
The ratio of electric fields on the axis and at equator of an electric dipole will be
A. 1:1
B. 2:1
C. 4:1
D. 1:4
Answer
217.5k+ views
Hint:Magnetic field strength is also called magnetic intensity or magnetic field intensity. Magnetic intensity can be calculated as the ratio of the strength of the magnetizing field to the permeability of free space. Be careful in order to find the electric field at the axis and at the equator of an electric dipole.
Formula used:
Magnitude of the intensity of electric field at a distance r on axial line is given as,
\[{E_a} = \dfrac{1}{{4\pi {\varepsilon _0}}} \times \dfrac{{2p}}{{{r^3}}}\]
Where p is electric dipole moment, \[{E_a}\] is the intensity of electric field on axial line, r is distance from dipole, k is coulomb’s constant, \[k = \dfrac{1}{{4\pi {\varepsilon _0}}} = 9 \times {10^9}N{m^2}\] and \[{\varepsilon _0}\] is permittivity.
Magnitude of the intensity of electric field at a distance r on equatorial line is given as,
\[{E_e} = \dfrac{1}{{4\pi {\varepsilon _0}}} \times \dfrac{p}{{{r^3}}}\]
Where p is the dipole moment, \[{E_e}\] is the intensity of the electric field on the equatorial line.
Complete step by step solution:
Given magnitude of intensity of electric field at a distance x on axial line is equal to magnitude of intensity of electric field at a distance y on equatorial line. As we know magnitude of the intensity of electric field at a distance x on axial line,
\[{E_a} = \dfrac{1}{{4\pi {\varepsilon _0}}} \times \dfrac{{2p}}{{{r^3}}}\]
Magnitude of the intensity of electric field at a distance y on equatorial line,
\[{E_e} = \dfrac{1}{{4\pi {\varepsilon _0}}} \times \dfrac{p}{{{r^3}}}\]
Now according to the question equating both the terms, we get
\[\dfrac{{{E_a}}}{{{E_e}}} = \dfrac{{k \times \dfrac{{2p}}{{{r^3}}}}}{{k \times \dfrac{p}{{{r^3}}}}}\]
\[where,{\rm{ }}k = \dfrac{1}{{4\pi {\varepsilon _0}}}\]
By arranging this
\[\dfrac{{{E_a}}}{{{E_e}}} = \dfrac{2}{1}\]
Therefore the ratio is, \[{E_a}:{E_e} = 2:1\]. Therefore the ratio of electric fields on the axis and at equator of an electric dipole will be
Hence option B is the correct answer.
Note: The magnetic intensity is how much the magnetic field can magnetize a substance. Also the magnetic intensity can be defined as the capability of the magnetic field to magnetize the substance. The intensity of magnetization is defined as the change in the magnetic moment per unit volume. The ratio gives the relation between two amounts of the same quantity showing how many times one amount is with the other.
Formula used:
Magnitude of the intensity of electric field at a distance r on axial line is given as,
\[{E_a} = \dfrac{1}{{4\pi {\varepsilon _0}}} \times \dfrac{{2p}}{{{r^3}}}\]
Where p is electric dipole moment, \[{E_a}\] is the intensity of electric field on axial line, r is distance from dipole, k is coulomb’s constant, \[k = \dfrac{1}{{4\pi {\varepsilon _0}}} = 9 \times {10^9}N{m^2}\] and \[{\varepsilon _0}\] is permittivity.
Magnitude of the intensity of electric field at a distance r on equatorial line is given as,
\[{E_e} = \dfrac{1}{{4\pi {\varepsilon _0}}} \times \dfrac{p}{{{r^3}}}\]
Where p is the dipole moment, \[{E_e}\] is the intensity of the electric field on the equatorial line.
Complete step by step solution:
Given magnitude of intensity of electric field at a distance x on axial line is equal to magnitude of intensity of electric field at a distance y on equatorial line. As we know magnitude of the intensity of electric field at a distance x on axial line,
\[{E_a} = \dfrac{1}{{4\pi {\varepsilon _0}}} \times \dfrac{{2p}}{{{r^3}}}\]
Magnitude of the intensity of electric field at a distance y on equatorial line,
\[{E_e} = \dfrac{1}{{4\pi {\varepsilon _0}}} \times \dfrac{p}{{{r^3}}}\]
Now according to the question equating both the terms, we get
\[\dfrac{{{E_a}}}{{{E_e}}} = \dfrac{{k \times \dfrac{{2p}}{{{r^3}}}}}{{k \times \dfrac{p}{{{r^3}}}}}\]
\[where,{\rm{ }}k = \dfrac{1}{{4\pi {\varepsilon _0}}}\]
By arranging this
\[\dfrac{{{E_a}}}{{{E_e}}} = \dfrac{2}{1}\]
Therefore the ratio is, \[{E_a}:{E_e} = 2:1\]. Therefore the ratio of electric fields on the axis and at equator of an electric dipole will be
Hence option B is the correct answer.
Note: The magnetic intensity is how much the magnetic field can magnetize a substance. Also the magnetic intensity can be defined as the capability of the magnetic field to magnetize the substance. The intensity of magnetization is defined as the change in the magnetic moment per unit volume. The ratio gives the relation between two amounts of the same quantity showing how many times one amount is with the other.
Recently Updated Pages
Elastic Collision in Two Dimensions Explained Simply

Elastic Collisions in One Dimension Explained

Electric Field of Infinite Line Charge and Cylinders Explained

Electric Flux and Area Vector Explained Simply

Electric Field of a Charged Spherical Shell Explained

Electricity and Magnetism Explained: Key Concepts & Applications

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Understanding Atomic Structure for Beginners

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Understanding Electromagnetic Waves and Their Importance

Understanding the Electric Field of a Uniformly Charged Ring

