solutions For Class 10 Maths Chapter 12 Surface Area And Volume

NCERT Solutions for Class 10 Maths Chapter Chapter 13 Statistics

NCERT Solutions for Class 10 Maths Chapter 11 Areas Related to Circles 2025-26

Pregnancy Week and Due Date Calculator: Find How Far Along You Are

Complete List of Class 10 Maths Formulas (Chapterwise)

NCERT Solutions for Class 10 Maths Chapter 15 Probability

