Out of $32$ persons, $30$ invest in national savings certificates and $17$ invest in shares. What is the number of persons who invest in both?
A. $13$
B. $15$
C. $17$
D. $19$
Answer
297k+ views
Hint: In this question, we are to find the number of persons who invest in both national savings certificates and shares. For this, we use the formula and by substituting the given values into it, we get the required value. Here the total persons represent the union and the persons who invest in both represent the intersection
Formula Used: Set: A collection of objects in which it is possible to decide whether a given object belongs to the collection or not is said to be a set. Those objects are nothing but the elements in the set.
Sets are represented in two ways: The roaster method and the set builder form
Roaster method:
The set of vowels – \[\left\{ a,\text{ }e,\text{ }i,\text{ }o,\text{ }u \right\}\]
The set of natural numbers – \[\left\{ 1,\text{ }2,\text{ }3,\text{ }\ldots . \right\}\]
Set builder form:
The set of vowels – \[\left\{ x:x\text{ }is\text{ }a\text{ }vowel\text{ }in\text{ }English\text{ }alphabet \right\}\]
The set of natural numbers – \[\left\{ x:x\text{ }is\text{ }a\text{ }natural\text{ }number \right\}\]
Some of the important mathematical sets:
$N$ - the natural number’s set - $N=\{1,2,3...\}$
$Z$- the set of integers - $Z=\{0,\pm 1,\pm 2,\pm 3,...\}$
If two sets $A,B$ where the set $A$ is said to be the subset of $B$ i.e., $A\subseteq B$ then every element of $A$ is in the set $B$ and the set $A$ is said to be the proper subset of $B$ i.e., \[A\subset B\] then $A\subseteq B$ and $A\ne B$.
Some of the important set operations:
$\begin{align}
& n(A\cup B)=n(A)+n(B)-n(A\cap B) \\
& n(A\cup B\cup C)=n(A)+n(B)+n(C)-n(A\cap B)-n(B\cap C)-n(C\cap A)+n(A\cap B\cap C) \\
\end{align}$
Complete step by step solution: Given that, there are $32$ persons. Here $30$ of them invested in national savings certificates and $17$ of them invested in shares.
Consider the set of persons who invested in national certificates as $N$ and the set of persons who invested in shares as $S$.
Then, the number of persons who invested in national savings is $n(N)=30$, the number of persons who invested in shares is $n(S)=17$, and the total number of persons are$n(N\cup S)=32$.
So, the number of persons who invested in both is represented by $n(N\cap S)$
From the theorem we have
$n(A\cup B)=n(A)+n(B)-n(A\cap B)$
Then,
$\begin{align}
& n(N\cup S)=n(N)+n(S)-n(N\cap S) \\
& \Rightarrow n(N\cap S)=n(N)+n(S)-n(N\cup S) \\
\end{align}$
On substituting the given values, we get
$n(N\cap S)=30+17-32=15$
Therefore, the number person who invested in both national savings and in shares is $15$ persons.
Option ‘B’ is correct
Note: Here, we have given all the required values for calculating the number of persons who invested in both. So, we can easily calculate by substituting them in the predefined formula.
Formula Used: Set: A collection of objects in which it is possible to decide whether a given object belongs to the collection or not is said to be a set. Those objects are nothing but the elements in the set.
Sets are represented in two ways: The roaster method and the set builder form
Roaster method:
The set of vowels – \[\left\{ a,\text{ }e,\text{ }i,\text{ }o,\text{ }u \right\}\]
The set of natural numbers – \[\left\{ 1,\text{ }2,\text{ }3,\text{ }\ldots . \right\}\]
Set builder form:
The set of vowels – \[\left\{ x:x\text{ }is\text{ }a\text{ }vowel\text{ }in\text{ }English\text{ }alphabet \right\}\]
The set of natural numbers – \[\left\{ x:x\text{ }is\text{ }a\text{ }natural\text{ }number \right\}\]
Some of the important mathematical sets:
$N$ - the natural number’s set - $N=\{1,2,3...\}$
$Z$- the set of integers - $Z=\{0,\pm 1,\pm 2,\pm 3,...\}$
If two sets $A,B$ where the set $A$ is said to be the subset of $B$ i.e., $A\subseteq B$ then every element of $A$ is in the set $B$ and the set $A$ is said to be the proper subset of $B$ i.e., \[A\subset B\] then $A\subseteq B$ and $A\ne B$.
Some of the important set operations:
$\begin{align}
& n(A\cup B)=n(A)+n(B)-n(A\cap B) \\
& n(A\cup B\cup C)=n(A)+n(B)+n(C)-n(A\cap B)-n(B\cap C)-n(C\cap A)+n(A\cap B\cap C) \\
\end{align}$
Complete step by step solution: Given that, there are $32$ persons. Here $30$ of them invested in national savings certificates and $17$ of them invested in shares.
Consider the set of persons who invested in national certificates as $N$ and the set of persons who invested in shares as $S$.
Then, the number of persons who invested in national savings is $n(N)=30$, the number of persons who invested in shares is $n(S)=17$, and the total number of persons are$n(N\cup S)=32$.
So, the number of persons who invested in both is represented by $n(N\cap S)$
From the theorem we have
$n(A\cup B)=n(A)+n(B)-n(A\cap B)$
Then,
$\begin{align}
& n(N\cup S)=n(N)+n(S)-n(N\cap S) \\
& \Rightarrow n(N\cap S)=n(N)+n(S)-n(N\cup S) \\
\end{align}$
On substituting the given values, we get
$n(N\cap S)=30+17-32=15$
Therefore, the number person who invested in both national savings and in shares is $15$ persons.
Option ‘B’ is correct
Note: Here, we have given all the required values for calculating the number of persons who invested in both. So, we can easily calculate by substituting them in the predefined formula.
Recently Updated Pages
Geometry of Complex Numbers Explained

JEE Main 2023 (February 1st Shift 2) Physics Question Paper with Answer Key

JEE Main 2023 (February 1st Shift 1) Maths Question Paper with Answer Key

JEE Main 2023 (February 1st Shift 2) Chemistry Question Paper with Answer Key

Hydrogen and Its Type Important Concepts and Tips for JEE Exam Preparation

JEE Main 2023 (February 1st Shift 1) Physics Question Paper with Answer Key

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Understanding the Electric Field of a Uniformly Charged Ring

Understanding Atomic Structure for Beginners

Derivation of Equation of Trajectory Explained for Students

Electron Gain Enthalpy and Electron Affinity Explained

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

NCERT Solutions For Class 11 Maths Chapter 6 Permutations And Combinations - 2026-27 Free PDF Download (Login Required)

NCERT Solutions For Class 11 Maths Chapter 9 Straight Lines - 2026-27 Free PDF Download (Sign-in Required)

NCERT Solutions For Class 11 Maths Chapter 4 Complex Numbers And Quadratic Equations - 2026-27 Free PDF Download (Login Required)

NCERT Solutions For Class 11 Maths Chapter 8 Sequences And Series - 2026-27 Free PDF Download (Login Required)

JEE Advanced 2026 Notification Out with Exam Date, Registration (Extended), Syllabus and More

