Answer
Verified
375k+ views
Hint: Permanent hardness cannot be removed by simple boiling, whereas temporary hardness can be removed by simple boiling.
-To calculate the temporary and permanent hardness of a sample we need to calculate the total number of moles of calcium and magnesium, which is present in the ions of salt.
Complete step by step answer:
The most commonly observed difference between soft and hard water is that hard water reacts with soap in order to form scum of solid soap, which is nothing but the white lather type substance which forms as a precipitate, due to presence of calcium and magnesium ions in the hard water, and soft water does not form scum of soap. The formation of soap scum on your skin is the main reason behind the fact that it is easier to rinse from your body while using soap, when you shower with hard water.
Hardness in water is produced due to the presence of magnesium ions, calcium ions or both. With increase in concentrations of magnesium ions, calcium ions or both, hardness of water also increases. The combined concentration of magnesium and calcium observed in a Solution is frequently referred to as total hardness.
When hard water is exposed to a higher temperature or in other words when it is boiled in the presence of bicarbonate \[{{\left( HC{{O}_{3}} \right)}^{}}\] or carbonate \[{{\left( C{{O}_{3}} \right)}^{2-}}\] the magnesium and/or calcium ions react with the bicarbonate and carbonate ions in order to form solid magnesium carbonate, calcium carbonate, or both.
Temporary hardness is generally more complex, because concentration of it is a function of the concentration of carbonates in relation to their reaction with calcium in magnesium.
Permanent hardness is a type of hardness which simply cannot be removed by boiling of water.
According to the question,
mole of \[Ca{{\left( HC{{O}_{3}} \right)}_{2}}=\dfrac{162\times {{10}^{-3}}mg}{162g/mole}=1\times {{10}^{-3}}moles\]
Mole of \[Ca\left( S{{O}_{4}} \right)=\dfrac{136\times {{10}^{-3}}g}{136g/mole}=1\times {{10}^{3}}mole\]
We know that total mole of \[Ca=2\times {{10}^{-3}}mole\]
which means mass of \[CaC{{O}_{3}}=2\times {{10}^{-3}}\times 100=0.2g\]
∴ ppm (permanent hardness) \[=\dfrac{6.2\times {{10}^{6}}}{1000}=200ppm\]
Now we will calculate mole of \[MgC{{l}_{2}}=\dfrac{95\times {{10}^{-3}}}{95}=1\times {{10}^{-3}}mole~\]
Mole \[Mg~=\dfrac{73\times {{10}^{-3}}}{146}=5\times {{10}^{-4}}mole\]
hence, mole \[Mg~=1.5\times {{10}^{-4}}mole\]
Mole of \[CaC{{O}_{3}}\] (In terms of mg) \[=1.5\times {{10}^{-3}}\]
mass \[=1.5\times {{10}^{-3}}=0.150g\]
therefore, ppm (temporary hardness) \[=\dfrac{0.150\times 106}{100}=150ppm\]
Since the temporary and permanent hardness of water are \[150ppm\text{ },200ppm\] respectively.
So the correct option is C.
Note: The extent of permanent and temporary hardness can be calculated by simply calculating the number of moles of calcium and magnesium present in the sample Solution which contains calcium bicarbonate, calcium sulphate as well as magnesium bicarbonate and magnesium chloride along with sodium chloride whose values where provided in the question.
-To calculate the temporary and permanent hardness of a sample we need to calculate the total number of moles of calcium and magnesium, which is present in the ions of salt.
Complete step by step answer:
The most commonly observed difference between soft and hard water is that hard water reacts with soap in order to form scum of solid soap, which is nothing but the white lather type substance which forms as a precipitate, due to presence of calcium and magnesium ions in the hard water, and soft water does not form scum of soap. The formation of soap scum on your skin is the main reason behind the fact that it is easier to rinse from your body while using soap, when you shower with hard water.
Hardness in water is produced due to the presence of magnesium ions, calcium ions or both. With increase in concentrations of magnesium ions, calcium ions or both, hardness of water also increases. The combined concentration of magnesium and calcium observed in a Solution is frequently referred to as total hardness.
When hard water is exposed to a higher temperature or in other words when it is boiled in the presence of bicarbonate \[{{\left( HC{{O}_{3}} \right)}^{}}\] or carbonate \[{{\left( C{{O}_{3}} \right)}^{2-}}\] the magnesium and/or calcium ions react with the bicarbonate and carbonate ions in order to form solid magnesium carbonate, calcium carbonate, or both.
Temporary hardness is generally more complex, because concentration of it is a function of the concentration of carbonates in relation to their reaction with calcium in magnesium.
Permanent hardness is a type of hardness which simply cannot be removed by boiling of water.
According to the question,
mole of \[Ca{{\left( HC{{O}_{3}} \right)}_{2}}=\dfrac{162\times {{10}^{-3}}mg}{162g/mole}=1\times {{10}^{-3}}moles\]
Mole of \[Ca\left( S{{O}_{4}} \right)=\dfrac{136\times {{10}^{-3}}g}{136g/mole}=1\times {{10}^{3}}mole\]
We know that total mole of \[Ca=2\times {{10}^{-3}}mole\]
which means mass of \[CaC{{O}_{3}}=2\times {{10}^{-3}}\times 100=0.2g\]
∴ ppm (permanent hardness) \[=\dfrac{6.2\times {{10}^{6}}}{1000}=200ppm\]
Now we will calculate mole of \[MgC{{l}_{2}}=\dfrac{95\times {{10}^{-3}}}{95}=1\times {{10}^{-3}}mole~\]
Mole \[Mg~=\dfrac{73\times {{10}^{-3}}}{146}=5\times {{10}^{-4}}mole\]
hence, mole \[Mg~=1.5\times {{10}^{-4}}mole\]
Mole of \[CaC{{O}_{3}}\] (In terms of mg) \[=1.5\times {{10}^{-3}}\]
mass \[=1.5\times {{10}^{-3}}=0.150g\]
therefore, ppm (temporary hardness) \[=\dfrac{0.150\times 106}{100}=150ppm\]
Since the temporary and permanent hardness of water are \[150ppm\text{ },200ppm\] respectively.
So the correct option is C.
Note: The extent of permanent and temporary hardness can be calculated by simply calculating the number of moles of calcium and magnesium present in the sample Solution which contains calcium bicarbonate, calcium sulphate as well as magnesium bicarbonate and magnesium chloride along with sodium chloride whose values where provided in the question.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred
What is the stopping potential when the metal with class 12 physics JEE_Main
The momentum of a photon is 2 times 10 16gm cmsec Its class 12 physics JEE_Main
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Fill the blanks with proper collective nouns 1 A of class 10 english CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Select the word that is correctly spelled a Twelveth class 10 english CBSE
What organs are located on the left side of your body class 11 biology CBSE
What is the z value for a 90 95 and 99 percent confidence class 11 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers