
Complete the following reaction \[RN{H_2} + {H_2}S{O_4} \to \]
A. \[{[RN{H_3}]^ + }HSO_4^ - \]
B. \[[RN{H_3}]_2^ + SO_4^{2 - }\]
C. \[RN{H_2}.{H_2}S{O_4}\]
D. No reaction
Answer
232.8k+ views
Hint: \[RN{H_2}\] is a general formula for an amine compound where R is the alkyl group. The nitrogen atom of the amine group contains a lone pair of electrons that it can donate to other atoms.
Complete Step by Step Solution:
In the given reaction, the two reactants are \[RN{H_2}\] and \[{H_2}S{O_4}\].\[RN{H_2}\] is the general representation of amine with R as an alkyl group whereas \[{H_2}S{O_4}\]is the chemical formula for sulphuric acid. Due to the presence of lone pair in the nitrogen atom, it acts as a base due to its ability to donate the lone pairs to other atoms and sulphuric acid is considered a strong acid as it completely dissociates to give its constituent hydrogen ion and sulphate ion on dissolving in water.
The reaction taking place between an acid and a base is known as a neutralisation reaction.
In a neutralisation reaction, an acid compound and a base compound react with each other to form salt as its main product by eliminating water molecules.
The complete reaction is shown below:
\[RN{H_2} + {H_2}S{O_4} \to [RN{H_3}]_2^ + SO_4^{2 - }\]
Therefore, the correct option is B.
Additional information:The pH of the salt is generally 7 but it can change depending upon the strength of an acid and base. If the acid is strong and the base is weak, the salt formed will have a pH of less than 7. If the base is strong and the acid is weak, then the salt form will have a pH of more than 7.
Note: It should be noted that the chemical formula of the salt is dependent on the alkyl group present in an amine. If the amine is \[C{H_3}C{H_2}N{H_2}\] than the salt formed will have the chemical formula \[[C{H_3}C{H_2}N{H_3}]_2^ + SO_4^{2 - }\] .
Complete Step by Step Solution:
In the given reaction, the two reactants are \[RN{H_2}\] and \[{H_2}S{O_4}\].\[RN{H_2}\] is the general representation of amine with R as an alkyl group whereas \[{H_2}S{O_4}\]is the chemical formula for sulphuric acid. Due to the presence of lone pair in the nitrogen atom, it acts as a base due to its ability to donate the lone pairs to other atoms and sulphuric acid is considered a strong acid as it completely dissociates to give its constituent hydrogen ion and sulphate ion on dissolving in water.
The reaction taking place between an acid and a base is known as a neutralisation reaction.
In a neutralisation reaction, an acid compound and a base compound react with each other to form salt as its main product by eliminating water molecules.
The complete reaction is shown below:
\[RN{H_2} + {H_2}S{O_4} \to [RN{H_3}]_2^ + SO_4^{2 - }\]
Therefore, the correct option is B.
Additional information:The pH of the salt is generally 7 but it can change depending upon the strength of an acid and base. If the acid is strong and the base is weak, the salt formed will have a pH of less than 7. If the base is strong and the acid is weak, then the salt form will have a pH of more than 7.
Note: It should be noted that the chemical formula of the salt is dependent on the alkyl group present in an amine. If the amine is \[C{H_3}C{H_2}N{H_2}\] than the salt formed will have the chemical formula \[[C{H_3}C{H_2}N{H_3}]_2^ + SO_4^{2 - }\] .
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding the Electric Field of a Uniformly Charged Ring

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions For Class 12 Chemistry Chapter 1 Solutions (2025-26)

Solutions Class 12 Chemistry Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 4 The d and f Block Elements (2025-26)

Biomolecules Class 12 Chemistry Chapter 10 CBSE Notes - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 10 Biomolecules (2025-26)

