Answer
Verified
105.9k+ views
Hint: Average speed may be defined as the total time taken by the man to cover the total distance. In this question first calculate the total time taken by the man to cover 320 km distance and then divide it by total time.
We know that $\left[ {{\text{time}} = \dfrac{{{\text{distance}}}}{{{\text{speed}}}}} \right]$
Given that the man travels first $160km$ at a speed of $64km/hr$
Time taken to cover $160km$ is
$ \Rightarrow {t_1} = \dfrac{{160}}{{64}}hr$
And the next $160km$ travels at a speed of $80km/hr$
Time taken to cover next $160km$ is
$ \Rightarrow {t_2} = \dfrac{{160}}{{80}}hr$
Total time taken to cover a distance of $320km$ is given by adding time ${t_1}$ and ${t_2}$
$
t = {t_1} + {t_2} \\
t = \left( {\dfrac{{160}}{{64}} + \dfrac{{160}}{{80}}} \right)hr \\
t = \dfrac{9}{2}hr \\
$
The average speed is
$
{\text{avg}}{\text{.speed}} = \dfrac{{{\text{distance}}}}{{{\text{time}}}} \\
= \dfrac{{320}}{{\dfrac{9}{2}}}km/hr \\
= \dfrac{{640}}{9}km/hr \\
= 71.11km/hr \\
$
Hence, the average speed for the first 320 km of the tour is 71.11Km/hr.
So, option C is the correct option.
Note: These types of problems are commonly word problems which tell to find anyone of these distance, time, speed and average speed. In these types of problems remember the relation between speed, distance and time. Read the statement carefully and make the conditions accordingly to solve the problem.
We know that $\left[ {{\text{time}} = \dfrac{{{\text{distance}}}}{{{\text{speed}}}}} \right]$
Given that the man travels first $160km$ at a speed of $64km/hr$
Time taken to cover $160km$ is
$ \Rightarrow {t_1} = \dfrac{{160}}{{64}}hr$
And the next $160km$ travels at a speed of $80km/hr$
Time taken to cover next $160km$ is
$ \Rightarrow {t_2} = \dfrac{{160}}{{80}}hr$
Total time taken to cover a distance of $320km$ is given by adding time ${t_1}$ and ${t_2}$
$
t = {t_1} + {t_2} \\
t = \left( {\dfrac{{160}}{{64}} + \dfrac{{160}}{{80}}} \right)hr \\
t = \dfrac{9}{2}hr \\
$
The average speed is
$
{\text{avg}}{\text{.speed}} = \dfrac{{{\text{distance}}}}{{{\text{time}}}} \\
= \dfrac{{320}}{{\dfrac{9}{2}}}km/hr \\
= \dfrac{{640}}{9}km/hr \\
= 71.11km/hr \\
$
Hence, the average speed for the first 320 km of the tour is 71.11Km/hr.
So, option C is the correct option.
Note: These types of problems are commonly word problems which tell to find anyone of these distance, time, speed and average speed. In these types of problems remember the relation between speed, distance and time. Read the statement carefully and make the conditions accordingly to solve the problem.
Recently Updated Pages
Write a composition in approximately 450 500 words class 10 english JEE_Main
Arrange the sentences P Q R between S1 and S5 such class 10 english JEE_Main
Write an article on the need and importance of sports class 10 english JEE_Main
Name the scale on which the destructive energy of an class 11 physics JEE_Main
Choose the exact meaning of the given idiomphrase The class 9 english JEE_Main
Choose the one which best expresses the meaning of class 9 english JEE_Main