Which of the following has maximum root mean square velocity at the same temperature?
(1) \[{\rm{S}}{{\rm{O}}_{\rm{2}}}\]
(2)\[{\rm{C}}{{\rm{O}}_{\rm{2}}}\]
(3)\[{{\rm{O}}_{\rm{2}}}\]
(4)\[{{\rm{H}}_{\rm{2}}}\]
Answer
271.2k+ views
Hint: Root mean square(rms) velocity defines square root of average velocity. The formula used for calculation of this velocity is \[{v_{rms}} = \sqrt {\dfrac{{3RT}}{M}} \] , where, R stands for gas constant, T stands for temperature, M stands for molar mass of the gas.
Complete Step by Step Solution:
In the given question, using the root rms velocity formula we can identify the gas having maximum rms speed.
rms velocity can be find out by the following formula,
\[{v_{rms}} = \sqrt {\dfrac{{3RT}}{M}} \]
Here, given a set of gases, we have to identify the gas which possesses maximum rms speed.
As R is gas constant and given that all gases are at same temperature, molar masses of each gas decide its rms speed.
So, \[{v_{rms}} = \sqrt {\dfrac{1}{M}} \], that means, rms velocity is indirectly proportional to molar mass of gases. So, the gas that possesses smaller molar mass has the maximum rms velocity.
So, now we will calculate the molar mass of each gas one by one.
Molar mass of \[{\rm{S}}{{\rm{O}}_{\rm{2}}} = 32 + 2 \times 16 = 32 + 32 = 64\,{\rm{u}}\]
Molar mass of \[{\rm{C}}{{\rm{O}}_{\rm{2}}} = 12 + 2 \times 16 = 12 + 32 = 44\,{\rm{u}}\]
Molar mass of \[{{\rm{O}}_{\rm{2}}} = 16 \times 2 = 32\,{\rm{u}}\]
Molar mass of \[{{\rm{H}}_{\rm{2}}} = 2 \times 1 = 2\,{\rm{u}}\]
As we have seen, hydrogen gas possesses the lowest molar mass among all the gases. Therefore, hydrogen gas possesses the highest rms velocity.
Hence, option (4) is right.
Note: It is to be noted that average velocity is different from rms velocity. Average velocity defines the arithmetic mean calculation of velocities of different gaseous molecules at a particular temperature. The average velocity can be found by the formula \[{v_{av}} = \sqrt {\dfrac{{8RT}}{{\pi M}}} \] . The rm velocity is always greater than average velocity.
Complete Step by Step Solution:
In the given question, using the root rms velocity formula we can identify the gas having maximum rms speed.
rms velocity can be find out by the following formula,
\[{v_{rms}} = \sqrt {\dfrac{{3RT}}{M}} \]
Here, given a set of gases, we have to identify the gas which possesses maximum rms speed.
As R is gas constant and given that all gases are at same temperature, molar masses of each gas decide its rms speed.
So, \[{v_{rms}} = \sqrt {\dfrac{1}{M}} \], that means, rms velocity is indirectly proportional to molar mass of gases. So, the gas that possesses smaller molar mass has the maximum rms velocity.
So, now we will calculate the molar mass of each gas one by one.
Molar mass of \[{\rm{S}}{{\rm{O}}_{\rm{2}}} = 32 + 2 \times 16 = 32 + 32 = 64\,{\rm{u}}\]
Molar mass of \[{\rm{C}}{{\rm{O}}_{\rm{2}}} = 12 + 2 \times 16 = 12 + 32 = 44\,{\rm{u}}\]
Molar mass of \[{{\rm{O}}_{\rm{2}}} = 16 \times 2 = 32\,{\rm{u}}\]
Molar mass of \[{{\rm{H}}_{\rm{2}}} = 2 \times 1 = 2\,{\rm{u}}\]
As we have seen, hydrogen gas possesses the lowest molar mass among all the gases. Therefore, hydrogen gas possesses the highest rms velocity.
Hence, option (4) is right.
Note: It is to be noted that average velocity is different from rms velocity. Average velocity defines the arithmetic mean calculation of velocities of different gaseous molecules at a particular temperature. The average velocity can be found by the formula \[{v_{av}} = \sqrt {\dfrac{{8RT}}{{\pi M}}} \] . The rm velocity is always greater than average velocity.
Recently Updated Pages
JoSAA Counselling 2026: JoSAA 2026 Mock Seat Allotment LIVE: Round 2 Result Released, Registration, Choice Filling and Ranks

Disproportionation Reaction: Definition, Example & JEE Guide

Hess Law of Constant Heat Summation: Definition, Formula & Applications

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Understanding the Electric Field of a Uniformly Charged Ring

Understanding Atomic Structure for Beginners

Derivation of Equation of Trajectory Explained for Students

Understanding the Different Types of Solutions in Chemistry

Other Pages
JEE Advanced 2026 Notification Out with Exam Date, Registration (Extended), Syllabus and More

JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

JEE Advanced Weightage Chapter Wise 2026 for Physics, Chemistry, and Mathematics

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

NCERT Solutions For Class 11 Chemistry In Hindi Chapter 1 Some Basic Concepts Of Chemistry - 2025-26

How to Convert a Galvanometer into an Ammeter or Voltmeter

