Courses for Kids
Free study material
Offline Centres
Store Icon

The shape of ${{\text{O}}_{\text{2}}}{{\text{F}}_{\text{2}}}$is similar to:
(A) ${{\text{C}}_{\text{2}}}{{\text{F}}_{\text{2}}}$
(B) ${{\text{O}}_{\text{2}}}{{\text{H}}_{\text{2}}}$
(C) ${{\text{H}}_{\text{2}}}{{\text{F}}_{\text{2}}}$
(D) ${{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}$

Last updated date: 22nd Jun 2024
Total views: 54.3k
Views today: 0.54k
54.3k+ views
Hint: The bonding in the oxygen in dioxygen difluoride is different than the usual. This is particularly because of the very short distance between $\text{O-O}$ the bond and a long-distance along with the $\text{O-F}$bond. Thus the two $\text{O-F}$ bonds are arranged in the two planes perpendicular to each other. Such that the ${{\text{O}}_{\text{2}}}{{\text{F}}_{\text{2}}}$ exhibit open book structure.

Complete step by step solution:
The ${{\text{O}}_{\text{2}}}{{\text{F}}_{\text{2}}}$has a large dihedral angle that approaches $\text{9}{{\text{0}}^{\text{0}}}\text{C}$ and has ${{\text{C}}_{\text{2}}}$ an axis of symmetry.
The VSEPR theory is used to decide the geometry of${{\text{O}}_{\text{2}}}{{\text{F}}_{\text{2}}}$.
The two oxygen atoms are bonded by the peroxide linkage. Each oxygen atom is bonded to a fluorine atom. The Lewis dot structure for the ${{\text{O}}_{\text{2}}}{{\text{F}}_{\text{2}}}$is as follows:

This ${{\text{O}}_{\text{2}}}{{\text{F}}_{\text{2}}}$ is an open book type structure. Since the oxygen has the two-electron pair the structure cannot be linear but it is like the fluorine atom is in a different plane. The structure is as follows:

Let's have a look at the option.
In ${{\text{C}}_{\text{2}}}{{\text{F}}_{\text{2}}}$ , the two carbon atoms are forming a covalent bond and each carbon is bonded to the two fluorine atom. the structure of the ${{\text{C}}_{\text{2}}}{{\text{F}}_{\text{2}}}$ is as shown below:

The two carbon atoms share the three bonds. Since the carbon is a $\text{sp}$ hybridized. The ${{\text{C}}_{\text{2}}}{{\text{F}}_{\text{2}}}$ have a linear structure.
Hydrogen peroxide ${{\text{O}}_{\text{2}}}{{\text{H}}_{\text{2}}}$ is a nonplanar molecule. Two oxygen are bonded with each other forming a peroxide bond. Each oxygen atom is bonded to the hydrogen atom. Since each oxygen has two lone pairs of electrons on it. The structure is not planar. Instead of that, it is non-planar when two hydrogen atoms are in a different plane. It has an open book structure as shown below.

 The ${{\text{H}}_{\text{2}}}{{\text{F}}_{\text{2}}}$ is a dimer of $\text{HF}$. Since the $\text{HF}$ is linear molecule the dimer ${{\text{H}}_{\text{2}}}{{\text{F}}_{\text{2}}}$ is also a linear molecule.

The ${{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}$ is a linear molecule. Here carbon is a $\text{sp}$ hybridized.
Therefore, hydrogen peroxide ${{\text{O}}_{\text{2}}}{{\text{H}}_{\text{2}}}$ has a similar shape ${{\text{O}}_{\text{2}}}{{\text{F}}_{\text{2}}}$.

Hence, (B) is the correct option.

Note: In general cases, the oxygen exhibits the $-2$ oxidation state. The peroxides like hydrogen peroxide have an unusual oxidation state of oxygen. The compound is electrically neutral. Thus oxidation state of oxygen is:
& \text{2(+1) + 2(x) = 0} \\
& \text{+2 = }-\text{2 x} \\
& \therefore \text{O}\text{.S}\text{.of oxygen = }-\frac{2}{2}=\text{ }-1 \\
Therefore, the oxidation state of oxygen in hydrogen peroxide is $\text{ }-1\text{ }$.
The lone pairs on oxygen restricts the linear structure of hydrogen peroxide or ${{\text{O}}_{\text{2}}}{{\text{F}}_{\text{2}}}$ and the structure is open book structure.