
A magnetic field of flux density 10T acts normal in a coil of 50 turns having $100c{m^2}$ an area. The e.m.f. induced if the coil is removed from the magnetic field in 0.1 seconds is:
A) 50V
B) 60V
C) 80V
D) 40V
Answer
233.1k+ views
Hint: The full form of EMF is electromotive force. It is defined as the electric potential that is produced by the electrochemical cell. Its unit is volt. Electromotive force is independent of the circuit resistance.
Complete step by step solution:
Given data:
The magnetic flux density, B = 10 T
N = 50 turns
Area, $A = 100c{m^2} = {10^{ - 2}}{m^2}$
Time change,dt = 0.1 sec
e. m. f induced in the coil =?
We know that $\phi = {\rm N}{\rm B}{\rm A}\cos \theta $
$\Rightarrow {\phi _1} = {\rm N}{\rm B}{\rm A}\cos \theta = NBA\cos 0 = NBA$ $\left( {\because \cos 0 = 1} \right)$
Thus substituting the values of N, B, and A we get
$\Rightarrow {\phi _1} = 50 \times 10 \times 1{0^{ - 2}} = 5Wb$
It is given that the coil is removed from the magnetic field. Then B = 0.
Hence ${\phi _2} = 0$
\[\therefore {\phi _2} - {\phi _1} = d\phi \]
\[ \Rightarrow d\phi = \left( {0 - 5} \right) = - 5Wb\]
We also know that e.m.f induces is given by the formula,
$\Rightarrow e.m.f = \dfrac{{d\phi }}{{dt}}$
$ \Rightarrow e.m.f = \dfrac{{ - 5}}{{0.1}} = 50V$
Thus the e.m.f induced in the coil is 50 V.
Hence the correct option is A.
Note: 1. Electromotive force can also be defined as the work done on the unit charge. In general, it remains constant. EMF can be negative.
2. The magnetic field, electric field, and gravitational field are caused by the electromotive force.
3. For the conversion of energy from one form to another form, in general, a battery or a generator will be used. Thus in these, one terminal will act as positively charged while the other terminal will act as negatively charged, and thus the EMF is the work done on the unit electric charge.
4. The field that passes through space thus making the magnetic force to move the electric charge is called the magnetic field. The unit of the magnetic field is Tesla.
Complete step by step solution:
Given data:
The magnetic flux density, B = 10 T
N = 50 turns
Area, $A = 100c{m^2} = {10^{ - 2}}{m^2}$
Time change,dt = 0.1 sec
e. m. f induced in the coil =?
We know that $\phi = {\rm N}{\rm B}{\rm A}\cos \theta $
$\Rightarrow {\phi _1} = {\rm N}{\rm B}{\rm A}\cos \theta = NBA\cos 0 = NBA$ $\left( {\because \cos 0 = 1} \right)$
Thus substituting the values of N, B, and A we get
$\Rightarrow {\phi _1} = 50 \times 10 \times 1{0^{ - 2}} = 5Wb$
It is given that the coil is removed from the magnetic field. Then B = 0.
Hence ${\phi _2} = 0$
\[\therefore {\phi _2} - {\phi _1} = d\phi \]
\[ \Rightarrow d\phi = \left( {0 - 5} \right) = - 5Wb\]
We also know that e.m.f induces is given by the formula,
$\Rightarrow e.m.f = \dfrac{{d\phi }}{{dt}}$
$ \Rightarrow e.m.f = \dfrac{{ - 5}}{{0.1}} = 50V$
Thus the e.m.f induced in the coil is 50 V.
Hence the correct option is A.
Note: 1. Electromotive force can also be defined as the work done on the unit charge. In general, it remains constant. EMF can be negative.
2. The magnetic field, electric field, and gravitational field are caused by the electromotive force.
3. For the conversion of energy from one form to another form, in general, a battery or a generator will be used. Thus in these, one terminal will act as positively charged while the other terminal will act as negatively charged, and thus the EMF is the work done on the unit electric charge.
4. The field that passes through space thus making the magnetic force to move the electric charge is called the magnetic field. The unit of the magnetic field is Tesla.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Understanding Uniform Acceleration in Physics

Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2025-26

Understanding Electromagnetic Waves and Their Importance

Understanding the Electric Field of a Uniformly Charged Ring

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

