
If arithmetic mean of two positive numbers is \[A\], their geometric mean is \[G\] and harmonic mean is \[H\], and then \[H\] is equal to
A. \[\frac{{{G^2}}}{A}\]
B. \[\frac{G}{{{A^2}}}\]
C. \[\frac{{{A^2}}}{G}\]
D. \[\frac{A}{{{G^2}}}\]
Answer
233.1k+ views
HINT:
We must use formulas for various types of means when answering questions of this nature. We are aware that the arithmetic mean (AM), geometric mean (GM), and harmonic mean are the three Pythagorean means (HM). Additionally, we are aware that the Arithmetic Mean (AM) equals \[\frac{{a + b}}{2}\], the Geometric Mean (GM) equals \[\sqrt {ab} \] and the Harmonic Mean (HM) equals \[\frac{{2ab}}{{(a + b)}}\] if a and b are two positive numbers.
Formula use:
if a and b are two positive numbers.
the Geometric Mean (GM) equals \[\sqrt {ab} \]
Arithmetic Mean (AM) equals \[\frac{{a + b}}{2}\]
Harmonic Mean (HM) equals \[\frac{{2ab}}{{(a + b)}}\]
Complete step-by-step solution
Now, we have to determine the relationship between the arithmetic, geometric, and harmonic means of two different positive real numbers denoted by \[A,G,H\] respectively.
Assuming that a and b are the two separate positive real numbers, we have
Arithmetic mean as,
\[ \Rightarrow AM = A = \frac{{(a + b)}}{2}\]
We have geometric mean as,
\[ \Rightarrow GM = G = \sqrt {ab} \]
We have Harmonic mean as,
\[ \Rightarrow HM = H = \frac{{2ab}}{{(a + b)}}\]
Thus, from the previous calculations, it is understood that,
\[ = \frac{{{G^2}}}{A}\]
We can prove that by substituting the values of \[G\] and \[A\] in the above formula, we get
\[ = \frac{{{{\left( {\sqrt {ab} } \right)}^2}}}{{\frac{{a + b}}{2}}}\]
Now, we have to apply the fraction rule \[\frac{a}{{\frac{b}{c}}} = \frac{{a \cdot c}}{b}\]:
\[ = \frac{{{{\left( {\sqrt {ab} } \right)}^2} \cdot 2}}{{a + b}}\]
On applying exponent rule \[{\left( {\sqrt {ab} } \right)^2} = ab\], we get
\[ = \frac{{ab \cdot 2}}{{a + b}}\]
Now, we have to rewrite the above expression, we get
\[ = \frac{{2ab}}{{a + b}}\]
Therefore, the value of \[H\] is equal to \[\frac{{{G^2}}}{A}\]
Hence, the option A is correct.
NOTE:
Students must be able to recall the arithmetic mean, geometric mean, and harmonic mean formulas for this type of question. When the distinction between GM and HM as well as between AM and GM is simplified, students must exercise caution. Students should also be aware that both differences are obviously greater than or equal to zero because they take the form of squares.
We must use formulas for various types of means when answering questions of this nature. We are aware that the arithmetic mean (AM), geometric mean (GM), and harmonic mean are the three Pythagorean means (HM). Additionally, we are aware that the Arithmetic Mean (AM) equals \[\frac{{a + b}}{2}\], the Geometric Mean (GM) equals \[\sqrt {ab} \] and the Harmonic Mean (HM) equals \[\frac{{2ab}}{{(a + b)}}\] if a and b are two positive numbers.
Formula use:
if a and b are two positive numbers.
the Geometric Mean (GM) equals \[\sqrt {ab} \]
Arithmetic Mean (AM) equals \[\frac{{a + b}}{2}\]
Harmonic Mean (HM) equals \[\frac{{2ab}}{{(a + b)}}\]
Complete step-by-step solution
Now, we have to determine the relationship between the arithmetic, geometric, and harmonic means of two different positive real numbers denoted by \[A,G,H\] respectively.
Assuming that a and b are the two separate positive real numbers, we have
Arithmetic mean as,
\[ \Rightarrow AM = A = \frac{{(a + b)}}{2}\]
We have geometric mean as,
\[ \Rightarrow GM = G = \sqrt {ab} \]
We have Harmonic mean as,
\[ \Rightarrow HM = H = \frac{{2ab}}{{(a + b)}}\]
Thus, from the previous calculations, it is understood that,
\[ = \frac{{{G^2}}}{A}\]
We can prove that by substituting the values of \[G\] and \[A\] in the above formula, we get
\[ = \frac{{{{\left( {\sqrt {ab} } \right)}^2}}}{{\frac{{a + b}}{2}}}\]
Now, we have to apply the fraction rule \[\frac{a}{{\frac{b}{c}}} = \frac{{a \cdot c}}{b}\]:
\[ = \frac{{{{\left( {\sqrt {ab} } \right)}^2} \cdot 2}}{{a + b}}\]
On applying exponent rule \[{\left( {\sqrt {ab} } \right)^2} = ab\], we get
\[ = \frac{{ab \cdot 2}}{{a + b}}\]
Now, we have to rewrite the above expression, we get
\[ = \frac{{2ab}}{{a + b}}\]
Therefore, the value of \[H\] is equal to \[\frac{{{G^2}}}{A}\]
Hence, the option A is correct.
NOTE:
Students must be able to recall the arithmetic mean, geometric mean, and harmonic mean formulas for this type of question. When the distinction between GM and HM as well as between AM and GM is simplified, students must exercise caution. Students should also be aware that both differences are obviously greater than or equal to zero because they take the form of squares.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding the Electric Field of a Uniformly Charged Ring

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions For Class 11 Maths Chapter 12 Limits and Derivatives (2025-26)

NCERT Solutions For Class 11 Maths Chapter 10 Conic Sections (2025-26)

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

Understanding Electromagnetic Waves and Their Importance

