Answer
Verified
40.2k+ views
Hint: Decomposition of ammonium derivatives liberates toxic gases like ammonia, nitrogen oxides and water vapor. Different ammonium derivatives liberate different combinations of gases.
Complete step by step answer:
* Decomposition of ammonium nitrate (\[N{{H}_{4}}N{{O}_{3}}\]) creates toxic gases like nitrogen oxides and water. The resulting nitrogen oxides will support combustion, even in the absence of oxygen.
\[\]\[N{{H}_{4}}N{{O}_{3}}\to {{N}_{2}}{{O}_{(g)}}\uparrow +2{{H}_{2}}O\]
* \[{{N}_{2}}O\] is called nitrous oxide or laughing gas.
* Decomposition of ammonium nitrite (\[N{{H}_{4}}N{{O}_{2}}\]) liberates nitrogen gas (\[{{N}_{2}}\]) and water vapor.
\[N{{H}_{4}}N{{O}_{2}}\to {{N}_{2}}_{(g)}\uparrow +2{{H}_{2}}O\]
* After decomposition ammonium nitrate (\[N{{H}_{4}}N{{O}_{3}}\]) liberates nitrous oxide (\[{{N}_{2}}O\]) and water.
* After decomposition ammonium nitrite (\[N{{H}_{4}}N{{O}_{2}}\]) liberates nitrogen gas (\[{{N}_{2}}\]) and water vapor.
* Ammonium nitrate and ammonium nitrite salts both form water vapor after decomposition. But ammonium nitrate forms nitrous oxide and ammonium nitrite forms nitrogen gas after decomposition.
* Option A is wrong, because \[N{{O}_{2}}\] is not going to release after decomposition of the given compounds.
* Option B is wrong, because \[N{{O}_{2}}\] and \[N{{O}_{3}}\] are not going to release after decomposition of the given compounds.
* Option D is wrong, because \[N{{O}_{3}}\] and \[N{{O}_{2}}\] are not going to release after decomposition of the given compounds.
* Ammonium nitrate and ammonium nitrite salts both form water vapor after decomposition.
So, the correct option is C.
Note: Don’t be confused with the oxides of nitrogen.
Ammonium nitrate (\[N{{H}_{4}}N{{O}_{3}}\])
Ammonium nitrite (\[N{{H}_{4}}N{{O}_{2}}\])
Nitrous Oxide (\[{{N}_{2}}O\])
Nitrogen Dioxide (\[N{{O}_{2}}\])
Complete step by step answer:
* Decomposition of ammonium nitrate (\[N{{H}_{4}}N{{O}_{3}}\]) creates toxic gases like nitrogen oxides and water. The resulting nitrogen oxides will support combustion, even in the absence of oxygen.
\[\]\[N{{H}_{4}}N{{O}_{3}}\to {{N}_{2}}{{O}_{(g)}}\uparrow +2{{H}_{2}}O\]
* \[{{N}_{2}}O\] is called nitrous oxide or laughing gas.
* Decomposition of ammonium nitrite (\[N{{H}_{4}}N{{O}_{2}}\]) liberates nitrogen gas (\[{{N}_{2}}\]) and water vapor.
\[N{{H}_{4}}N{{O}_{2}}\to {{N}_{2}}_{(g)}\uparrow +2{{H}_{2}}O\]
* After decomposition ammonium nitrate (\[N{{H}_{4}}N{{O}_{3}}\]) liberates nitrous oxide (\[{{N}_{2}}O\]) and water.
* After decomposition ammonium nitrite (\[N{{H}_{4}}N{{O}_{2}}\]) liberates nitrogen gas (\[{{N}_{2}}\]) and water vapor.
* Ammonium nitrate and ammonium nitrite salts both form water vapor after decomposition. But ammonium nitrate forms nitrous oxide and ammonium nitrite forms nitrogen gas after decomposition.
* Option A is wrong, because \[N{{O}_{2}}\] is not going to release after decomposition of the given compounds.
* Option B is wrong, because \[N{{O}_{2}}\] and \[N{{O}_{3}}\] are not going to release after decomposition of the given compounds.
* Option D is wrong, because \[N{{O}_{3}}\] and \[N{{O}_{2}}\] are not going to release after decomposition of the given compounds.
* Ammonium nitrate and ammonium nitrite salts both form water vapor after decomposition.
So, the correct option is C.
Note: Don’t be confused with the oxides of nitrogen.
Ammonium nitrate (\[N{{H}_{4}}N{{O}_{3}}\])
Ammonium nitrite (\[N{{H}_{4}}N{{O}_{2}}\])
Nitrous Oxide (\[{{N}_{2}}O\])
Nitrogen Dioxide (\[N{{O}_{2}}\])
Recently Updated Pages
silver wire has diameter 04mm and resistivity 16 times class 12 physics JEE_Main
A parallel plate capacitor has a capacitance C When class 12 physics JEE_Main
A series combination of n1 capacitors each of value class 12 physics JEE_Main
When propyne is treated with aqueous H2SO4 in presence class 12 chemistry JEE_Main
Which of the following is not true in the case of motion class 12 physics JEE_Main
The length of a potentiometer wire is 10m The distance class 12 physics JEE_MAIN
Other Pages
Explain the construction and working of a GeigerMuller class 12 physics JEE_Main
Oxidation state of S in H2S2O8 is A 6 B 7 C +8 D 0 class 12 chemistry JEE_Main
A closed organ pipe and an open organ pipe are tuned class 11 physics JEE_Main
Which of the following is a buffer solution A CH3COOH class 11 chemistry JEE_Main
The mole fraction of the solute in a 1 molal aqueous class 11 chemistry JEE_Main
The resultant of vec A and vec B is perpendicular to class 11 physics JEE_Main