
The circumference of the base of a 24 m high conical tent is 44 m. Calculate the length of a canvas used in making the tent if the width of the canvas is 2 m.
A. 257 m
B. 275 m
C. 752 m
D. 285 m
Answer
240.3k+ views
Hint: Here, we will use the formula of circumference \[2\pi r\] to find the radius of the circle. Then we will find the slant height \[l = \sqrt {{h^2} + {r^2}} \] to find the surface area of the canonical tent \[\pi rl\]. Then the surface area is divided by the width for the length of required canvas.
Complete step-by-step solution
Given that the height \[h\] is 24 m.
Let the radius of the base of a conical tent is \[r\] meters and the slant height be \[l\] meters.
We know that the circumference of a circle is \[2\pi r\], where \[r\] is the radius of the circle.
Since we are given that the circumference of the conical tent is 44 m.
\[ \Rightarrow 2\pi r = 44\]
Dividing the above equation by \[2\pi \] on each of the sides, we get
\[
\Rightarrow \dfrac{{2\pi r}}{{2\pi }} = \dfrac{{44}}{{2\pi }} \\
\Rightarrow r = \dfrac{{44}}{{2\pi }} \\
\]
Substituting the value of \[\pi \] in the above equation and simplify it, we get
\[
\Rightarrow r = \dfrac{{44}}{{2 \times \dfrac{{22}}{7}}} \\
\Rightarrow r = \dfrac{{44 \times 7}}{{2 \times 22}} \\
\Rightarrow r = 7{\text{ m}} \\
\]
We will now find the slant height \[l\] by substituting the values of \[h\] and \[r\] in the equation \[l = \sqrt {{h^2} + {r^2}} \].
\[
\Rightarrow l = \sqrt {{7^2} + {{24}^2}} \\
\Rightarrow l = \sqrt {49 + 576} \\
\Rightarrow l = \sqrt {625} \\
\Rightarrow l = 25{\text{ m}} \\
\]
Substituting the above values of \[r\] and \[l\] in the surface area \[\pi rl\], we get
\[
{\text{Surface area}} = \pi rl \\
= \dfrac{{22}}{7} \times 7 \times 25 \\
= 22 \times 25 \\
= 550{\text{ }}{{\text{m}}^2} \\
\]
We know that the area of canvas is equal to the surface area of the cone.
Thus, the area of the canvas is 550 m\[^2\].
Using the width of the canvas is 2 m, we will now find the length of the canvas by dividing the area of canvas by 2.
\[
{\text{Length of canvas}} = \dfrac{{{\text{Area of canvas}}}}{2} \\
= \dfrac{{550}}{2} \\
= 275{\text{ m}} \\
\]
Thus, the length of canvas used in making the tent is 275 m.
Hence, the option B is correct.
Note: In this question, students should be familiar with formulae of circumference of a circle, \[2\pi r\] and the surface area of cone, \[\pi rl\]. We will use the equality of area of canvas and the surface area of the cone for the correct solution. We have to divide the area of the canvas by the width of the canvas to find the length of the canvas.
Complete step-by-step solution
Given that the height \[h\] is 24 m.
Let the radius of the base of a conical tent is \[r\] meters and the slant height be \[l\] meters.
We know that the circumference of a circle is \[2\pi r\], where \[r\] is the radius of the circle.
Since we are given that the circumference of the conical tent is 44 m.
\[ \Rightarrow 2\pi r = 44\]
Dividing the above equation by \[2\pi \] on each of the sides, we get
\[
\Rightarrow \dfrac{{2\pi r}}{{2\pi }} = \dfrac{{44}}{{2\pi }} \\
\Rightarrow r = \dfrac{{44}}{{2\pi }} \\
\]
Substituting the value of \[\pi \] in the above equation and simplify it, we get
\[
\Rightarrow r = \dfrac{{44}}{{2 \times \dfrac{{22}}{7}}} \\
\Rightarrow r = \dfrac{{44 \times 7}}{{2 \times 22}} \\
\Rightarrow r = 7{\text{ m}} \\
\]
We will now find the slant height \[l\] by substituting the values of \[h\] and \[r\] in the equation \[l = \sqrt {{h^2} + {r^2}} \].
\[
\Rightarrow l = \sqrt {{7^2} + {{24}^2}} \\
\Rightarrow l = \sqrt {49 + 576} \\
\Rightarrow l = \sqrt {625} \\
\Rightarrow l = 25{\text{ m}} \\
\]
Substituting the above values of \[r\] and \[l\] in the surface area \[\pi rl\], we get
\[
{\text{Surface area}} = \pi rl \\
= \dfrac{{22}}{7} \times 7 \times 25 \\
= 22 \times 25 \\
= 550{\text{ }}{{\text{m}}^2} \\
\]
We know that the area of canvas is equal to the surface area of the cone.
Thus, the area of the canvas is 550 m\[^2\].
Using the width of the canvas is 2 m, we will now find the length of the canvas by dividing the area of canvas by 2.
\[
{\text{Length of canvas}} = \dfrac{{{\text{Area of canvas}}}}{2} \\
= \dfrac{{550}}{2} \\
= 275{\text{ m}} \\
\]
Thus, the length of canvas used in making the tent is 275 m.
Hence, the option B is correct.
Note: In this question, students should be familiar with formulae of circumference of a circle, \[2\pi r\] and the surface area of cone, \[\pi rl\]. We will use the equality of area of canvas and the surface area of the cone for the correct solution. We have to divide the area of the canvas by the width of the canvas to find the length of the canvas.
Recently Updated Pages
Area vs Volume: Key Differences Explained for Students

Mutually Exclusive vs Independent Events: Key Differences Explained

Know The Difference Between Fluid And Liquid

Dimensions of Charge: Dimensional Formula, Derivation, SI Units & Examples

How to Calculate Moment of Inertia: Step-by-Step Guide & Formulas

Difference Between Crystalline and Amorphous Solid: Table & Examples

Trending doubts
JEE Mains Result 2026 OUT Check Scorecard Percentile Cutoff and Toppers

JEE Main Marks vs Percentile 2026: Calculate Percentile and Rank Using Marks

JEE Main 2026 Expected Cutoff Category Wise Qualifying Marks & Percentile

JEE Main 2026: Session 1 Results Out and Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Jan 21 Shift 1 Question Papers with Solutions & Answer Keys – Detailed Day 1 Analysis

JEE Mains Marks vs Rank 2026 – Estimate Your Rank with JEE Scores

Other Pages
CBSE Class 10 Maths Question Paper 2026 OUT Download PDF with Solutions

CBSE Class 10 Maths 2025 Set 1 Question Paper (Standard)

CBSE Class 10 Maths Question Paper Set 3 2025 (Standard) – PDF, Solutions & Analysis

Complete List of Class 10 Maths Formulas (Chapterwise)

NCERT Solutions For Class 10 Maths Chapter 12 Surface Area And Volume - 2025-26

NCERT Solutions For Class 10 Maths Chapter 11 Areas Related To Circles - 2025-26

