A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. Find the average speed for the first 320 km of the tour.
\[
A.{\text{ }}35.55Km/hr \\
B.{\text{ }}36Km/hr \\
C.{\text{ }}71.11Km/hr \\
D.{\text{ }}77Km/hr \\
\]
Answer
269.4k+ views
Hint: Average speed may be defined as the total time taken by the man to cover the total distance. In this question first calculate the total time taken by the man to cover 320 km distance and then divide it by total time.
We know that $\left[ {{\text{time}} = \dfrac{{{\text{distance}}}}{{{\text{speed}}}}} \right]$
Given that the man travels first $160km$ at a speed of $64km/hr$
Time taken to cover $160km$ is
$ \Rightarrow {t_1} = \dfrac{{160}}{{64}}hr$
And the next $160km$ travels at a speed of $80km/hr$
Time taken to cover next $160km$ is
$ \Rightarrow {t_2} = \dfrac{{160}}{{80}}hr$
Total time taken to cover a distance of $320km$ is given by adding time ${t_1}$ and ${t_2}$
$
t = {t_1} + {t_2} \\
t = \left( {\dfrac{{160}}{{64}} + \dfrac{{160}}{{80}}} \right)hr \\
t = \dfrac{9}{2}hr \\
$
The average speed is
$
{\text{avg}}{\text{.speed}} = \dfrac{{{\text{distance}}}}{{{\text{time}}}} \\
= \dfrac{{320}}{{\dfrac{9}{2}}}km/hr \\
= \dfrac{{640}}{9}km/hr \\
= 71.11km/hr \\
$
Hence, the average speed for the first 320 km of the tour is 71.11Km/hr.
So, option C is the correct option.
Note: These types of problems are commonly word problems which tell to find anyone of these distance, time, speed and average speed. In these types of problems remember the relation between speed, distance and time. Read the statement carefully and make the conditions accordingly to solve the problem.
We know that $\left[ {{\text{time}} = \dfrac{{{\text{distance}}}}{{{\text{speed}}}}} \right]$
Given that the man travels first $160km$ at a speed of $64km/hr$
Time taken to cover $160km$ is
$ \Rightarrow {t_1} = \dfrac{{160}}{{64}}hr$
And the next $160km$ travels at a speed of $80km/hr$
Time taken to cover next $160km$ is
$ \Rightarrow {t_2} = \dfrac{{160}}{{80}}hr$
Total time taken to cover a distance of $320km$ is given by adding time ${t_1}$ and ${t_2}$
$
t = {t_1} + {t_2} \\
t = \left( {\dfrac{{160}}{{64}} + \dfrac{{160}}{{80}}} \right)hr \\
t = \dfrac{9}{2}hr \\
$
The average speed is
$
{\text{avg}}{\text{.speed}} = \dfrac{{{\text{distance}}}}{{{\text{time}}}} \\
= \dfrac{{320}}{{\dfrac{9}{2}}}km/hr \\
= \dfrac{{640}}{9}km/hr \\
= 71.11km/hr \\
$
Hence, the average speed for the first 320 km of the tour is 71.11Km/hr.
So, option C is the correct option.
Note: These types of problems are commonly word problems which tell to find anyone of these distance, time, speed and average speed. In these types of problems remember the relation between speed, distance and time. Read the statement carefully and make the conditions accordingly to solve the problem.
Recently Updated Pages
Area vs Volume: Key Differences Explained for Students

Mutually Exclusive vs Independent Events: Key Differences Explained

Geometry of Complex Numbers Explained

Circuit Switching vs Packet Switching: Key Differences Explained

Disproportionation Reaction: Definition, Example & JEE Guide

Hess Law of Constant Heat Summation: Definition, Formula & Applications

Trending doubts
JEE Main Marks vs Percentile 2026: Predict Your Score Easily

JEE Main Cutoff 2026: Category-wise Qualifying Percentile

JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Marks vs Rank 2026: Expected Rank for 300 to 0 Marks

NIT Cutoff 2026: Tier-Wise Opening and Closing Ranks for B.Tech. Admission

JEE Mains 2026 Subject Wise Percentile Explained

Other Pages
CBSE Class 10 Maths Question Paper 2026 OUT Download PDF with Solutions

Complete List of Class 10 Maths Formulas (Chapterwise)

NCERT Solutions For Class 10 Maths Chapter 11 Areas Related To Circles - 2025-26

All Mensuration Formulas with Examples and Quick Revision

NCERT Solutions For Class 10 Maths Chapter 13 Statistics - 2025-26

NCERT Solutions For Class 10 Maths Chapter 14 Probability - 2025-26

