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Hint:$NaHS{O_3}$ is known as sodium bisulfite or sodium hydrogen sulphite. It is a crystalline solid which is white in colour and it smells like rotten eggs. $NaHS{O_3}$ reacts with organic compounds containing carbonyl groups giving Addition products.
Complete step by step answer:
Sodium Bisulphite reacts with carbonyl compounds majorly with aldehydes and ketones having a small aliphatic chain. It generally does not react with aromatic ketones due to steric hindrance posed by the large sized benzene ring.
The addition of sodium bisulphite is a nucleophilic addition. It breaks into its constituent ions, that are, sodium cation and hydrogen sulphite anion. The anion acts as the nucleophile and attacks the carbonyl carbon which is electrophilic in nature. An alkoxide intermediate is formed having a tetrahedral shape. Finally, intermolecular proton transfer takes place in the compound from the bisulphite group to the oxygen atom giving the final addition product.
Bisulphite ion is large in size and thus faces high steric hindrance if larger substituent groups are present on the carbonyl carbon. Thus, the reaction preferably takes place in case of aldehydes and methyl ketones.
In option A, we have an aldehyde.
In option B and D, we have methyl ketones.
While in option C, The given ketone has two Ethyl groups attached to it. The incoming nucleophile faces higher steric hindrance and reaction does not take place.
Thus, the correct answer is C.
Note:
The reaction of sodium bisulfite with carbonyl compounds occurs from the Sulphur atom and not the oxygen. Sulphur is less electronegative than oxygen and thus has a higher tendency to donate electrons. As a result, it is a better nucleophile as compared to oxygen.
Complete step by step answer:
Sodium Bisulphite reacts with carbonyl compounds majorly with aldehydes and ketones having a small aliphatic chain. It generally does not react with aromatic ketones due to steric hindrance posed by the large sized benzene ring.
The addition of sodium bisulphite is a nucleophilic addition. It breaks into its constituent ions, that are, sodium cation and hydrogen sulphite anion. The anion acts as the nucleophile and attacks the carbonyl carbon which is electrophilic in nature. An alkoxide intermediate is formed having a tetrahedral shape. Finally, intermolecular proton transfer takes place in the compound from the bisulphite group to the oxygen atom giving the final addition product.
Bisulphite ion is large in size and thus faces high steric hindrance if larger substituent groups are present on the carbonyl carbon. Thus, the reaction preferably takes place in case of aldehydes and methyl ketones.
In option A, we have an aldehyde.
In option B and D, we have methyl ketones.
While in option C, The given ketone has two Ethyl groups attached to it. The incoming nucleophile faces higher steric hindrance and reaction does not take place.
Thus, the correct answer is C.
Note:
The reaction of sodium bisulfite with carbonyl compounds occurs from the Sulphur atom and not the oxygen. Sulphur is less electronegative than oxygen and thus has a higher tendency to donate electrons. As a result, it is a better nucleophile as compared to oxygen.
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