Answer
Verified
393.9k+ views
Hint: A chemical compound, which comprises boron and hydrogen and has a chemical formula of ${B_2}{H_6}$ is diborane. It has no color, and a pyrophoric gas. Other names of diborane are bromoethane, diboron hexahydride and boron hydride. The molecular mass of diborane is $27.67\,g/mol.$
Complete step by step answer:
Based on the molecular orbital theory, the hybridization on each of the two boron atoms is $s{p^3}.$ Of the four orbitals that are hybrid, three orbitals have one electron each whereas the fourth orbital is empty. Two of the four orbitals of each boron atom overlap with two end hydrogen atoms producing two normal B-H sigma bonds. One of the remaining hybrid orbital of one of the boron atoms, 1s orbital of hydrogen atoms and one of hybrid orbitals of the other boron atoms overlap to give a delocalized orbital casing the three nuclei with a pair of electrons. Such a bond is called a three center two electron $\left( {3C - 2e} \right)$ bond.
We can draw the structure of diborane as,
From the structure of diborane, we can see that four atoms of hydrogen are attached to atoms of boron by means of covalent bond. Hence, there are four 2-centered 2-electron bonds.
We can see that two hydrogen atoms are linked via bridges, and it is linked to two atoms of boron. Hence, there are two 3-centered-2-electron bonds.
$\left( {H - B} \right)\xrightarrow{{}}2C - 2e$ bonds
$\left( {B - H - B} \right)\xrightarrow{{}}3C - 2e$ bonds
The 3C-2e bond is also known as banana bond.
$\therefore $Option (D) is correct.
Note:
We know that diborane is flammable gas at room temperature. It has a sweet odor. Diborane on combustion releases a large amount of energy. It can be prepared by the reaction of metal hydride with boron. It reacts with methanol to form trimethyl borate. We can use diborane as propellant in a rocket, used in production of borophosphosilicate, used as a reducing agent. It could act as catalyst and as rubber vulcanizer in polymerization reactions. It is used as a doping agent in manufacturing semiconductor devices.
Complete step by step answer:
Based on the molecular orbital theory, the hybridization on each of the two boron atoms is $s{p^3}.$ Of the four orbitals that are hybrid, three orbitals have one electron each whereas the fourth orbital is empty. Two of the four orbitals of each boron atom overlap with two end hydrogen atoms producing two normal B-H sigma bonds. One of the remaining hybrid orbital of one of the boron atoms, 1s orbital of hydrogen atoms and one of hybrid orbitals of the other boron atoms overlap to give a delocalized orbital casing the three nuclei with a pair of electrons. Such a bond is called a three center two electron $\left( {3C - 2e} \right)$ bond.
We can draw the structure of diborane as,
From the structure of diborane, we can see that four atoms of hydrogen are attached to atoms of boron by means of covalent bond. Hence, there are four 2-centered 2-electron bonds.
We can see that two hydrogen atoms are linked via bridges, and it is linked to two atoms of boron. Hence, there are two 3-centered-2-electron bonds.
$\left( {H - B} \right)\xrightarrow{{}}2C - 2e$ bonds
$\left( {B - H - B} \right)\xrightarrow{{}}3C - 2e$ bonds
The 3C-2e bond is also known as banana bond.
$\therefore $Option (D) is correct.
Note:
We know that diborane is flammable gas at room temperature. It has a sweet odor. Diborane on combustion releases a large amount of energy. It can be prepared by the reaction of metal hydride with boron. It reacts with methanol to form trimethyl borate. We can use diborane as propellant in a rocket, used in production of borophosphosilicate, used as a reducing agent. It could act as catalyst and as rubber vulcanizer in polymerization reactions. It is used as a doping agent in manufacturing semiconductor devices.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred
What is the stopping potential when the metal with class 12 physics JEE_Main
The momentum of a photon is 2 times 10 16gm cmsec Its class 12 physics JEE_Main
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Summary of the poem Where the Mind is Without Fear class 8 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Write an application to the principal requesting five class 10 english CBSE
What organs are located on the left side of your body class 11 biology CBSE
What is the z value for a 90 95 and 99 percent confidence class 11 maths CBSE