Answer
Verified
39.6k+ views
Hint: First find out the hybridization of the molecule and accordingly see what the structure can be.
Formula used: Formula for finding out the hybridization of any molecule:
$H = 1/2\left[ {V + M - C + A} \right]$
Where, V=number of valence electrons;
M=monovalent atoms;
C=positive charge;
A=negative charge.
Complete step by step answer:
-Hybridization is basically a concept according to which atomic orbitals of different atoms fuse together to form new hybridized molecular orbitals. This fusing influences the molecular geometry and the bonding properties of the molecules.
So, to find out the shape of any molecule we first need to find out its hybridizations number. Each hybridization number has been assigned a suitable structure that should be formed. This gives us the shape of the molecules.
-Lets begin with finding out the hybridization of $Xe{F_6}$ :
It has V = 8 because Xe has 8 electrons in its outermost shell;
M = 6 because in this molecule all the 6 F atoms are monovalent in nature;
C and A = 0 because the molecule is neutral.
Using formula: $H = 1/2\left[ {V + M - C + A} \right]$
=1/2 [8+6+0+0]
=7
Since the hybridization number is 7, the hybridization of the molecule is $s{p^3}{d^3}$. We can also say that Xe has 8 electrons in its outermost shell of which 6 form bonds with F atoms leaving behind 1 lone pair. Hence the molecule of $Xe{F_6}$ has 6 bond pairs and 1 lone pair of electrons.
Since, $Xe{F_6}$ has $s{p^3}{d^3}$ hybridization, its geometry will be distorted octahedral.
So, the correct option is: (3) distorted octahedral.
Note: In such questions mistakes are made only while putting the values of V, M, C and A in hybridization formula. So, be very careful while putting these values.
Formula used: Formula for finding out the hybridization of any molecule:
$H = 1/2\left[ {V + M - C + A} \right]$
Where, V=number of valence electrons;
M=monovalent atoms;
C=positive charge;
A=negative charge.
Complete step by step answer:
-Hybridization is basically a concept according to which atomic orbitals of different atoms fuse together to form new hybridized molecular orbitals. This fusing influences the molecular geometry and the bonding properties of the molecules.
So, to find out the shape of any molecule we first need to find out its hybridizations number. Each hybridization number has been assigned a suitable structure that should be formed. This gives us the shape of the molecules.
-Lets begin with finding out the hybridization of $Xe{F_6}$ :
It has V = 8 because Xe has 8 electrons in its outermost shell;
M = 6 because in this molecule all the 6 F atoms are monovalent in nature;
C and A = 0 because the molecule is neutral.
Using formula: $H = 1/2\left[ {V + M - C + A} \right]$
=1/2 [8+6+0+0]
=7
Since the hybridization number is 7, the hybridization of the molecule is $s{p^3}{d^3}$. We can also say that Xe has 8 electrons in its outermost shell of which 6 form bonds with F atoms leaving behind 1 lone pair. Hence the molecule of $Xe{F_6}$ has 6 bond pairs and 1 lone pair of electrons.
Since, $Xe{F_6}$ has $s{p^3}{d^3}$ hybridization, its geometry will be distorted octahedral.
So, the correct option is: (3) distorted octahedral.
Note: In such questions mistakes are made only while putting the values of V, M, C and A in hybridization formula. So, be very careful while putting these values.
Recently Updated Pages
silver wire has diameter 04mm and resistivity 16 times class 12 physics JEE_Main
A parallel plate capacitor has a capacitance C When class 12 physics JEE_Main
A series combination of n1 capacitors each of value class 12 physics JEE_Main
When propyne is treated with aqueous H2SO4 in presence class 12 chemistry JEE_Main
Which of the following is not true in the case of motion class 12 physics JEE_Main
The length of a potentiometer wire is 10m The distance class 12 physics JEE_MAIN
Other Pages
The mole fraction of the solute in a 1 molal aqueous class 11 chemistry JEE_Main
If a wire of resistance R is stretched to double of class 12 physics JEE_Main
A closed organ pipe and an open organ pipe are tuned class 11 physics JEE_Main
when an object Is placed at a distance of 60 cm from class 12 physics JEE_Main
Formula for number of images formed by two plane mirrors class 12 physics JEE_Main
Dissolving 120g of urea molwt60 in 1000g of water gave class 11 chemistry JEE_Main