
If the rate of ghee increases by ${\text{Rs}}.30\;{\text{per}}\;{\text{kg}}$, one would receive $1\;{\text{kg}}$ ghee less for ${\text{Rs}}.900$. Find the original rate of ghee per kg.
Answer
232.8k+ views
Hint:Choose variables to represent unknown, write down the equation for the given problem in terms of assumed unknown and solve the equation to find the value of the original rate of ghee per kilogram.
Complete step by step solution:
A word problem is a mathematical practice where significant information on the problem is presented in ordinary form rather than in mathematical expression. A word problem is a maths question written as one sentence or more that requires children to apply their maths knowledge to a real-life scenario.
The easiest way to solve the word problem is to represent unknown numbers with variables, translate the rest of the word problem into a mathematical expression and finally solve the problem. Word problem is a technique of thinking how to determine the problem and solve it.
Let $x$ be the original rate of ghee.
Then,
According to question,
The new rate of ghee is ${\text{Rs}}.\left( {x + 30} \right)\;{\text{per}}\;{\text{kg}}$……..(1)
The original rate of ghee for ${\text{Rs}}.900$is $\dfrac{{900}}{x}\;{\text{kg}}$………(2)
The new quantity of ghee at new price is $\dfrac{{900}}{{x + 30}}\;{\text{kg}}$………(3)
Now, one would receive $1\;{\text{kg}}$of ghee for ${\text{Rs}}.900$.
Thus, the new quantity of ghee is equal to the original quantity of ghee minus one.
Therefore,$\dfrac{{900}}{{x + 30}} = \dfrac{{900}}{x} - 1$……..(4).
Solve the above equation as,
$
{x^2} + 30x - 2700 = 0 \\
\left( {x + 180} \right)\left( {x - 150} \right) = 0 \\
x + 180 = 0 \\
x - 150 = 0 \\
$
Substitute both the phrases equals to zero,
$
x = - 180 \\
x = 150 \\
$
It is known that the rate cannot be negative. Therefore, the original rate of ghee is $x = 150$.
Hence, the option B is correct.
Note:On solving the word problems always be careful where you need to take the English words and solve them into mathematics. These types of questions are always based on representing the unknown numbers with variables on the given information.
Complete step by step solution:
A word problem is a mathematical practice where significant information on the problem is presented in ordinary form rather than in mathematical expression. A word problem is a maths question written as one sentence or more that requires children to apply their maths knowledge to a real-life scenario.
The easiest way to solve the word problem is to represent unknown numbers with variables, translate the rest of the word problem into a mathematical expression and finally solve the problem. Word problem is a technique of thinking how to determine the problem and solve it.
Let $x$ be the original rate of ghee.
Then,
According to question,
The new rate of ghee is ${\text{Rs}}.\left( {x + 30} \right)\;{\text{per}}\;{\text{kg}}$……..(1)
The original rate of ghee for ${\text{Rs}}.900$is $\dfrac{{900}}{x}\;{\text{kg}}$………(2)
The new quantity of ghee at new price is $\dfrac{{900}}{{x + 30}}\;{\text{kg}}$………(3)
Now, one would receive $1\;{\text{kg}}$of ghee for ${\text{Rs}}.900$.
Thus, the new quantity of ghee is equal to the original quantity of ghee minus one.
Therefore,$\dfrac{{900}}{{x + 30}} = \dfrac{{900}}{x} - 1$……..(4).
Solve the above equation as,
$
{x^2} + 30x - 2700 = 0 \\
\left( {x + 180} \right)\left( {x - 150} \right) = 0 \\
x + 180 = 0 \\
x - 150 = 0 \\
$
Substitute both the phrases equals to zero,
$
x = - 180 \\
x = 150 \\
$
It is known that the rate cannot be negative. Therefore, the original rate of ghee is $x = 150$.
Hence, the option B is correct.
Note:On solving the word problems always be careful where you need to take the English words and solve them into mathematics. These types of questions are always based on representing the unknown numbers with variables on the given information.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding the Electric Field of a Uniformly Charged Ring

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions For Class 11 Maths Chapter 12 Limits and Derivatives (2025-26)

NCERT Solutions For Class 11 Maths Chapter 10 Conic Sections (2025-26)

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

Understanding Electromagnetic Waves and Their Importance

