Answer
Verified
394.8k+ views
Hint: The fusion of an organic compound with metallic sodium for testing nitrogen, sulphur and halogens is known as Lassaigne’s test and it is a general test for detection of nitrogen, sulphur and halogens. This test is also known as sodium fusion test and it is primarily used for qualitative analysis of various elements.
Complete step by step answer:
The elements such as halogens, nitrogen and sulphur are covalently bonded to the organic compounds. For their detection, we need to convert them to their ionic form for performing respective tests for their detection. As per principle, on fusion Na converts all elements present in an organic compound in ionic form. The ionic salts formed are extracted by boiling with distilled water and the process is known as sodium fusion extraction.
\[
{Na + C + N \to {\text{ }}NaCN} \\
{2Na + S \to {\text{ }}Na_2S}
Na + X \to NaX\left( {X = Cl,{\text{ }}Br,{\text{ }}or{\text{ }}I} \right) \\
\]
For testing nitrogen,
The extract is converted to sodium ferrocyanide by heating with ferrous sulphate and acidified with concentrated $H_2SO_4$. The presence Prussian blue precipitate of ferric ferrocyanide indicates the presence of nitrogen. The reactions occur,
\[6NaCN{\text{ }} + {\text{ }}FeS{O_4} \to {\text{ }}N{a_4}\left[ {Fe{{\left( {CN} \right)}_6}} \right]{\text{ }} + {\text{ }}N{a_2}S{O_4}\]
Here, the formula for Sodium ferrocyanide is \[N{a_4}\left[ {Fe{{\left( {CN} \right)}_6}} \right]\]
\[N{a_4}\left[ {Fe{{\left( {CN} \right)}_6}} \right] + {\text{ }}F{e^3}^ + \to F{e_4}{\left[ {Fe{{\left( {CN} \right)}_6}} \right]_3}\]
Here, the formula for Ferric ferrocyanide is \[F{e_4}{\left[ {Fe{{\left( {CN} \right)}_6}} \right]_3}\]
For testing Sulphur,
Sulphide ions are tested using sodium nitroprusside. The appearance of violet colour indicates presence of sulphur.
Below is the reaction that occurs
\[
N{a_2}S{\text{ }} + {\text{ }}N{a_2}\left[ {Fe{{\left( {CN} \right)}_5}NO} \right]\; \to \;N{a_4}\left[ {Fe{{\left( {CN} \right)}_5}NOS} \right] \\
{\text{}}(Sodium{\text{ }}nitroprusside){\text{}}(violet{\text{ }}colour) \\
\]
For testing halogens,
For the case of testing extract for the presence of halogens such as Cl, Br, I we will add silver nitrate solution after acidifying with dil. $HNO_3$ to it. A yellowish white precipitate sparingly soluble in ammonium hydroxide $(NH_4OH)$ indicates presence of Bromine(Br), yellowish precipitate insoluble in ammonium hydroxide $(NH_4OH)$ indicates presence of Iodine(I), White precipitate soluble in $(NH_4OH)$ indicates presence of Chlorine.
Note:
We only need to use sodium fusing with organic compounds as the resultant sodium compounds are soluble in water. If we discuss the use of potassium in place of sodium for fusion then the resultant compounds are insoluble in water and hence, the test is impossible to proceed.
Complete step by step answer:
The elements such as halogens, nitrogen and sulphur are covalently bonded to the organic compounds. For their detection, we need to convert them to their ionic form for performing respective tests for their detection. As per principle, on fusion Na converts all elements present in an organic compound in ionic form. The ionic salts formed are extracted by boiling with distilled water and the process is known as sodium fusion extraction.
\[
{Na + C + N \to {\text{ }}NaCN} \\
{2Na + S \to {\text{ }}Na_2S}
Na + X \to NaX\left( {X = Cl,{\text{ }}Br,{\text{ }}or{\text{ }}I} \right) \\
\]
For testing nitrogen,
The extract is converted to sodium ferrocyanide by heating with ferrous sulphate and acidified with concentrated $H_2SO_4$. The presence Prussian blue precipitate of ferric ferrocyanide indicates the presence of nitrogen. The reactions occur,
\[6NaCN{\text{ }} + {\text{ }}FeS{O_4} \to {\text{ }}N{a_4}\left[ {Fe{{\left( {CN} \right)}_6}} \right]{\text{ }} + {\text{ }}N{a_2}S{O_4}\]
Here, the formula for Sodium ferrocyanide is \[N{a_4}\left[ {Fe{{\left( {CN} \right)}_6}} \right]\]
\[N{a_4}\left[ {Fe{{\left( {CN} \right)}_6}} \right] + {\text{ }}F{e^3}^ + \to F{e_4}{\left[ {Fe{{\left( {CN} \right)}_6}} \right]_3}\]
Here, the formula for Ferric ferrocyanide is \[F{e_4}{\left[ {Fe{{\left( {CN} \right)}_6}} \right]_3}\]
For testing Sulphur,
Sulphide ions are tested using sodium nitroprusside. The appearance of violet colour indicates presence of sulphur.
Below is the reaction that occurs
\[
N{a_2}S{\text{ }} + {\text{ }}N{a_2}\left[ {Fe{{\left( {CN} \right)}_5}NO} \right]\; \to \;N{a_4}\left[ {Fe{{\left( {CN} \right)}_5}NOS} \right] \\
{\text{}}(Sodium{\text{ }}nitroprusside){\text{}}(violet{\text{ }}colour) \\
\]
For testing halogens,
For the case of testing extract for the presence of halogens such as Cl, Br, I we will add silver nitrate solution after acidifying with dil. $HNO_3$ to it. A yellowish white precipitate sparingly soluble in ammonium hydroxide $(NH_4OH)$ indicates presence of Bromine(Br), yellowish precipitate insoluble in ammonium hydroxide $(NH_4OH)$ indicates presence of Iodine(I), White precipitate soluble in $(NH_4OH)$ indicates presence of Chlorine.
Note:
We only need to use sodium fusing with organic compounds as the resultant sodium compounds are soluble in water. If we discuss the use of potassium in place of sodium for fusion then the resultant compounds are insoluble in water and hence, the test is impossible to proceed.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred
What is the stopping potential when the metal with class 12 physics JEE_Main
The momentum of a photon is 2 times 10 16gm cmsec Its class 12 physics JEE_Main
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Summary of the poem Where the Mind is Without Fear class 8 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Write an application to the principal requesting five class 10 english CBSE
What organs are located on the left side of your body class 11 biology CBSE
What is the z value for a 90 95 and 99 percent confidence class 11 maths CBSE