
The smallest bond angle is found in
A. \[IF_7\]
B. \[CH_4\]
C. \[BeF_2\]
D. \[BF_3\]
Answer
164.4k+ views
Hint: \[IF_7\] has a pentagonal bipyramidal structure.
\[CH_4\], \[BeF_2\], and \[BF_3\] have tetrahedral, linear, and trigonal planar geometry respectively.
Linear molecules have a bond angle of \[180^o\] which is the highest bond angle.
Complete step by step solution:Here in this question, we have to find out which of the given molecules has the smallest bond angle.
The shape is predicted by VSEPR theory.
A. \[IF_7\]
Here Iodine is the central atom. It is an interhalogen compound.
Iodine has seven valence electrons all of which make a bond with each electron of seven F atoms.
It contains seven bond pairs and zero lone pairs.
So, its structure is pentagonal bipyramidal.
Five bond pairs are in the same plane at an angle of \[72^o\], and the remaining two bond pairs are perpendicular to the plane creating an angle of \[90^o\] with the plane.

Image: Structure of \[IF_7\]
So, A is correct.
B. \[CH_4\]
Here carbon is the central atom.
It has four valence electrons in its valence shell all of which are involved in bond formation.
So, there are four bond pairs.
So, it has a tetrahedral structure.
The bond angle is \[109^o\].
So, B is incorrect.
C. \[BeF_2\]
Here beryllium is the central atom.
It has two valence electrons in its valence shell all of which are involved in bond formation.
So, there are two bond pairs.
So, it has a tetrahedral structure.
The bond angle is \[180^o\].
So, C is incorrect.
D. \[BF_3\]
Here boron is the central atom.
It has three valence electrons in its valence shell all of which are involved in bond formation.
So, there are three bond pairs.
So, it has a trigonal planar structure.
The bond angle is \[120^o\].
So, D is incorrect.
So, \[IF_7\] has a pentagonal pyramidal structure and has the smallest bond angle.
So, option A is correct.
Note: An interhalogen compound is a molecule that includes two or more distinct halogen atoms and no atoms of elements from any other group.
Most interhalogen compounds are binary i.e., composed of two distinct elements.
\[CH_4\], \[BeF_2\], and \[BF_3\] have tetrahedral, linear, and trigonal planar geometry respectively.
Linear molecules have a bond angle of \[180^o\] which is the highest bond angle.
Complete step by step solution:Here in this question, we have to find out which of the given molecules has the smallest bond angle.
The shape is predicted by VSEPR theory.
A. \[IF_7\]
Here Iodine is the central atom. It is an interhalogen compound.
Iodine has seven valence electrons all of which make a bond with each electron of seven F atoms.
It contains seven bond pairs and zero lone pairs.
So, its structure is pentagonal bipyramidal.
Five bond pairs are in the same plane at an angle of \[72^o\], and the remaining two bond pairs are perpendicular to the plane creating an angle of \[90^o\] with the plane.

Image: Structure of \[IF_7\]
So, A is correct.
B. \[CH_4\]
Here carbon is the central atom.
It has four valence electrons in its valence shell all of which are involved in bond formation.
So, there are four bond pairs.
So, it has a tetrahedral structure.
The bond angle is \[109^o\].
So, B is incorrect.
C. \[BeF_2\]
Here beryllium is the central atom.
It has two valence electrons in its valence shell all of which are involved in bond formation.
So, there are two bond pairs.
So, it has a tetrahedral structure.
The bond angle is \[180^o\].
So, C is incorrect.
D. \[BF_3\]
Here boron is the central atom.
It has three valence electrons in its valence shell all of which are involved in bond formation.
So, there are three bond pairs.
So, it has a trigonal planar structure.
The bond angle is \[120^o\].
So, D is incorrect.
So, \[IF_7\] has a pentagonal pyramidal structure and has the smallest bond angle.
So, option A is correct.
Note: An interhalogen compound is a molecule that includes two or more distinct halogen atoms and no atoms of elements from any other group.
Most interhalogen compounds are binary i.e., composed of two distinct elements.
Recently Updated Pages
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

Atomic Structure - Electrons, Protons, Neutrons and Atomic Models

Displacement-Time Graph and Velocity-Time Graph for JEE

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 11 Chemistry In Hindi Chapter 1 Some Basic Concepts of Chemistry

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

NCERT Solutions for Class 11 Chemistry Chapter 7 Redox Reaction

Instantaneous Velocity - Formula based Examples for JEE

Thermodynamics Class 11 Notes: CBSE Chapter 5
