
The magnifying power of an astronomical telescope is $8$, then the ratio of the focal length of the objective to the focal length of the eyepiece is:
\[(A)8\]
\[(B)\dfrac{1}{8}\]
\[(C)0.45\]
\[(D){\text{None of these}}\]
Answer
218.7k+ views
Hint: Magnification power is the amount that defines how much an instrument that can enlarge an object. Find the formula of the magnifying power of the astronomical telescope, you will find the required ratio by putting the value given in the problem.
Formula used:
\[{\text{Magnifying power = }}\dfrac{{{\text{focal length of the objective}}}}{{{\text{focal length of the eye piece}}}}\]
Complete step by step answer:
A telescope is generally of two types – Astronomical telescope and Terrestrial telescope. The stars of the sky are observed by the Astronomical telescope. In this case, the final image is inverse according to the object.
Magnification power is the amount that defines how much an instrument that can enlarge an object. This has a direct relationship with the focal length. The magnification or the magnifying power also changes when the eyepiece changes.
The magnifying power of the telescope is defined as the ratio of the focal length of the objective and the focal length of the eyepiece i.e.
\[{\text{Magnifying power = }}\dfrac{{{\text{focal length of the objective}}}}{{{\text{focal length of the eye piece}}}}\]
Here we are asked the ratio of the focal length of the objective to the focal length of the eyepiece.
Given, The magnifying power of an astronomical telescope is $8$.
\[\therefore {\text{Magnifying power = 8 = }}\dfrac{{{\text{focal length of the objective}}}}{{{\text{focal length of the eye piece}}}}\]
So the amount is $8$ .
Hence the right answer is In option A, 8.
Note: The telescope is structural of two types: a Refracting telescope and a Reflecting telescope. In the Refracting telescope, the objective is made up of one or more lenses. In the Reflecting telescope, big concave or parabolic mirrors are used as the objective.
Nowadays many types of telescopes are used like Radio Telescope, Infrared Telescope, X-ray Telescope, High energy Telescope, and Gravitational-wave Telescope.
Formula used:
\[{\text{Magnifying power = }}\dfrac{{{\text{focal length of the objective}}}}{{{\text{focal length of the eye piece}}}}\]
Complete step by step answer:
A telescope is generally of two types – Astronomical telescope and Terrestrial telescope. The stars of the sky are observed by the Astronomical telescope. In this case, the final image is inverse according to the object.
Magnification power is the amount that defines how much an instrument that can enlarge an object. This has a direct relationship with the focal length. The magnification or the magnifying power also changes when the eyepiece changes.
The magnifying power of the telescope is defined as the ratio of the focal length of the objective and the focal length of the eyepiece i.e.
\[{\text{Magnifying power = }}\dfrac{{{\text{focal length of the objective}}}}{{{\text{focal length of the eye piece}}}}\]
Here we are asked the ratio of the focal length of the objective to the focal length of the eyepiece.
Given, The magnifying power of an astronomical telescope is $8$.
\[\therefore {\text{Magnifying power = 8 = }}\dfrac{{{\text{focal length of the objective}}}}{{{\text{focal length of the eye piece}}}}\]
So the amount is $8$ .
Hence the right answer is In option A, 8.
Note: The telescope is structural of two types: a Refracting telescope and a Reflecting telescope. In the Refracting telescope, the objective is made up of one or more lenses. In the Reflecting telescope, big concave or parabolic mirrors are used as the objective.
Nowadays many types of telescopes are used like Radio Telescope, Infrared Telescope, X-ray Telescope, High energy Telescope, and Gravitational-wave Telescope.
Recently Updated Pages
A square frame of side 10 cm and a long straight wire class 12 physics JEE_Main

The work done in slowly moving an electron of charge class 12 physics JEE_Main

Two identical charged spheres suspended from a common class 12 physics JEE_Main

According to Bohrs theory the timeaveraged magnetic class 12 physics JEE_Main

ill in the blanks Pure tungsten has A Low resistivity class 12 physics JEE_Main

The value of the resistor RS needed in the DC voltage class 12 physics JEE_Main

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Understanding Uniform Acceleration in Physics

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Understanding Atomic Structure for Beginners

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding Centrifugal Force in Physics

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Degree of Dissociation: Meaning, Formula, Calculation & Uses

