A point on parabola ${y^2} = 18x$ at which the ordinate increases at twice the rate of the abscissa is:
\[
A.\left( {\dfrac{9}{8},\dfrac{9}{2}} \right) \\
B.\left( {2, - 4} \right) \\
C.\left( {\dfrac{{ - 9}}{8},\dfrac{9}{2}} \right) \\
D.\left( {2,4} \right) \\
\]
Answer
368.4k+ views
Hint: Differentiate the given curve equation and equate with the curve equation to find the points.
Given that:
Curve equation ${y^2} = 18x$
Ordinate increases twice the abscissa
So, $\dfrac{{dy}}{{dx}} = 2$ -- (1)
Differentiating the given parabola equation we get
$
2ydy = 18dx \\
\dfrac{{dy}}{{dx}} = \dfrac{{18}}{{2y}} \\
$ --- (2)
From equation 1 and 2, we have
$
\dfrac{{18}}{{2y}} = 2 \\
y = \dfrac{9}{2} \\
$
Substituting the value of $y$ obtained in the given curve equation:
$
\Rightarrow {y^2} = 18x \\
\Rightarrow \dfrac{{81}}{4} = 18x \\
\Rightarrow x = \dfrac{9}{8} \\
$
Hence, the point is $\left( {\dfrac{9}{8},\dfrac{9}{2}} \right)$
Correct answer is option A.
Note:The following curve given in the question represents a parabola about x-axis. The parabola is the locus of points in that plane that are equidistant from both the directrix and the focus.
Given that:
Curve equation ${y^2} = 18x$
Ordinate increases twice the abscissa
So, $\dfrac{{dy}}{{dx}} = 2$ -- (1)
Differentiating the given parabola equation we get
$
2ydy = 18dx \\
\dfrac{{dy}}{{dx}} = \dfrac{{18}}{{2y}} \\
$ --- (2)
From equation 1 and 2, we have
$
\dfrac{{18}}{{2y}} = 2 \\
y = \dfrac{9}{2} \\
$
Substituting the value of $y$ obtained in the given curve equation:
$
\Rightarrow {y^2} = 18x \\
\Rightarrow \dfrac{{81}}{4} = 18x \\
\Rightarrow x = \dfrac{9}{8} \\
$
Hence, the point is $\left( {\dfrac{9}{8},\dfrac{9}{2}} \right)$
Correct answer is option A.
Note:The following curve given in the question represents a parabola about x-axis. The parabola is the locus of points in that plane that are equidistant from both the directrix and the focus.
Last updated date: 29th Sep 2023
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Total views: 368.4k
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