There are 42 protons and 53 neutrons in the atom of an element. This element is represented as:
A. $_{42}{{X}^{95}}$
B. $_{42}{{X}^{53}}$
C. $_{53}{{X}^{42}}$
D. $_{95}{{X}^{42}}$
Answer
252.6k+ views
Hint: We know that the atomic number or we can also say that the proton number of a chemical element is the number of protons found in the nucleus of every atom of that element. The atomic number uniquely identifies a chemical element. It is identical to the charge number of the nucleus. On the other hand, the atomic mass number also known as nucleon number is defined as the total number of protons and neutrons in an atomic nucleus taken together. Based on this concept we have to solve this question.
Complete step by step answer:
In general, an element is always represented in the form of $_{\text{Z}}{{\text{X}}^{\text{A}}}$ where,
$\mathrm{A}=$ mass number and $\mathrm{Z}=$proton number
Given that,
$\mathrm{Z}=42$ and the number of neutrons is$\text{N}=53$
Thus, we get the mass number as
Total number of protons + Total number of neutrons
Hence, we get,
$A=Z+N=42+53=95$
Therefore, with the mass number being 95 and the number of protons being 42, the element can be represented as ${ }_{42} \mathrm{X}^{95}$.
Thus, the element will be ${ }_{42} \mathrm{X}^{95}$.
Therefore, the correct answer is Option A.
Note It should be known to us that the electrons are fundamental particles so they cannot be decomposed into the constituents. They are therefore not made or composed. An electron acts as a point charge and a point mass. We can never see the subatomic particles directly, but can only infer from observation of such indirect effects like tracks. If there are many of them and they are emitting some radiation, and also if we shine some radiation on them and receive back the response this will also constitute a kind of seeing.
Complete step by step answer:
In general, an element is always represented in the form of $_{\text{Z}}{{\text{X}}^{\text{A}}}$ where,
$\mathrm{A}=$ mass number and $\mathrm{Z}=$proton number
Given that,
$\mathrm{Z}=42$ and the number of neutrons is$\text{N}=53$
Thus, we get the mass number as
Total number of protons + Total number of neutrons
Hence, we get,
$A=Z+N=42+53=95$
Therefore, with the mass number being 95 and the number of protons being 42, the element can be represented as ${ }_{42} \mathrm{X}^{95}$.
Thus, the element will be ${ }_{42} \mathrm{X}^{95}$.
Therefore, the correct answer is Option A.
Note It should be known to us that the electrons are fundamental particles so they cannot be decomposed into the constituents. They are therefore not made or composed. An electron acts as a point charge and a point mass. We can never see the subatomic particles directly, but can only infer from observation of such indirect effects like tracks. If there are many of them and they are emitting some radiation, and also if we shine some radiation on them and receive back the response this will also constitute a kind of seeing.
Recently Updated Pages
States of Matter Chapter For JEE Main Chemistry

Young’s Double Slit Experiment Derivation Explained

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Wheatstone Bridge – Principle, Formula, Diagram & Applications

Circuit Switching vs Packet Switching: Key Differences Explained

Mass vs Weight: Key Differences Explained for Students

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Hybridisation in Chemistry – Concept, Types & Applications

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

Other Pages
CBSE Class 12 Physics Question Paper 2026: Download SET-wise PDF with Answer Key & Analysis

JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

JEE Advanced Marks vs Rank 2025 - Predict Your IIT Rank Based on Score

