In a survey of $400$ students in a school, $100$ were listed as taking apple juice, $150$ as taking orange juice and $75$ were listed as taking both apple as well as orange juice. Then, which of the following is/are true?
1. $150$ students were taking at least one juice.
2. $225$ students were taking neither apple juice nor orange juice.
A. Only (1) is true
B. Only (2) is true
C. Both (1) and (2) are true
D. None of these
Answer
249.6k+ views
Hint: A set is a well-defined group of items. In contrast to integers, we can define and investigate the properties of sets. An operation in set theory is an exercise in combining different sets so that a new set with distinct features is obtained. In this question, for first part apply the concept of union and intersection of sets and for second complement of sets.
Formula Used:
Sets formula –
$n\left( {X \cup Y} \right) = n\left( X \right) + n\left( Y \right) - n\left( {X \cap Y} \right)$
Complement of the set –
$n{\left( A \right)^C} = n\left( U \right) - n\left( A \right)$
Complete step by step solution:
Let, $U$ be the set of total number of students in a survey
$X$ be the set of students taking apple juice and $Y$ taking orange juice
$ \Rightarrow n\left( U \right) = 400,n\left( X \right) = 100,n\left( Y \right) = 150,n\left( {X \cap Y} \right) = 75$
Using, $n\left( {X \cup Y} \right) = n\left( X \right) + n\left( Y \right) - n\left( {X \cap Y} \right)$
$n\left( {X \cup Y} \right) = 100 + 150 - 75$
$n\left( {X \cup Y} \right) = 175$
Which implies that $175$ students were taking at least one juice.
Now, $n\left( {{X^C} \cap {Y^C}} \right) = n{\left( {X \cup Y} \right)^C}$
$n\left( {{X^C} \cap {Y^C}} \right) = n\left( U \right) - n\left( {X \cup Y} \right)$
$n\left( {{X^C} \cap {Y^C}} \right) = 400 - 175$
$n\left( {{X^C} \cap {Y^C}} \right) = 225$
$ \Rightarrow 225$ students were taking neither apple nor orange juice.
Option ‘C’ is correct
Note: The key concept involved in solving this problem is the good knowledge of Sets. Students must remember that the union of two sets $A$ and $B$ is the set of all elements that are either in $A$ or in $B$, i.e. $A \cup B$, whereas the intersection of two sets $A$ and $B$ is the set of all common elements. The complement of a set is the set that contains all of the universal set's elements that are not present in the provided set.
Formula Used:
Sets formula –
$n\left( {X \cup Y} \right) = n\left( X \right) + n\left( Y \right) - n\left( {X \cap Y} \right)$
Complement of the set –
$n{\left( A \right)^C} = n\left( U \right) - n\left( A \right)$
Complete step by step solution:
Let, $U$ be the set of total number of students in a survey
$X$ be the set of students taking apple juice and $Y$ taking orange juice
$ \Rightarrow n\left( U \right) = 400,n\left( X \right) = 100,n\left( Y \right) = 150,n\left( {X \cap Y} \right) = 75$
Using, $n\left( {X \cup Y} \right) = n\left( X \right) + n\left( Y \right) - n\left( {X \cap Y} \right)$
$n\left( {X \cup Y} \right) = 100 + 150 - 75$
$n\left( {X \cup Y} \right) = 175$
Which implies that $175$ students were taking at least one juice.
Now, $n\left( {{X^C} \cap {Y^C}} \right) = n{\left( {X \cup Y} \right)^C}$
$n\left( {{X^C} \cap {Y^C}} \right) = n\left( U \right) - n\left( {X \cup Y} \right)$
$n\left( {{X^C} \cap {Y^C}} \right) = 400 - 175$
$n\left( {{X^C} \cap {Y^C}} \right) = 225$
$ \Rightarrow 225$ students were taking neither apple nor orange juice.
Option ‘C’ is correct
Note: The key concept involved in solving this problem is the good knowledge of Sets. Students must remember that the union of two sets $A$ and $B$ is the set of all elements that are either in $A$ or in $B$, i.e. $A \cup B$, whereas the intersection of two sets $A$ and $B$ is the set of all common elements. The complement of a set is the set that contains all of the universal set's elements that are not present in the provided set.
Recently Updated Pages
JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Isoelectronic Definition in Chemistry: Meaning, Examples & Trends

Ionisation Energy and Ionisation Potential Explained

Iodoform Reactions - Important Concepts and Tips for JEE

Introduction to Dimensions: Understanding the Basics

Instantaneous Velocity Explained: Formula, Examples & Graphs

Trending doubts
Understanding the Angle of Deviation in a Prism

Understanding Centrifugal Force in Physics

Understanding Electromagnetic Waves and Their Importance

JEE Main 2026 Session 2 Registration (Reopened): Apply Now

BITSAT 2026 Registration Open: Check Last Date, Exam Dates & Correction Window

Understanding Newton’s Laws of Motion

Other Pages
NCERT Solutions For Class 11 Maths Chapter 4 Complex Numbers And Quadratic Equations - 2025-26

NCERT Solutions For Class 11 Maths Chapter 12 Limits And Derivatives - 2025-26

NCERT Solutions For Class 11 Maths Chapter 8 Sequences And Series - 2025-26

NCERT Solutions For Class 11 Maths Chapter 6 Permutations And Combinations - 2025-26

NCERT Solutions For Class 11 Maths Chapter 5 Linear Inequalities - 2025-26

Free Roofing Calculator – Estimate Roof Area & Material Online

