Question

The value of $G$ is______
A. \[6.673 \times {10^{ - 11}}N{m^{ - 2}}k{g^2}\]
B. \[6.673 \times {10^{ - 11}}N{m^2}k{g^2}\]
C. \[6.673 \times {10^{ - 11}}N{m^2}k{g^{ - 2}}\]
D. \[6.673 \times {10^{ - 11}}N{m^{ - 2}}k{g^{ - 2}}\]

Answer 1

Hint: In this question, we are required to write the constant value of $G$ where $G$ is the Gravitational constant. In physics a constant also known as physical constant is a physical quantity that is universal in nature and has constant value all the time.

Complete step by step solution:
In this question, we need to write the value of the G. Here, G refers to the Gravitational constant. We know that in the entire universe gravity is present which tends to attract particles and it is a key element which defines and holds the physical connection between space and matter.

According to the Newton’s law of Universal Gravitation, every particle attracts other particle in the universe with a force which is directly proportional to the product of the masses and inversely proportional to the square of their distance, it is represented by the equation
\[F = \dfrac{{G{m_1}{m_2}}}{{{r^2}}}\]
Where, \[{m_1},{m_2}\] is the mass of the two bodies respectively, \[r\] is the distance between the two bodies and \[G\] is the universal Gravitational constant.

Now we can write the formula of Newton’s law of Universal Gravitation in the terms of Gravitational constant as
\[G = \dfrac{{F \times {r^2}}}{{{m_1}{m_2}}}\]
Therefore, the value of Gravitational constant will be \[6.673 \times {10^{ - 11}}N{m^2}k{g^{ - 2}}\].

Hence, option C is the correct answer<\b>.

Note: In physics a constant are some numbers with units that cannot be calculated from any type of physical theory. These physical quantities are indicated by a physical constant and do not depend on the unit system to express the quantity.