
The words that can be formed using alphabets \[A, H, L, U,\] and \[R\] are written as in a dictionary (no alphabet is repeated). Then find the rank of the word \[RAHUL\].
A. \[71\]
B. \[72\]
C. \[73\]
D. \[74\]
Answer
161.1k+ views
Hint In the given question, 5 alphabets are given. By using the factorial function, we will find the number of words formed using the given alphabets and the rank of the word \[RAHUL\].
Formula used
Factorial: The factorial of a non-negative integer is the product of all positive integers less than or equal to that number.
\[n! = 1 \cdot 2 \cdot 3 \cdot ....\left( {n - 1} \right) \cdot n\]
Complete step by step solution:
The given alphabets are \[A, H, L, U,\] and \[R\].
In the dictionary, the order of alphabets is \[A, H, L, R,\] and \[U\].
The words formed before \[RAHUL\] will starts with the letters \[A, H, L\] or \[R\].
Let’s calculate the number of words that comes before the word \[RAHUL\].
A number of words are formed when the first letter is \[A\]:
If \[A\] is the first letter and the other 4 letters are placed without repetition, then
A number of words start with \[A\]: \[4! = 24\]
A number of words are formed when the first letter is \[H\]:
If \[H\] is the first letter and the other 4 letters are placed without repetition, then
A number of words start with \[H\]: \[4! = 24\]
A number of words are formed when the first letter is \[L\]:
If \[L\] is the first letter and the other 4 letters are placed without repetition, then
A number of words start with \[L\]: \[4! = 24\]
In alphabetic manner, the only word starts with \[R\] and comes before \[RAHUL\] is \[RAHLU\].
So, the number of words comes before \[RAHUL\] in the dictionary is
Number of words \[ = 24 + 24 + 24 + 1\]
\[ \Rightarrow \] Number of words \[ = 73\]
Therefore, the rank of the word \[RAHUL\] is \[74\].
Hence the correct option is D.
Note: Students often get confused about the calculation of repetition and without repetition conditions. For without repetition, we will use factorial and for repetition, we will use permutation formula.
Formula used
Factorial: The factorial of a non-negative integer is the product of all positive integers less than or equal to that number.
\[n! = 1 \cdot 2 \cdot 3 \cdot ....\left( {n - 1} \right) \cdot n\]
Complete step by step solution:
The given alphabets are \[A, H, L, U,\] and \[R\].
In the dictionary, the order of alphabets is \[A, H, L, R,\] and \[U\].
The words formed before \[RAHUL\] will starts with the letters \[A, H, L\] or \[R\].
Let’s calculate the number of words that comes before the word \[RAHUL\].
A number of words are formed when the first letter is \[A\]:
If \[A\] is the first letter and the other 4 letters are placed without repetition, then
A number of words start with \[A\]: \[4! = 24\]
A number of words are formed when the first letter is \[H\]:
If \[H\] is the first letter and the other 4 letters are placed without repetition, then
A number of words start with \[H\]: \[4! = 24\]
A number of words are formed when the first letter is \[L\]:
If \[L\] is the first letter and the other 4 letters are placed without repetition, then
A number of words start with \[L\]: \[4! = 24\]
In alphabetic manner, the only word starts with \[R\] and comes before \[RAHUL\] is \[RAHLU\].
So, the number of words comes before \[RAHUL\] in the dictionary is
Number of words \[ = 24 + 24 + 24 + 1\]
\[ \Rightarrow \] Number of words \[ = 73\]
Therefore, the rank of the word \[RAHUL\] is \[74\].
Hence the correct option is D.
Note: Students often get confused about the calculation of repetition and without repetition conditions. For without repetition, we will use factorial and for repetition, we will use permutation formula.
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