Courses
Courses for Kids
Free study material
Free LIVE classes
More

# JEE Chapter- Chemical Bonding and Molecular Structure

Get interactive courses taught by top teachers

## Introduction to Chemical Bonding and Molecular Structure

Last updated date: 01st Apr 2023
Total views: 97.5k
Views today: 10

We'll look at the structure of atoms as well as the subatomic particles that make up atoms in this chapter. To understand the bond formation, one must first appreciate the electronic structure of atoms or the arrangement of electrons around the central nucleus.

This chapter is one of the most important, simple, and high-scoring for competitive exams like JEE Main 2022 and JEE Advanced 2022, and mastering it will help you do well on the exams.

## JEE Main Chemistry Chapter-wise Solutions 2022-23

### Important Topics of Chemical Bonding and Molecular Structure:

• Chemical Bonding

• Fajan’s rule

• Lewis Dot Structures

• Formal charge

• Hybridization

• Valence Bond Theory

• Molecular Orbital Theory

• VSEPR Theory

### Explanation

Chemical bonding

The force of attraction between the atoms or ions of molecules occur due to sharing of electrons or by transfer of electrons from the atoms to complete octet and attain stability.

Valence shell electrons

The outer shell electrons that take part in chemical bonding are known as valence shell electrons.

### Octet Rule:

The octet rule states that the atoms combine either by transfer of valence electron(s) or by sharing of valence electron(s) to form molecules by completing the octet of electrons in their valence shell to attain the nearest noble gas configuration (hydrogen element completes its duplet to attain the configuration of helium).

• Limitations of Octet Rule:

1. Incomplete Octet: The central atom of some molecules have incomplete octet i.e less than eight electrons in their valence shell. This is generally observed in the molecule of elements which has less than four valence electrons.

Example: BeCl2 (2 valence shell electrons in Be), BF3(3 valence shell electrons in B), LiH  (1 valence shell electron in Li).

1. Odd-Electron Molecules: The molecules which are formed from the atom containing odd electrons in the valence shell.

Example: Molecules of nitrogen- Nitric oxide (NO) and nitrogen dioxide (NO2).

1. Extended Electron: The molecules of some elements contain more than eight electrons in the valence shell of central atoms. The elements of the 3rd period and beyond have d orbitals which also participate in the chemical bonding.

Example: BrCl3 XeF2, PCl5, SF6

1. Noble Gas Compounds: Noble gases have complete octet but some noble gases such as xenon and krypton form compound with fluorine and oxygen.

Example: XeOF2, XeF6, KrF2, XeO3

### Lewis Dot Structures:

G.N. Lewis proposed the notations to represent the elements with their valence electrons. The valence electrons are represented by the dot around the symbol of the element.

Example:

The molecules can also be represented by the lewis symbol notations in which:

• Each atom shares a single electron to form an electron pair.

• Each electron pair represents the bond.

• The atoms combine to attain the noble gas configuration and each atom should  have 8 electrons around it.

Example:

Lewis dot structure of Cl2 molecules.

• The single electron pair between two atoms represents a single covalent bond.

Example: H2O, NH3

• The two-electron pairs shared between two atoms represent the double bond.

Example : O2, CO2

• The three electron pairs shared between two atoms represent the triple bond.

Example: CO, C2H2, N2

### Covalent Bond:

The covalent bond is formed by sharing of electron (s) between two atoms. Atoms combine to become stable by attaining the nearest noble gas configuration.

A single covalent bond is formed when a single electron pair is shared between the atoms, a double covalent bond is formed when two electron pairs are shared, and a triple bond is formed when three electron pairs are shared.

### Formal Charge:

The formal charge is the charge on each atom of the molecule or ion. The ions are represented by the net charge possessed by the ion whereas the formal charge is the charge possessed by each atom in the molecule or ion. In lewis's structure, the atoms in molecules or ions are represented by their formal charge.

The formal charge of an atom in a molecule or ion is given by the formula:

Formal Charge  =   V - N - ½  (B)

where

V: Total number of valence electrons present in the free atom

N: Total number of nonbonded electrons or lone pairs

B: Total number of bonded or shared electrons

The molecules in which the atoms possessing the smallest formal charge are considered to have the lowest energy and more stability.

### Ionic or Electrovalent Bond:

Ionic or electrovalent bond is formed by the transfer of electron(s) from one atom to another to become stable by attaining the nearest noble gas configuration.  The loss of electron(s) from the atom forms a positively charged ion is known as cation and the gaining of electron(s) forms a negatively charged ion known as an anion. There is a strong electrostatic force of attraction between cations and anions, this force is the ionic bond.

Conditions for the formation of ionic bonds:

• Low ionization enthalpy of cation

• High electron gain affinity of anion

• High lattice energy of ionic crystal

Ionisation Enthalpy: It is the amount of energy required to remove loosely bound electrons from an isolated gaseous state of an atom.

M(g)   $⟶$$\longrightarrow$    M+(g) +  e

Electron Gain Enthalpy: It is the amount of energy released when an electron is gained by the gas phase atom in its ground state.

X(g)   +  eー      $⟶$$\longrightarrow$    X(g)

Lattice Enthalpy: The amount of energy required to completely separate one-mole ionic crystal into its constituent ions in the gaseous state is known as lattice enthalpy of an ionic crystal. The more the lattice enthalpy of ionic crystal, the more is the stability of ion ionic crystal.

The factor on which the lattice enthalpy of the ionic crystal depends:

• Size of ions: Smaller the size of ions more will be the lattice enthalpy.

• Charge on ions: Greater the charge on the ions stronger will be interionic attraction and hence more will be the lattice enthalpy.

### Bond Parameters:

• Bond Length:

1. It is the equilibrium distance between the nuclei of the two bonded atoms in a molecule.

2. The bond length of a covalent molecule is determined by the covalent radii of each bonded atom.

3. The bond length order of single, double and triple bond:

Triple bond  <  double bond  <  single bond

• Bond Angle:

1. It is the angle between the orbitals of molecules containing the bonded electron around the central atom.

2. It helps in determining the shape of the molecule.

3. It is expressed in degrees.

The factor that affects the bond angle:

•  Bond angle is proportional to the electronegativity of the central atom and inversely proportional to the electronegativity of the peripheral atoms.

• Bond angle is proportional to the percentage of s character of the hybridised orbitals and inversely proportional to the percentage of p character of the hybridised orbitals.

• The bond angle is proportional to bp-bp repulsion and inversely proportional to lp-bp and lp-lp repulsion.

• The bond angle is proportional to the size of peripheral atoms of the molecule.

• Bond Enthalpy:

1. It is the amount of energy required to break one mole of a particular type of bond between the two atoms of a molecule in a gaseous state.

2. The more the bond enthalpy, the more will be the more stability of the bond.

3. For polyatomic molecules, the bond enthalpy is the average or mean bond enthalpy of all the bonds in the molecule.

The factors affecting the bond enthalpy:

• The chemical environment of the bond is to be broken.

• The more the number of bonds to break the more will be the bond enthalpy. The order of bond enthalpy:

Triple bond  >  Double bond  >  Single bond

• Bond Order:

1. Bond order is the number of electron pairs or bonds present shared between two atoms of a molecule.

2. For single bond: one electron pair is shared between two atoms → bond order = 1

For double bond: two electron pairs are shared between two atoms → bond order = 2

For triple bond: three electron pairs are shared between two atoms → bond order = 3

1. Isoelectronic structures of molecules or ions have the same bond order.

• Resonance Structure:

1. The resonance structure is the group of Lewis structures formed due to the delocalization of electrons in a polyatomic molecule or ion.

Example: benzene and CO32-

1. The single lewis structure of the molecule could not explain the properties of some polyatomic molecules or ions, which is the implication that the molecule has resonance structures.

• The Polarity of Bonds:

1. The bond formed between two different atoms (or heteronuclear atoms) of the molecule has polarity in a bond due to the difference in electronegativity of different atoms and is hence known as a polar bond. Example: HCl, H2O

2. The polarity in bonds gives rise to the dipole moment in the molecule. The dipole moment in the molecule.

• Dipole Moment:

1. The dipole moment is the product of charge (Q) and distance of separation between the atoms(r).

2. The dipole moment is a vector quantity and it is denoted by the symbol μ.

3. The unit of dipole moment is debye (D).

4. The resultant dipole moment of a molecule helps in determining the shape and polarity of a molecule.

### Fagan's Rule:

It states that the covalent bond has some partial ionic character whereas the ionic bonds have partial covalent character. The partial covalent character in an ionic bond can be measured in terms of the following Fajan’s rule:

• The smaller the size of the cation and greater the size of the anion the more will be the covalent character in the ionic bond.

• The cations with greater charge contribute to the more covalent character in the ionic bond.

• Transition metal cations are more polarising than the cation with a noble gas configuration with the same charge and size as that of transition metal cations.

For the ionic character in covalent bond, the conditions will be opposite on the covalent characters in the ionic bond.

### Valence Shell Electron Pair Repulsion (VSEPR) Theory:

This theory helps in determining the shape of the molecule of covalent compounds on the basis of the repulsion of the lone pair and bond pairs in the free spatial arrangement around the central atom of the molecule. The postulates of the VSEPR are as follows:

• Only valence shell electron pairs around the central atom contribute to the shape of the molecule.

• The electron pair repels each other as these are negatively charged due to their negatively charged electron cloud.

• Electron pairs occupy the spherical space around the central atom such that they are at maximum distance from each other and have minimum repulsion between them.

• Multiple bonds are treated as a single electron pair.

The repulsion order of bond pair(bp) and lone pair(lp) is:

lp-lp  >  lp-bp > bp-bp

### Hybridisation:

• It is the mixing of two orbits of nearly different energy levels to get the same number of orbitals of the equivalent energy and shape.

For example: The 1s and 2p orbitals of the same shell hybridize to give 3 orbitals of sp2 hybridisation.

• Number of hybrid orbitals can be determined by the formula:

Number of hybrid orbitals (X)  =   ½ (Total valence electron of central atoms) - Total number of monovalent atoms - charge on cation + charge on the anion.

Or

Number of hybrid orbitals (X)   =  number of bond pairs  +  number of lone pairs on central atoms

• Hybridisation helps in the determination of the geometry of molecules. The bond pairs and lone pairs both are responsible for the geometry of the molecule whereas only bond pairs are responsible for the shape of the molecule.

 Number of Hybrid Orbitals Hybridisation Geometry 2 sp Linear 3 sp2 Trigonal Planar 4 sp3 Tetrahedral 5 sp3d Trigonal bipyramidal 6 sp3d2 Octahedral 7 sp3d3 Pentagonal bipyramidal

Table: Hybridisation corresponding to the number of hybrid orbital and geometry of molecule

### Valence Bond Theory:

This theory states that, when the two atoms are brought closer to each other, there are some attractive forces as well as some repulsive forces acting between the two atoms. When the bond is formed, the net attractive force is balanced by the repulsive forces.

Let us consider two hydrogen atoms which contain nuclei NA and NB and electrons in the valence shell as eA and eB. When the two atoms are brought closer, the attractive forces- NA - eA  and  NB - eB  ; also NA - eB and   NA - eA  acts between the atoms whereas the repulsive forces- NA -NB and eA and eB also act at the same time. A stage is reached when the net attractive force is balanced by net repulsive force, and the bond between two hydrogen atoms is formed.

### Types of Covalent Bond:

There are two types of covalent bonds:

• Sigma (σ) Bond: This type of covalent bond is formed by the head-on overlapping of two atomic orbitals along the internuclear axis.

1. s-s Overlapping: The two half-filled s-orbitals of the two atoms overlap along the internuclear axis.

1. s-p Overlapping: The half-filled s-orbital of one atom overlaps with the half-filled p-orbital of another atom along the internuclear axis.

1. p-p Overlapping: The half-filled p-orbital of one atom overlaps with the half-filled p-orbital of another atom along the internuclear axis.

• Pi (π) Bond:  This type of covalent bond is formed by the lateral or sidewise overlapping of two atomic orbitals perpendicular to the internuclear axis.

### Strength of Sigma (σ) and pi(π) Bond:

• Sigma (σ) bond is formed by the head-on overlapping whereas the pi (π) bond is formed by sideways overlapping of the orbital.

• The extent of overlapping is greater in the sigma (σ) bond than in pi (π) bond. Therefore, the strength of the sigma (σ)bond is more than the pi (π) bond.

• In multiple bonds between the atoms, pi bonds are formed in addition to the presence of sigma bonds.

### Molecular Orbital Theory (MOT):

• According to MOT, the atomic orbital of the atoms combines with a linear combination of atomic orbital (LCAO) to form the molecular orbitals.

• The addition of atomic orbital gives rise to the bonding molecular orbital whereas the subtraction of atomic orbitals gives rise to the antibonding molecular orbital. The antibonding MOs are represented by (*) and they have more energy than bonding MOs.

ψMO =  ψA   ±  ψB

Bonding MOs:            σ 2s,  σ2pz, π2py, π2px

Antibonding MOs:    σ* 2s,  σ*2pz,  π*2py  π*2px

Electronic Configuration of Molecule:

The distribution of electrons in the orbital of molecules in the increasing order of energy is known as the electronic configuration of molecules.

• The electronic configuration of molecules which have more than 14 electrons such as O2 has 16 electron, have electronic configuration as follows:

σ 1s2,  σ* 1s2, σ 2s2,  σ* 2s2, σ2pz2 (π2py2=  π2px2) , (π*2py1 =π*2px1)

• The electronic configuration of molecules which have equal to or less than 14 electrons such as N2 has 14 electrons, have electronic configuration as follows:

σ 1s2,  σ* 1s2, σ 2s2,  σ* 2s2, (π2px2=  π2py2), σ2pz2

Bond Order:

Bond order is half of the difference of the electrons in bonding orbital and antibonding orbitals.

B.O.  =  ½ (Nb - Na)

where, Nb = Total number of electrons in bonding orbital

Na = Total number of electrons in antibonding orbital

Example : O2

B.O. (O2)= (10 - 6)/2  =  4/2  =  2

The O2 molecule has 2 bonds between each O atom.

Magnetic Properties:

The molecule is said to be diamagnetic if all the electrons in the molecular orbitals are paired. The molecule is said to be paramagnetic if the electron has at least one unpaired electron in the molecular orbital.

Example: O2 molecule is a paramagnetic in nature as it has 2 unpaired electrons in each in the  π*2py1 and  π*2px1

Spin only magnetic moment can be calculated by the formula:

μs = $\sqrt{n\left(n+2\right)}$$\sqrt{n(n + 2)}$

where,  n : Number of unpaired electrons

### Hydrogen Bonding:

When the highly electronegative elements such as fluorine, nitrogen and oxygen, are bonded covalently with the H atom, the electron of a hydrogen atom is slightly shifted towards the highly electronegative atom, which develops a partial positive charge on H atom. The partial positive charged hydrogen atom is attracted towards the electronegative atom causing hydrogen bonding.

There are two types of hydrogen bonding:

• Intermolecular Hydrogen Bonding: The hydrogen bonding is formed between two molecules of the same or different compounds.

Example: H2O, HF

Hδ+-Fδ-……Hδ+-Fδ-…Hδ+-Fδ-…Hδ+-Fδ-

• Intramolecular Hydrogen Bonding: The hydrogen bonding is formed when the highly electronegative (O, F, N) atom in the molecule is attracted to the hydrogen atom bonded to the electronegative atom (O, N, F) within the molecule.

Example: o-nitrophenol

### Solved Examples From the Chapter

Example 1:  Hybridisation state of chlorine in ClF3 is :

1. sp3

2. sp3d

3. sp3d2

4. sp3d3

Solution: (b)

Bond pairs = 3, lone pairs = 2    ⇒   hybridisations = sp3d

Key Points:

Number of hybrid orbitals   =  number of bond pairs  +  number of lone pairs on central atoms

Example 2: As the s-character of hybridised orbital increases, the bond angle

1. increase

2. becomes zero

3. does not change

4. decrease

Solution:  (a) increase

The bond angle increases with increase in percentage of s character of the hybridized orbitals.

Key Points:

The factor that affects the bond angle:

• Bond angle is proportional to the electronegativity of the central atom and inversely proportional to the electronegativity of the peripheral atoms.

• Bond angle is proportional to the percentage of s character of the hybridized orbitals and inversely proportional to the percentage of p character of the hybridized orbitals.

• Bond angle is proportional to bp-bp repulsion and inversely proportional to lp-bp and lp-lp repulsion.

• Bond angle is proportional to size of peripheral atoms of molecule.

Example 3: Using MO theory, predict which of the following species has the shortest bond length?

1. O2

2. O22—

3. O22+

4. O2

Solution: (b)

• Electronic configuration of O2(17 electron): σ 1s2,  σ* 1s2, σ 2s2,  σ* 2s2, σ2pz2 (π2py2=  π2px2) , (π*2py2 =π*2px1)

B.O. = ½ (10 - 7) = 1.5

• Electronic configuration of O22—(18 electron): σ 1s2,  σ* 1s2, σ 2s2,  σ* 2s2, σ2pz2 (π2py2=  π2px2) , (π*2py2 =π*2px2)

B.O. = ½ (10 - 8) = 1

• Electronic configuration of O22+(14 electron):  σ 1s2,  σ* 1s2, σ 2s2,  σ* 2s2, (π2py2=  π2px2), σ2pz2

B.O. = ½ (10 - 4) = 3

• Electronic configuration of O2+(15 electron): σ 1s2,  σ* 1s2, σ 2s2,  σ* 2s2, σ2pz2 (π2py2=  π2px2) , (π*2py1 =π*2px)

B.O. = ½ (10 - 5) = 2.5

More the bond order, the shorter the bond length. Therefore, the bond length order is:

O22—      >           O2      >             O2+        >            O22+

Key Points:

• The electronic configuration of molecules which have more than 14 electrons such as O2 has 16 electron, have electronic configuration as follows:

σ 1s2,  σ* 1s2, σ 2s2,  σ* 2s2, σ2pz2 (π2py2=  π2px2) , (π*2py1 =π*2px1)

• The electronic configuration of molecules which have equal to or less than 14 electrons such as N2 has 14 electrons, have electronic configuration as follows:

σ 1s2,  σ* 1s2, σ 2s2,  σ* 2s2, (π2py2=  π2px2), σ2pz2

• Bond length is inversely proportional to the bond order of molecules.

### Solved Questions from the Previous Year Question Papers

Question 1: The correct set from the following in which both pairs are in correct order of melting point is :

1. LiCI > LiF;  NaCI > MgO

2. LiCI > LiF ; MgO > NaCI

3. LiF > LiCI;NaCI> MgO

4. LiF > LiCI ; MgO > NaCI

Solution: (d) More the ionic character in the bond, more will be the melting point of the compound.

According to Fajan’s rule, the bigger the cation and the smaller the anion more

will be the ionic character in the bond.

Size of anion:

F   <   Cl

Size of cation:

Mg+  >   Na+

Therefore, the correct order of melting point in the given compound:

LiF > LiCl

MgO > NaCI

Question 2: The bond order and the magnetic characteristics of CN are :

1. 3, paramagnetic

2.  2 ½ , paramagnetic

3. 3, diamagnetic

4. 2 ½ , diamagnetic

Solution: (a)  Total number of electron in CN : 6 + 7 + 1 = 14

Electronic configuration of CN(14 electron):  σ 1s2,  σ* 1s2, σ 2s2,  σ* 2s2, (π2px2=  π2py2), σ2pz2

B.O. = ½ (10 - 4) = 3

In the MOs of  CN , all the electrons are paired so the molecule is diamagnetic in nature.

Question 3: The correct statement about ICl5 and ICl4 is

1. ICl5 is square pyramidal and  ICl4 is square planar.

2. ICl5 is trigonal bipyramidal and  ICl4is tetrahedral.

3. ICl5 is square pyramidal and  ICl4 is tetrahedral

4. Both are isostructural.

Solution:  (a)    ICl5 : 5 bond pairs + 1 lone pairs ⟶ sp3d2 hybridisation ⇒   Geometry: octahedral;   Shape :  square pyramidal

ICl4: 4 bond pairs + 2 lone pairs ⟶ sp3d2 hybridisation ⇒  Geometry: Octahedral; Shape :  Square planar shape

### Practice Questions

Question 1:  The bond order and magnetic behaviour of O2 ion are respectively :

1. 1.5 and paramagnetic

2. 1.5 and diamagnetic

3. 2 and diamagnetic

4. 1 and paramagnetic

Question 2: The ion that has sp3d2 hybridisation of the central atom:

are:

1. [ICl2]

2. [ICl4]

3. [IF6]

4. [BrF2]

### Conclusion:

It is concluded from various theories that the valence shell electrons assist in the bond creation either by sharing electrons or by transferring electrons, according to various theories. The ionic bond generated by electron transfer has some covalent character that can be quantified by Fajan's rule, whereas the covalent bond formed by exchanging electrons has some ionic character.

The topics of chemical bonding and molecular structure are relevant for the JEE competitive examination. This chapter of the examination has a wide range of questions, including easy, medium, and difficult ones. For the purposes of the examination, this article includes all of the significant and important issues.

See More

## JEE Main Important Dates

View all JEE Main Exam Dates
JEE Main 2023 January and April Session exam dates and revised schedule have been announced by the NTA. JEE Main 2023 January and April Session will now be conducted on 24-Jan-2023 to 31-Jan-2023 and 6-Apr-2023 to 12-Apr-2023, and the exam registration closes on 12-Jan-2023 and Apr-2023. You can check the complete schedule on our site. Furthermore, you can check JEE Main 2023 dates for application, admit card, exam, answer key, result, counselling, etc along with other relevant information.
See More
View all JEE Main Exam Dates

## JEE Main Information

Application Form
Eligibility Criteria
Reservation Policy
Exam Centres
NTA has announced the JEE Main 2023 January session application form release date on the official website https://jeemain.nta.nic.in/. JEE Main 2023 January and April session Application Form is available on the official website for online registration. Besides JEE Main 2023 January and April session application form release date, learn about the application process, steps to fill the form, how to submit, exam date sheet etc online. Check our website for more details. April Session's details will be updated soon by NTA.

## JEE Main Syllabus

View JEE Main Syllabus in Detail
It is crucial for the the engineering aspirants to know and download the JEE Main 2023 syllabus PDF for Maths, Physics and Chemistry. Check JEE Main 2023 syllabus here along with the best books and strategies to prepare for the entrance exam. Download the JEE Main 2023 syllabus consolidated as per the latest NTA guidelines from Vedantu for free.
See More
View JEE Main Syllabus in Detail

## JEE Main 2023 Study Material

View all study material for JEE Main
JEE Main 2023 Study Materials: Strengthen your fundamentals with exhaustive JEE Main Study Materials. It covers the entire JEE Main syllabus, DPP, PYP with ample objective and subjective solved problems. Free download of JEE Main study material for Physics, Chemistry and Maths are available on our website so that students can gear up their preparation for JEE Main exam 2023 with Vedantu right on time.
See More
All
Mathematics
Physics
Chemistry
See All

## JEE Main Question Papers

see all
Download JEE Main Question Papers & ​Answer Keys of 2022, 2021, 2020, 2019, 2018 and 2017 PDFs. JEE Main Question Paper are provided language-wise along with their answer keys. We also offer JEE Main Sample Question Papers with Answer Keys for Physics, Chemistry and Maths solved by our expert teachers on Vedantu. Downloading the JEE Main Sample Question Papers with solutions will help the engineering aspirants to score high marks in the JEE Main examinations.
See More

View all JEE Main Important Books
In order to prepare for JEE Main 2023, candidates should know the list of important books i.e. RD Sharma Solutions, NCERT Solutions, RS Aggarwal Solutions, HC Verma books and RS Aggarwal Solutions. They will find the high quality readymade solutions of these books on Vedantu. These books will help them in order to prepare well for the JEE Main 2023 exam so that they can grab the top rank in the all India entrance exam.
See More
Maths
NCERT Book for Class 12 Maths
Physics
NCERT Book for Class 12 Physics
Chemistry
NCERT Book for Class 12 Chemistry
Physics
H. C. Verma Solutions
Maths
R. D. Sharma Solutions
Maths
R.S. Aggarwal Solutions
See All

## JEE Main Mock Tests

View all mock tests
JEE Main 2023 free online mock test series for exam preparation are available on the Vedantu website for free download. Practising these mock test papers of Physics, Chemistry and Maths prepared by expert teachers at Vedantu will help you to boost your confidence to face the JEE Main 2023 examination without any worries. The JEE Main test series for Physics, Chemistry and Maths that is based on the latest syllabus of JEE Main and also the Previous Year Question Papers.
See More

## JEE Main 2023 Cut-Off

JEE Main Cut Off
NTA is responsible for the release of the JEE Main 2023 January and April Session cut off score. The qualifying percentile score might remain the same for different categories. According to the latest trends, the expected cut off mark for JEE Main 2023 January and April Session is 50% for general category candidates, 45% for physically challenged candidates, and 40% for candidates from reserved categories. For the general category, JEE Main qualifying marks for 2021 ranged from 87.8992241 for general-category, while for OBC/SC/ST categories, they ranged from 68.0234447 for OBC, 46.8825338 for SC and 34.6728999 for ST category.
See More

## JEE Main 2023 Results

NTA will release the JEE Main 2023 January and April sessions exam dates on the official website, i.e. {official-website}. Candidates can directly check the date sheet on the official website or https://jeemain.nta.nic.in/. JEE Main 2023 January and April sessions is expected to be held in February and May. Visit our website to keep updates of the respective important events of the national entrance exam.
See More
Rank List
Counselling
Cutoff
JEE Main 2023 state rank lists will be released by the state counselling committees for admissions to the 85% state quota and to all seats in IIT colleges. JEE Main 2023 state rank lists are based on the marks obtained in entrance exams. Candidates can check the JEE Main 2023 state rank list on the official website or on our site.

## JEE Top Colleges

View all JEE Main 2023 Top Colleges
Want to know which Engineering colleges in India accept the JEE Main 2023 scores for admission to Engineering? Find the list of Engineering colleges accepting JEE Main scores in India, compiled by Vedantu. There are 1622 Colleges that are accepting JEE Main. Also find more details on Fees, Ranking, Admission, and Placement.
See More

## FAQs on JEE Chapter- Chemical Bonding and Molecular Structure

FAQ

1. Is the chemical bonding chapter important for JEE main?

Yes, chemical bonding is an important chapter for JEE main exam as the questions appearing in the examination paper are of easy level in terms of difficulty. The 2-3  questions from this chapter come in the exam papers.

2. What are the important topics in chemical bonding for JEE main?

The important topics in chemical bonding for JEE main are:

• Lewis dot structures

• Fajan’s rule

• Valence Shell Electron Pair Repulsion (VSEPR) theory

• Resonance Structure

• Molecular Orbital Theory (MOT)

• Magnetic Properties of molecules

• Dipole Moment

• Hydrogen bonding

3. Is chemical bonding there in JEE main?

Yes, chemical bonding is an important topic even for JEE main as it is the basis for the important chapters and topics of chemistry.

## JEE Main Upcoming Dates

Vedantu offers free live Master Classes for CBSE Class 6 to 12, ICSE, JEE Main, JEE 2023, & more by India’s best teachers. Learn all the important concepts concisely along with amazing tricks to score high marks in your class and other competitive exams.
See More
JEE Main Exam April Session Starts
06 May 202335 days remaining
JEE Main Exam April Session Ends
12 May 202341 days remaining

JEE News
JEE Blogs