
The words that can be formed using alphabets \[A, H, L, U,\] and \[R\] are written as in a dictionary (no alphabet is repeated). Then find the rank of the word \[RAHUL\].
A. \[71\]
B. \[72\]
C. \[73\]
D. \[74\]
Answer
232.8k+ views
Hint In the given question, 5 alphabets are given. By using the factorial function, we will find the number of words formed using the given alphabets and the rank of the word \[RAHUL\].
Formula used
Factorial: The factorial of a non-negative integer is the product of all positive integers less than or equal to that number.
\[n! = 1 \cdot 2 \cdot 3 \cdot ....\left( {n - 1} \right) \cdot n\]
Complete step by step solution:
The given alphabets are \[A, H, L, U,\] and \[R\].
In the dictionary, the order of alphabets is \[A, H, L, R,\] and \[U\].
The words formed before \[RAHUL\] will starts with the letters \[A, H, L\] or \[R\].
Let’s calculate the number of words that comes before the word \[RAHUL\].
A number of words are formed when the first letter is \[A\]:
If \[A\] is the first letter and the other 4 letters are placed without repetition, then
A number of words start with \[A\]: \[4! = 24\]
A number of words are formed when the first letter is \[H\]:
If \[H\] is the first letter and the other 4 letters are placed without repetition, then
A number of words start with \[H\]: \[4! = 24\]
A number of words are formed when the first letter is \[L\]:
If \[L\] is the first letter and the other 4 letters are placed without repetition, then
A number of words start with \[L\]: \[4! = 24\]
In alphabetic manner, the only word starts with \[R\] and comes before \[RAHUL\] is \[RAHLU\].
So, the number of words comes before \[RAHUL\] in the dictionary is
Number of words \[ = 24 + 24 + 24 + 1\]
\[ \Rightarrow \] Number of words \[ = 73\]
Therefore, the rank of the word \[RAHUL\] is \[74\].
Hence the correct option is D.
Note: Students often get confused about the calculation of repetition and without repetition conditions. For without repetition, we will use factorial and for repetition, we will use permutation formula.
Formula used
Factorial: The factorial of a non-negative integer is the product of all positive integers less than or equal to that number.
\[n! = 1 \cdot 2 \cdot 3 \cdot ....\left( {n - 1} \right) \cdot n\]
Complete step by step solution:
The given alphabets are \[A, H, L, U,\] and \[R\].
In the dictionary, the order of alphabets is \[A, H, L, R,\] and \[U\].
The words formed before \[RAHUL\] will starts with the letters \[A, H, L\] or \[R\].
Let’s calculate the number of words that comes before the word \[RAHUL\].
A number of words are formed when the first letter is \[A\]:
If \[A\] is the first letter and the other 4 letters are placed without repetition, then
A number of words start with \[A\]: \[4! = 24\]
A number of words are formed when the first letter is \[H\]:
If \[H\] is the first letter and the other 4 letters are placed without repetition, then
A number of words start with \[H\]: \[4! = 24\]
A number of words are formed when the first letter is \[L\]:
If \[L\] is the first letter and the other 4 letters are placed without repetition, then
A number of words start with \[L\]: \[4! = 24\]
In alphabetic manner, the only word starts with \[R\] and comes before \[RAHUL\] is \[RAHLU\].
So, the number of words comes before \[RAHUL\] in the dictionary is
Number of words \[ = 24 + 24 + 24 + 1\]
\[ \Rightarrow \] Number of words \[ = 73\]
Therefore, the rank of the word \[RAHUL\] is \[74\].
Hence the correct option is D.
Note: Students often get confused about the calculation of repetition and without repetition conditions. For without repetition, we will use factorial and for repetition, we will use permutation formula.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding the Electric Field of a Uniformly Charged Ring

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions For Class 11 Maths Chapter 12 Limits and Derivatives (2025-26)

NCERT Solutions For Class 11 Maths Chapter 10 Conic Sections (2025-26)

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

Understanding Electromagnetic Waves and Their Importance

