The ratio of electrostatic constant to gravitational constant is nearly
(A) ${10^{10}}$
(B) ${10^5}$
(C) ${10^{20}}$
(D) $100$
Answer
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Hint To answer this question we should know that the electrostatic constant is the proportionality constant in the electrodynamics equations. The value of this constant depends upon the medium that the objects which are charged are immersed in. And the gravitational constant is defined as the physical constant that appears in the equation of Newton's laws of gravitation.
Complete step by step answer
We know that,
The Electrostatic Constant is represented as K which is given as: $9 \times {10^9}N{m^2}{C^{ - 2}}$
The Gravitational Constant is represented as G which is given as: $6.67 \times {10^{ - 11}}N{m^2}k{g^{ - 2}}$
So now the ratio between the Electrostatic Constant or K and Gravitational Constant or G is given as:
$\dfrac{K}{G} = \dfrac{{9 \times {{10}^9}}}{{6.67 \times {{10}^{ - 11}}}} = 1.3493 \times {10^{20}}$
So, the ration of the electrostatic constant to the gravitational constant is given as nearly as ${10^{20}}$.
Hence, the correct answer is Option C.
Note We should know that electrostatic force is defined as the attractive or the repulsive force between the two electrically charged objects. The like charges will repel each other and the unlike charges will attract each other. On the other hand, the gravitational force is defined as the attraction of the earth’s mass for the objects which are nearer to the surface of the earth. It should be known to us that more will be the object far from the surface of the earth, the less will be the gravity. The gravitational force is described as the product of the masses of the objects divided by the square of the distance between the objects.
Complete step by step answer
We know that,
The Electrostatic Constant is represented as K which is given as: $9 \times {10^9}N{m^2}{C^{ - 2}}$
The Gravitational Constant is represented as G which is given as: $6.67 \times {10^{ - 11}}N{m^2}k{g^{ - 2}}$
So now the ratio between the Electrostatic Constant or K and Gravitational Constant or G is given as:
$\dfrac{K}{G} = \dfrac{{9 \times {{10}^9}}}{{6.67 \times {{10}^{ - 11}}}} = 1.3493 \times {10^{20}}$
So, the ration of the electrostatic constant to the gravitational constant is given as nearly as ${10^{20}}$.
Hence, the correct answer is Option C.
Note We should know that electrostatic force is defined as the attractive or the repulsive force between the two electrically charged objects. The like charges will repel each other and the unlike charges will attract each other. On the other hand, the gravitational force is defined as the attraction of the earth’s mass for the objects which are nearer to the surface of the earth. It should be known to us that more will be the object far from the surface of the earth, the less will be the gravity. The gravitational force is described as the product of the masses of the objects divided by the square of the distance between the objects.
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