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NCERT Solutions for Class 11 Biology Chapter 17 - Breathing And Exchange Of Gases

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Solutions for NCERT Class 11 Biology Chapter 17 - Breathing and Exchange of Gases

Students appearing for CBSE Science test usually struggle with the topic of breathing and gas exchange. The NCERT Solutions for Class 11 Biology Chapter 17 Breathing and Gas Exchange ensure excellent exam outcomes. It will also inspire students to study without feeling pressed. NCERT Solutions for Class 11 Biology Chapter 17 Breathing and Gas Exchange comply to CBSE standards, making them a great resource for students wishing to flourish academically.


Class:

NCERT Solutions for Class 11

Subject:

Class 11 Biology

Chapter Name:

Chapter 17 - Breathing and Exchange of Gases

Content-Type:

Text, Videos, Images and PDF Format

Academic Year:

2024-25

Medium:

English and Hindi

Available Materials:

Chapter Wise

Other Materials

  • Important Questions

  • Revision Notes


Breathing and Exchange of Gases Chapter at a Glance - Class 11 NCERT Solutions


Breathing and Exchange of Gases


Breathing and Exchange of Gases

Competitive Exams after 12th Science

Access NCERT Solutions for Class XI Biology Chapter-17 - Breathing and Exchange of Gases

1. Define vital capacity. What is its significance?  

Ans. The vital capacity (Vc) is the maximum amount of air that a person can expel from the lungs after a maximum inspiration. The quantity of cubic inches or cubic centimetres of air that can be forcefully expelled following a full inhalation is the lungs' breathing capacity. In the human body, it is around 3.5 to 4.5 litres. 

Promotes the supply of fresh air and the removal of stale air, thus increasing the gas exchange between tissue and the environment.


2. State the volume of air remaining in the lungs after a normal breathing. 

Ans. The volume of air remaining within the lungs after a traditional expiration is understood as functional residual capacity (FRC). It comprises expiratory reserve volume (ERV) and residual volume (RV). ERV is the maximum volume of air that will be exhaled after a traditional expiration. It's about 1000 ml to 1500 ml. RV is the volume of air remaining within the lungs after maximum expiration. It's about 1100 mL to 1500 ml.

∴ = + FRC ERV RV 

≅1500 + 1500  

≅3000 mL  

The functional residual capacity of the human lungs is about 2500 – 3000 ml. 


3. Diffusion of gases occurs in the alveolar region only and not in the other parts of the respiratory system. Why?  

Ans. Each alveolus is composed of a thin, highly permeable layer of squamous cells. Blood capillaries are also composed of layers of squamous cells. The oxygen-rich air enters the human body through the nose and reaches the alveoli. The deoxygenated blood from the body is transported to the heart through a vein. The heart pumps it into the lungs to supply oxygen. The exchange of O2 and CO2 occurs between the capillaries surrounding the alveoli and the gas present in the alveoli. Therefore, the alveoli are the place for gas exchange. Due to pressure or concentration differences, gas exchange is carried out by simple diffusion.


The barrier between the alveoli and, by extension, the capillaries is extremely thin, allowing gases to diffuse from higher partial pressures to lower partial pressures. The blood that reaches the alveoli has the lower partial pressure of O2 and better partial pressure of CO2   as compared to alveolar air. Hence, oxygen gas diffuses into the blood. Simultaneously, CO2 diffuses out of the blood and into the alveoli.


4. What are the major transport mechanisms for CO2? Explain.  

Ans. Plasma and red blood cells carry carbon dioxide because they are easily soluble in water.

Through plasma:  

Approximately 7% of the CO2 is transported through the plasma in a dissolved state. Carbon dioxide will combine with the water to form carbonic acid.  

As the process of forming carbonic acid is slow, only a small amount of carbon dioxide is carried this way.  

Through RBCs:  

Approx 25% of CO 2 is transported with the help of red blood cells as carbaminohemoglobin.  Carbon dioxide will bind to the amino groups on the polypeptide chains of haemoglobin and form a compound which is known as carbaminohemoglobin.  

Through sodium bicarbonate:  

Approximately 70% of CO2 is transported within the sort of sodium bicarbonate. As CO2 diffuses into the plasma, an outsized amount of it combines with water to make acid within the presence of the enzyme carbonic anhydrase. Carbonic anhydrase is an enzyme that contains zinc that accelerates the formation of acid. This carbonic acid formed will dissociate into bicarbonate (HCO3–) and hydrogen ions (H+). 

Carbonic anhydrase CO H O 2 2 + ⎯⎯⎯⎯⎯⎯→H CO 2 3 

Carbonic H CO HCO H 2 3 anhydrase 3 ⎯⎯⎯⎯→ +− +


5. What will be the pO2and 2 pCO in the atmospheric air compared to those in the alveolar air? 

(i) pO2lesser, 2 pCOhigher  

(ii) pO2higher, 2 pCOlesser  

(iii) pO2higher, 2 pCOhigher  

(iv) pO2lesser, 2 pCOlesser 

Ans. (ii) pO2 higher, 2 pCO lesser  

The partial pressure of oxygen in atmospheric air tends to be more than the partial pressure of oxygen in alveolar air. In atmospheric air, the pO2 is approximately 159 mm Hg. In alveolar air, it's approximately 104 mm Hg. The partial pressure of CO2 in atmospheric air is lower. as CO2 within the alveolar air. In atmospheric air, the pCO2 is around 0.3 mmHg. In alveolar air, it's about 40 mm Hg.


6. Explain the process of inspiration under normal conditions. 

Ans. Inspiration, or inhalation, is the process by which air is brought into the lungs from outside the body. It's performed by creating a pressure gradient between the lungs and therefore the atmosphere. When air enters the lungs, the diaphragm expands into the abdomen, increasing the space within the thoracic cavity to accommodate the air that's inhaled.


The volume of the chest chamber within the anteroposterior axis increases because the external intercostal muscles contract, causing the ribs and sternum to maneuver outward, increasing the quantity of the chest chamber within the dorsoventral axis. Chest volume results in an identical increase in lung volume. As a result of this increase, the intrapulmonary pressure becomes less than air pressure, causing air from outside the body to flow into the lungs.


Inspiration and Expiration Reworked

Inspiration and Expiration Reworked


7. How is respiration regulated?  

Ans. The center of the breathing rhythm, located in the area of ​​the medulla of the brain, is primarily responsible for regulating breathing. The pneumatic center can change the function of the respiratory rhythm center by sending signals to reduce the inspiratory rate. The chemosensitive region is near the respiratory center. It is sensitive to carbon dioxide and hydrogen ions. This area sends signals to change the expiratory rate to remove connections.


Receptors in the carotid artery and aorta record the concentrations of carbon dioxide and hydrogen ions in the blood. As the carbon dioxide level rises, the respiratory center sends nerve impulses for the necessary changes. 


8. What is the effect of 2 pCO on oxygen transport? 

Ans. pCO2 plays a really important role in oxygen transport. within the alveolus, low pCO2 and high pO2 promote the formation of haemoglobin. In tissues, high pCO2 and low pO2 favour the dissociation of an oxygen atom from the oxyhemoglobin. Hence the affinity of haemoglobin for oxygen is aggravated by the decrease in pCO2 within the blood. Therefore, oxygen is carried within the blood as oxyhemoglobin, and oxygen is dissociated from it within the tissues.


9. What happens to the respiratory process in a man going up a hill?  

Ans. The oxygen content of the atmosphere decreases with an increase in altitude. As a result, each breath a man takes upward provides him with less oxygen. The amount of oxygen in the blood reduces as a result. The respiratory rate increases in response to a lack of oxygen. the oxygen content of the blood. At the same time, the frequency of the heartbeat increases in order to increase the oxygen supply to the blood.


10. What is the site of gaseous exchange in an insect?  

Ans. In the case of insects, the exchange of gas takes place through a huge network of tubes known collectively because of the tracheal system. The tiny openings which are present on the edges of an insect's body are called stigmas. Oxygen-rich air enters through the spiracles. The spiracles are connected to the network of the tubes. Oxygen enters into the windpipe from the spiracles. From here, oxygen diffuses into the body cells. The movement of CO2 follows the other path. CO2 from the body's cells first enters the windpipe then leaves the body through the spiracles.


11. Define the oxygen dissociation curve. Can you suggest any reason for its sigmoidal pattern? 

Ans. The oxygen dissociation curve is a graph showing the percentage saturation of oxyhemoglobin at various partial pressures of oxygen.


Oxygen Dissociation Curve

Oxygen Dissociation Curve


The curve shows us the equilibrium of oxyhemoglobin and haemoglobin at different partial pressures. 

The partial pressure of oxygen in the lungs is high, so haemoglobin binds to oxygen and forms oxyhemoglobin. 

Tissues have low levels of oxygen, so oxyhemoglobin releases oxygen in tissues to form haemoglobin. 

The sigmoid form of the dissociation curve is due to the binding of oxygen to haemoglobin. As the first oxygen molecule binds to haemoglobin, the binding affinity of the second oxygen molecule increases. The haemoglobin then attracts more oxygen.


12. Have you heard about hypoxia? Try to gather information about it, and discuss it with your friends.  

Ans. Hypoxia is a condition characterized by insufficient or decreased oxygen supply to the lungs and caused by various extrinsic factors such as decreased pO2, insufficient oxygen, etc. The different types of hypoxia are;-.

  • Hypoxemic hypoxia  

In this hypoxia, there is a decrease in the oxygen content of the blood due to the low oxygen partial pressure in the arterial blood.  

  • Anaemic hypoxia  

This hypoxia results in a decrease in haemoglobin concentration.

  • Stagnant or ischemic hypoxia  

This type of hypoxia results in a lack of oxygen in the blood due to poor circulation. It occurs when a person is exposed to a cold temperature for a long period of time.  

  • Histotoxic hypoxia 

In this type of hypoxia, the tissues cannot use oxygen, which occurs with carbon monoxide or cyanide poisoning.


13. Distinguish Between  

(a) IRV and ERV  

Inspiratory Reserve Volume (IRV)

Expiratory Reserve Volume(ERV)

This is defined as the maximum volume of the air that can be breathed in after a normal inspiration.

It is the maximum volume of air that can be exhaled i.e released out after a normal expiration.

It is approx 2500-3500 ml in human lungs.

It is approx 1000-1100 ml in human lungs. 


(b) Inspiratory Capacity and Expiratory Capacity  

Inspiratory Capacity (IC)

Expiratory Capacity (EC)

It is defined as the volume of the air that can be inhaled easily after a normal expiration.

It is defined as the volume of air that can be exhaled easily after a normal inspiration.

It comprises inspiratory reserve volume and tidal volume.

IC = TV + IRV

It comprises expiratory reverse volume and tidal volume.

EC = TV + ERV


(c) Vital Capacity and Total lung Capacity 

Vital Capacity (VC) 

Total lung Capacity (TLC)

It is defined as the maximum volume of air that can be exhaled easily after a maximum inspiration. It includes IC and ERV.

It is defined as the volume of air in the lungs after maximum inspiration. It includes IC, ERV, and residual volume.


It is approximately 4000 mL in the human lungs.

It is approximately 5000 – 6000 mL in the human lungs.


14. What is Tidal volume? Find out the Tidal volume (approximate value) for a healthy human in an hour. 

Ans. Tidal volume is defined as the volume of air that is inspired or expired during normal respiration.  It is approximately 6000 to 8000 mL of air per minute.  

The hourly tidal volume for a human with a good health is calculated as shown below:  

Tidal volume = 6000 to 8000 mL/minute  

Tidal volume in an hour = 6000 to 8000 mL ×(60 min)  

= 3.6 x10 5 ml to 4.8x10 5 ml

Therefore, the hourly tidal volume for a human with good health is around

3.6 x10 5 ml to 4.8x10 5 ml.


NCERT Biology Class 11 Breathing and Exchange of Gases PDF

Usually, students can be seen panicking over finding accurate solutions to the textbook questions. As they have multiple subjects to study, they are always in a hurry to complete a chapter as fast as possible. To make you all understand the chapter in simple words, Vedantu has come up with Breathing and Exchange of Gases Class 11 NCERT Solutions. These responses ease the strain on students by thoroughly answering each textbook question. Furthermore, all of the textual solutions were written by great Biology teachers who worked hard to ensure that their pupils thoroughly understood each concept.


Vedantu has introduced NCERT Biology Class 11 Breathing and Exchange of Gases PDF to students which will not only save their time but will also help them gain a better understanding and knowledge of the chapter without any difficulties. The PDF is one of the most convenient ways for students to study from as it will always be available offline after downloading and at the same time does not require even a second to get downloaded. The PDF will provide them with all the common questions that may appear in the examinations and will prepare them to achieve outstanding results.


NCERT Solutions for Class 11 Biology Chapter 17

The chapter Breathing and Exchange of Gases is the 17th chapter of NCERT Biology book for Class 11 and falls under the 5th unit named Human Physiology. Ch 17 Bio Class 11 deals with differentiation, meaning, importance and definitions of breathing and respiration in an in-depth manner. Class 11 Biology Chapter 17 NCERT Solutions provide answers to the topics dealing with the human respiratory system, the organs of the human respiratory system, the gases exchanged while breathing and respiration take place, disorders of the human respiratory system and many such concepts.


Diagrams are used to systematically explain the working of the human respiratory system, transportation of oxygen and carbon dioxide and many other processes involved in respiration. Harmful effects caused by phenomena like air pollution and activities like smoking are discussed to make students aware of the dangers brought by them. Effects of everyday diet are also mentioned in this chapter. Class 11 Biology Ch 17 NCERT Solutions elaborates all the above concepts in fragments, to increase the readability of the chapter.


Marks Weightage of NCERT Solutions Class 11 Biology Chapter 17 Breathing and Exchange of Gases

Biology Chapter 17 for 11 class The chapter on breathing and gas exchange is part of the fifth unit of a seven-chapter human physiology textbook. The entire topic is worth 18 points on the year-end examinations, whereas it is worth 20% on the NEET tests. If you examine the Ch. 17 Biology Class 11 NCERT Answers, you may be confident that you will easily obtain all of those marks. Vedantu provides NCERT Answers for Class 11 Biology Chapter 17 to help you pass your exams and secure your future.


Benefits of NCERT Solutions Class 11 Biology Chapter 17 Breathing and Exchange of Gases.

After going through Class 11 Biology Ch 17 NCERT Solutions, students will be able to sit for the examinations with newfound self-confidence and peace of mind. 

  • As the solutions are written and explained by Biology experts, the concepts are easily understandable by students.

  • The solutions are written by taking into consideration the pattern and marks allotted to the chapter.

  • All the textbook questions are solved with detailed examinations and diagrams are drawn where the need arises.

  • CBSE guidelines are followed while preparing the answers, making the structure more accurate and systematic.

  • PDF could be used for a quick revision before the examinations as all the answers will be available in the same place.


Important Concepts Covered in Breathing and Exchange of Gases

From this chapter, students will learn the mechanism of breathing. The respiratory organs in the human respiratory system make breathing easier. The various respiratory volumes and capacities, gas exchange, and movement are also discussed in this chapter. Finally, it talks about the several respiratory problems that students should be aware of.

Find out the important subtopics from the chapter Breathing and Exchange of Gases.

  • Respiratory Organs

  • Mechanism of Breathing

  • Exchange of Gases

  • Transport of Gases

  • Regulation of Respiration

  • Disorders of the Respiratory System


Conclusion

Students must read the NCERT Solutions for Chapter 17 Breathing and Gas Exchange while preparing for their Class 11 CBSE exam. It is also essential for the NEET Exam. This article covers all of the critical NCERT questions and solutions for Class 11 Biology Chapter 17, "Breathing and Gas Exchange." The solutions are presented in simple language since they were chosen by Subject Experts.

FAQs on NCERT Solutions for Class 11 Biology Chapter 17 - Breathing And Exchange Of Gases

1. Explain the Effects on the Respiratory System of a Man While Climbing a Hill.

The amount of oxygen keeps on decreasing as the altitude increases. The amount of oxygen starts decreasing as the man starts climbing up the hill. As the level of oxygen starts decreasing, the man is unable to breathe in the required amount of oxygen into the blood. In response to the declined oxygen in the blood, the respiratory rate increases making it difficult to breathe. The blood is in a constant need for more oxygen. To supply the blood with oxygen, the heartbeat rate of that person also increases.

2. Briefly Explain the Site of Gaseous Exchange in an Insect.

Insects have a trachea system which comprises a network of tubes. Exchange of gases occurs through the trachea system. Spiracles are the small openings present on the side of the insect’s body, which are responsible for absorbing oxygen-rich air inside the body. The spiracles are connected to the trachea. The oxygen then gets transported to trachea via spiracles. The oxygen starts defusing in the body. Whereas, the carbon dioxide takes the reverse path. From the cell of the body, it travels to the tracheas and exits from the spiracles.

3. According to Chapter 17 of Class 11 Biology, Diffusion of gases occurs in the alveolar region only and not in the other parts of the respiratory system. Why?

For efficient diffusion of gases, the region should meet the following characteristics to be capable enough for the important process. They are;

  • The membrane should be permeable to gases and should be thin and moist too.

  • It should have a large surface area.

  • It should have high vascularity.

All these characteristics are met by the alveolar membrane, thus, it is the best place for respiratory exchange among all other parts of the respiratory system. A detailed explanation is available on Vedantu.

4. What happens to the respiratory process in a man going up a hill according to Chapter 17 of Class 11 Biology?

With increasing altitude, the oxygen level depreciates in the atmosphere. Therefore, when a man climbs up the hill the amount of oxygen he gets while breathing also decreases. Thus, oxygen levels in the blood also decrease and as a result of this, to compensate for this declining level of oxygen, the respiratory rate increases. The heart also has to work faster to supply oxygen to the organs and thus, heartbeat increases. These solutions make it easier for students by offering detailed answers to all textbook questions. Furthermore, all of the textual responses are created by top Biology teachers who have worked hard to ensure that students fully comprehend each idea.

5. Explain the process of inspiration under normal conditions as discussed in Chapter 17 of Class 11 Biology.

The process through which fresh air enters the lungs is known as inspiration. The diaphragm, intercostal muscles, and abdominal muscles are all crucial. The most significant muscles for inspiration are the diaphragm and external intercostal muscles. The diaphragm and external intercostal muscles contract, increasing the volume of the thoracic cavity. Relaxation of abdominal muscles occurs during inspiration, allowing the diaphragm to compress the abdominal organs. As a result, the overall volume of the thoracic cavity grows, and the air pressure in the lungs decreases. Because of the increased pressure outside the body, the air is now rushing into the lungs. This is the order in which air flows during inspiration.

6. How is respiration regulated according to Chapter 17 of Class 11 Biology?

Both the neurological and chemical systems are in charge of respiration. The medulla oblongata and pons Varolii include clusters of neurons that make up the respiratory centre in the brain. The respiratory centre is in charge of controlling the rate and depth of breathing.


The dorsal respiratory group of neurons is found in the medulla oblongata's dorsal part. This group of neurons is mostly in charge of inspiration.


In the ventrolateral region of the medulla oblongata, there is a group of neurons known as the ventral group. These can either inspire or cause exhalation.


Chemoreceptors in the carotid and aortic bodies chemically control respiration. Excess carbon dioxide or hydrogen ions stimulate the respiratory centre of the brain, which increases the inspiratory and expiratory impulses to the respiratory muscles. Acidosis is caused by increased CO2. The importance of oxygen in respiratory rhythm regulation is negligible. For more, refer to the notes of Chapter 17 of Class 11 Biology by Vedantu which are available to download free of cost.

7. Define the oxygen dissociation curve according to Chapter 17 of Class 11 Biology. Can you suggest any reason for its sigmoidal pattern?

A curve called the oxygen haemoglobin dissociation curve graphically depicts the relationship between partial pressure of oxygen (pO2) and % saturation of haemoglobin with oxygen (O2) (also called oxygen dissociation curve).


The sigmoidal structure of the oxygen haemoglobin dissociation curve is due to two features that are important in oxygen transport. These are the two properties:

  • Despite considerable increases in oxygen tension beyond p02 of 70-80 mm Hg, minimal oxygen loss from haemoglobin occurs. The comparatively flat segment of the curve depicts this.

  • Any additional drop in p02 below 40 mm Hg results in a disproportionately higher oxygen release from the haemoglobin. It causes the curve to be sigmoid and results in the steeper portion of the curve.