
A charge q is moving in a magnetic field then the magnetic force does not depend upon
A. Charge
B. Mass
C. Velocity
D. Magnetic field
Answer
233.1k+ views
Hint: Lorentz’s law of force states that when a charged particle is moving in a region of the magnetic field, then due to interaction of the charge with the magnetic field there is force experienced by the moving charge.
Formula used:
\[\overrightarrow F = q\left( {\overrightarrow v \times \overrightarrow B } \right)\], here \[\overrightarrow F \]is the magnetic force acting on the charged particle of charge q moving with velocity \[\overrightarrow v \]in the magnetic field \[\overrightarrow B \]
Complete answer:
Let the mass of the particle is m and the charge is q.
If the magnetic field in the region is \[\overrightarrow B \] then the magnetic force acting on the particle which is moving with velocity\[\overrightarrow v \],
\[\vec F = q\left( {\vec v \times \vec B} \right)\]
Then the magnitude of the magnetic force acting on the charged particle moving in the magnetic field region is,
\[F = qvB\sin \theta \], here \[\theta \] is the angle made by the velocity with a magnetic field vector.
So, the magnetic force acting on the charge particle depends on;
- Charge on the particle
- Speed of the particle
- Magnetic field strength of the region
- The angle between the magnetic field and the velocity vector
Hence, the magnitude of the magnetic force acting on the particle is independent of the mass of the charged particle.
Therefore, the correct option is (B).
Note:The direction of the magnetic force on the charged particle depends on the nature of the charge but the magnitude of the magnetic force doesn’t depend on the nature of the charge on the particle.
Formula used:
\[\overrightarrow F = q\left( {\overrightarrow v \times \overrightarrow B } \right)\], here \[\overrightarrow F \]is the magnetic force acting on the charged particle of charge q moving with velocity \[\overrightarrow v \]in the magnetic field \[\overrightarrow B \]
Complete answer:
Let the mass of the particle is m and the charge is q.
If the magnetic field in the region is \[\overrightarrow B \] then the magnetic force acting on the particle which is moving with velocity\[\overrightarrow v \],
\[\vec F = q\left( {\vec v \times \vec B} \right)\]
Then the magnitude of the magnetic force acting on the charged particle moving in the magnetic field region is,
\[F = qvB\sin \theta \], here \[\theta \] is the angle made by the velocity with a magnetic field vector.
So, the magnetic force acting on the charge particle depends on;
- Charge on the particle
- Speed of the particle
- Magnetic field strength of the region
- The angle between the magnetic field and the velocity vector
Hence, the magnitude of the magnetic force acting on the particle is independent of the mass of the charged particle.
Therefore, the correct option is (B).
Note:The direction of the magnetic force on the charged particle depends on the nature of the charge but the magnitude of the magnetic force doesn’t depend on the nature of the charge on the particle.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding Uniform Acceleration in Physics

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2025-26

Understanding the Electric Field of a Uniformly Charged Ring

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

Understanding Electromagnetic Waves and Their Importance

